HTML button inside a Razor component within a Razor page - html

I have a page called CreateForm
On my CreateForm page, after the customer enters the data, they can preview their entry before I save it to the database. Their Preview is a Razor component and contains an html button to submit.
The problem I have is if a customer is click happy, he may click the button multiple times creating multiple copies. Therefore I want to disable the button after the first click. How can I grab the button's handle?
From the CreateForm razor page, I have this embeded Razor component
<CustomerPreviewRequest HeadingToShow="#HeadingToShowPreviewCustomerScreen"
onBack="MoveToPreviousPage"
CurrentCustomerSubmission="#_model">
</CustomerPreviewRequest>
inside the CustomerPreviewRequest, here's how I define the button
<button aria-label="Submit Request." type="submit" class="login100-form-btn" style="background-color:#1a2b57"
tabindex="0" id="submitForm">
Submit Request
</button>

Do you only want the customer to submit the data once and then disable the submit button? You can take a look at this simple demo:
View:
<p style="text-align:center">
<form id="yourFormId" name="yourFormId" method="post" action="#">
<input type="text" /><br />
<input type="submit" class="submitBtn" value="Submit Requestt" />
</form>
</p>
<!--script to disable the submit button -->
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js">
</script>
<script type="text/javascript">
$(document).ready(function () {
$(".submitBtn").click(function () {
$(".submitBtn").attr("disabled", true);
return true;
});
});
</script>
Result:

Related

Submit buttons' value doesn't pass when used in modal

There is a button in a form (shown below). The button properly passes its value on submit to the code below when employed in a regular(if you want to call it regular) Django-templated HTML page.
<button type="submit" class="btn btn-primary" name="revoke" value="1" form="my-form">Revoke</button>
The serialized data will contain revoke and its value
`$('#my-form').on('submit', function(event) {
event.preventDefault();
console.log($(this).serialize());
However, if the form is embedded in a modal as provided by Bootstrap 4, the serialized data has the rest of the form data, but no revoke. It would be very nice if the button passed the revoke as well.
As serialize() methods create a string with parameter separated by & you can attach value of button as well using "&revoke=" + $("[name=revoke]").val() then this will also get passed to your backend page.
Demo Code :
$('#my-form').on('submit', function(event) {
event.preventDefault();
//attch revoke as well
var formdatas = $(this).serialize() + "&revoke=" + $("[name=revoke]").val();
console.log(formdatas)
})
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<form id="my-form">
<input type="text" name="acd">
<input type="text" name="acd1">
<button type="submit" class="btn btn-primary" name="revoke" value="1" form="my-form">Revoke</button>
</form>

User input text box to display on same page

I have a text box for user input, how can I take the input a user enters and display it on the same page (without reloading or redirecting to a different page). (example, comments on YouTube videos)
Here is my code for the user input text box so far:
<div class="container">
<form>
<label for="post" id="post">What's on your mind?</label><br>
<input type="text" id="post-box" name="post">
<button>Comment</button>
</form>
</div>
Do you mean like this? It require DOM manipulation and event listener. Make sure refer this two to help you more. :D
First, add event listener to listen any changes on keyboard press for the form (even though i just put it globally). Here all the your listener references https://www.w3schools.com/jsref/dom_obj_event.asp
Second change the innerHTML to display ur name. Here for your references
https://www.w3schools.com/jsref/prop_html_innerhtml.asp
<html>
<p id="p-display"></p>
<div class="container">
<form>
<label for="post" id="post">What's on your mind?</label><br>
<input type="text" id="post-box" name="post">
<button id="btn-submit">Comment</button>
</form>
</div>
</html>
<script>
var post_item = document.getElementById("post-box");
var btn = document.getElementById("btn-submit");
addEventListener("keyup", function changeValue()
{
console.log(post_item.value);
document.getElementById("p-display").innerHTML = post_item.value;
});
</script>

How can i send query string with html submit button to another page?

I have this html code:
<input type="text" id="text1" placeholder="نام کاربری">
and this submit button:
<button type="submit" id="login-button" Onclick="window.location.href='Handler1.ashx?username='"+text1+"'" >ورود</button>
but up href not send html text box value with query string and send empty value,what happen?how can i solve that?thanks.
You need to call a function to set the url, rather than just reference the text box by id:
<script type="text/javascript">
function setUrl() {
window.location.href = 'Handler1.ashx?username=' + document.getElementById('text1').value;
};
</script>
<button type="submit" id="login-button" Onclick="setUrl(); return false;" >
Note: The return false is to prevent the button from submitting the form. A better solution would be to remove the ;return false; and change the button type from submit to button.

