Swift - ObjectMapper: Mapping jsonString - json

I have two models:
class CellModel: StaticMappable {
static func objectForMapping(map: Map) -> BaseMappable? {
return nil
}
func mapping(map: Map) {
id <- map["id"]
title <- map["title"]
description <- map["description"]
}
private var id: Int
private var title: String
private var description: String
init(id: Int, title: String, description: String) {
self.id = id
self.title = title
self.description = description
}
}
and
class CellModelArray: StaticMappable {
var cells = [CellModel]()
static func objectForMapping(map: Map) -> BaseMappable? {
return nil
}
func mapping(map: Map) {
cells <- map["cells"]
}
}
I created a jsonString from object like this:
let jsonString = Mapper().toJSONString(rootModel, prettyPrint: false)
and json looks like this:
{"cells":[{"id":0,"title":"Header","description":"Description"},{"description":"Description","id":0,"title":"Header"},{"description":"Description","id":1,"title":"Header"},{"id":0,"title":"Header","description":"Description"},{"description":"Description","title":"Header","id":0}]}
Then I want to take this string and convert it back to the object, but when I try it like that:
var cells = CellModelArray()
cells = Mapper<CellModelArray>().map(JSONString: code) ?? CellModelArray()
it does not work and returns nil. Thank you for your help.

Please drop ObjectMapper.
It's a library of merit but since Swift 4 (introduced 2017) it has become obsolete in favor of the built-in and swiftier Codable protocol.
The main benefit is that the model files can be structs (value types) and it's much more reliable because the developer doesn't have to take care of literal string keys
This is sufficient
struct Model: Codable {
let cells : [Cell]
}
struct Cell: Codable {
let id: Int
let title: String
let description: String
}
The given JSON string
let jsonString = """
{"cells":[{"id":0,"title":"Header","description":"Description"},{"description":"Description","id":0,"title":"Header"},{"description":"Description","id":1,"title":"Header"},{"id":0,"title":"Header","description":"Description"},{"description":"Description","title":"Header","id":0}]}
"""
can be decoded and encoded with this code
do {
// Decode the JSON
let decoded = try JSONDecoder().decode(Model.self, from: Data(jsonString.utf8))
print(decoded)
// Encode it back
let encoded = try JSONEncoder().encode(decoded)
print(String(data: encoded, encoding: .utf8)!)
} catch {
print(error)
}

Related

Swift: How to declare a node type which match any arbitrary JSON?

Following code loads JSON from a file, and expecting it has an xsd type.
struct xsd: Decodable {
var name: String
var address: String
}
do {
if let jsonURL = Bundle.main.url(forResource: "user", withExtension: "json") {
let jsonData = try Data(contentsOf: jsonURL)
let jsonDecoder = JSONDecoder()
let persons = try jsonDecoder.decode(xsd.self, from: jsonData)
print(persons)
let ii = 7
}
} catch {
}
What if xsd would be more dynamic and it would match any arbitrary JSON in the file?
How can I define a type which would represent a JSON attribute-key pairs? It should be a recursive structure.
Here guy define one for HTML. https://theswiftdev.com/result-builders-in-swift/
I would do the same for JSON.
This is a Node for HTML:
public struct Node {
public enum `Type` {
case standard // <name>contents</name>
case comment // <!-- contents -->
case empty // <name>
case group // *group*<p>Lorem ipsum</p>*group*
}
public let type: `Type`
public let name: String?
public let contents: String?
public init(type: `Type` = .standard,
name: String? = nil,
contents: String? = nil) {
self.type = type
self.name = name
self.contents = contents
}
}

