I have two tables.
job_table.
job_id job_type job_type *****
1 1 Day *****
2 2 Night
3 3 Day & Night.
4 3 Day & Night.
and task_entry table.
task_entry_id job_type task_option_type
1 1 Day
2 1 Day
3 1 Day
4 2 Night
5 3 Day
6 3 Night
7 3 Day
8 3 Night
If job id is 3 then there will be 2 entries one for Day and one for Night.
Else only one entry.
I want to get the total count of jobs with task_entries like this,
job_id task_entry_count
1 3
2 1
3 2
That is if job_type is 3 then count should be count/2. (Day&Night).
Else count should be normal count.
You can JOIN the two tables together and then use GROUP BY to get the number of total count of jobs.
SELECT jt.job_id,
ROUND(SUM (CASE WHEN jt.job_type = 3 THEN 0.5 ELSE 1 END), 0) AS task_entry_count
FROM job_table jt INNER JOIN task_entry te
ON jt.job_type = te.job_type
GROUP BY jt.job_id
In MySQL I'm tasked with a big dataset, with data from 1970 to 2010.
I want to check for consistency: check if each instance occurs minimum one time per year. I took a snippet from 1970-1972 as example to demonstrate my problem.
input:
id year counts
-- ---- ---------
1 1970 1
1 1971 1
2 1970 3
2 1971 8
2 1972 1
3 1970 4
expected:
id 1970-1972
-- ----------
1 no
2 yes
3 no
I though about counting within the date range and then taking those out who had 3 counts: 1970, 1971, 1972. The following query doesn't force the check on each point in the range though.
select id, count(*)
from table1
WHERE (year BETWEEN '1970' AND '1972') AND `no_counts` >= 1
group by id
What to do?
You can use GROUP BY with CASE / inline if.
Using CASE. SQL Fiddle
select id,CASE WHEN COUNT(distinct year) = 3 THEN 'yes'ELSE 'No' END "1970-72"
from abc
WHERE year between 1970 and 1972
GROUP BY id
Using inline IF. SQL Fiddle
select id,IF( COUNT(distinct year) = 3,'yes','No') "1970-72"
from abc
WHERE year between 1970 and 1972
GROUP BY id
You can use a having clause with distinct count:
select `id`
from `table1`
where `year` between '1970' and '1972'
group by id
having count(distinct `year`) = 3
Do you expect this?
select id, count(*)
from table1
WHERE (year BETWEEN '1970' AND '1972')
group by id
having count(distinct year) = 3
I have example data
ID DAY ORDER TIME PRODUCT
1 1 1 1 1
2 1 1 1 2
3 1 1 1 3
4 1 2 2 1
5 1 2 2 2
6 1 2 2 3
7 1 2 *3* 1
8 1 2 *3* 2
9 1 2 *3* 3
I want to prevent to having mltiple orders in different time at same day. if I set unique index on DAY,ORDER,TIME I will not be able to insert multiple time anyway, but I want to disable multiple different TIME. Is this possible with mysql?
Have can I find all records where there multiple different TIME value in same DAY and ORDER and delete them?
in this case I would like to delete records 7,8 ad 9 with SQL query because it is duplicate ORDER inserted.
I don't want to normalize table I will stick with this database structure.
Thank you very much
You can use delete with a join clause to find the duplicates and delete them:
delete
from t join
(select day, "order", min(time) as tokeeptime
from t
group by day, "order"
) tokeep
on t.day = tokeep.day and t."order" = tokeep."order" and t.time <> tokeeptime;
DELETE a
FROM tableName a
INNER JOIN
(
SELECT a.DAY, a.ORDER, MAX(a.TIME) Time
FROM tableName a
GROUP BY a.DAY, a.ORDER
HAVING COUNT(DISTINCT TIME) > 1
) b ON a.DAY = b.DAY AND
a.Order = b.Order AND
a.Time = b.Time
SQLFiddle Demo
I am having an issue with a SELECT command in MySQL. I have a database of securities exchanged daily with maturity from 1 to 1000 days (>1 mio rows). I would like to get the outstanding amount per day (and possibly per category). To give an example, suppose this is my initial dataset:
DATE VALUE MATURITY
1 10 3
1 15 2
2 10 1
3 5 1
I would like to get the following output
DATE OUTSTANDING_AMOUNT
1 25
2 35
3 15
Outstanding amount is calculated as the total of securities exchanged still 'alive'. That means, in day 2 there is a new exchange for 10 and two old exchanges (10 and 15) still outstanding as their maturity is longer than one day, for a total outstanding amount of 35 on day 2. In day 3 instead there is a new exchange for 5 and an old exchange from day 1 of 10. That is, 15 of outstanding amount.
Here's a more visual explanation:
Monday Tuesday Wednesday
10 10 10 (Day 1, Value 10, matures in 3 days)
15 15 (Day 1, 15, 2 days)
10 (Day 2, 10, 1 day)
5 (Day 3, 5, 3 days with remainder not shown)
-------------------------------------
25 35 15 (Outstanding amount on each day)
Is there a simple way to get this result?