Prevent submitted form from opening in same popup

My code: <form method='post' target='_blank'... I have multiple of these forms on my page with the same action attribute.
Problem: Only one popup ever opens. If a second form is submitted, it replaces the first form's popup.
How do I get a new popup for each form? (Preferably without changing the action attribute.)
EDIT: I tried adding a random number (Math.floor(Math.random()*1000)) as a null parameter in the action url. This still opens in the same popup.
NOTE: There is no JS being used. However, I'd accept a JS answer.
Complete working code :-
<html>
<head>
<script>
function popup(form) {
var popup_id = 'popup_'+form.id
window.open(form.action, popup_id, 'width=400,height=400,resizeable,scrollbars');
form.target = popup_id;
}
</script>
</head>
<body>
<form id="form1" action="page.php" onsubmit="popup(this); return false;">
<input type="submit" value="save" />
</form>
<form id="form2" action="page.php" onsubmit="popup(this);return false;">
<input type="submit" value="save" />
</form>
</body>
</html>

Multiple submit buttons in an HTML form

Let's say you create a wizard in an HTML form. One button goes back, and one goes forward. Since the back button appears first in the markup when you press Enter, it will use that button to submit the form.
Example:
<form>
<!-- Put your cursor in this field and press Enter -->
<input type="text" name="field1" />
<!-- This is the button that will submit -->
<input type="submit" name="prev" value="Previous Page" />
<!-- But this is the button that I WANT to submit -->
<input type="submit" name="next" value="Next Page" />
</form>
I would like to get to decide which button is used to submit the form when a user presses Enter. That way, when you press Enter the wizard will move to the next page, not the previous. Do you have to use tabindex to do this?
I'm just doing the trick of floating the buttons to the right.
This way the Prev button is left of the Next button, but the Next comes first in the HTML structure:
.f {
float: right;
}
.clr {
clear: both;
}
<form action="action" method="get">
<input type="text" name="abc">
<div id="buttons">
<input type="submit" class="f" name="next" value="Next">
<input type="submit" class="f" name="prev" value="Prev">
<div class="clr"></div><!-- This div prevents later elements from floating with the buttons. Keeps them 'inside' div#buttons -->
</div>
</form>
Benefits over other suggestions: no JavaScript code, accessible, and both buttons remain type="submit".
Change the previous button type into a button like this:
<input type="button" name="prev" value="Previous Page" />
Now the Next button would be the default, plus you could also add the default attribute to it so that your browser will highlight it like so:
<input type="submit" name="next" value="Next Page" default />
Give your submit buttons the same name like this:
<input type="submit" name="submitButton" value="Previous Page" />
<input type="submit" name="submitButton" value="Next Page" />
When the user presses Enter and the request goes to the server, you can check the value for submitButton on your server-side code which contains a collection of form name/value pairs. For example, in ASP Classic:
If Request.Form("submitButton") = "Previous Page" Then
' Code for the previous page
ElseIf Request.Form("submitButton") = "Next Page" Then
' Code for the next page
End If
Reference: Using multiple submit buttons on a single form
If the fact that the first button is used by default is consistent across browsers, put them the right way around in the source code, and then use CSS to switch their apparent positions.
float them left and right to switch them around visually, for example.
Sometimes the provided solution by palotasb is not sufficient. There are use cases where for example a "Filter" submits button is placed above buttons like "Next and Previous". I found a workaround for this: copy the submit button which needs to act as the default submit button in a hidden div and place it inside the form above any other submit button.
Technically it will be submitted by a different button when pressing Enter than when clicking on the visible Next button. But since the name and value are the same, there's no difference in the result.
<html>
<head>
<style>
div.defaultsubmitbutton {
display: none;
}
</style>
</head>
<body>
<form action="action" method="get">
<div class="defaultsubmitbutton">
<input type="submit" name="next" value="Next">
</div>
<p><input type="text" name="filter"><input type="submit" value="Filter"></p>
<p>Filtered results</p>
<input type="radio" name="choice" value="1">Filtered result 1
<input type="radio" name="choice" value="2">Filtered result 2
<input type="radio" name="choice" value="3">Filtered result 3
<div>
<input type="submit" name="prev" value="Prev">
<input type="submit" name="next" value="Next">
</div>
</form>
</body>
</html>
This cannot be done with pure HTML. You must rely on JavaScript for this trick.
However, if you place two forms on the HTML page you can do this.
Form1 would have the previous button.
Form2 would have any user inputs + the next button.