ObjectMapper returrning NIL in Swift

I'm trying to use Object mapper https://github.com/Hearst-DD/ObjectMapper to convert a JSON string into a Swift object. Note I've simplified the object to a single field here - obviously my real response has more fields!
My response is:
data arrray response [{
chat = {
"_id" = 1;
}}]
So I want to convert to my chat class:
public class Chat: Mappable {
var _id: String? }
public required init?(map: Map){
}
public func mapping(map: Map) {
_id <- map["_id"]
}
}
So I convert my data array to a dictionary
let jsonResponse = dataArray [0]
let discResponse = jsonResponse as! Dictionary<String,AnyObject>
I can even access my field manually
let chat = discResponse["chat"]
let id = chat!["_id"]
print ("CHAT ID", id)
But mapping to the object
let jsonData = try! JSONSerialization.data(withJSONObject: chat, options: .prettyPrinted)
let user = Chat(JSONString: String( describing: jsonData))
returns nil
Why?
Just putting my comment as an answer, if someone will stuck on the same issue: use Mapper<Chat>().map(JSONObject: chat). It should help your cause.

Swift Failable Initializer with SwiftyJSON

I’m trying to initialise a simple data model object with some JSON from SwiftyJSON. I’d like the initialiser to fail and return nil if any of the required JSON values aren’t present. Here’s my code:
class ProductCategory: NSObject {
let id: String
let sortOrder: Int
let name: String
let imageURL: String
let ranges: [String]
init?(json: JSON) {
if let jsonID = json["id"].string,
jsonSortOrder = json["sortOrder"].int,
jsonName = json["name"].string,
jsonImageURL = json["imageURL"].string {
id = jsonID
sortOrder = jsonSortOrder
name = jsonName
imageURL = jsonImageURL
ranges = json["ranges"].arrayValue.map { $0.string! }
} else {
return nil
}
}
}
I’d expect this to work. In the event that we didn’t hit all those json values, simply return nil and bail out. However, I get an error on the return nil, stating:
All stored properties of a class instance must be initialized before
returning nil from an initializer.
I’m confused: isn’t the point of a failable initializer that I can bail out without setting it up if something goes wrong? The object returned would be nil, why would there be any value in setting up its properties?
So here’s what I ended up doing – Greg was right but I ended up switching to a struct as a result:
struct ProductCategory {
let id: String
let sortOrder: Int
let name: String
let imageURL: String
let ranges: [String]
init?(json: JSON) {
guard let jsonID = json["id"].string,
let jsonSortOrder = json["sortOrder"].int,
let jsonName = json["name"].string,
let jsonImageURL = json["image"].string else {
return nil
}
self.id = jsonID
self.sortOrder = jsonSortOrder
self.name = jsonName
self.imageURL = jsonImageURL
self.ranges = json["ranges"].arrayValue.map { $0.string! }
}
}
Failable Initializers for Classes:
"For classes, however, a failable initializer can trigger an initialization failure only after all stored properties introduced by that class have been set to an initial value and any initializer delegation has taken place."
So
init?(json: JSON) {
self.id = json["id"].string
self.sortOrder = json["sortOrder"].int
...
if ... { return nil }
}

How to serialize or convert Swift objects to JSON?

