Not sure if this question is duplicated yet or not.
I have a simplified table below
User
Interest
Jason
Art
Jason
Sport
Sam
Sport
Sam
Art
Steve
Sport
Desmond
Sport
Tania
Art
Here's the result that I want to achieve
Interest
Count
Art
2
Sport
2
Both
2
I Managed to make a subquery to achieve the value for the Both data by this query
SELECT COUNT(USER) FROM (
SELECT User, COUNT(DISTINCT Interest) as interest_type FROM table WHERE interest_type = 2)
But for the user that are exclusively have Interest in Art and in Sport it's not separated.
You could use conditional aggregation here:
WITH cte AS (
SELECT User,
CASE WHEN COUNT(CASE WHEN Interest = 'Art' THEN 1 END) > 0 AND
COUNT(CASE WHEN Interest = 'Sport' THEN 1 END) > 0
THEN 'Both'
WHEN COUNT(CASE WHEN Interest = 'Art' THEN 1 END) > 0
THEN 'Art'
ELSE 'Sport' END AS Interest
FROM yourTable
GROUP BY User
)
SELECT Interest, COUNT(*) AS Count
FROM cte
GROUP BY Interest;
On MySQL or BigQuery, we can shorten the above to:
WITH cte AS (
SELECT User,
CASE WHEN SUM(Interest = 'Art') > 0 AND SUM (Interest = 'Sport') > 0
THEN 'Both'
WHEN SUM(Interest = 'Art') > 0
THEN 'Art'
ELSE 'Sport' END AS Interest
FROM yourTable
GROUP BY User
)
SELECT Interest, COUNT(*) AS Count
FROM cte
GROUP BY Interest;
Assuming your database supports the over() clause:
select
case when num_interests = 1 then interest else 'both' end as interest
, count(distinct user) as "Count"
from (
select
interest
, user
, count(*) over(partition by user) as num_interests
from yourTable
) d
group by
case when num_interests = 1 then interest else 'both' end
Related
Decided to break my query in to bits, to help communicate what I am trying to achieve.
I have some information about a Customer and the Coupon Code they've used, in this format
Customer
Coupon Code
1
FreeDel
1
FreeDel
1
FreeDel
1
1562733
1
8842939
1
847hr64
1
83jd63j
1
FreeDel
1
8eh33jr
1
AA-2637
1
AA-9837
1
Save200
1
Save200
I want to sort it so that: If a known coupon-code prefix is available, then using syntax like this:
CASE WHEN Coupon Code LIKE 'AA-%' THEN 'AA-'
CASE WHEN Coupon Code IS UNIQUE THEN 'UNIQUE'
CASE WHEN Coupon Code IS NOT UNIQUE THEN 'NON-UNIQUE'
And so to output
Count
Customer
Coupon Code Type
6
1
Non-Unique
2
1
AA-
5
1
Unique
In this ideal, the known prefixes are added first as cases, and then unknown, unrepeated Coupon Codes are labelled Unique and then repeated Coupon Codes are labelled Non-Unique.
Any help would be super appreciated! :)
Table edits
You could count them separately:
select sum(cnt), customer, 'Non-Unique'
from (
select customer, coupon_code, count(*) as cnt
from ccodes
where coupon_code not like 'AA-%'
group by customer, coupon_code
having cnt>1
) as q
group by customer
union
select count(*), customer, 'AA-'
from ccodes
where coupon_code like 'AA-%'
group by customer
union
select sum(cnt), customer, 'Unique'
from (
select customer, coupon_code, count(*) as cnt
from ccodes
where coupon_code not like 'AA-%'
group by customer, coupon_code
having cnt=1
) as q
group by customer
See db-fiddle
You can use aggregation and conditional logic:
(case when sum( code like 'AA-%' ) > 0 then 'AA-'
when min(code) = max(code) then 'UNIQUE'
else 'NON-UNIQUE'
end)
You can incorporate this into an aggregation query as:
select grp, count(*)
from (select c.customer,
(case when sum( code like 'AA-%' ) > 0 then 'AA-'
when min(code) = max(code) then 'UNIQUE'
else 'NON-UNIQUE'
end) as grp,
count(*)
from c
group by customer
) x
group by grp;
I have a table which consists of the following details
Customer
Deal
DealStage
A
D1
Lost
A
D2
Won
A
D3
Contacted
B
D4
Conatcted
B
D5
Lost
C
D6
Lost
D
D7
Lost
I have to develop a query where I should get the unique highest stage for each customer. The Stage priority is Won > Contacted > Lost. For Example, A is having three deals which are Won, Lost, and Contacted. So I should be considering Won. Similarly Contacted for B and Lost for C and D
Is it possible to get an Output like
Customer
Highets Stage
A
Won
B
Contacted
C
Lost
D
Lost
By this, I can generate a pivot table that looks like
Stage
CustomerCount
Won
1
Contacted
1
Lost
2
Thanks in Advance
One option uses aggregation and field():
select customer,
case min(field(deal_stage, 'Won', 'Contacted', 'Lost'))
when 1 then 'Won'
when 2 then 'Contacted'
when 3 then 'Lost'
end as highest_stage
from mytable
group by customer
Actually we could combine this with elt():
select customer,
elt(
min(field(deal_stage, 'Won', 'Contacted', 'Lost')),
