The column 'PrizeMoneyBreakDown' includes a number of strings seperated by a semi-colon. I am trying to remove the strings 'total value', 'trophy total value', and 'welfare fund' from the data. These strings only appear sometimes in the data so it is not as simple as just removing the last three strings. I need to write a query that removes the strings IF they appear.
Example of data:
1st,5285;2nd,1680;3rd,885;4th,550;5th,350;6th,350;7th,350;8th,350;total_value,10000;welfare_fund,200;trophy_total_value,150;
Desired output of data:
1st,5285;2nd,1680;3rd,885;4th,550;5th,350;6th,350;7th,350;8th,350
Current code (only removes the words 'total value' etc - does not remove prize money associated with string):
SELECT PrizeMoneyBreakDown,
REPLACE(REPLACE(REPLACE(PrizeMoneyBreakDown,'total_value',""),'welfare_fund',""),'trophy_total_value',"") as new
FROM race2;
On MySQL 8+, we can use REGEXP_REPLACE:
SELECT PrizeMoneyBreakDown,
REGEXP_REPLACE(PrizeMoneyBreakDown,
'(total_value|welfare_fund|trophy_total_value),\\d+;',
'') AS NewPrizeMoneyBreakDown
FROM race2;
If you want to update the actual column then use:
UPDATE race2
SET PrizeMoneyBreakDown = REGEXP_REPLACE(
PrizeMoneyBreakDown,
'(total_value|welfare_fund|trophy_total_value),\\d+;',
'')
WHERE PrizeMoneyBreakDown REGEXP '(total_value|welfare_fund|trophy_total_value),\\d+;';
Related
i would like to perform Mysql search & replace with random characters, taken from a list. I cannot use regex, since my version is way prior to 8.
instead of the below,
i would like to change for instance the letter u with one out of (a,e,i,f,k) randomly.
UPDATE products
SET
productDescription = REPLACE(productDescription,
'abuot',
'about');
Is there a mysql command for this task?
Actually my goal is to get in the lastnames column, new names that are not exactly like the real ones, so one could work on "anonymous" data.
I would like to replace all rows in a certain column. Say in table products, in column description, we have data like:
abcud
ieruie
kjuklkllu
uiervfd
With the replace function, we would not want to create something like: replace e with i,
but replace e with one of (a,e,i,f,k)
example desired output:
abced
ierfie
kjiklkllk
aiervfd
like i said, we plan to use this into last names, we plan to replace many characters with random ones from a list, in an effort to create anonymous data in the column that contains last names.
On a next step, i would like to do the same, in order to make anonymous telephone numbers.
example
726456273
827364878
347823472
replace 3 with one of 0-9,
output:
726456279
827664878
547821472
SELECT REPLACE('product abuot Description',
SUBSTRING('product abuot Description', CHARINDEX('abuot', 'product abuot Description') ,5) , 'about')
CREATE FUNCTION smart_replace ( argument TEXT,
search_for CHAR(1),
replace_with TEXT )
RETURNS TEXT
NO SQL
BEGIN
SET argument = REPLACE(argument, search_for, CHAR(0));
REPEAT
SET argument = CONCAT( SUBSTRING_INDEX(argument, CHAR(0), 1),
SUBSTRING(replace_with FROM CEIL(RAND() * LENGTH(replace_with)) FOR 1),
SUBSTRING(argument FROM 2 + LENGTH(SUBSTRING_INDEX(argument, CHAR(0), 1))));
UNTIL NOT LOCATE(CHAR(0), argument) END REPEAT;
RETURN argument;
END
replace e with one of (a,e,i,f,k)
SELECT smart_replace(table.column, 'e', 'aeifk')
replace 3 with one of 0-9
SELECT smart_replace(table.phone, 'e', '0123456789')
I have this column in a table which is comma delimited to separate the values.
Here's the sample data:
2003,2004
2003,2005
2003,2006
2003,2004,2005
2003,2007
I want to get all data that contains only 1 comma.
I've been playing around with the '%' and '_' wildcards, but I can't seem to get the results I need.
