Alias Sequelize - mysql

Question

I have this query in sequelize:
Domicilio.hasMany(User, {foreignKey: 'UserId'});
const abonados = await Domicilio.findAll({include: User});
Which result is the following:
SELECT domicilio.DomicilioId, _users.UserId AS _users.UserId, _users.UserName AS _users.UserName, _users.FullName AS _users.FullName, _users.Password AS _users.Password, _users.Documento AS _users.Documento, _users.Cuit AS _users.Cuit, _users.Email AS _users.Email, _users.FechaBajada AS _users.FechaBajada, _users.FechaContrato AS _users.FechaContrato, _users.FechaNacimiento AS _users.FechaNacimiento, _users.Phone AS _users.Phone, _users.FailedPasswordCount AS _users.FailedPasswordCount, _users.IsActive AS _users.IsActive, _users.IsLocked AS
_users.IsLocked, _users.IsTestUser AS _users.IsTestUser, _users.LastLoginDate AS _users.LastLoginDate, _users.createdAt AS _users.createdAt, _users.createdBy AS _users.createdBy, _users.deletedAt AS _users.deletedAt, _users.deletedBy AS _users.deletedBy, _users.updatedAt AS _users.updatedAt, _users.updatedBy AS _users.updatedBy, _users.CondicionIVAId AS _users.CondicionIVAId, _users.OnuId AS _users.OnuId, _users.ServicioId AS _users.ServicioId FROM domicilio AS domicilio LEFT OUTER JOIN _user AS _users ON domicilio.DomicilioId = _users.UserId;
But I don't need the ALIAS of each of the columns of table _user. E.g _user.UserId I need only the name of each column without alias. Is there any way to aproach this?

Answer 1

There are some ways to change the value of the returning column
First I would suggest that you fetch only the columns really needed
by you at the model endpoint that way the response is concise.
Please refer the code below in which you can see how you can provide
alias in an association, the alias you provide in there is the one
which is used during the include you can fiddle around to get the
desired behavior. Also, you can tweak your findAll with option
params like {raw: true}
Official Docs:
https://sequelize.org/master/manual/assocs.html
https://sequelize.org/master/class/lib/model.js~Model.html#static-method-findAll
Ship.belongsTo(Captain, { as: 'leader' }); // This creates the `leaderId` foreign key in Ship.
// Eager Loading no longer works by passing the model to `include`:
console.log((await Ship.findAll({ include: Captain })).toJSON()); // Throws an error
// Instead, you have to pass the alias:
console.log((await Ship.findAll({ include: 'leader' })).toJSON());
// Or you can pass an object specifying the model and alias:
console.log((await Ship.findAll({
include: {
model: Captain,
as: 'leader'
}
})).toJSON());
Second but not very recommended way is to provide a raw query with
the parameter [Do not use javascript template string to pass the
args] here you have control over the params and conditions
Docs for raw query: https://sequelize.org/master/manual/raw-queries.html
Lastly, you can use alias in attribute to customize the value's key
to anything you like
const abonados = await Domicilio.findAll({
include: User,
attributes: [['UserId', 'newUserId'], ['UserName 'newUserName']]
});
P.S: literal might also come in handy at times.