When the user presses Enter in Form2, the Next submit button would fire.
I would use JavaScript to submit the form. The function would be triggered by the OnKeyPress event of the form element and would detect whether the Enter key was selected. If this is the case, it will submit the form.
Here are two pages that give techniques on how to do this: 1, 2. Based on these, here is an example of usage (based on here):
<SCRIPT TYPE="text/javascript">//<!--
function submitenter(myfield,e) {
var keycode;
if (window.event) {
keycode = window.event.keyCode;
} else if (e) {
keycode = e.which;
} else {
return true;
}
if (keycode == 13) {
myfield.form.submit();
return false;
} else {
return true;
}
}
//--></SCRIPT>
<INPUT NAME="MyText" TYPE="Text" onKeyPress="return submitenter(this,event)" />
If you really just want it to work like an install dialog, just give focus to the "Next" button OnLoad.
That way if the user hits Return, the form submits and goes forward. If they want to go back they can hit Tab or click on the button.
You can do it with CSS.
Put the buttons in the markup with the Next button first, then the Prev button afterwards.
Then use CSS to position them to appear the way you want.
This works without JavaScript or CSS in most browsers:
<form>
<p><input type="text" name="field1" /></p>
<p><a href="previous.html">
<button type="button">Previous Page</button></a>
<button type="submit">Next Page</button></p>
</form>
Firefox, Opera, Safari, and Google Chrome all work. As always, Internet Explorer is the problem.
This version works when JavaScript is turned on:
<form>
<p><input type="text" name="field1" /></p>
<p><a href="previous.html">
<button type="button" onclick="window.location='previous.html'">Previous Page</button></a>
<button type="submit">Next Page</button></p>
</form>
So the flaw in this solution is:
Previous Page does not work if you use Internet Explorer with JavaScript off.
Mind you, the back button still works!
If you have multiple active buttons on one page then you can do something like this:
Mark the first button you want to trigger on the Enter keypress as the default button on the form. For the second button, associate it to the Backspace button on the keyboard. The Backspace eventcode is 8.
$(document).on("keydown", function(event) {
if (event.which.toString() == "8") {
var findActiveElementsClosestForm = $(document.activeElement).closest("form");
if (findActiveElementsClosestForm && findActiveElementsClosestForm.length) {
$("form#" + findActiveElementsClosestForm[0].id + " .secondary_button").trigger("click");
}
}
});
<script src="https://ajax.aspnetcdn.com/ajax/jQuery/jquery-3.2.1.min.js"></script>
<form action="action" method="get" defaultbutton="TriggerOnEnter">
<input type="submit" id="PreviousButton" name="prev" value="Prev" class="secondary_button" />
<input type="submit" id='TriggerOnEnter' name="next" value="Next" class="primary_button" />
</form>
Changing the tab order should be all it takes to accomplish this. Keep it simple.
Another simple option would be to put the back button after the submit button in the HTML code but float it to the left so it appears on the page before the submit button.
Another simple option would be to put the back button after the submit button in the HTML code, but float it to the left, so it appears on the page before the submit button.
Changing the tab order should be all it takes to accomplish this. Keep it simple.
The first time I came up against this, I came up with an onclick()/JavaScript hack when choices are not prev/next that I still like for its simplicity. It goes like this:
#model myApp.Models.myModel
<script type="text/javascript">
function doOperation(op) {
document.getElementById("OperationId").innerText = op;
// you could also use Ajax to reference the element.
}
</script>
<form>
<input type="text" id = "TextFieldId" name="TextField" value="" />
<input type="hidden" id="OperationId" name="Operation" value="" />
<input type="submit" name="write" value="Write" onclick='doOperation("Write")'/>
<input type="submit" name="read" value="Read" onclick='doOperation("Read")'/>
</form>
When either submit button is clicked, it stores the desired operation in a hidden field (which is a string field included in the model the form is associated with) and submits the form to the Controller, which does all the deciding. In the Controller, you simply write:
// Do operation according to which submit button was clicked
// based on the contents of the hidden Operation field.
if (myModel.Operation == "Read")
{
// Do read logic
}
else if (myModel.Operation == "Write")
{
// Do write logic
}
else
{
// Do error logic
}
You can also tighten this up slightly using numeric operation codes to avoid the string parsing, but unless you play with enumerations, the code is less readable, modifiable, and self-documenting and the parsing is trivial, anyway.
From https://html.spec.whatwg.org/multipage/forms.html#implicit-submission
A form element's default button is the first submit button in tree
order whose form owner is that form element.