'Won', 'Contacted', 'Lost'
) as highest_stage
from mytable
group by customer
You can then generate the final result with another level of aggregation:
select highest_stage, count(*)
from (
select customer,
elt(
min(field(deal_stage, 'Won', 'Contacted', 'Lost')),
'Won', 'Contacted', 'Lost'
) as highest_stage
from mytable
group by customer
) t
group by highest_stage
Use windows function as follows:
select * from
(select t.*,
row_number() over (partition by customer
order by case when dealstage = 'Won' then 1
when dealstage = 'Contacted' then 2
when dealstage = 'Lost' then 3
end
) as rn
from your_table t)
where rn = 1;
These are really two different problems. I would, in fact, recommend different approaches to the two. For the first, conditional aggregation:
select customer,
coalesce(max(case when state = 'Won' then state end),
max(case when state = 'Contacted' then state end),
max(case when state = 'Lost' then state end)
) as biggest_state
from t
group by customer;
However, for your final result, I would recommend a correlated subquery:
select t.state, count(*)
from t
where t.state = (select t2.state
from t2
where t2.customer = t.customer
order by field(state, 'Won', 'Contact', 'Lost')
limit 1
)
group by t.state;
Note: This assumes that the original data does not have duplicate rows. If it does, then count(distinct) is one adjustment.
I have a table called votes with 4 columns: id, name, choice, date.
****id****name****vote******date***
****1*****sam*******A******01-01-17
****2*****sam*******B******01-05-30
****3*****jon*******A******01-01-19
My ultimate goal is to count up all the votes, but I only want to count 1 vote per person, and specifically each person's most recent vote.
In the example above, the result should be 1 vote for A, and 1 vote for B.
Here is what I currently have:
select name,
sum(case when uniques.choice = A then 1 else 0 end) votesA,
sum(case when uniques.choice = B then 1 else 0 end) votesB
FROM (
SELECT id, name, choice, max(date)
FROM votes
GROUP BY name
) uniques;
However, this doesn't work because the subquery is indeed selecting the max date, but it's not including the correct choice that is associated with that max date.
Don't think "group by" to get the most recent vote. Think of join or some other option. Here is one way:
SELECT v.name,
SUM(v.choice = 'A') as votesA,
SUM(v.choice = 'B') as votesB
FROM votes v
WHERE v.date = (SELECT MAX(v2.date) FROM votes v2 WHERE v2.name = v.name)
GROUP BY v.name;
Here is a SQL Fiddle.
Your answer are close but need to JOIN self
Subquery get Max date by name then JOIN self.
select
sum(case when T.vote = 'A' then 1 else 0 end) votesA,
sum(case when T.vote = 'B' then 1 else 0 end) votesB
FROM (
SELECT name,Max(date) as date
FROM T
GROUP BY name
) AS T1 INNER JOIN T ON T1.date = T.date
SQLFiddle
Try this
SELECT
choice,
COUNT(1)
FROM
votes v
INNER JOIN
(
SELECT
id,
max(date)
FROM
votes
GROUP BY
name
) tmp ON
v.id = tmp.id
GROUP BY
choice;
Something like this (if you really need count only last vote of person)
SELECT
sum(case when vote='A' then cnt else 0 end) voteA,
sum(case when vote='B' then cnt else 0 end) voteB
FROM
(SELECT vote,count(distinct name) cnt
FROM (
SELECT name,vote,date,max(date) over (partition by name) maxd
FROM votes
)
WHERE date=maxd
GROUP BY vote
)
PS. MySQL v 8
select
name,
sum( case when choice = 'A' then 1 else 0 end) voteA,
sum( case when choice = 'B' then 1 else 0 end) voteB
from
(
select id, name, choice
from votes
where date = (select max(date) from votes t2
where t2.name = votes.name )
) t
group by name
Or output just one row for the total counts of VoteA and VoteB:
select
sum( case when choice = 'A' then 1 else 0 end) voteA,
sum( case when choice = 'B' then 1 else 0 end) voteB
from
(
select id, name, choice
from votes
where date = (select max(date) from votes t2
where t2.name = votes.name )
) t
Based on #d-shish solution, and since introduction (in MySQL 5.7) of ONLY_FULL_GROUP_BY, the GROUP BY statement must be placed in subquery like this :
SELECT v.`name`,
SUM(v.`choice` = 'A') as `votesA`,
SUM(v.`choice` = 'B') as `votesB`
FROM `votes` v
WHERE (
SELECT MAX(v2.`date`)
FROM `votes` v2
WHERE v2.`name` = v.`name`
GROUP BY v.`name` # << after
) = v.`date`
# GROUP BY v.`name` << before
Otherwise, it won't work anymore !
I will create a graph of population by gender every year, and the graph looks like the image below.
But I'm having a hard time with the query.
