Hello I am a beginner in CSS and HTML. I would like to create something a div like this for my school project.
I tried the transform:skewed(25deg) but it wont make my box div balance.
As the comments mention, you can achieve that kind of slant by using clip-path. You just need to make sure to match the path on both your inner + outer elements in order for the border to line up correctly.
.outside {
position: relative;
width: 70vmin;
height: 70vmin;
background: red;
-webkit-clip-path: polygon(0 0, 100% 10%, 100% 100%, 0% 100%);
clip-path: polygon(0 0, 100% 10%, 100% 100%, 0% 100%);
}
.inside {
position: absolute;
top: 5px;
left: 5px;
right: 5px;
bottom: 5px;
background: black;
-webkit-clip-path: polygon(0 0, 100% 10%, 100% 100%, 0% 100%);
clip-path: polygon(0 0, 100% 10%, 100% 100%, 0% 100%);
}
<div class="outside">
<div class="inside"></div>
</div>
If you need a transparent background simliar to the picture you ahve you have to use 2 elements for the top and the bottom and cut it away like this:
:root {
--thickness: 10px;
--color: red;
--width: 50vw;
--total-height: 80vh;
--offset-height: 20vh;
}
.clip-path-top {
width: var(--width);
height: var(--offset-height);
background-color: var(--color);
clip-path: polygon(0 0, var(--thickness) 0, 100% calc(100% - var(--thickness)), 100% 100%, calc(100% - var(--thickness)) 100%, var(--thickness) var(--thickness), var(--thickness) 100%, 0 100%);
}
.clip-path-bottom {
width: var(--width);
height: calc(var(--total-height) - var(--offset-height));
background-color: var(--color);
clip-path: polygon(0 0, var(--thickness) 0, var(--thickness) calc(100% - var(--thickness)), calc(100% - var(--thickness)) calc(100% - var(--thickness)), calc(100% - var(--thickness)) 0, 100% 0, 100% 100%, 0 100%);
}
/* for demo-purpose only */
body {
margin: 0;
min-height: 100vh;
display: flex;
flex-direction: column;
justify-content: center;
align-items: center;
background-color: gray;
}
<div class="clip-path-top"></div>
<div class="clip-path-bottom"></div>
Apply the skew to a pseudo element:
.box {
width: 250px;
height: 250px;
border-bottom: 5px solid red;
position: relative;
overflow: hidden;
}
.box:before {
content: "";
position: absolute;
inset: 0;
border: 5px solid red;
border-bottom: none;
transform-origin: left;
transform: skewY(10deg); /* adjust this */
}
<div class="box"></div>
Related
So, I'm trying to fade out an image that has border-radius: 50% but I can't seem to get it down.
<section id="main">
<h1>Non-Important-Text</h1>
<h4>
it's all fun and games until you can't find a damn solution....
</h4>
<div id="img-container">
<img src="./assets/1.jpg" />
</div>
</section>
/* ... */
#main #img-container {
border-radius: 50%;
display: inline-block;
position: relative;
}
#main #img-container img {
width: 30em;
border-radius: 50%;
display: block;
border: 1px solid white;
}
#main #img-container img::after {
content: "";
display: block;
background: radial-gradient(
ellipse at center,
rgba(255, 255, 255, 0) 0%,
rgba(255, 255, 255, 1) 100%
); /* This doesn't work! */
border-radius: 50%;
position: absolute;
top: 0;
left: 0;
right: 0;
bottom: 0;
}
My Image, is circle, and does have a border. But it doensn't get faded out( in a circular way). How can I achieve that
Goal:
What I Get:
I tried everything from, radial-gradient, -webkit-gradient, to even, -webkit-radial-gradient. But they all produce the same result!
you need to use mask-image
div{
background: skyblue;
padding: 20px;
}
img{
-webkit-mask-image: radial-gradient(circle at center, rgba(0,0,0,1) 0, rgba(0,0,0,0) 70%);
mask-image: radial-gradient(circle at center, rgba(0,0,0,1) 0, rgba(0,0,0,0) 70%);
display: block;
margin: 0 auto
}
<div><img src='data:image/jpeg;base64,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' /></div>
I coded the display of two beveled photos on top of each other and I try to make it responsive without success (I think that using the right units of measurement we can do it).