This below class
class User: NSManagedObject {
#NSManaged var id: Int
#NSManaged var name: String
}
Needs to be converted to
{
"id" : 98,
"name" : "Jon Doe"
}
I tried manually passing the object to a function which sets the variables into a dictionary and returns the dictionary. But I would want a better way to accomplish this.
In Swift 4, you can inherit from the Codable type.
struct Dog: Codable {
var name: String
var owner: String
}
// Encode
let dog = Dog(name: "Rex", owner: "Etgar")
let jsonEncoder = JSONEncoder()
let jsonData = try jsonEncoder.encode(dog)
let json = String(data: jsonData, encoding: String.Encoding.utf8)
// Decode
let jsonDecoder = JSONDecoder()
let secondDog = try jsonDecoder.decode(Dog.self, from: jsonData)
Along with Swift 4 (Foundation) now it is natively supported in both ways, JSON string to an object - an object to JSON string.
Please see Apple's documentation here JSONDecoder() and here JSONEncoder()
JSON String to Object
let jsonData = jsonString.data(using: .utf8)!
let decoder = JSONDecoder()
let myStruct = try! decoder.decode(myStruct.self, from: jsonData)
Swift Object to JSONString
let encoder = JSONEncoder()
encoder.outputFormatting = .prettyPrinted
let data = try! encoder.encode(myStruct)
print(String(data: data, encoding: .utf8)!)
You can find all details and examples here Ultimate Guide to JSON Parsing With Swift 4
UPDATE: Codable protocol introduced in Swift 4 should be sufficient for most of the JSON parsing cases. Below answer is for people who are stuck in previous versions of Swift and for legacy reasons
EVReflection :
This works of reflection principle. This takes less code and also supports NSDictionary, NSCoding, Printable, Hashable and Equatable
Example:
class User: EVObject { # extend EVObject method for the class
var id: Int = 0
var name: String = ""
var friends: [User]? = []
}
# use like below
let json:String = "{\"id\": 24, \"name\": \"Bob Jefferson\", \"friends\": [{\"id\": 29, \"name\": \"Jen Jackson\"}]}"
let user = User(json: json)
ObjectMapper :
Another way is by using ObjectMapper. This gives more control but also takes a lot more code.
Example:
class User: Mappable { # extend Mappable method for the class
var id: Int?
var name: String?
required init?(_ map: Map) {
}
func mapping(map: Map) { # write mapping code
name <- map["name"]
id <- map["id"]
}
}
# use like below
let json:String = "{\"id\": 24, \"name\": \"Bob Jefferson\", \"friends\": [{\"id\": 29, \"name\": \"Jen Jackson\"}]}"
let user = Mapper<User>().map(json)
I worked a bit on a smaller solution that doesn't require inheritance. But it hasn't been tested much. It's pretty ugly atm.
https://github.com/peheje/JsonSerializerSwift
You can pass it into a playground to test it. E.g. following class structure:
//Test nonsense data
class Nutrient {
var name = "VitaminD"
var amountUg = 4.2
var intArray = [1, 5, 9]
var stringArray = ["nutrients", "are", "important"]
}
class Fruit {
var name: String = "Apple"
var color: String? = nil
var weight: Double = 2.1
var diameter: Float = 4.3
var radius: Double? = nil
var isDelicious: Bool = true
var isRound: Bool? = nil
var nullString: String? = nil
var date = NSDate()
var optionalIntArray: Array<Int?> = [1, 5, 3, 4, nil, 6]
var doubleArray: Array<Double?> = [nil, 2.2, 3.3, 4.4]
var stringArray: Array<String> = ["one", "two", "three", "four"]
var optionalArray: Array<Int> = [2, 4, 1]
var nutrient = Nutrient()
}
var fruit = Fruit()
var json = JSONSerializer.toJson(fruit)
print(json)
prints
{"name": "Apple", "color": null, "weight": 2.1, "diameter": 4.3, "radius": null, "isDelicious": true, "isRound": null, "nullString": null, "date": "2015-06-19 22:39:20 +0000", "optionalIntArray": [1, 5, 3, 4, null, 6], "doubleArray": [null, 2.2, 3.3, 4.4], "stringArray": ["one", "two", "three", "four"], "optionalArray": [2, 4, 1], "nutrient": {"name": "VitaminD", "amountUg": 4.2, "intArray": [1, 5, 9], "stringArray": ["nutrients", "are", "important"]}}
This is not a perfect/automatic solution but I believe this is the idiomatic and native way to do such. This way you don't need any libraries or such.
Create an protocol such as:
/// A generic protocol for creating objects which can be converted to JSON
protocol JSONSerializable {
private var dict: [String: Any] { get }
}
extension JSONSerializable {
