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I have table like this, and i want to output the result like output table, can anyone tell me how to do it, in MySQL
You can use left join like so :
SELECT tb_session.SESSION AS SESSION, tb_class.CLASS AS CLASS from tb_schedul LEFT JOIN tb_session ON tb_schedule.ID_SESSION = tb_session.ID LEFT JOIN tb_schedul.ID_CLASS = tb_class.ID
Good morning, you can use LEFT JOIN
try it:
SELECT tb_session.SESSION, tb_schedul.ID_CLASS FROM tb_session LEFT JOIN tb_schedul
ON tb_session.ID = tb_schedul.ID_SESSION;
Related
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I have a table in SQL Server where a row contains a Json column - something like this:
ResponseText
RequestId
{"LosUnqCod":0,"LosMidId":23}
96173722
{"LosUnqCod":1,"LosMidId":5}
96173721
I want to have a table in this shape:
LosUnqCod
LosMidId
RequestId
0
23
96173722
1
5
96173721
how to open this json?
Hi every body I found my answer and want to share with anyone who has the same issue as I does
SELECT
reqTbl.LosUnqCod ,
a.RequestId
FROM [dbo].[a] CROSS APPLY
OPENJSON( dbo.a.responsetext)
WITH (
LosUnqCod nvarchar(50)
) AS reqTbl
You don't have to use OPENJSON if you only have one JSON object (not an array) per SQL row, you can use JSON_VALUE instead:
SELECT
JSON_VALUE(a.responsetext, '$.LosUnqCod') LosUnqCod,
JSON_VALUE(a.responsetext, '$.LosMidId') LosMidId,
a.RequestId
FROM [dbo].[a];
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Below is the code failing in Hive:
(Alias at 6:5 (END) is not recognized)
INSERT INTO WRKT_REGULATORY_COMPONE_RECLASS
select
case
when WRKT_REGULATORY_COMPONENT_FINAL.REVENUE_FLAG != 'Y'
AND WRKT_REGULATORY_COMPONENT_FINAL.EXCLUDED_FLAG = 'Y'
THEN WRKT_REGULATORY_COMPONE_RECLASS.EXECUTION_ORDER = '1'
END
FROM WRKT_REGULATORY_COMPONENT_FINAL
this one: THEN WRKT_REGULATORY_COMPONE_RECLASS.EXECUTION_ORDER = '1' is wrong
after THEN it should be literal 1 or column
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ERROR: syntax error at or near "r"
Query was:
Delete r,ur from un_received_compansation_reason ur join received_compensation_info r on received_compensation_info.compensation_info_id = un_received_compansation_reason.compensation_info_id where compensation_info_id=2
You have specific table aliases, so try writing the query as:
Delete r, ur
from un_received_compansation_reason ur join
received_compensation_info r
on r.compensation_info_id = ur.compensation_info_id
where r.compensation_info_id = 2;
You need to use table aliases in time joining key like below
Delete r,ur from un_received_compansation_reason ur join
received_compensation_info r on
r.compensation_info_id = ur.compensation_info_id
where ur.compensation_info_id=2
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I need to write a query which need to replace email result by 0 when it's null
UPDATE tblName SET email = 0 WHERE email is null;
Use the ifnull() function:
ifnull(email,"0")
You can use the coalesce function:
SELECT COALESCE(email, '0') FROM some_table
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I have 3 mysql queries in php (one for each category/widget), all 3 queries together should output 3 * 6 = 18 results. So if one query returns less, more results from the other queries should be used.
How can i do that? Thanks.
Instantiate 2 variables , keep count of selected rows and execute query using these counters
for example this will be your first query execiton
$default = 6;
$limit= $default;
$some_result = mysql("SELECT * FROM table LIMIT $limit");
then you can use this for every query-limit
$limit = $limit - count($some_result) + $default;