Here's where I'm at (I put fixed pixel sizes on the elements so you can see the desired rendering) :
.container {
display: flex;
-webkit-box-orient: vertical;
-webkit-box-direction: normal;
-ms-flex-direction: column;
flex-direction: column;
-webkit-box-align: center;
-ms-flex-align: center;
align-items: center;
width: 100%;
margin-right: auto;
margin-left: auto;
}
.img-shape {
width: 400px;
height: 400px;
overflow: hidden;
}
.img-shape:nth-child(2n-1) {
border-top-left-radius: 1.3rem;
border-top-right-radius: 1.3rem;
-webkit-clip-path: polygon(0% 0, 100% 0, 100% 50%, 0 100%);
clip-path: polygon(0% 0, 100% 0, 100% 50%, 0 100%);
}
.img-shape:nth-child(2n) {
margin-top: -185px;
border-bottom-right-radius: 1.3rem;
border-bottom-left-radius: 1.3rem;
-webkit-clip-path: polygon(0 50%, 100% 0, 100% 100%, 0 100%);
clip-path: polygon(0 50%, 100% 0, 100% 100%, 0 100%);
}
.img-shape img {
width: 100%;
}
<div class="container">
<div class="img-shape">
<img src="https://cdn.pixabay.com/photo/2020/11/10/10/08/architecture-5729165_960_720.jpg" alt="test">
</div>
<div class="img-shape">
<img src="https://cdn.pixabay.com/photo/2020/11/10/01/34/pet-5728249_960_720.jpg" alt="test">
</div>
</div>
Below the maximum .max-width size, I'd like the content to fit the size of the .container without distortion or offset.
Would you be able to help me?
Thank you
PS : Do you think my code is feasible in production or is there a risk of incompatibility?
Update the code like below and rely on percentage:
.container {
max-width: 400px;
margin: auto
}
.img-shape {
overflow: hidden;
position:relative;
}
.img-shape::before { /* this will maitain a square shape */
content:"";
padding-top:100%;
display:block;
}
.img-shape:nth-child(2n-1) {
border-radius: 1.3rem 1.3rem 0 0;
clip-path: polygon(0% 0, 100% 0, 100% 50%, 0 100%);
}
.img-shape:nth-child(2n) {
margin-top: calc(-50% + 20px); /* the gap is 20px */
border-radius: 0 0 1.3rem 1.3rem;
clip-path: polygon(0 50%, 100% 0, 100% 100%, 0 100%);
}
.img-shape img {
position:absolute;
top:0;
left:0;
width: 100%;
height:100%;
object-fit:cover;
object-position:top;
}
<div class="container">
<div class="img-shape">
<img src="https://cdn.pixabay.com/photo/2020/11/10/10/08/architecture-5729165_960_720.jpg" alt="test">
</div>
<div class="img-shape">
<img src="https://cdn.pixabay.com/photo/2020/11/10/01/34/pet-5728249_960_720.jpg" alt="test">
</div>
</div>
That you can also simplify like below:
.container {
max-width: 400px;
margin: auto
}
.container::before,
.container::after{
content: "";
padding-top: 100%;
display: block;
background:top/cover;
}
.container::before {
border-radius: 1.3rem 1.3rem 0 0;
clip-path: polygon(0% 0, 100% 0, 100% 50%, 0 100%);
background-image:url(https://cdn.pixabay.com/photo/2020/11/10/10/08/architecture-5729165_960_720.jpg)
}
.container::after {
margin-top: calc(-50% + 20px); /* the gap is 20px */
border-radius: 0 0 1.3rem 1.3rem;
clip-path: polygon(0 50%, 100% 0, 100% 100%, 0 100%);
background-image:url(https://cdn.pixabay.com/photo/2020/11/10/01/34/pet-5728249_960_720.jpg)
}
<div class="container"></div>
I need to create a responsive triangle <div>. I was able to create it using css skewed, but it is not responsive, when I change the screen width it gets messed up. Can someone help me? Thank you very much in advance!