Query
SELECT
year_added,
COUNT(case when gender='Male' then 1 end) as malecount,
COUNT(case when gender='Female' then 1 end) as femalecount,
COUNT(*) as totalcount
FROM tbl
WHERE status = 1
GROUP BY year_added
Result
In the result, 2016 male count is 4 and female count is 8. In 2017, I want the male count of 2016 to be added on the male count on 2017, meaning 2017 male count will be 5, same with female count and total count. I provided an image below of what the result should look like. Can you help me how to do this for me to proceed on doing the graph? Or is there any other way to achieve this?
Try this:
SELECT
year_added,
#malecount_v := #malecount_v + malecount as malecount,
#femalecount_v := #femalecount_v + femalecount as femalecount,
#totalcount_v := #totalcount_v + totalcount as totalcount
FROM (
SELECT
year_added,
COUNT(case when gender='Male' then 1 end) as malecount,
COUNT(case when gender='Female' then 1 end) as femalecount,
COUNT(*) as totalcount
FROM tbl
WHERE status = 1
GROUP BY year_added
ORDER BY year_added
) t1
CROSS JOIN (SELECT #malecount_v := 0, #femalecount_v := 0, #totalcount_v := 0) t2
In Mysql you can do it with variables, like:
SELECT
year_added,
(#iMalecount := (COUNT(CASE WHEN gender = 'Male' THEN 1 END) + #iMalecount)) AS malecount,
(#iFemalecount := (COUNT(CASE WHEN gender = 'Female' THEN 1 END) + #iFemalecount)) AS femalecount,
(#iTotalcount := (COUNT(gender) + #iTotalcount)) AS totalcount
FROM tbl
WHERE status = 1
GROUP BY year_added
but is not 100% fiable as you can read in the documentation.
In other SQL flavour probably you need a stored procedure.
you can simply use
WITH TableCount AS
(
SELECT
year_added,
COUNT(case when gender='Male' then 1 end) as malecount,
COUNT(case when gender='Female' then 1 end) as femalecount,
COUNT(*) as totalcount
FROM tbl
WHERE status = 1
GROUP BY year_added
)
And after that use following query
SELECT
SUM(malecount) as 'malecount',
SUM(femalecount) as 'femalecount',
SUM(totalcount) as 'totalcount'
FROM TableCount
If you are using MySql you can use temporary table to do something like CTE
CREATE TEMPORARY TABLE IF NOT EXISTS TableCount AS (
SELECT
year_added,
COUNT(case when gender='Male' then 1 end) as malecount,
COUNT(case when gender='Female' then 1 end) as femalecount,
COUNT(*) as totalcount
FROM tbl
WHERE status = 1
GROUP BY year_added
)
And then you can use above query
SELECT
SUM(malecount) as 'malecount',
SUM(femalecount) as 'femalecount',
SUM(totalcount) as 'totalcount'
FROM TableCount
You can use the TEMPORARY keyword when creating a table. A TEMPORARY
table is visible only to the current session, and is dropped
automatically when the session is closed. This means that two
different sessions can use the same temporary table name without
conflicting with each other or with an existing non-TEMPORARY table of
the same name. (The existing table is hidden until the temporary table
is dropped.) To create temporary tables, you must have the CREATE
TEMPORARY TABLES privilege.
By using temporary table concept you can achieve common table expression kind of functionality in MySql
The link is http://sqlzoo.net/wiki/The_JOIN_operation. Question No.13.
Now I can list all the matches as long as there is at least one goal with the code:
SELECT mdate,
team1,
SUM(CASE WHEN teamid = team1 THEN 1 ELSE 0 END) AS score1,
team2,
SUM(CASE WHEN teamid = team2 THEN 1 ELSE 0 END) AS score2 FROM
game JOIN goal ON (id = matchid)
GROUP BY id
ORDER BY mdate, matchid, team1, team2
However there are some games the score of which is 0:0. My code can't display these games, and can't find other available solutions. Really hope someone can help me with this problem.
SELECT mdate,
team1,
SUM(CASE WHEN teamid = team1 THEN 1 ELSE 0 END) AS score1,
team2,
SUM(CASE WHEN teamid = team2 THEN 1 ELSE 0 END) AS score2 FROM
game LEFT JOIN goal ON (id = matchid)
GROUP BY mdate,team1,team2
ORDER BY mdate, matchid, team1, team2
You want to GROUP BY columns without aggregate functions in the SELECT and use a LEFT JOIN.
Try LEFT JOIN insted of JOIN. Because you need to show all games even if there are no goals.
SELECT G.mDate
,G.Team1
,ISNULL( (SELECT COUNT(*) FROM goal WHERE teamid = G.Team1), 0) AS Team1_Goals
,G.Team2
,ISNULL( (SELECT COUNT(*) FROM goal WHERE teamid = G.Team2), 0) AS Team2_Goals
FROM Game G
WHERE EXISTS (SELECT 1
FROM goal
WHERE matchid = G.matchid)
If you are using MSSQL engine remove the ORDER BY clause from the accepted answer