i want to include the rows also in the query instead of doing a different query to count its record, how can i do in mysql
my query looks like this
SELECT
tblItems.ItemsID,
tblItems.ItemsTitle,
tblItems.ItemsManager_ContactID,
tblItems.EndDate_Scheduled,
tblItems.ItemsViews_Target,
tblviews.viewsName,
tblcontact.FirstName,
tblcontact.LastName
FROM
tblItems
LEFT OUTER JOIN tblviews ON (tblItems.Items_viewsID = tblviews.viewsID)
LEFT OUTER JOIN tblcontact ON (tblItems.ItemsManager_ContactID = tblcontact.ContactID)
WHERE (tblItems.ItemsStatusID = 7)
ORDER BY tblItems.EndDate_Scheduled ASC, Items_viewsID ASC
i am not sure where i can add count, in SQL we can do but in mYsql i have no idea
If you want to determine the count of the returned rows, you will have to execute the same query again, but instead of selecting the rows, select the count:
SELECT count(*)
FROM
tblItems
LEFT OUTER JOIN tblviews ON (tblItems.Items_viewsID = tblviews.viewsID)
LEFT OUTER JOIN tblcontact ON (tblItems.ItemsManager_ContactID = tblcontact.ContactID)
WHERE (tblItems.ItemsStatusID = 7)
ORDER BY tblItems.EndDate_Scheduled ASC, Items_viewsID ASC
Related
Without going into the details of the tables, here is a query that outputs 34 rows.
SELECT `t`.`id_product`,
`product_lang`.`name`,
supplies_detail.id_supplies_detail,
`supplies_in_process`.id_supply
FROM `ps_product` `t`
LEFT OUTER JOIN `ps_product_lang` `product_lang` ON (`product_lang`.`id_product` = `t`.`id_product`)
LEFT OUTER JOIN `supplies_detail` `supplies_detail` ON (`supplies_detail`.`id_product` = `t`.`id_product`)
LEFT OUTER JOIN `supplies` `supplies_in_process`
ON (`supplies_detail`.`id_supply` = `supplies_in_process`.`id_supply`) AND
(supplies_in_process.state = 'added')
WHERE ((product_lang.name NOT LIKE '[del]%') AND (t.group_id = '14884'))
ORDER BY t.id_product DESC;
Query without GROUP BY
But it is important for the processor to understand that there will be no rows with duplicate t.id_product in the result, so we add GROUP BY t.id_product to this query.
The result changes to:
Query with GROUP BY
With exactly the same 34 rows we get additional unrelated data. How did it happen?
Thanks
MySQL 8.0.25-15
What I am trying to do it with below code, getting all keywords with their positions via LEFT JOIN, it works fine but it shows the first position of each keyword, but I want to show the last position that recorded (by date).
SELECT keyword.id, keyword.title, keyword.date, rank.position FROM keyword
LEFT JOIN rank
ON rank.wordid = keyword.id
GROUP BY keyword.id
ORDER BY keyword.date DESC
How can I do this? Should I use subquery or what? Is there any way to do this without a subquery?
SAMPLE DATA
What I want:
Get 17 instead of 13, I mean last record of position.
Do not use group by for this! You want to filter, so use a where clause. In this case, using a correlated subquery works well:
SELECT k.id, k.title, k.date, r.position
FROM keyword k LEFT JOIN
rank r
ON r.wordid = k.id AND
r.date = (SELECT MAX(r2.date)
FROM rank r2
WHERE r2.wordid = k.id
)
ORDER BY k.date DESC
You can use below query
SELECT keyword.id, keyword.title, keyword.date, rankNew.position FROM keyword LEFT JOIN (
SELECT rank.wordid, rank.position FROM rank ORDER BY rank.id DESC LIMIT 0, 1) AS rankNew ON (rankNew.wordid = keyword.id);
You can get more reference from Retrieving the last record in each group - MySQL
I am attempting to count the number of rows from a given query. But count returns more rows than it should. What is happening?
This query returns only 1 row.
select *
from `opportunities`
inner join `companies` on `opportunities`.`company_id` = `companies`.`id`
left join `opportunityTags` on `opportunities`.`id` = `opportunityTags`.`opportunity_id`
where `opportunities`.`isPublished` = '1' and `opportunities`.`Company_id` = '1'
group by `opportunities`.`id` ;
This query returns that there are 3 rows.
select count(*) as aggregate
from `opportunities`
inner join `companies` on `opportunities`.`company_id` = `companies`.`id`
left join `opportunityTags` on `opportunities`.`id` = `opportunityTags`.`opportunity_id`
where `opportunities`.`isPublished` = '1' and `opportunities`.`Company_id` = '1'
group by `opportunities`.`id`;
When you select count(*) it is counting before the group by. You can probably (unfortunately my realm is SQL Server and I don't have a mySQL instance to test) fix this by using the over() function.
For example:
select count(*) over (partition by `opportunities`.`id`)
EDIT: Actually doesn't look like this is available in mySQL, my bad. How about just wrapping the whole thing in a new select statement? It's not the most elegant solution, but will give you the figure you're after.
Some sql query gives me the following result:
As you can see, it already has GROUP BY.
So what I need? I need to group it again (by treatment_name) and count rows for each group. See more details on screenshot.