First of all in the main subquery we find SUM of all Values for current date. Then add to them values from previous dates according their MATURITY (the second subquery).
SQLFiddle demo
select T1.Date,T1.SumValue+
IFNULL((select SUM(VALUE)
from T
where
T1.Date between
T.Date+1 and T.Date+Maturity-1 )
,0)
FROM
(
select Date,
sum(Value) as SumValue
from T
group by Date
) T1
order by DATE
I'm not sure if this is what you are looking for, perhaps if you give more detail
select
DATE
,sum(VALUE) as OUTSTANDING_AMOUNT
from
NameOfYourTable
group by
DATE
Order by
DATE
I hope this helps
Each date considers each row for inclusion in the summation of value
SELECT d.DATE, SUM(m.VALUE) AS OUTSTANDING_AMOUNT
FROM yourTable AS d JOIN yourtable AS m ON d.DATE >= m.MATURITY
GROUP BY d.DATE
ORDER BY d.DATE
A possible solution with a tally (numbers) table
SELECT date, SUM(value) outstanding_amount
FROM
(
SELECT date + maturity - n.n date, value, maturity
FROM table1 t JOIN
(
SELECT 1 n UNION ALL
SELECT 2 UNION ALL
SELECT 3 UNION ALL
SELECT 4 UNION ALL
SELECT 5
) n ON n.n <= maturity
) q
GROUP BY date
Output:
| DATE | OUTSTANDING_AMOUNT |
-----------------------------
| 1 | 25 |
| 2 | 35 |
| 3 | 15 |
Here is SQLFiddle demo
I have a record set for inspections of many pieces of equipment. The four cols of interest are equip_id, month, year, myData.
My requirement is to have EXACTLY ONE record per month for each piece of equipment.
I have a query that makes the data unique over equip_id, month, year. So there is no more than one record for each month/year for a piece of equipment. But now I need to simulate data for the missing month. I want to simply go back in time to get the last piece of my data.
So that may seem confusing, so I'll show by example.
Given this sample data:
equip_id month year myData
-----------------------------
1 1 2010 500
1 2 2010 600
1 5 2010 800
2 2 2010 300
2 4 2010 400
2 6 2010 500
I want this output:
equip_id month year myData
-----------------------------
1 1 2010 500
1 2 2010 600
1 3 2010 600
1 4 2010 600
1 5 2010 800
2 2 2010 300
2 3 2010 300
2 4 2010 400
2 5 2010 400
2 6 2010 500
Notice that I'm filling in missing data with the data from the month (or two months etc.) before. Also note that if the first record for equip 2 is in 2/2010 than I don't need a record for 1/2010 even though I have one for equip 1.
I just need exactly one record for each month/year for each piece of equipment. So if the record does not exist I just want to go back in time and grab the data for that record.
Thanks!
By no means perfect:
SELECT equip_id, month, mydata
FROM (
SELECT equip_id, month, mydata FROM equip
UNION ALL
SELECT EquipNum.equip_id, EquipNum.Num,
(SELECT Top 1 mydata
FROM equip
WHERE equip.month<n.num And equip.equip_id=equipnum.equip_id
ORDER BY equip.month desc) AS Data
FROM
(SELECT e.equip_id, n.Num
FROM
(SELECT DISTINCT equip_id FROM equip) AS e,
Numbers AS n) AS EquipNum
LEFT JOIN equip
ON (EquipNum.Num = equip.month)
AND (EquipNum.equip_id = equip.equip_id)
WHERE EquipNum.Num<DMax("month","equip")
AND
(SELECT top 1 mydata
FROM equip
WHERE equip.month<n.num And equip.equip_id=equipnum.equip_id
ORDER BY equip.month desc) Is Not Null
AND equip.equip_id Is Null AND equip.Month Is Null) AS x
ORDER BY equip_id, month
For this to work you need a Numbers table, in this case it needs only hold integers from 1 to 12. The numbers table I used is called Numbers and the field is called Num.
