Problems with mysql CREATE TABLE syntax - mysql

I try to create table in mysql with the following command:
CREATE TABLE keys (id INT(10), key VARCHAR(100));
and it always gives me an error like this:
ERROR 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'keys (id INT(10), key VARCHAR(100))' at line 1`


So both the table name keys and the field key are reserved in the Mysql namespace. If you choose a different table name (e.g. keys_tbl) and rename the second field something like key_id, your code will work.


You should be very carefully with table and columns naming, you might face a lot of problems in the future.
I suggest find names that are not MySQL reserved words
If you still want to keep the names you should put in in backticks.
mysql> CREATE TABLE keys (id INT(10), key VARCHAR(100));
ERROR 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'keys (id INT(10), key VARCHAR(100))' at line 1
mysql> CREATE TABLE `keys` (id INT(10), `key` VARCHAR(100));
Query OK, 0 rows affected, 1 warning (0.97 sec)
mysql> show create table keys;
ERROR 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'keys' at line 1
mysql>
mysql>
mysql> show create table `keys`;
+-------+-----------------------------------------------------------------------------------------------------------------------------------------------------+
| Table | Create Table |
+-------+-----------------------------------------------------------------------------------------------------------------------------------------------------+
| keys | CREATE TABLE `keys` (
`id` int DEFAULT NULL,
`key` varchar(100) DEFAULT NULL
) ENGINE=InnoDB DEFAULT CHARSET=utf8mb4 COLLATE=utf8mb4_0900_ai_ci |
+-------+-----------------------------------------------------------------------------------------------------------------------------------------------------+
1 row in set (0.01 sec)
Note that you have to use backticks when using the table

Related

mysql error for a create table statement from shell client

Im trying to run the following from the mysql shell client:
MySQL localhost:33060+ ssl plaything SQL > CREATE TABLE areas (id SERIAL PRIMARY KEY, area_name VARCHAR);
and keep getting the following error:
ERROR: 1064: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ')' at line 1
where could I be going wrong?

solved by yoss:
try this: CREATE TABLE areas ( id int NOT NULL AUTO_INCREMENT, area_name varchar(255), PRIMARY KEY (id) );
varchar did not have number of characters specified in the original statement

MySQL database schema syntax behaving strangely

I'm trying to write a MySQL database (called security_db.sql) in which I outline some tables about a security guard job. The code itself is below. Sorry about the weird formatting.
drop database if exists security;
create database security;
use security;
drop table if exists caller;
drop table if exists number;
drop table if exists officer;
drop table if exists suspect;
drop table if exists report;
drop table if exists car;
drop table if exists writeup;
drop table if exists activitylog;
drop table if exists ticket;
create table caller
(
firstname varchar(64),
lastname varchar(64),
cellnumber int unsigned not null primary key,
location varchar(64),
);
insert into caller (firstname, lastname, cellnumber, location)
values (`Braydon`, `Rekart`, `2174088935`, `Stoddard`);
create table report
(
incidentreport varchar(64) not null primary key,
);
insert into report (incidentreport) values (`Testing this database.`);
reate table activitylog
(
report text not null,
date int not null primary key,
location varchar(64) not null,
);
insert into activitylog (report, date, location) values (`Testing this
database`, `112233`, `OlinMahan`);
create table number
(
securityphone int not null primary key,
);
insert into number (securityphone) values (`1217666666`);
create table suspect
(
suspectfirstname varchar(64) not null,
suspectlastname varchar(64) not null,
weight int,
height int,
suspectid int not null primary key,
);
insert into suspect (suspectfirstname, suspectlastname, suspectid)
values (`Braydon`, `Rekart`, `3`);
create table writeup
(
recipientfirstname varchar(64) not null,
recipientlastname varchar(64) not null,
whogaveit varchar(64) not null,
reason text not null,
writeupid int not null primary key,
reason text not null,
writeupid int not null primary key,
);
insert into writeup (recipientfirstname, recipientlastname,
whogaveit, reason, writeupid) values (`Braydon`, `Rekart`, `Karson`, `Late`,
`45`);
create table officer
(
officerid int not null primary key,
position varchar(64) not null,
firstname varchar(64) not null,
lastname varchar(64) not null,
);
insert into officer (officerid, position, firstname, lastname)
values (`1`, `Crewhead`, `Braydon`, `Rekart`);
create table car
(
make varchar(64),
color varchar(64),
model varchar(64),
licenseplatenumber varchar not null primary key,
);
insert into car (licenseplatenumber) values (`N33D4SP33D`);
create table ticket
(
ticketnumber int primary key,
writerfirstname varchar(64) not null,
writerlastname varchar(64) not null,
recipientfirstname varchar(64) not null,
recipientlastname varchar(64) not null,
recipientfirstname varchar(64) not null,
recipientlastname varchar(64) not null,
writerid int,
);
insert into ticket (ticketnumber, writerfirstname, writerlastname,
recipientfirstname, recipientlastname)
values (`3`, `Braydon`, `Rekart`, `Karson`, `Gragert`);
The errors it gives me are as follows.
mysql> use security
Database changed
mysql> source security.db
Query OK, 0 rows affected (0.01 sec)
Query OK, 1 row affected (0.00 sec)
Database changed
Query OK, 0 rows affected, 1 warning (0.00 sec)
Query OK, 0 rows affected, 1 warning (0.00 sec)
Query OK, 0 rows affected, 1 warning (0.00 sec)
Query OK, 0 rows affected, 1 warning (0.00 sec)
Query OK, 0 rows affected, 1 warning (0.00 sec)
Query OK, 0 rows affected, 1 warning (0.00 sec)
Query OK, 0 rows affected, 1 warning (0.00 sec)
Query OK, 0 rows affected, 1 warning (0.00 sec)
Query OK, 0 rows affected, 1 warning (0.00 sec)
ERROR 1064 (42000): You have an error in your SQL syntax; check the
manual that corresponds to your MySQL server version for the right
syntax to use near ')' at line 7
ERROR 1146 (42S02): Table 'security.caller' doesn't exist
ERROR 1064 (42000): You have an error in your SQL syntax; check the
manual that corresponds to your MySQL server version for the right
syntax to use near ')' at line 4
ERROR 1146 (42S02): Table 'security.report' doesn't exist
ERROR 1064 (42000): You have an error in your SQL syntax; check the
manual that corresponds to your MySQL server version for the right
syntax to use near ')' at line 6
ERROR 1146 (42S02): Table 'security.activitylog' doesn't exist
ERROR 1064 (42000): You have an error in your SQL syntax; check the
manual that corresponds to your MySQL server version for the right
syntax to use near ')' at line 4
ERROR 1146 (42S02): Table 'security.number' doesn't exist
ERROR 1064 (42000): You have an error in your SQL syntax; check the
manual that corresponds to your MySQL server version for the right
syntax to use near ')' at line 8
ERROR 1146 (42S02): Table 'security.suspect' doesn't exist
ERROR 1064 (42000): You have an error in your SQL syntax; check the
manual that corresponds to your MySQL server version for the right
syntax to use near ')' at line 8
ERROR 1146 (42S02): Table 'security.writeup' doesn't exist
ERROR 1064 (42000): You have an error in your SQL syntax; check the
manual that corresponds to your MySQL server version for the right
syntax to use near ')' at line 7
ERROR 1146 (42S02): Table 'security.officer' doesn't exist
ERROR 1064 (42000): You have an error in your SQL syntax; check the
manual that corresponds to your MySQL server version for the right
syntax to use near 'not null primary key, )' at line 6
ERROR 1146 (42S02): Table 'security.car' doesn't exist ERROR 1064
(42000): You have an error in your SQL syntax; check the manual that
corresponds to your MySQL server version for the right syntax to use
near ')' at line 9
ERROR 1146 (42S02): Table 'security.ticket' doesn't exist
No matter how I fiddle around with the syntax I can't seem to figure it out. I feel like it's a total rookie mistake but I need help. Thank you.

