Take element from a string in VB6 - json

Question

I have a string in this format similar to the json. Generated by the following code:
str = "{"
str &= Chr(34) & "code" & Chr(34) + ":" & Chr(34) & "0000001" & Chr(34)
str &= Chr(34) & "name" & Chr(34) + ":" & Chr(34) & "product 1" & Chr(34)
str &= Chr(34) & "value" & Chr(34) + ":" & Chr(34) & "150.00" & Chr(34)
str &= "}"
I just need to get the value after the code, name and value.
I cannot find an effective method to do this, as I will have to generalize to more terms later. How can I do this without transforming to JSON?

Answer 1

The code snippet you provide produces this string:
{"code":"0000001""name":"product 1""value":"150.00"}
Assuming you really are using VB6 to process this string, the following code breaks out the values:
Private Sub Test(ByVal str As String)
Dim groups As Variant
Dim values As Variant
Dim i As Integer
str = Replace(str, "{", "")
str = Replace(str, "}", "")
str = Replace(str, """""", ",")
str = Replace(str, """", "")
groups = Split(str, ",")
For i = LBound(groups) To UBound(groups)
values = Split(groups(i), ":")
Debug.Print values(1)
Next
End Sub

Answer 2

Something like this should help (untested):
colon% = 0
Dim completed as Boolean
while completed = false
colon% = InStr(colon% + 1, str, ":")
If colon% > 0 Then
value$ = Mid$(str, colon + 1, InStr(colon% + 2, str, Chr(34)) - colon%)
' ... do whatever with value$ here...
Else
completed = true
End If
Wend