I am trying to make sort of a search engine that searched through JSON values in my Database.
I have a table with a column called data in data there is a JSON string, example:
{"type_geld":"cash","bedrag":15.0,"totaal":8899.0,"reden":"itemshop-bought-item","citizenid":"EHT44095","steamnaam":"Finn"}
Now I want to search through the key steamnaam I am currently using this query:
SELECT * FROM logs_1 WHERE JSON_CONTAINS(lower(`data`), '"finn"', "$.steamnaam")
This does give me the rows that contain finn as a value in the steamname JSON.
But now I want to also make it check if it's not exactly the same, but almost the same. So basically a LIKE search. Can I achieve this with JSON_CONTAINS or something like that?
So if I type fin instead of finn I also want it to list the rows because it almost matches finn.
I tried a lot of things, but could not figure it out, hope someone has the solution for me! Thank you.
The solution I found:
Apparently after googling a bit more, I found this query, that exactly does what I want:
SELECT * FROM logs_1 WHERE JSON_EXTRACT(lower(`data`), "$.steamnaam") LIKE "%fin%"
The only concern I have if this will stay fast with a lot of rows..
SELECT *
FROM logs_1
WHERE data->>'$.steamnaam' LIKE '%fin%' /* COLLATE according CI collation */
Related
I have some fields in a MYSQL database with the following content:
eq":"fieldname1+fieldname2+fieldname3+fieldname4/4
The numbers are always different, so it could also be something like:
eq":"fieldname11+fieldname22+fieldname8/10
I would like to run a query to achieve the following:
eq":"((fieldname1+fieldname2+fieldname3+fieldname4)/4, 2)
I currently have the following query
UPDATE wp_wrdydtdbww_cp_calculated_fields_form_settings
SET form_structure = REPLACE(form_structure, '???', '???')
WHERE id IN (1,2,3);
The problem is, that there are a lot of additional strings, containing 'fieldname' or '/' as well, so I need to replace the exact structure.
Can somebody help me to modify it?
I tried something with the LIKE pattern (%), but can't get it to work as I always replace other parts of strings as well.
Thanks!
I have a table with 3 columns something like below,
expert table
id - 1589
name - Jhonny
expert_in - 1,12,8 (Values similar like this)
The experts_in contains another table's foreign key
experts_in table
id - 1
expert_in - painting
I want search experts who are expert in some jobs while searching for experts
SELECT * FROM `experts` WHERE expert_in LIKE 1%
The above query brings all experts with 11,12,13...etc. I want only exact word. I know LIKE will bring all. Is there any way to achieve this without altering table. Thanks in advance.
You should use REGEXP. Try this query:
SELECT * FROM experts
WHERE expert_in REGEXP '[[:<:]]1[[:>:]]';
Output: See Live Demo on SQLFiddle
Note: You can adjust searching string based on your requirement above REGEXP is searching exact word.
if you can alter the data (not the table/schema) you should append and prepend another comma, so you can search with where col like "%,123,%", this will always fit on an exact value. Otherwise you have to use regex with something like ,?123,?
I have a table dictionary which contains a list of words Like:
ID|word
---------
1|hello
2|google
3|similar
...
so i want if somebody writes a text like
"helo iam looking for simlar engines for gogle".
Now I want to check every word if it exists in the database, if not it should
get me the similar word for the word. For example: helo = hello, simlar = similar, gogle = google.
Well, i want to fix the spelling errors. In my database i have a full dictionary of all english words. I coudn't find any mysql function which helps me. LIKE isn't helpfull in my situation.
you can use soundex() function for comparing phonetically
your query should be something like:
select * from table where soundex(word) like soundex('helo');
and this will return you the hello row
There is a function that does roughly want you want, but it's intensive and will slow queries down. You might be able to use in your circumstances, I have used it before. It's called Levenshtein. You can get it here How to add levenshtein function in mysql?
What you want to do is called a fuzzy search. You could use the SOUNDEX function in MySQL, documented here:
http://dev.mysql.com/doc/refman/5.7/en/string-functions.html#function_soundex
You query would look like:
SELECT * FROM dictionary where SOUNDEX(word) = SOUNDEX(:yourSearchTerm)
... where your search term is bound to the :yourSearchTerm parameter value.
A next step would be to try implementing and making use of a Levenshtein function in MySQL. One is described here:
http://www.artfulsoftware.com/infotree/qrytip.php?id=552
The Levenshtein distance between two strings is the minimum number of
operations needed to transform one string into the other, where an
operation may be insertion, deletion or substitution of one character.
You might also consider looking into databases that are aimed at full text searching, such as Elastic Search, which provides this natively:
https://www.elastic.co/guide/en/elasticsearch/reference/current/query-dsl-fuzzy-query.html
I'm trying to search through a database of sofware titles for those that have an interior capital letter (e.g PowerPoiint, inCase).
I tried
select * from table where field REGEXP '^([a-z][A-Z]+)+$'
This seemed to work as it returned a subset of the table and most were correct but a fair amount were not (e.g Alias). Clearly it is doing something right but not sure what; could it be that the ascii is somehow messed up?
Try this as your RegEx pattern:
^[A-z]+[A-Z][A-z]+$
It will match all the examples above (PowerPoint, inCase), and not match 'Alias', one of the examples that you are having trouble with.
Ok so the main problem is a poorly designed php script.. but I cant do any thing about that right now..
So I turn to you for some help! :)
I want to list all items that start with "a%".. easy!.. well not here.. by default the search is made with wildcards "%string%".
SELECT DISTINCT `Select2` FROM `items` WHERE `Select2` LIKE "%a%"
And I can´t change the search script... :/
Is there anyway that you can think of to get me around this problem?
There is no way to get around something hardcoded like that. But, since the results will include the results you are looking for, as well as substring matches, you can filter out the substring matches on the application side.