/// Converts a JSONSerializable conforming class to a JSON object.
func json() rethrows -> Data {
try JSONSerialization.data(withJSONObject: self.dict, options: nil)
}
}
Then implement it in your class such as:
class User: JSONSerializable {
var id: Int
var name: String
var dict { return ["id": self.id, "name": self.name] }
}
Now:
let user = User(...)
let json = user.json()
Note: if you want json as a string, it is very simply to convert to a string: String(data: json, encoding .utf8)
Some of the above answers are completely fine, but I added an extension here, just to make it much more readable and usable.
extension Encodable {
var convertToString: String? {
let jsonEncoder = JSONEncoder()
jsonEncoder.outputFormatting = .prettyPrinted
do {
let jsonData = try jsonEncoder.encode(self)
return String(data: jsonData, encoding: .utf8)
} catch {
return nil
}
}
}
struct User: Codable {
var id: Int
var name: String
}
let user = User(id: 1, name: "name")
print(user.convertToString!)
//This will print like the following:
{
"id" : 1,
"name" : "name"
}
Not sure if lib/framework exists, but if you would like to do it automatically and you would like to avoid manual labour :-) stick with MirrorType ...
class U {
var id: Int
var name: String
init(id: Int, name: String) {
self.id = id
self.name = name
}
}
extension U {
func JSONDictionary() -> Dictionary<String, Any> {
var dict = Dictionary<String, Any>()
let mirror = reflect(self)
var i: Int
for i = 0 ; i < mirror.count ; i++ {
let (childName, childMirror) = mirror[i]
// Just an example how to check type
if childMirror.valueType is String.Type {
dict[childName] = childMirror.value
} else if childMirror.valueType is Int.Type {
// Convert to NSNumber for example
dict[childName] = childMirror.value
}
}
return dict
}
}
Take it as a rough example, lacks proper conversion support, lacks recursion, ... It's just MirrorType demonstration ...
P.S. Here it's done in U, but you're going to enhance NSManagedObject and then you'll be able to convert all NSManagedObject subclasses. No need to implement this in all subclasses/managed objects.
struct User:Codable{
var id:String?
var name:String?
init(_ id:String,_ name:String){
self.id = id
self.name = name
}
}
Now just make your object like this
let user = User("1","pawan")
do{
let userJson = try JSONEncoder().encode(parentMessage)
}catch{
fatalError("Unable To Convert in Json")
}
Then reconvert from json to Object
let jsonDecoder = JSONDecoder()
do{
let convertedUser = try jsonDecoder.decode(User.self, from: userJson.data(using: .utf8)!)
}catch{
}
2021 | SWIFT 5.1 | Results solution
Input data:
struct ConfigCreds: Codable {
// some params
}
usage:
// get JSON from Object
configCreds
.asJson()
.onSuccess{ varToSaveJson = $0 }
.onFailure{ _ in // any failure code }
// get object of type "ConfigCreds" from JSON
someJsonString
.decodeFromJson(type: ConfigCreds.self)
.onSuccess { configCreds = $0 }
.onFailure{ _ in // any failure code }
Back code:
#available(macOS 10.15, *)
public extension Encodable {
func asJson() -> Result<String, Error>{
JSONEncoder()
.try(self)
.flatMap{ $0.asString() }
}
}
public extension String {
func decodeFromJson<T>(type: T.Type) -> Result<T, Error> where T: Decodable {
self.asData()
.flatMap { JSONDecoder().try(type, from: $0) }
}
}
///////////////////////////////
/// HELPERS
//////////////////////////////
#available(macOS 10.15, *)
fileprivate extension JSONEncoder {
func `try`<T : Encodable>(_ value: T) -> Result<Output, Error> {
do {
return .success(try self.encode(value))
} catch {
return .failure(error)
}
}
}
fileprivate extension JSONDecoder {
func `try`<T: Decodable>(_ t: T.Type, from data: Data) -> Result<T,Error> {
do {
return .success(try self.decode(t, from: data))
} catch {
return .failure(error)
}
}
}
fileprivate extension String {
func asData() -> Result<Data, Error> {
if let data = self.data(using: .utf8) {
return .success(data)
} else {
return .failure(WTF("can't convert string to data: \(self)"))
}
}
}
fileprivate extension Data {
func asString() -> Result<String, Error> {
if let str = String(data: self, encoding: .utf8) {
return .success(str)
} else {
return .failure(WTF("can't convert Data to string"))
}
}
}
fileprivate func WTF(_ msg: String, code: Int = 0) -> Error {
NSError(code: code, message: msg)
}

