How can I display the records received from this query in ASC?
SELECT accounts.Nickname, chat.AccountID, chat.Message, chat.DateTime, accounts.Color
FROM (chat INNER JOIN accounts ON chat.AccountID = accounts.AccountID)
ORDER BY chat.MessageID DESC
LIMIT 100
Put your original query in a derived table (the subquery), and order its result in ASC order.
SELECT * FROM
(
SELECT accounts.Nickname, chat.AccountID, chat.Message, chat.DateTime, accounts.Color, chat.MessageID
FROM (chat INNER JOIN accounts ON chat.AccountID = accounts.AccountID)
ORDER BY chat.MessageID DESC
LIMIT 100
) dt
ORDER BY MessageID ASC
Related
am trying to count number of rows associated with a particular row from another table
SELECT *
FROM
(
(SELECT COUNT(*) totalusers
FROM mox_admin
, caspartition
WHERE mox_admin.partitionid = caspartition.id
)
) tita
, caspartition
ORDER
BY caspartition.id DESC
LIMIT 0,5
But the query keep returning the total count of rows in the "moz_admin" table
Here is what i did though i think is not the most efficient method
"SELECT * FROM caspartition ORDER BY caspartition.id DESC LIMIT 0, 5";
//execute the query then loop through
while($partition_data = mysqli_fetch_array($result)) {
$partition_id = $partition_data['id'];
$subquery_sql = "SELECT COUNT(*) AS totalusers FROM moz_admin WHERE partitionid = '$partition_id'";
$subquery_sql = mysqli_fetch_array(mysqli_query($conn, $subquery_sql));
$no_of_users = $subquery_sql[totalusers];
}
The whole point is making this a single SQL query instead querying the table for each row i loop through.
Thanks in advance.
You should combine these into one single query. The query would be:
SELECT cp.id, COUNT(a.partitionid) as cnt
FROM (SELECT *
FROM caspartition
ORDER BY caspartition.id DESC
LIMIT 0, 5
) cp LEFT JOIN
moz_admin a
ON a.partitionid = cp.id
GROUP BY cp.id;
Lets say I have a list of url's and I want to find out the url that is the most unique. I mean which is appearing the fewest. Here is an example of the database:
3598 ('www.emp.de/blog/tag/fear-factory/',)
3599 ('www.emp.de/blog/tag/white-russian/',)
3600 ('www.emp.de/blog/musik/die-emp-plattenkiste-zum-07-august-2015/',)
3601 ('www.emp.de/Warenkorb/car_/',)
3602 ('www.emp.de/ter_dataprotection/',)
3603 ('hilfe.monster.de/my20/faq.aspx#help_1_211589',)
3604 ('jobs.monster.de/l-nordrhein-westfalen.aspx',)
3605 ('karriere-beratung.monster.de',)
3606 ('karriere-beratung.monster.de',)
In this case it should return jobs.monster.de or hilfe.monster.de. I only want one return value. Is that possible with pure mysql?
It should be some kind of counting of the main url before the ".de"
At this moment I do it this way:
con.execute("select url, date from urls_to_visit ORDER BY RANDOM() LIMIT 1")
You could join the table on itself where ID's are not identical and count those, Then order by descending order and limit to 1 result.
not checked.
SELECT COUNT(*) as hitcount,
SUBSTRING_INDEX(t1.`url`,'.',2) as url
FROM table t1
INNER JOIN table t2 ON
SUBSTRING_INDEX(t1.`url`,'.',2) = SUBSTRING_INDEX(t2.`url`,'.',2)
AND t1.id <> t2.id
GROUP BY SUBSTRING_INDEX(t1.`url`,'.',2)
ORDER BY hitcount ASC
LIMIT 1
EDIT
Just checked on this, and it doesn't quite work.
I came up with this alternative, which uses a subquery to group all the domains together and get a count.