Here is what I want:
This is the code I have so far:
.skewed-box-one:before {
background-color: red;
content: '';
height: 100px;
width: 30.05%;
display: block;
visibility: visible;
position: absolute;
top: -40px;
transform: skewY(8deg);
border-top: 3px solid #BBDEFB;
}
.skewed-box-one:after {
background-color: red;
content: '';
height: 130px;
width: 70%;
display: block;
visibility: visible;
position: absolute;
top: -46px;
right: 0;
transform: skewY(-4deg);
border-top: 3px solid #BBDEFB;
}
<div class="skewed-box-one"></div>
You could use CSS clip-path, do note that broswer support is limited. With this tool you can generate the shape you want.
.triangle1 {
clip-path: polygon(50% 0%, 100% 84%, 100% 100%, 0 100%, 0 84%);
background: red;
width: 100%;
height: 100%;
}
.triangle2 {
clip-path: polygon(50% 0%, 0% 100%, 100% 100%);;
background: red;
width: 100%;
height: 100%;
}
.container {
width: 50%;
height: 300px;
margin-bottom: 20px;
}
<div class="container">
<div class="triangle1">1</div>
</div>
<div class="container">
<div class="triangle2">2</div>
</div>
I could solve this problem with #SuperDJ help, usingclip-path. I also find this website that helps to draw shapes:
https://bennettfeely.com/clippy/
Here is the final code i used:
.triangle1 {
position: absolute;
-webkit-clip-path: polygon(21% 96%, 0 54%, 100% 54%);
clip-path: polygon(21% 96%, 0 54%, 100% 54%);
background: #BBDEFB;
width: 100%;
height: 200px;
margin-top: -40px;
}
Thanks very much everybody that tryed to help and a special thanks to #SuperDJ!
Here is another idea more supported than clip-path using background coloration
.box-down {
height:80px;
padding-bottom:50px;
background:
linear-gradient(to bottom right,red 48%, transparent 50%) bottom right/30% 50px,
linear-gradient(to bottom left ,red 48%, transparent 50%) bottom left/70.1% 50px,
red content-box;
background-repeat:no-repeat;
}
.box-up {
height:80px;
padding-top:50px;
background:
linear-gradient(to top right,red 48%, transparent 50%) top right/70% 50px,
linear-gradient(to top left ,red 48%, transparent 50%) top left /30.1% 50px,
red content-box;
background-repeat:no-repeat;
margin-top:20px;
}
<div class="box-down"></div>
<div class="box-up"></div>
I am attempting to display an image, and want it to carry into a little triangle under the <div>. I have seen this question which drags the triangle across the whole page. I would like to display a triangle that only takes up a small space (like the image) Instead of the solid colored background, there's a background image.
div {
width: 100%;
background-image: url("https://www.shopmarriott.com/images/products/v2/xlrg/Marriott-platinum-stitch-bed-bedding-set-mar-101-st-gy_xlrg.jpg");
max-height: 200px;
padding: 75px;
position: relative;
background-size:cover;
padding-bottom:100px;
overflow:hidden;
}
div:after {
margin-left:-30px;
left: 50%;
content:'';
margin-left: -30px;
margin-top: 70px;
position:absolute;
border-left:30px solid #fff;
border-right:30px solid #fff;
border-top:30px solid transparent;
}
h1 {
color: white;
font-size: 36px;
text-align: center;
}
<div>
<h1>Sheets</h1>
</div>
You would have to use clip-path if your using a background image.
div {
background-image: url(https://upload.wikimedia.org/wikipedia/commons/thumb/3/3a/Cat03.jpg/1200px-Cat03.jpg);
background-repeat: no-repeat;
background-size: cover;
width: 500px;
height: 500px;
-webkit-clip-path: polygon(0% 0%, 100% 0%, 100% 75%, 66% 75%, 50% 99%, 33% 75%, 0% 75%);
clip-path: polygon(0% 0%, 100% 0%, 100% 75%, 66% 75%, 50% 99%, 33% 75%, 0% 75%);
}
<div></div>
To help you create the size and style you want you can use this online Clippy tool (hint: select the "Message" pre-made shape and play with that)
.container {
position:relative;
background-color:#e15915;
height:320px !important;
width:100% !important;
}
.container:after {
content:'';
position: absolute;
top: 100%;
left: 0;
right: 0;
margin: 0 auto;
width: 0;
height: 0;
border-top: solid 50px #e15915;
border-left: solid 50px transparent;
border-right: solid 50px transparent;
}
http://jsfiddle.net/9AbYc/1/
I want to make a div into 2 triangles (as shown in below, no problem if 1 is background of parent) upper one with one color and lower one with another. I dont mind how it is implemented but i want to do it in css (not javascript). I tried with css rotation, (code below), but its not responsive. In smaller or wider screen it is distorted . Any way to implement this in css?