Deserialize JSON / NSDictionary to Swift objects

Is there a way to properly deserialize a JSON response to Swift objects resp. using DTOs as containers for fixed JSON APIs?
Something similar to http://james.newtonking.com/json or something like this example from Java
User user = jsonResponse.readEntity(User.class);
whereby jsonResponse.toString() is something like
{
"name": "myUser",
"email": "user#example.com",
"password": "passwordHash"
}
SWIFT 4 Update
Since you give a very simple JSON object the code prepared for to handle that model. If you need more complicated JSON models you need to improve this sample.
Your Custom Object
class Person : NSObject {
var name : String = ""
var email : String = ""
var password : String = ""
init(JSONString: String) {
super.init()
var error : NSError?
let JSONData = JSONString.dataUsingEncoding(NSUTF8StringEncoding, allowLossyConversion: false)
let JSONDictionary: Dictionary = NSJSONSerialization.JSONObjectWithData(JSONData, options: nil, error: &error) as NSDictionary
// Loop
for (key, value) in JSONDictionary {
let keyName = key as String
let keyValue: String = value as String
// If property exists
if (self.respondsToSelector(NSSelectorFromString(keyName))) {
self.setValue(keyValue, forKey: keyName)
}
}
// Or you can do it with using
// self.setValuesForKeysWithDictionary(JSONDictionary)
// instead of loop method above
}
}
And this is how you invoke your custom class with JSON string.
override func viewDidLoad() {
super.viewDidLoad()
let jsonString = "{ \"name\":\"myUser\", \"email\":\"user#example.com\", \"password\":\"passwordHash\" }"
var aPerson : Person = Person(JSONString: jsonString)
println(aPerson.name) // Output is "myUser"
}
I recommend that you use code generation (http://www.json4swift.com) to create native models out of the json response, this will save your time of parsing by hand and reduce the risk of errors due to mistaken keys, all elements will be accessible by model properties, this will be purely native and the models will make more sense rather checking the keys.
Your conversion will be as simple as:
let userObject = UserClass(userDictionary)
print(userObject!.name)
Swift 2: I really like the previous post of Mohacs! To make it more object oriented, i wrote a matching Extension:
extension NSObject{
convenience init(jsonStr:String) {
self.init()
if let jsonData = jsonStr.dataUsingEncoding(NSUTF8StringEncoding, allowLossyConversion: false)
{
do {
let json = try NSJSONSerialization.JSONObjectWithData(jsonData, options: []) as! [String: AnyObject]
// Loop
for (key, value) in json {
let keyName = key as String
let keyValue: String = value as! String
// If property exists
if (self.respondsToSelector(NSSelectorFromString(keyName))) {
self.setValue(keyValue, forKey: keyName)
}
}
} catch let error as NSError {
print("Failed to load: \(error.localizedDescription)")
}
}
else
{
print("json is of wrong format!")
}
}
}
custom classes:
class Person : NSObject {
var name : String?
var email : String?
var password : String?
}
class Address : NSObject {
var city : String?
var zip : String?
}
invoking custom classes with JSON string:
var jsonString = "{ \"name\":\"myUser\", \"email\":\"user#example.com\", \"password\":\"passwordHash\" }"
let aPerson = Person(jsonStr: jsonString)
print(aPerson.name!) // Output is "myUser"
jsonString = "{ \"city\":\"Berlin\", \"zip\":\"12345\" }"
let aAddress = Address(jsonStr: jsonString)
print(aAddress.city!) // Output is "Berlin"
Yet another JSON handler I wrote:
https://github.com/dankogai/swift-json
With it you can go like this:
let obj:[String:AnyObject] = [
"array": [JSON.null, false, 0, "", [], [:]],
"object":[
"null": JSON.null,
"bool": true,
"int": 42,
