Pop() and append() to next row - google-apps-script

Question

In this spreadsheet, I have a row with all the employee data, with values coming from another table; In order to create the layout requested, I need 3 rows per employee, each row starting with the |1|,|1.1|,|1.1|, I found some code here that allows me to append two rows to every row of data, but no idea how to move the |1.1|,GTF,'100' to the next row, and then, |1.1|,PPA,'15' to the next one.
This is what i have:
|1|,'900','04000','0000','0','0000','0','11','0','S','A',|1.1|,GTF,'100',|1.1|,PPA,'15'
|1|,'986','01000','0000','0','0000','0','14','0','S','A',|1.1|,GTF,'110',|1.1|,PPA,'30'
|1|,'1046','01000','0000','0','0000','0','14','0','S','A',|1.1|,GTF,'120',|1.1|,PPA,'45'
And what Im looking for is to look like this:
|1|,'900','04000','0000','0','0000','0','11','0','S','A'
|1.1|,GTF,'100'
|1.1|,PPA,'15'
|1|,'986','01000','0000','0','0000','0','14','0','S','A',
|1.1|,GTF,'110'
|1.1|,PPA,'30'
function insertRows() {
var startRow = 1;
var ss = SpreadsheetApp.getActiveSpreadsheet();
var sheet = ss.getSheetByName("Prenom");
var sourceRange = sheet.getRange(startRow, 1, sheet.getLastRow());
var sheetData = sourceRange.getValues();
var numRows = sourceRange.getNumRows() - startRow;
// Logger.log(numRows);
for (var i=numRows; i > -1; i--) {
if (sheetData[i].join("")) {
sheet.insertRowsAfter(i + startRow, 2);
}
}
}
Which leaves me with two empty rows. ty

Answer 1

You have to split the cell value every time |1.1| is found. There are several ways to do this. For example, you can combine indexOf and splice and in the sample below.
After you have done that, use setValues to overwrite the original data.
Code sample:
function insertRows() {
var startRow = 1;
var ss = SpreadsheetApp.getActiveSpreadsheet();
var sheet = ss.getSheetByName("Prenom");
var sourceRange = sheet.getRange(startRow, 1, sheet.getLastRow());
var sheetData = sourceRange.getValues().flat();
sheetData = sheetData.map(cell => {
const array = cell.split(",");
const outputArray = [];
let index = 0;
while (index >= 0) {
index = array.indexOf("|1.1|", 1);
if (index !== -1) section = array.splice(0, index).join(",");
else section = array.join(",");
outputArray.push(section);
}
return outputArray;
}).flat().map(row => [row]);
sheet.getRange(startRow, 1, sheetData.length, sheetData[0].length).setValues(sheetData);
}

Answer 2

function separate() {
const s = `|1|,'900','04000','0000','0','0000','0','11','0','S','A',|1.1|,GTF,'100',|1.1|,PPA,'15'
|1|,'986','01000','0000','0','0000','0','14','0','S','A',|1.1|,GTF,'110',|1.1|,PPA,'30'
|1|,'1046','01000','0000','0','0000','0','14','0','S','A',|1.1|,GTF,'120',|1.1|,PPA,'45'`;
let r = s.match(/([^']+[^|]+)/g);
Logger.log(r.join('\n'));
}
Execution log
12:02:55 PM Notice Execution started
12:02:55 PM Info ||1|,'900','04000','0000','0','0000','0','11','0','S','A',
|1.1|,GTF,'100',
|1.1|,PPA,'15'
|1|,'986','01000','0000','0','0000','0','14','0','S','A',
|1.1|,GTF,'110',
|1.1|,PPA,'30'
|1|,'1046','01000','0000','0','0000','0','14','0','S','A',
|1.1|,GTF,'120',
|1.1|,PPA,'45'
12:02:56 PM Notice Execution completed
function separate() {
const s = `|1|,'900','04000','0000','0','0000','0','11','0','S','A',|1.1|,GTF,'100',|1.1|,PPA,'15'
|1|,'986','01000','0000','0','0000','0','14','0','S','A',|1.1|,GTF,'110',|1.1|,PPA,'30'
|1|,'1046','01000','0000','0','0000','0','14','0','S','A',|1.1|,GTF,'120',|1.1|,PPA,'45'`;
let r = s.match(/([^']+[^|]+)/g).map(e => [e]);
let sh = SpreadsheetApp.getActiveSheet();
sh.getRange(1,1,r.length).setValues(r);
}