If the user agent supports letting the user submit a form implicitly
(for example, on some platforms hitting the "enter" key while a text
field is focused implicitly submits the form)...
Having the next input be type="submit" and changing the previous input to type="button" should give the desired default behavior.
<form>
<input type="text" name="field1" /> <!-- put your cursor in this field and press Enter -->
<input type="button" name="prev" value="Previous Page" /> <!-- This is the button that will submit -->
<input type="submit" name="next" value="Next Page" /> <!-- But this is the button that I WANT to submit -->
</form>
This is what I have tried out:
You need to make sure you give your buttons different names
Write an if statement that will do the required action if either button is clicked.
<form>
<input type="text" name="field1" /> <!-- Put your cursor in this field and press Enter -->
<input type="submit" name="prev" value="Previous Page" /> <!-- This is the button that will submit -->
<input type="submit" name="next" value="Next Page" /> <!-- But this is the button that I WANT to submit -->
</form>
In PHP,
if(isset($_POST['prev']))
{
header("Location: previous.html");
die();
}
if(isset($_POST['next']))
{
header("Location: next.html");
die();
}
I came across this question when trying to find an answer to basically the same thing, only with ASP.NET controls, when I figured out that the ASP button has a property called UseSubmitBehavior that allows you to set which one does the submitting.
<asp:Button runat="server" ID="SumbitButton" UseSubmitBehavior="False" Text="Submit" />
Just in case someone is looking for the ASP.NET button way to do it.
<input type="submit" name="prev" value="Previous Page">
<input type="submit" name="prev" value="Next Page">
Keep the name of all submit buttons the same: "prev".
The only difference is the value attribute with unique values. When we create the script, these unique values will help us to figure out which of the submit buttons was pressed.
And write the following coding:
btnID = ""
if Request.Form("prev") = "Previous Page" then
btnID = "1"
else if Request.Form("prev") = "Next Page" then
btnID = "2"
end if
With JavaScript (here jQuery), you can disable the prev button before submitting the form.
$('form').on('keypress', function(event) {
if (event.which == 13) {
$('input[name="prev"]').prop('type', 'button');
}
});
I solved a very similar problem in this way:
If JavaScript is enabled (in most cases nowadays) then all the submit buttons are "degraded" to buttons at page load via JavaScript (jQuery). Click events on the "degraded" button typed buttons are also handled via JavaScript.
If JavaScript is not enabled then the form is served to the browser with multiple submit buttons. In this case hitting Enter on a textfield within the form will submit the form with the first button instead of the intended default, but at least the form is still usable: you can submit with both the prev and next buttons.
Working example:
<html>
<head>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.4/jquery.min.js"></script>
</head>
<body>
<form action="http://httpbin.org/post" method="post">
If JavaScript is disabled, then you CAN submit the form
with button1, button2 or button3.
If you press enter on a text field, then the form is
submitted with the first submit button.
If JavaScript is enabled, then the submit typed buttons
without the 'defaultSubmitButton' style are converted
to button typed buttons.
If you press Enter on a text field, then the form is
submitted with the only submit button
(the one with class defaultSubmitButton)
If you click on any other button in the form, then the
form is submitted with that button's value.
<br />
<input type="text" name="text1" ></input>
<button type="submit" name="action" value="button1" >button 1</button>
<br />
<input type="text" name="text2" ></input>
<button type="submit" name="action" value="button2" >button 2</button>
<br />
<input type="text" name="text3" ></input>
<button class="defaultSubmitButton" type="submit" name="action" value="button3" >default button</button>
</form>
<script>
$(document).ready(function(){
/* Change submit typed buttons without the 'defaultSubmitButton'
style to button typed buttons */
$('form button[type=submit]').not('.defaultSubmitButton').each(function(){
$(this).attr('type', 'button');
});
/* Clicking on button typed buttons results in:
1. Setting the form's submit button's value to
the clicked button's value,
2. Clicking on the form's submit button */
$('form button[type=button]').click(function( event ){
var form = event.target.closest('form');
var submit = $("button[type='submit']",form).first();
submit.val(event.target.value);
submit.click();
});
});
</script>
</body>
</html>
You can use Tabindex to solve this issue. Also changing the order of the buttons would be a more efficient way to achieve this.
Change the order of the buttons and add float values to assign them the desired position you want to show in your HTML view.
A maybe somewhat more modern approach over the CSS float method could be a solution using flexbox with the order property on the flex items. It could be something along those lines:
