Mysql problem to see if two selects are the same - mysql

Question

SELECT table_grouping_code, gui_field_code, gui_interface_id, dictionary_code, property_name, position INTO #test
FROM table_grouping_layout
WHERE company_code = "TEST";
SELECT table_grouping_code, gui_field_code, gui_interface_id, dictionary_code, property_name, position INTO #doximtrx
FROM table_grouping_layout
WHERE company_code = "DOXIMTRX";
select #test = #doximtrx;
I tried this, that seems very logica to me, but mysql says: ERROR CODE 1222: the used select statement have a different number of columns. How can it be possible?? I copied the query, only changing the code.
Example of data in the table

Answer 1

You are trying to select many columns into a single variable. The correct syntax for that part of your query is:
SELECT
GROUP_CONCAT(table_grouping_code ORDER BY table_grouping_code)
, GROUP_CONCAT(gui_field_code ORDER BY gui_field_code)
, GROUP_CONCAT(gui_interface_id ORDER BY gui_interface_id)
, GROUP_CONCAT(dictionary_code ORDER BY dictionary_code)
, GROUP_CONCAT(property_name ORDER BY property_name)
, GROUP_CONCAT(position ORDER BY position)
FROM
table_grouping_layout
WHERE
company_code = 'TEST'
INTO
#t1, #t2, #t3, #t4, #t5, #t6;
SELECT
GROUP_CONCAT(table_grouping_code ORDER BY table_grouping_code)
, GROUP_CONCAT(gui_field_code ORDER BY gui_field_code)
, GROUP_CONCAT(gui_interface_id ORDER BY gui_interface_id)
, GROUP_CONCAT(dictionary_code ORDER BY dictionary_code)
, GROUP_CONCAT(property_name ORDER BY property_name)
, GROUP_CONCAT(position ORDER BY position)
FROM
table_grouping_layout
WHERE
company_code = 'DOXIMTRX'
INTO
#d1, #d2, #d3, #d4, #d5, #d6;
How to compare results is a different story:
SELECT ifNull(
#t1 = #d1
and #t2 = #d2
and #t3 = #d3
and #t4 = #d4
and #t5 = #d5
and #t6 = #d6
, false
) as result;
TEST DATA:
select * from table_grouping_layout;
table_grouping_code
gui_field_code
gui_interface_id
dictionary_code
property_name
position
company_code
1
2
3
4
5
6
DOXIMTRX
1
3
3
4
5
6
TEST
1
1
3
4
5
6
DOXIMTRX
1
2
3
4
5
6
TEST
QUERY RESULT:
result
0

Answer 2

Variables are meant to hold one value. Neither one row nor one column nor one table.
Comparing two data sets can be achieved with a combination of UNIONand EXCEPT or with a full outer join. Unfortunately, MySQL does neither support EXCEPT nor FULL OUTER JOIN.
Here is a workaround:
with t as (select * from table_grouping_layout where company_code = 'TEST')
, d as (select * from table_grouping_layout where company_code = 'DOXIMTRX')
select 'MISMATCH' as status, t.position
from table_grouping_layout t
join table_grouping_layout d
on t.position = d.position
and not
(
t.table_grouping_code <=> t.table_grouping_code and
t.gui_field_code <=> t.gui_field_code and
t.gui_interface_id <=> t.gui_interface_id and
t.dictionary_code <=> t.dictionary_code and
t.property_name <=> t.property_name
)
union all
select 'TEST MISSING' as status, position
from d
where position not in (select position from t)
union all
select 'DOXIMTRX MISSING' as status, position
from t
where position not in (select position from d)
order by position;
Another approach using aggregation:
select
position,
case
when sum(company_code = 'TEST') = 0 then 'TEST MISSING'
when sum(company_code = 'DOXIMTRX') = 0 then 'DOXIMTRX MISSING'
when not
(
max(table_grouping_code) <=> min(table_grouping_code) and count(table_grouping_code) in (0,2)
max(gui_field_code) <=> min(gui_field_code) and count(gui_field_code) in (0,2)
max(gui_interface_id) <=> min(gui_interface_id) and count(gui_interface_id) in (0,2)
max(dictionary_code) <=> min(dictionary_code) and count(dictionary_code) in (0,2)
max(property_name) <=> min(property_name) and count(property_name) in (0,2)
) then 'MISMATCH'
else 'MATCH' end as status
from table_grouping_layout
where company_code in ('TEST', 'DOXIMTRX')
group by position
order by position;