My target SQL is the following, which is valid,
SELECT a.agreement_group_id,
(select id from agreement_t where agreement_group_id = a.agreement_group_id and
active = 'Y'),
...
FROM ets.agreement_t a
WHERE requester_uniqueidentifier = '0010079170'
GROUP BY a.agreement_group_id
ORDER BY a.agreement_group_id
But SqlAlchemy is producing the following -- and complaining that I don't have anon_1 in GROUP BY due to its placement of the sub-select in FROM,
SELECT agreement_t_1.agreement_group_id AS agreement_t_1_agreement_group_id,
anon_1.id AS anon_1_id,
...
FROM ets.agreement_t AS agreement_t_1,
(SELECT ets.agreement_t.id AS id
FROM ets.agreement_t, ets.agreement_t AS agreement_t_1
WHERE ets.agreement_t.agreement_group_id = agreement_t_1.agreement_group_id AND
ets.agreement_t.active = 'Y') AS anon_1
WHERE agreement_t_1.requester_uniqueidentifier = '0010079170'
GROUP BY agreement_t_1.agreement_group_id, anon_1.id
ORDER BY agreement_t_1.agreement_group_id
Python SqlAlchemy code:
agreement = aliased(AgreementT)
subqueryActive = db_session.query(AgreementT.id).filter(
(AgreementT.agreement_group_id == agreement.agreement_group_id),
(AgreementT.active == 'Y')
).subquery()
result = (db_session.query(
agreement.agreement_group_id,
subqueryActive,
...
.filter(*filters)
.group_by(agreement.agreement_group_id)
.order_by(agreement.agreement_group_id)
.all())
I don't need any other Joins. As you can see, the subquery subqueryActive already references the alias agreement which is used in the main query. So why is the Sub-Select not placed properly in the SELECT, but rather in the FROM, with the following error?
psycopg2.errors.GroupingError: column "anon_1.id" must appear in the GROUP BY clause or be used in an aggregate function
LINE 1: ...ent_group_id AS agreement_t_1_agreement_group_id, anon_1.id ...
^
If the sub-Select should be part of the SELECT, we can't use .subquery(), we need to use .label() instead.
Example here: https://stackoverflow.com/a/43655840/1005607
Thanks for the tip #Ilja Everilä
Related
I want to select a bunch distinct records based off a composite key. In SQL I'd write something like this:
SELECT * FROM security WHERE (
exchange_code = 'exchange_code_1' AND code = 'code_1')
OR (exchange_code = 'exchange_code_2' AND code = 'code_2')
...
OR (exchange_code = 'exchange_code_N' AND code = 'code_N')
)
With SQLAlchemy I'd like to use the filter clause like:
query = sess.query(Security)
[query.filter(
and_(Security.exchange_code == security.exchange_code,
Security.code == security.code)
) for security in securities]
result = query.all()
The problem is filter and where join clauses with an AND not an OR... is there some way to use filter with OR?
Or is my only choice to generate a bunch of individual select's and UNION them? Something like:
first = exchanges.pop()
query = reduce(lambda query, exchange: query.union(exchange.pk_query),
first.pk_query())
query.all()
Use or_:
query = sess.query(Security).filter(
or_(*(and_(Security.exchange_code == security.exchange_code,
Security.code == security.code)
for security in securities)))
If your database supports it, you should use tuple_ instead.
I am trying to use the following query in SQL Server
SELECT [AL].[Subscriptions].Id,
[AL].[Subscriptions].name,
[AL].[Subscriptions].description,
[AL].[Subscriptions].price,
[AL].[Subscriptions].iconFileName,
IIf(a.expiryDate > Now(), 'TRUE', 'FALSE') AS isSubsByUser
FROM [AL].[Subscriptions]
LEFT JOIN (SELECT *
FROM [AL].[UserSubscriptions]
WHERE userId = 13259) AS a
ON Subscriptions.Id = a.itemid;
but always get the error
Error in list of function arguments: '>' not recognized.
Unable to parse query text.
How do I resolve it?
Like Martin Smith said you need to use a case statement. Also it looks like you are only using a couple of fields in the derived table therefor I would suggest not using *. I put a example below.
SELECT [AL].[Subscriptions].Id,
[AL].[Subscriptions].name,
[AL].[Subscriptions].description,
[AL].[Subscriptions].price,
[AL].[Subscriptions].iconFileName,
case when a.expiryDate > GetDate() then 'TRUE' else 'FALSE' end AS isSubsByUser
FROM [AL].[Subscriptions]
LEFT JOIN (SELECT expiryDate, itemid
FROM [AL].[UserSubscriptions]
WHERE userId = 13259) AS a
ON Subscriptions.Id = a.itemid;
I try to do the follwoing request in SQLAlchemy (ORM) :
SELECT id, ref_prog FROM stepvand_1c_1t.equipment_day_hour
WHERE id IN (SELECT id FROM stepvand_1c_1t.equipment WHERE equipment_type='L')
I did :
subq = session.query(Equipment)
subq = subq.filter(Equipment.equipment_type == "L").subquery()
query = session.query(EquipmentDayHour)
query = query.filter(EquipmentDayHour.id.in_(subq))
But that doesn't work...