Here is full query:
SELECT
treatment_summaries.*
FROM `treatment_summaries`
INNER JOIN
`treatments`
ON
`treatments`.`treatment_summary_id` = `treatment_summaries`.`id`
AND
(treatment <> '' and treatment is not null)
INNER JOIN
`treatment_reviews`
ON
`treatment_reviews`.`treatment_id` = `treatments`.`id`
INNER JOIN
`conditions_treatment_reviews`
ON
`conditions_treatment_reviews`.`treatment_review_id` = `treatment_reviews`.`id`
INNER JOIN
`conditions` ON `conditions`.`id` = `conditions_treatment_reviews`.`condition_id`
INNER JOIN `conditions_treatment_summaries` `conditions_treatment_summaries_join`
ON
`conditions_treatment_summaries_join`.`treatment_summary_id` = `treatment_summaries`.`id`
INNER JOIN `conditions` `conditions_treatment_summaries`
ON `conditions_treatment_summaries`.`id` = `conditions_treatment_summaries_join`.`condition_id`
WHERE
`conditions`.`id` = 9
AND `conditions`.`id` IN (9)
AND (latest_review_id is not null)
GROUP BY
treatment_reviews.id
ORDER BY
treatment_summaries.reviews_count desc
LIMIT 20 OFFSET 0
Maybe there is another issue, cause GROUP BY should not leave same lines (for given column), but anyway you can wrap it like this:
SELECT * FROM ( YOUR_SQL_SELECT_WITH_EVERYTHING ) GROUP BY id
So the result you get will behave as another table and you can do all operations like GROUP BY again.
I have a function that gets a SQL code and inserts a count field in it and executes the query to return the number of rows in it. The objective is to have a dynamic SQL code and be able to get its record count no matter what code it has, because I use it in a registry filter window and I never know what code may be generated, because the user can add as many filters as he/she wants.
But as I use the group by clause, the result is wrong because it is counting the number of times a main registry appears because of the use on many join connections.
The result of that code above should only one row with a columns with 10 as result, but I get a new table with the first columns with a 2 in the first row and a 1 on the other rows.
If I take off the group by clause I will receive a 11 as a count result, but the first row will be counted twice.
What should I do to get a single row and the correct number?
SELECT
COUNT(*) QUERYRECORDCOUNT, // this line appears only in the Count() function
ARTISTA.*,
CATEGORIA.NOME AS CATEGORIA,
ATIVIDADE.NOME AS ATIVIDADE,
LOCALIDADE.NOME AS CIDADE,
MATRICULA.NUMERO AS MAP
FROM
ARTISTA
LEFT JOIN PERFIL ON PERFIL.REGISTRO = ARTISTA.ARTISTA_ID
LEFT JOIN CATEGORIA ON CATEGORIA.CATEGORIA_ID = PERFIL.CATEGORIA
LEFT JOIN ATIVIDADE ON ATIVIDADE.ATIVIDADE_ID = PERFIL.ATIVIDADE
LEFT JOIN LOCALIDADE ON LOCALIDADE.LOCALIDADE_ID = ARTISTA.LOCAL_ATIV_CIDADE
LEFT JOIN MATRICULA ON MATRICULA.REGISTRO = ARTISTA.ARTISTA_ID
WHERE
((ARTISTA.SIT_PERFIL <> 'NORMAL') AND (ARTISTA.SIT_PERFIL <> 'PRIVADO'))
GROUP BY
ARTISTA.ARTISTA_ID
ORDER BY
ARTISTA.ARTISTA_ID;
This always gives you the number of rows for any query you have:
Select count(*) as rowcount from
(
Paste your query here
) as countquery
Since your are GROUPING BY ARTISTA.ARTISTA_ID, COUNT(*) QUERYRECORDCOUNT will return records count for each ARTISTA.ARTISTA_ID value.
If you want GLOBAL count, then you need to use a nested query:
SELECT COUNT(*) AS QUERYRECORDCOUNT
FROM (SELECT
ARTISTA.*,
CATEGORIA.NOME AS CATEGORIA,
ATIVIDADE.NOME AS ATIVIDADE,
LOCALIDADE.NOME AS CIDADE,
MATRICULA.NUMERO AS MAP
FROM
ARTISTA
LEFT JOIN PERFIL ON PERFIL.REGISTRO = ARTISTA.ARTISTA_ID
LEFT JOIN CATEGORIA ON CATEGORIA.CATEGORIA_ID = PERFIL.CATEGORIA
LEFT JOIN ATIVIDADE ON ATIVIDADE.ATIVIDADE_ID = PERFIL.ATIVIDADE
LEFT JOIN LOCALIDADE ON LOCALIDADE.LOCALIDADE_ID = ARTISTA.LOCAL_ATIV_CIDADE
LEFT JOIN MATRICULA ON MATRICULA.REGISTRO = ARTISTA.ARTISTA_ID
WHERE
((ARTISTA.SIT_PERFIL <> 'NORMAL') AND (ARTISTA.SIT_PERFIL <> 'PRIVADO'))
GROUP BY
ARTISTA.ARTISTA_ID
ORDER BY
ARTISTA.ARTISTA_ID);
In this case, you may not need to select those many columns.
If you need to retrieve the all records count with details, then better to use two separate queries.