"double": 3.141592653589793,
"string": "a α\t弾\n𪚲",
"array": [],
"object": [:]
],
"url":"http://blog.livedoor.com/dankogai/"
]
let json = JSON(obj)
json.toString()
json["object"]["null"].asNull // NSNull()
json["object"]["bool"].asBool // true
json["object"]["int"].asInt // 42
json["object"]["double"].asDouble // 3.141592653589793
json["object"]["string"].asString // "a α\t弾\n𪚲"
json["array"][0].asNull // NSNull()
json["array"][1].asBool // false
json["array"][2].asInt // 0
json["array"][3].asString // ""
As you see no !? needed between subscripts.
In addition to that you can apply your own schema like this:
//// schema by subclassing
class MyJSON : JSON {
override init(_ obj:AnyObject){ super.init(obj) }
override init(_ json:JSON) { super.init(json) }
var null :NSNull? { return self["null"].asNull }
var bool :Bool? { return self["bool"].asBool }
var int :Int? { return self["int"].asInt }
var double:Double? { return self["double"].asDouble }
var string:String? { return self["string"].asString }
var url: String? { return self["url"].asString }
var array :MyJSON { return MyJSON(self["array"]) }
var object:MyJSON { return MyJSON(self["object"]) }
}
let myjson = MyJSON(obj)
myjson.object.null // NSNull?
myjson.object.bool // Bool?
myjson.object.int // Int?
myjson.object.double // Double?
myjson.object.string // String?
myjson.url // String?
There's a great example by Apple for deserializing JSON with Swift 2.0
The trick is to use the guard keyword and chain the assignments like so:
init?(attributes: [String : AnyObject]) {
guard let name = attributes["name"] as? String,
let coordinates = attributes["coordinates"] as? [String: Double],
let latitude = coordinates["lat"],
let longitude = coordinates["lng"],
else {
return nil
}
self.name = name
self.coordinates = CLLocationCoordinate2D(latitude: latitude, longitude: longitude)
}
I personally prefer native parsing vs any 3rd party, as it is transparent and magic-less. (and bug less?)
Using quicktype, I generated your model and serialization helpers from your sample:
import Foundation
struct User: Codable {
let name: String
let email: String
let password: String
}
extension User {
static func from(json: String, using encoding: String.Encoding = .utf8) -> OtherUser? {
guard let data = json.data(using: encoding) else { return nil }
return OtherUser.from(data: data)
}
static func from(data: Data) -> OtherUser? {
let decoder = JSONDecoder()
return try? decoder.decode(OtherUser.self, from: data)
}
var jsonData: Data? {
let encoder = JSONEncoder()
return try? encoder.encode(self)
}
var jsonString: String? {
guard let data = self.jsonData else { return nil }
return String(data: data, encoding: .utf8)
}
}
Then parse User values like this:
let user = User.from(json: """{
"name": "myUser",
"email": "user#example.com",
"password": "passwordHash"
}""")!
I wrote this small open-source library recently that lets you quickly and easily deserialize dictionaries into Swift objects: https://github.com/isair/JSONHelper
Using it, deserializing data becomes as easy as this:
var myInstance = MyClass(data: jsonDictionary)
or
myInstance <-- jsonDictionary
And models need to look only like this:
struct SomeObjectType: Deserializable {
var someProperty: Int?
var someOtherProperty: AnotherObjectType?
var yetAnotherProperty: [YetAnotherObjectType]?
init(data: [String: AnyObject]) {
someProperty <-- data["some_key"]
someOtherProperty <-- data["some_other_key"]
yetAnotherProperty <-- data["yet_another_key"]
}
}
Which, in your case, would be:
struct Person: Deserializable {
var name: String?
var email: String?
var password: String?
init(data: [String: AnyObject]) {
name <-- data["name"]
email <-- data["email"]
password <-- data["password"]
}
}