Python tells me that the subrequest has too many columns.
I think you should only change one line of your sample code:
# error: includes all columns of Equipment
`subq = session.query(Equipment)`
# correct: include only ID column
`subq = session.query(Equipment.id)`
However, I believe that you can do this without subquery:
query = (session.query(EquipmentDayHour).
# version-1: if you have a relationship between EquipmentDayHour and Equipment
join(Equipment).
# version-2: if you do not have such relationship
#join(Equipment, EquipmentDayHour.id==Equipment.id).
filter(Equipment.equipment_type == "L")
)
I have a contact table I wish to query when a certain condition exists. I tried the query below but am getting a syntax error.
SELECT *
FROM contact_details
WHERE contactDeleted` =0
AND IF ( contactVisibility = "private"
, SELECT * FROM contact_details
WHERE contactUserId = 1
, IF( contactVisibility = "group"
, SELECT * FROM contact_details
WHERE contactGroup = 3
)
)
If I'm understanding your question correctly (which is difficult with the lack of info you've provided. Sample datasets and expected outcomes are typically helpful), then I don't believe you need IFs at all for what you want. The following will return contacts that are not deleted and who either have (visibility = "private" and userId = 1) OR (visibility = "group" and group = 3)
SELECT *
FROM contact_details
WHERE contactDeleted = 0
AND (
(contactVisibility = "public")
OR
(contactVisibility = "private" AND contactUserId = 1)
OR
(contactVisibility = "group" AND contactGroup = 3)
)
I am assuming you want to use the IF() function and not the statement which is for stored functions..
Refer to this link for more information on that.
Notice that you have put 2 select statements in there, where the custom return values are supposed to be. So you are returning a SELECT *... now notice that in your upper level sql statement you have an AND.. so you basically writing AND SELECT *.. which will give you the syntax error.
Try using .. AND x IN (SELECT *) .. to find if x is in the returned values.
Let me also list this link to make use of an existing and well written answer which may also applicable to your question.
I have a multi-table SQL query.
My need is: The query should I generate a single line by 'etablissement_id' ... and all information that I want to be back in the same query.
The problem is that this query is currently on a table where "establishment" may have "multiple photos" and suddenly, my query I currently generates several lines for the same id...
I want the following statement - LEFT JOINetablissementContenuMultimediaON etablissement.etablissement_id = etablissementContenuMultimedia.etablissementContenuMultimedia_etablissementId - only a single multimedia content is displayed. Is it possible to do this in the query below?
Here is the generated query.
SELECT DISTINCT `etablissement`. * , `etablissementContenuMultimedia`. * , `misEnAvant`. * , `quartier`. *
FROM `etablissement`
LEFT JOIN `etablissementContenuMultimedia` ON etablissement.etablissement_id = etablissementContenuMultimedia.etablissementContenuMultimedia_etablissementId
LEFT JOIN `misEnAvant` ON misEnAvant.misEnAvant_etablissementId = etablissement.etablissement_id
LEFT JOIN `quartier` ON quartier_id = etablissement_quartierId
WHERE (
misEnAvant_typeMisEnAvantId =1
AND (
misEnAvant_dateDebut <= CURRENT_DATE
AND CURRENT_DATE <= misEnAvant_dateFin
)
)
AND (
etablissement_isActive =1
)
ORDER BY `etablissement`.`etablissement_id` ASC
LIMIT 0 , 30
Here is the code used ZF
public function find (){
$db = Zend_Db_Table::getDefaultAdapter();
$oSelect = $db->select();
$oSelect->distinct()
->from('etablissement')
->joinLeft('etablissementContenuMultimedia', 'etablissement.etablissement_id = etablissementContenuMultimedia.etablissementContenuMultimedia_etablissementId')
->joinLeft('misEnAvant', 'misEnAvant.misEnAvant_etablissementId = etablissement.etablissement_id')
->joinLeft('quartier', 'quartier_id = etablissement_quartierId ')
->where ('misEnAvant_typeMisEnAvantId = 1 AND (misEnAvant_dateDebut <= CURRENT_DATE AND CURRENT_DATE <= misEnAvant_dateFin) ')
->where ('etablissement_isActive = 1')
->order(new Zend_Db_Expr('RAND()'));
$zSql = $oSelect->__toString();
if(isset($_GET['debug']) AND $_GET['debug'] == 1)
echo $zSql ;
//die();
$oResultEtablissement = $db->fetchAll($oSelect);
return $oResultEtablissement ;
}
Can you help me?
Sincerely,
If you are looking to have only one of the media displayed out of many regardless of which it may be then you can just add a limit to the query? After that you can tweak the query for ASCending or DESCending perhaps?
Is this query supposed to have images (or image as it were) for one establishment, or one image each for each active establishment? I see you have a limit 0,30 which means you're likely paginating....
If the result you want is a search for only one establishment, and the first image it comes to would work fine .. just use "limit 1" and you'll only get one result.
I took the time to redo the whole model of the database ... and now it works. There was no solution for a system as flawed