<div style="display: flex">
<input type="submit" name="next" value="Next Page" style="order: 1" />
<input type="submit" name="prev" value="Previous Page" style="order: 0" />
</div>
Of course it depends on your document structure whether this is a feasible approach or not, but I find flex items much easier to control than floating elements.
Instead of struggling with multiple submits, JavaScript or anything like that to do some previous/next stuff, an alternative would be to use a carousel to simulate the different pages.
Doing this :
You don't need multiple buttons, inputs or submits to do the previous/next thing, you have only one input type="submit" in only one form.
The values in the whole form are there until the form is submitted.
The user can go to any previous page and any next page flawlessly to modify the values.
Example using Bootstrap 5.0.0 :
<div id="carousel" class="carousel slide" data-ride="carousel">
<form action="index.php" method="post" class="carousel-inner">
<div class="carousel-item active">
<input type="text" name="lastname" placeholder="Lastname"/>
</div>
<div class="carousel-item">
<input type="text" name="firstname" placeholder="Firstname"/>
</div>
<div class="carousel-item">
<input type="submit" name="submit" value="Submit"/>
</div>
</form>
<a class="btn-secondary" href="#carousel" role="button" data-slide="prev">Previous page</a>
<a class="btn-primary" href="#carousel" role="button" data-slide="next">Next page</a>
</div>
I think this is an easy solution for this. Change the Previous button type to button, and add a new onclick attribute to the button with value jQuery(this).attr('type','submit');.
So, when the user clicks on the Previous button then its type will be changed to submit and the form will be submitted with the Previous button.
<form>
<!-- Put your cursor in this field and press Enter -->
<input type="text" name="field1" />
<!-- This is the button that will submit -->
<input type="button" onclick="jQuery(this).attr('type','submit');" name="prev" value="Previous Page" />
<!-- But this is the button that I WANT to submit -->
<input type="submit" name="next" value="Next Page" />
</form>
Problem
A form may have several submit buttons.
When pressing return in any input, the first submit button is used by the browser.
However, sometimes we want to use a different/later button as default.
Options
Add a hidden submit button with the same action first (☹️ duplication)
Put the desired submit button first in the form and then move it to the correct place via CSS (☹️ may not be feasible, may result in cumbersome styling)
Change the handling of the return key in all form inputs via JavaScript (☹️ needs javascript)
None of the options is ideal, so we choose 3. because most browsers have JavaScript enabled.
Chosen solution
// example implementation
document.addEventListener('DOMContentLoaded', (ev) => {
for (const defaultSubmitInput of document.querySelectorAll('[data-default-submit]')) {
for (const formInput of defaultSubmitInput.form.querySelectorAll('input')) {
if (formInput.dataset.ignoreDefaultSubmit != undefined) { continue; }
formInput.addEventListener('keypress', (ev) => {
if (ev.keyCode == 13) {
ev.preventDefault();
defaultSubmitInput.click();
}
})
}
}
});
<!-- example markup -->
<form action="https://postman-echo.com/get" method="get">
<input type="text" name="field1">
<input type="submit" name="submit" value="other action">
<input type="submit" name="submit" value="default action" data-default-submit> <!-- this button will be used on return -->
</form>
It may be useful to be able to remove the enhancement from some inputs. This can be achieved by:
<input type="text" name="field2" data-ignore-default-submit> <!-- uses browser standard behaviour -->
Here a complete code pen.
When a button is clicked with a mouse (and hopefully by touch), it records the X,Y coordinates. This is not the case when it is invoked by a form, and these values are normally zero.
So you can do something like this:
function(e) {
const isArtificial = e.screenX === 0 && e.screenY === 0
&& e.x === 0 && e.y === 0
&& e.clientX === 0 && e.clientY === 0;
if (isArtificial) {
return; // DO NOTHING
} else {
// OPTIONAL: Don't submit the form when clicked
// e.preventDefault();
// e.stopPropagation();
}
// ...Natural code goes here
}
Using the example you gave:
<form>
<input type="text" name="field1" /><!-- Put your cursor in this field and press Enter -->
<input type="submit" name="prev" value="Previous Page" /> <!-- This is the button that will submit -->
<input type="submit" name="next" value="Next Page" /> <!-- But this is the button that I WANT to submit -->
</form>
If you click on "Previous Page", only the value of "prev" will be submitted. If you click on "Next Page" only the value of "next" will be submitted.
If however, you press Enter somewhere on the form, neither "prev" nor "next" will be submitted.
So using pseudocode you could do the following:
If "prev" submitted then
Previous Page was click
Else If "next" submitted then
Next Page was click
Else
No button was click