If you would like parse from and to json without the need to manually map keys and fields, then you could also use EVReflection. You can then use code like:
var user:User = User(json:jsonString)
or
var jsonString:String = user.toJsonString()
The only thing you need to do is to use EVObject as your data objects base class.
See the GitHub page for more detailed sample code
I am expanding upon Mohacs and Peter Kreinz's excellent answers just a bit to cover the array of like objects case where each object contains a mixture of valid JSON data types. If the JSON data one is parsing is an array of like objects containing a mixture of JSON data types, the do loop for parsing the JSON data becomes this.
// Array of parsed objects
var parsedObjects = [ParsedObject]()
do {
let json = try NSJSONSerialization.JSONObjectWithData(jsonData, options: []) as [Dictionary<String, AnyObject>]
// Loop through objects
for dict in json {
// ParsedObject is a single instance of an object inside the JSON data
// Its properties are a mixture of String, Int, Double and Bool
let parsedObject = ParsedObject()
// Loop through key/values in object parsed from JSON
for (key, value) in json {
// If property exists, set the value
if (parsedObject.respondsToSelector(NSSelectorFromString(keyName))) {
// setValue can handle AnyObject when assigning property value
parsedObject.setValue(keyValue, forKey: keyName)
}
}
parsedObjects.append(parsedObject)
}
} catch let error as NSError {
print("Failed to load: \(error.localizedDescription)")
}
This way lets you get the user from a URL. It's parse the NSData to a NSDictionary and then to your NSObject.
let urlS = "http://api.localhost:3000/"
func getUser(username: Strung) -> User {
var user = User()
let url = NSURL(string: "\(urlS)\(username)")
if let data = NSData(contentsOfURL: url!) {
setKeysAndValues(user, dictionary: parseData(data))
}
return user
}
func setKeysAndValues (object : AnyObject, dictionary : NSDictionary) -> AnyObject {
for (key, value) in dictionary {
if let key = key as? String, let value = value as? String {
if (object.respondsToSelector(NSSelectorFromString(key))) {
object.setValue(value, forKey: key)
}
}
}
return object
}
func parseData (data : NSData) -> NSDictionary {
var error: NSError?
return NSJSONSerialization.JSONObjectWithData(data, options: NSJSONReadingOptions.MutableContainers, error: &error) as! NSDictionary
}
In Swift 4, You can use the Decoding, CodingKey protocols to deserialize the JSON response:
Create the class which confirm the decodable protocol
class UserInfo: Decodable
Create members of the class
var name: String
var email: String
var password: String
Create JSON key enum which inherits from CodingKey
enum UserInfoCodingKey: String, CodingKey {
case name
case password
case emailId
}
Implement init
required init(from decoder: Decoder) throws
The whole class look like :
Call Decoder
// jsonData is JSON response and we get the userInfo object
let userInfo = try JsonDecoder().decode(UserInfo.self, from: jsonData)
You do this by using NSJSONSerialization. Where data is your JSON.
First wrap it in an if statement to provide some error handling capablity
if let data = data,
json = try NSJSONSerialization.JSONObjectWithData(data, options: []) as? [String: AnyObject] {
// Do stuff
} else {
// Do stuff
print("No Data :/")
}
then assign them:
let email = json["email"] as? String
let name = json["name"] as? String
let password = json["password"] as? String
Now, This will show you the result:
print("Found User iname: \(name) with email: \(email) and pass \(password)")
Taken from this Swift Parse JSON tutorial. You should check out the tutorial as it goes a lot more in depth and covers better error handling.