How do I sum amount for specific user in mysql query? - mysql

Question

I have three tables I am working with:
users table contains users id, name and status
supply_history table contains id, users_id, amount and status
rejected_deal table contains id, users_id, rejected_amount and also status.
What I am trying to find is to sum up each users supply_amount and rejected amount where users status, supply_history status and rejected_deal status is 1.
Here is what I have tried so far.
SELECT users.id, users.name,
sum(supply_history.amount) as supply_amount,
sum(rejected_deal.rejected_amount) as rejected_amount
from users
inner join supply_history on supply_history.users_id=users.id
inner join rejected_deal on rejected_deal.users_id=users.id
where users.status='1' and rejected_deal.status='1' and supply_history.status='1'
GROUP by users.id;
My current query result is bellow.
id
name
supply_amount
rejected_amount
1
Skipper
50
20
2
Private
200
20
The result I am looking for
id
name
supply_amount
rejected_amount
1
Skipper
50
10
2
Private
100
20
Bellow is my three tables
users table.
id
name
status
1
Skipper
1
2
Private
1
supply_history table.
id
users_id
amount
status
1
1
20
1
2
1
30
1
3
2
100
1
rejected_deal table.
id
users_id
rejected_amount
status
1
2
15
1
2
2
5
1
3
1
10
1
How do I solve this query please help. Thank you.

Answer 1

You are joining supply_history rows and rejected_deal rows to user rows. But supply_history and rejected_deal are not directly related. For one user, you create thus all combinations of supply_history and rejected_deal. The result is:
id
name
status
sh_id
users_id
amount
status
rd_id
users_id
rejected_amount
status
1
Skipper
1
1
1
20
1
2
2
5
1
1
Skipper
1
2
1
30
1
3
1
10
1
2
Private
1
3
2
100
1
1
2
15
1
2
Private
1
3
2
100
1
1
2
15
1
When you aggregate this data set, you add up amounts multifold. (Each value gets multiplied with the number of rows for the user in the other table).
Instead join the sums to the user:
select u.id, u.name, sh.supply_amount, rd.rejected_amount
from users u
left outer join
(
select users_id, sum(amount) as supply_amount
from supply_history
where status = 1
group by users_id
) sh on sh.users_id = u.id
left outer join
(
select users_id, sum(rejected_amount) as rejected_amount
from rejected_deal
where status = 1
group by users_id
) rd on rd.users_id = u.id
where u.status = 1
order by u.id;
I've turned your inner joins into outer joins for the case a user doesn't have entries in both tables. If you only want users that have data in both tables, then change this back to inner joins.
And if you want to enhance the query's readability, you may consider using WITH clauses: https://dev.mysql.com/doc/refman/8.0/en/with.html.

Answer 2

use Over for sum like this
SELECT users.id, users.name,
sum(supply_history.amount) OVER(PARTITION BY users.id, ORDER BY users.id) as supply_amount,
sum(rejected_deal.rejected_amount) OVER(PARTITION BY users.id, ORDER BY users.id) as rejected_amount
from users
inner join supply_history on supply_history.users_id=users.id
inner join rejected_deal on rejected_deal.users_id=users.id
where users.status='1' and rejected_deal.status='1' and supply_history.status='1'

Answer 3

try using sub queries to be something like that :
SELECT users.id, users.name,
(select sum(amount) from supply_history s where s.users_id = users.id and s.status = '1' ) as supply_amount ,
(select sum(rejected_amount) from rejected_deal r where r.users_id = users.id and r.status = '1' ) as rejected_amount
from users
where users.status='1';