EDIT re years comment
SELECT equip_id, year, month, mydata
FROM (
SELECT equip_id, year, month, mydata FROM equip
UNION ALL
SELECT en.equip_id, en.year, en.Num, (SELECT Top 1 mydata
FROM equip e
WHERE e.month<n.num And e.year=en.year And e.equip_id=en.equip_id
ORDER BY e.month desc) AS Data
FROM (SELECT e.equip_id, n.Num, y.year
FROM
(SELECT DISTINCT equip_id FROM equip) AS e,
Numbers AS n,
(SELECT DISTINCT year FROM equip) AS y) AS en
LEFT JOIN equip AS e ON en.equip_id = e.equip_id
AND en.year = e.year
AND en.Num = e.month
WHERE en.Num<DMax("month","equip") AND
(SELECT Top 1 mydata
FROM equip e
WHERE e.month<n.num And e.year=en.year And e.equip_id=en.equip_id
ORDER BY e.month desc) Is Not Null
AND e.equip_id Is Null
AND e.Month Is Null) AS x
ORDER BY equip_id, year, month
I've adjusted to account for year and month... The primary principles remain the same as the original queries presented where just the month. However, for applying a month and year, you need to test for the SET of YEAR + MONTH, ie: what happens if Nov/2009, then jump to Feb/2010, You can't rely on just a month being less than another, but the "set". So, I've apply the year * 12 + month to prevent a false value such as Nov=11 + year=2009 = 2009+11 = 2020, then Feb=2 of year=2010 = 2010+2 = 2012... But 2009*12 = 24108 + Nov = 11 = 24119 compared to 2010*12 = 24120 + Feb =2 = 24122 -- retains proper sequence per year/month combination. The rest of the principles apply. However, one additional, I created a table to represent the span of years to consider. For my testing, I added a sample Equip_ID = 1 entry with a Nov-2009, and Equip_ID = 2 with a Feb-2011 entry and the proper roll-over works too. (Table C_Years, column = year and values of 2009, 2010, 2011)
SELECT
PYML.Equip_ID,
PYML.Year,
PYML.Mth,
P1.MyData
FROM
( SELECT
PAll.Equip_ID,
PAll.Year,
PAll.Mth,
( SELECT MAX( P1.Year*12+P1.Mth )
FROM C_Preset P1
WHERE PAll.Equip_ID = P1.Equip_ID
AND P1.Year*12+P1.Mth <= PAll.CurYrMth) as MaxYrMth
FROM
( SELECT
PYM1.Equip_ID,
Y1.Year,
M1.Mth,
Y1.Year*12+M1.Mth as CurYrMth
FROM
( SELECT p.equip_id,
MIN( p.year*12+p.mth ) as MinYrMth,
MAX( p.year*12+p.mth ) as MaxYrMth
FROM
C_Preset p
group by
1
) PYM1,
C_Years Y1,
C_Months M1
WHERE
Y1.Year*12+M1.Mth >= PYM1.MinYrMth
AND Y1.Year*12+M1.Mth <= PYM1.MaxYrMth
) PAll
) PYML,
C_Preset P1
WHERE
PYML.Equip_ID = P1.Equip_ID
AND PYML.MaxYrMth = P1.Year*12+P1.Mth
If this is going to be a repetative thing/report, I would just create a temporary table with 12 months -- then use that as the primary table, and do a left OUTER join to the rest of your data. This way, you know you'll always get every month, but only when a valid join to the "other side" is identified, you'll get that data too. Ooops... missed your point about the filling in missing elements from the last element... Thinking...
The following works... and I'll describe the elements to what is going on. First, I created a temp table "C_Months" with a column Mth (month) with numbers 1-12. I used "Mth" as an abbreviation of Month to not cause possible conflict with POSSIBLE reserved word MONTH. Additionally, in my query, the table reference "C_Preset" is the prepared set of data you mentioned you already have of distinct elements.
SELECT
LVM.Equip_ID,
LVM.Mth,
P1.Year,
P1.MyData
FROM
( SELECT
JEM.Equip_ID,
JEM.Mth,
( SELECT MAX( P.Mth )
FROM C_Preset P
WHERE P.Equip_ID = JEM.Equip_ID
AND P.Mth <= JEM.Mth ) as MaxMth
FROM
( SELECT distinct
p.equip_id,
c.mth
FROM
C_months c,
C_Preset p
group by
1, 2
HAVING
c.mth >= MIN( p.Mth )
and c.mth <= MAX( p.Mth )
ORDER BY
1, 2 ) JEM
) LVM,
C_Preset P1
WHERE
LVM.Equip_ID = P1.Equip_ID
AND LVM.MaxMth = P1.Mth
ORDER BY
1, 2
The inner most query is a query of the available months (C_Months) associated with a given equipment ID. In your example, equipment ID 1 had a values of 1,2,5. So this would return 1, 2, 3, 4, 5. And for Equipment ID 2, it started with 2, but ended with 6, so it would return 2, 3, 4, 5, 6. Hence the aliased reference JEM (Just Equipment Months)
Then, the field selection for MaxMth (Maximum month)... This is the TRICKY ONE
( SELECT MAX( P.Mth )
FROM C_Preset P
WHERE P.Equip_ID = JEM.Equip_ID
AND P.Mth <= JEM.Mth ) as MaxMth
From this, stating I want the maximum month AVAILABLE (from JEM) associated with the given equipment that is AT OR LESS than the month In question (detecting the highest "valid" equipment item/month within the qualified list. The result of this would result in...
Equip_ID Mth MaxMth
1 1 1
1 2 2
1 3 2
1 4 2
1 5 5
2 2 2
2 3 2
2 4 4
2 5 4
2 6 6
So, for your example of ID = 1, you had months 1, 2, 5 (3 and 4 were missing), so the last valid month that 3 and 4 would refer to is sequence #2's month. Likewise for ID = 2, you had months 2, 4 and 6... Here, 3 would refer back to 2, 5 would refer back to 4.
The rest is the easy part. Now, we join your LVM (Last Valid Month) result as shown above to your original C_Preset (less records). But since we now have the last valid month to directly associate to an existing record in the C_Preset, we join by equipment id and the MaxMth colum, and NOT THE ACTUAL month.
Hope this helps... Again, you'll probably have to change my "mth" column references to "month" to match your format.