Scala manipulate json object - json

Question

I have a dynamic json object generated with a certain format and I would like to manipulate that object to map it to another format in scala.
The problem is that the names of the fields are dynamic so "field1" and "field2" can be anything.
Is there any way to do it dynamically in scala?
The original object:
{
"field1": {
"value" "some value 1",
"description": "some test description",
...
},
"field2": {
"value" "some value 2",
"description": "some test description",
...
}
}
And I'd like to convert it to something like:
{
"field1": "some value 1",
"field2": "some value 2"
}

Answer 1

You can collect all keys and then check if the downField("value") exists
import io.circe._
import io.circe.literal.JsonStringContext
object CirceFieldsToMap {
def main(args: Array[String]): Unit = {
val json: Json =
json"""{
"field1": {
"foo" : "bar1",
"value" : "foobar1"
},
"field2": {
"foo" : "bar2",
"value" : "foobar2"
},
"field3": {
"foo" : "bar2"
}
}"""
implicit val decodeFoo = new Decoder[Map[String, Option[String]]] {
final def apply(c: HCursor): Decoder.Result[Map[String, Option[String]]] = {
val result = c.keys.get //// You should handle the .get properly ( if None it breaks)
.toList
.foldLeft(List.empty[(String, Option[String])]) { case (acc, key) =>
acc :+ (key, c.downField(key).downField("value").as[String].toOption)
}
Right(result.toMap)
}
}
val myField01 = json.as[Map[String, Option[String]]]
println(myField01) //Right(Map(field1 -> Some(foobar1), field2 -> Some(foobar2), field3 -> None))
}
}