You have an extra comma after the last field definition in every single create table statement, therefore none of the tables are created and none of the insert can succeed.
Example:
...
location varchar(64) not null, <- this comma
);
You also use backticks around the values to be inserted incorrectly. Backticks are used to enclose object identifiers, such as table or field names. String values should be enclosed by single or double quotes, numeric values should not be enclosed.
Example:
insert into caller (firstname, lastname, cellnumber, location)
values ('Braydon', 'Rekart', 2174088935, 'Stoddard');

Unable to create table with column name "schemas" [duplicate]

This question already has answers here:
Is "key" a reserved word in MySqli? I'm getting an error
(2 answers)
Closed 6 years ago.
When I tried to execute following statement.
create table user_schemas (user_id varchar(255) not null, schemas varchar(255));
I am getting following error.
ERROR 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'schemas varchar(255))' at line 1
When I change the column name "schemas" to something else, it is working fine.
mysql> create table user_schemas (user_id varchar(255) not null, schemas varchar(255));
ERROR 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'schemas varchar(255))' at line 1
mysql>
mysql> create table user_schemas (user_id varchar(255) not null, rules varchar(255));
Query OK, 0 rows affected (0.01 sec)
Any idea on how to solve this problem??

If you want to use reserved words in the SQL syntax you must use Backticks (`) like:
create table user_schemas (
user_id varchar(255) not null,
`schemas` varchar(255)
);

Insert Column Name into Table if Column Name does not already exist

IF COL_LENGTH('Characters', 'name') IS NULL
BEGIN
ALTER TABLE `Characters` ADD `name` INT(32) UNSIGNED NOT NULL;
END
I am trying to write some sql that will insert a column name into the table "Characters" if it is not already existant, however I am getting errors which I do not understand (quite new to SQL) and I could use some help understanding why it is not working. I have gotten the IF part from another Question, and the ALTER part from the DBMS I'm using, PhpMyAdmin 2.11.4.
It is using MySQL 5.6 apparently and this is the error:
MySQL said: Documentation
#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'IF COL_LENGTH('Characters', 'name') IS NULL
BEGIN
ALTER TABLE `Characters` AD' at line 1

Error when enterting this command ALTER TABLE `report` AUTO_INCREMENT = 1

I get an error when using this command to alter my SQL table
Error message:
#1064 - You have an error in your SQL syntax;
check the manual that corresponds to your MySQL server version for the right
syntax to use near 'ALTER TABLE `report` AUTO_INCREMENT = 1, 30' at line 2`
Any idea of that?

So why would you say AUTO_INCREMENT=1,30 ?
It has to be one number, and not a comma separated list of numbers.
ALTER TABLE report AUTO_INCREMENT=1
or
ALTER TABLE report AUTO_INCREMENT=30
Reference: MySQL