body {
background: #eee;
}
.darker {
position: fixed;
top: -94%;
left: -10%;
width: 150%;
height: 150%;
background: #dd4f39;
-webkit-transform: rotate(30deg);
transform: rotate(30deg);
}
<div class="darker"> </div>
I found an interesting way to do this from here, which uses clip-path
.Answering my own question so that everyone can use it.
html,
body {
margin: 0;
}
body {
background: #eee;
}
.box {
width: 100vw;
height: 100vh;
background-color: #dd4f39;
clip-path: polygon(0 0, 100% 0, 100% 100%);
}
<div class="box"></div>
This is one way of doing it. But this use case is strictly with respect to vw. Just make sure to give the same value to these elements
div and it's pseudo element should have same width and border-left respectively.
div and it's pseudo element should have same height and border-top respectively.
html, body {
margin: 0;
}
.box {
width: 100vw;
height: 100vh;
background-color: white;
}
.box::after {
content: ' ';
border-top: 100vh solid #dd4f39;
border-left: 100vw solid transparent;
width: 0;
position: absolute;
}
<div class="box"></div>
JS fiddle
https://jsfiddle.net/kqsrmrss/2/
You can do that with a skewed pseudo element. The main trick is to keep the aspect ratio the same or else the sloped angle will fail
Fiddle demo
Stack snippet Note 1
body {
background: #eee;
}
.darker {
position: absolute;
top: 0;
left: 0;
width: 100%;
padding-top: 50%;
background: #dd4f39;
overflow: hidden;
}
.darker::after {
content: '';
position: absolute;
top: 0;
left: 0;
width: 100%;
height: 100%;
background: gray;
transform: skewY(26.5deg);
transform-origin: left top;
}
<div class="darker"></div>
Optionally, you can add media query to control the angle at different screen sizes
Fiddle demo 2
With a tiny script running when window resize's, you can control the angle and make it fully responsive both horizontally and vertically.
Note 1 Based on a comment, the Stack snippet might not work properly, and if, try the fiddle demos.
Please Use this code snippet.
div {
width: 100%;
height: 100px;
}
.diagonalRising {
border: 1pt solid black;
background: linear-gradient(to right bottom, #eeeeee 0%, #eeeeee 49.9%, #eeeeee 50%, #000000 51%, #dd4f39 51.1%, #dd4f39 100%);
}
.diagonalFalling {
background: linear-gradient(to right top, #eeeeee 0%, #eeeeee 49.9%, #000000 50%, #000000 51%, #dd4f39 51.1%, #dd4f39 100%);
}
.diagonalCross {
position: relative;
background: linear-gradient(to right bottom, rgba(0, 0, 0, 0) 0%, rgba(0, 0, 0, 0) 49.9%, rgba(0, 0, 0, 1) 50%, rgba(0, 0, 0, 1) 51%, rgba(0, 0, 0, 0) 51.1%, rgba(0, 0, 0, 0) 100%);
}
.diagonalCross:after {
content: "";
display: block;
position: absolute;
width: 100%;
height: 100%;
top: 0;
left: 0;
z-index: -1;
background: linear-gradient(to right top, #ffffff 0%, #ffffff 49.9%, #000000 50%, #000000 51%, #ffffff 51.1%, #ffffff 100%);
}
<div class="diagonalRising"></div>
<div class="diagonalFalling"></div>
<div class="diagonalCross"></div>
Try this,
.box::after {
background: #E52A35
content: '';
position: absolute;
width: 100%;
height: 100vh;
background-color: #dd4f39;
clip-path: polygon(52% 13%, 104% -1%, -1% 0%);
}