SELECT column FROM table WHERE column like '%_,%'
Replace the , with '' empty set then take the original length less the replaced length. if 1 then only 1 comma if > 1 then more than 1 comma.
The length difference would represent the number of commas.
Length(column) - length(Replace(column,',','')) as NumOfCommas
or
where Length(column) - length(Replace(column,',','')) =1
While this may solve the problem, I agree with what others have indicated. Storing multiple values in a single column in a RDBMS is asking for more trouble. Better to normalize the data and get it to at least 3rd Normal form!
You can also use find_in_set() method which searches a value in comma separated list, by picking the last value of column using substring_index we can then check result of find_in_set should be 2 so that its the second and last value from list
select *
from demo
where find_in_set(substring_index(data,',',-1),data) = 2
Demo
Maybe another solution is to use regular expression in your case it can look like this ^[0-9]{4},[0-9]{4}$ :
SELECT * FROM MyTable WHERE ColName REGEXP '^[0-9]{4},[0-9]{4}$'
Or if you want all non comma one or more time :
SELECT * FROM MyTable WHERE ColName REGEXP '^[^,]*,[^,]*$'
I have a table, one of the columns contains a text values, some of which are comma separated string, like this:
Downtown, Market District, Warehouse District
I need to modify my query to see is a given value matches this column. I decided that using IN() is the best choice.
SELECT *
FROM t1
WHERE myValue IN (t1.nighborhood)
I am getting spotty results - sometimes I return records and sometimes not. If there's a value in t1.nighborhood that matches myValue, I do get data.
I checked and there are no MySQL errors. What am I missing?
You can use FIND_IN_SET() to search a comma-delimited list:
SELECT *
FROM t1
WHERE FIND_IN_SET(myValue, REPLACE(t1.nighborhood, ', ', ','));
The REPLACE() is necessary to remove the extra spaces.
Another solution is to use regex to match your search value surrounded by commas if necessary:
SELECT *
FROM t1
WHERE t1.nighborhood REGEXP CONCAT('(^|, )', myValue, '(, |$)');
In general, it's bad design to store distinct values in a single column. The data should be normalized into a related table with a foreign key.
eg : field name = User_id
Value=abc later i want to insert xyz without disturbing abc Value= abc,xyz i want to insert efg without disturbing abc then Value= abc,xyz,efg and so on
i want to seperating each value by using ","(comma). can any one help me out
In MySQL you could often refer to the value of a column just by using the column name. And to concatenate strings with a separator there's a nifty function called concat_ws (concat with separator).
In your case the code would look something like
UPDATE YourTable
SET Value = CONCAT_WS(',', Value, 'cde')
WHERE User_id = 123;
Good Luck!
MySQL CONCAT_WS() function is used to join two or more strings with separator. The separator specified in the first argument is added between two strings. The separator itself can be a string. If the separator is NULL the result is NULL.
Click hear for more information
My current query looks like this:
$query = "SELECT * FROM t WHERE (data LIKE '$findme') OR (data LIKE '%$findme|%') OR (data LIKE '%|$findme%')";
The data in this column contains items that are delimited by pipe symbols ("|") and I need the query to find all records that contain any occurrences of an item in this field. Additionally, if there's only one item in this column, there will not be a "|" symbol present.
EXAMPLE:
$findme = "12";
QUERY SHOULD MATCH:
13|23|12
12
12|23
3|12|42
QUERY SHOULD NOT MATCH:
123|32
34|123
I'm not sure if using REGEXP would make this easier, but if so, any solution is welcome. Thanks!
SQLFiddle Example:
http://sqlfiddle.com/#!3/32afd/5
Using a combination of REPLACE() and FIND_IN_SET(), you can replace the | with commas, and locate your value $findme in the pipe-delimited set:
SELECT *
FROM table
/* Replace | with , and search in the set */
WHERE FIND_IN_SET('$find_me', REPLACE(data, '|', ',')) > 0
Note that this only works if the delimited values in data do not contain commas.
In the long run, the appropriate solution to this is to separate out the delimited column data into another properly normalized one to many table.