Sql Query Json Array items by Value - json

Question

I have searched and can't seem to find somewhere doing exactly what I am trying.
I have a json similar to as follows in multiple rows in my database:
{
"date": "0001-01-01T00:00:00",
"details": {
"detail": [
{
"item": "11",
"value": "xt"
},
{
"item": "12",
"value": "xy"
},
{
"item": "13",
"value": "xz"
},
{
"item": "14",
"value": "zz"
}
]
}
}
I want to do sql that does this:
select ID
jsonColumn.value where item=11 as X
jsonColumn.value where item=12 as Y
from tbl
So I have results like this
----------------------
|ID |X |Y |
----------------------
|1 |xt |xy |
----------------------
I have tried using JSONVALUE but I seem to need to do it by the array item number like this:
'$.details.detail[3].value'
which doesn't really work
I have also tried this:
SELECT id, x.item, x.value
FROM
tbl F
CROSS APPLY (select *
FROM OPENJSON(F.Json,'$.details.detail')
CROSS APPLY OPENJSON(value)
WITH (item NVARCHAR(25) '$.item',
value NVARCHAR(max) '$.value') As x
where F.ID=55
Which I can use to print out all the items and values but then I'd have to query each separately again.
Is there a way of combining the two in to one big query that won't be completely inefficient?

Answer 1

Seems what you want is a pivot. I personally use conditional aggregation over the far more restrictive PIVOT operator. The JSON you supplied was invalid, so I took some liberties correcting it in my sandbox environment:
SELECT --ID,
MAX(CASE d.item WHEN 11 THEN d.[value] END) AS X,
MAX(CASE d.item WHEN 12 THEN d.[value] END) AS Y
FROM (VALUES(#JSON))V(J) --Your Table
CROSS APPLY OPENJSON(V.J,'$.details')
WITH (detail nvarchar(MAX) AS JSON ) OJ
CROSS APPLY OPENJSON(OJ.detail)
WITH(item int,
[value] nvarchar(2)) d;
If you are using this against a table, and not limiting the data to a single row, you'll need to also add a GROUP BY clause on the relevant columns (ID?).