SELECT subq.count as hitcount,SUBSTRING_INDEX(t1.`url`,'.',2) as domain
FROM hits t1
INNER JOIN
(SELECT COUNT(*) as count,
SUBSTRING_INDEX(`url`,'.',2) as domain
FROM hits GROUP BY SUBSTRING_INDEX(`url`,'.',2)
) subq
ON subq.domain = SUBSTRING_INDEX(t1.`url`,'.',2)
GROUP BY SUBSTRING_INDEX(t1.`url`,'.',2)
ORDER BY hitcount ASC
LIMIT 1
working fiddle
Given your sample data (ignoring the parentheses, because I have no idea what those are doing), this query should do what you want:
select substring_index(url, '.', 2) as domain, count(*) as cnt
from table t
group by substring_index(url, '.', 2)
order by cnt desc
limit 1;
I'm trying to join two tables so I can easily order it, as one contains the names of items and the other doesn't. The tables:
user_games: UGID, UID, APPID, playtime
games_steam: APPID, name
my SQL so far:
SELECT user_games.*
FROM user_games
JOIN games_steam ON user_games.APPID = games_steam.APPID
WHERE user_games.UID = '76561197996836099'
GROUP BY user_games.APPID
ORDER BY games_steam.name ASC
LIMIT 0, 30
Just no idea how to get the name column into this aswell.
Is this what you are looking for?
SELECT user_games.*, games_steam.name
FROM user_games
JOIN games_steam
ON user_games.APPID = games_steam.APPID
WHERE user_games.UID = '76561197996836099'
GROUP BY user_games.APPID
ORDER BY games_steam.name ASC
LIMIT 0, 30
I have a query which does the job but instead of the trans_inventory (which is an ID of the location) I need to get the location_name.
This one is working to get the id
SELECT *
FROM {TABLE}
WHERE trans_product = 646
ORDER BY trans_date2 DESC Limit 1
But I wonder if I can do it this way, somehow embed the location table, I have tried but below doesn't work
SELECT *, site_location.location_name
FROM site_trans
cross join
(select *
From site_location)
site_location
WHERE trans_product=646 ORDER BY trans_date2 DESC Limit 1
sl.location in the JOIN must be the site_location location id field name - I used locastion_id but it might be likely id as well. I used LEFT JOIN to avoid missing site_trans in case there is no matching location id.
SELECT s.*, sl.location_name
FROM site_trans AS s
LEFT JOIN site_location AS sl ON sl.location_id = s.location_id
WHERE s.trans_product=646
ORDER BY s.trans_date2 DESC
Limit 1
This query below is perfect in producing the result for horse_id = 1 ... but I want to do this for all horses in the database. Can anyone share with me how to tweak this query so I can do that?
SELECT figures.entry_id,
max(figures.beyer)
FROM
( SELECT hrdb_lines.horse_id,
hrdb_entries.entry_id,
hrdb_lines.beyer
FROM hrdb_entries
INNER JOIN hrdb_lines
ON hrdb_lines.horse_id = hrdb_entries.horse_id
WHERE hrdb_lines.horse_id = 1
ORDER BY hrdb_lines.line_date DESC
LIMIT 2
) as figures
Perhaps I'm doing it all wrong too.
I think the following would generate the desired results:
SELECT `entry_id`, `beyer`
FROM (SELECT hrdb_entries.entry_id,
MAX( hrdb_lines.beyer )
FROM hrdb_entries
INNER JOIN hrdb_lines
ON hrdb_lines.horse_id = hrdb_entries.horse_id
GROUP BY hrdb_lines.horse_id
ORDER BY hrdb_lines.line_date DESC
) AS figures
If I'm understanding your question, something like this should be close:
SELECT
figures.horse_id,
figures.entry_id,
max(figures.beyer)
FROM
(SELECT
hrdb_lines.horse_id,
hrdb_entries.entry_id,
hrdb_lines.beyer
FROM hrdb_entries
INNER JOIN hrdb_lines ON hrdb_lines.horse_id = hrdb_entries.horse_id
ORDER BY hrdb_lines.line_date DESC
) as figures
GROUP BY figures.horse_id
One option to limit the MAX to just the most recent 2 beyer fields is to add a row number to the results and only include rows 1 and 2.
SELECT
figures.horse_id,
figures.entry_id,
max(figures.beyer)
FROM
(SELECT
#rn:=if(#prev_horse_id=horse_id,#rn+1,1) rn,
hrdb_lines.horse_id,
hrdb_entries.entry_id,
hrdb_lines.beyer,
#prev_horse_id:=hrdb_lines.horse_id
FROM hrdb_entries
INNER JOIN hrdb_lines ON hrdb_lines.horse_id = hrdb_entries.horse_id
INNER JOIN (SELECT #rn:=0) r
ORDER BY hrdb_lines.horse_id, hrdb_lines.line_date DESC
) as figures
WHERE rn <= 2
GROUP BY figures.horse_id