Get dates from weekdays between 2 dates MySQL future schedule - mysql

Im trying to create a schedule table per week of year with MySQL
I have a table with the following Sample data:
employee
start_date
end_date
weekday
shift_start
shift_end
1
2021-10-01
2021-10-31
0
08:00:00
17:00:00
1
2021-10-01
2021-10-31
2
08:00:00
17:00:00
1
2021-10-01
2021-10-31
4
08:00:00
17:00:00
2
2021-10-01
2021-10-31
0
08:00:00
17:00:00
2
2021-10-01
2021-10-31
3
08:00:00
17:00:00
2
2021-10-01
2021-10-31
4
08:00:00
17:00:00
The schedule is the same every week, hence the weekday column.
I also have a calendar table for simplicity with dates for coming 2 years with the following schema:
fulldate
year
month
day
week
dayofweek
0000-00-00
0000-9999
0-11
0-30
0-53
0-6
I want to have a table output like the following for a certain weeknumber: (example week 40 of 2021)
date
employee
weekday
shift_start
shift_end
2021-10-04
1
0
08:00:00
17:00:00
2021-10-04
2
0
08:00:00
17:00:00
2021-10-06
1
2
08:00:00
17:00:00
2021-10-07
2
3
08:00:00
17:00:00
2021-10-08
1
4
08:00:00
17:00:00
2021-10-08
2
4
08:00:00
17:00:00
I have been stuck on this for a while and I haven't found a solution on the internet or made a single step in creating the table. Any help in the right direction would be greatly appreciated

Solution for your problem is:
SELECT
c.fulldate as date,
t.employee,
t.weekday,
t.shift_start,
t.shift_end
FROM calendar AS c
INNER JOIN table1 AS t
ON c.dayofweek = t.weekday
ORDER BY c.fulldate,t.employee,t.weekday
Demo Link: http://sqlfiddle.com/#!9/4c8681/4
Explanation:
Calendar table should be inner joined with input table on weekday column to get those dates for which result is required.
'WHERE' clause can be used to filter out the result as per the requirement. For example, if output is required for 40th week then use "WHERE c.week=40" in above query before 'ORDER BY' clause to get desired result.

Related

Time difference without considering times between 0am ~ 4am. MySQL

MySQL version 8.0
I want to calculate time difference between two datetime column.
And get rows where duration >= 12:00:00.
which I would normally do:
select id
, start_time
, end_time
, timediff(end_time, start_time) as duration
from table;
which I would get something like this:
id start_time end_time duration
0 1 2020-06-01 01:00:00 2020-06-01 14:00:00 13:00:00
1 2 2020-06-01 01:00:00 2020-06-01 18:00:00 17:00:00
2 3 2020-06-01 19:00:00 2020-06-02 10:00:00 15:00:00
3 4 2020-06-02 04:00:00 2020-06-02 16:00:00 12:00:00
For duration column I don't want times between 00:00:00 ~ 04:00:00 to be added towards the duration. So for the first row duration = 10:00:00 since 01:00:00~14:00:00 = 10:00:00, ignoring times between 00:00:00 ~ 04:00:00
same for second row we substract 3 hours from duration.
so my desired output would be:
id start_time end_time duration
0 1 2020-06-01 01:00:00 2020-06-01 14:00:00 10:00:00
1 2 2020-06-01 01:00:00 2020-06-01 18:00:00 14:00:00
2 3 2020-06-01 19:00:00 2020-06-02 10:00:00 11:00:00
3 4 2020-06-02 04:00:00 2020-06-02 16:00:00 12:00:00
There are lots of rows where times include minutes and seconds too.
Thanks in advance!
I've grabbed all rows where duration >= 12:00:00.
Then separated data into 4 regions depending on their start_time.
a_region = 00~04
b_region = 04~12
c_region = 12~16
d_region = 16~24
For a_region I've subtracted 04:00:00 - start_time which is time we should compensate to duration in a_region.
compensation = 04:00:00 - start_time
compensated_time = duration - compensation.
For b_region it needs no compensation if it has passed 00~04 it means it already passed duration = 12:00:00.
For c_region,
compensation = 16:00:00 - start_time
compensated_time = duration - compensation
For d_region since we've grabbed duration >= 12:00:00
it will pass all of 00~04 therefore
compensated_time = duration - 04:00:00.
I solved it using Python but above is the logic I've used.
One option uses greatest():
select id
, start_time
, end_time
, timediff(
greatest(,
end_time,
date_format(end_time, '%Y-%m-%d 04:00:00')
),
greatest(
start_time,
date_format(start_time, '%Y-%m-%d 04:00:00')
)
) as duration
from table;

How to get particular column data from mysql table?

I have table like this,
tid vid emp_id stop_time dates
----------------------------------------
1 5680 6 01:00 am 2017-05-19
2 5680 6 04:00 am 2017-05-19
3 5680 3 07:00 am 2017-05-19
4 5680 3 05:00 pm 2017-05-19
5 5680 6 08:00 am 2017-05-20
I want the particular value, for above this e.g i need this values 04:00 am and 05:00 pm and 08:00 am. That means i need last enter value of emp_id also particular dates based.
Demo data:
http://sqlfiddle.com/#!9/3f6e59/1
use subquery
select * from third_table
where tid in (select max(tid) from third_table
where dates between '2017-05-19' and '2017-05-20' group by emp_id,dates)

How to find sales per hour between two date

Suppose I have 5 records for a sales table.
ID Name datetime_col
1 ABC 2016-09-15 02:07:56
2 HSJ 2016-09-31 11:45:45
3 JSD 2016-11-26 07:09:56
4 JUH 2016-12-31 12:00:00
5 IGY 2017-01-13 14:00:07
I want to find how many records are there in sales table for each hour between 2016-09-15 AND 2017-01-13
Then result should be like
Hour sales_at_this_hour
2016-09-15 01:00:00 0
2016-09-15 02:00:00 1
2016-09-15 03:00:00 0
...
...
2017-01-13 01:00:00 0
2017-01-13 02:00:00 0
2017-01-13 03:00:00 0
....
2017-01-13 14:00:00 1
Then find the average of sales_at_this_hour using MySQL
EDIT: sorry not fully understand the question at first.
Use DATE_FORMAT
select
DATE_FORMAT(datetime_col, '%Y-%m-%d %h:00:00') as date,
count(id) as count
from table_name
group by date;
Get result with hours that has sales_at_this_hour > 1 (not exactly what you ask for)
datetime_col count
2016-02-04 05:00:00 5
2016-02-04 07:00:00 1
2016-02-04 08:00:00 5
2016-02-04 10:00:00 10
2016-02-04 11:00:00 1
Provide start_date and end_date, and then use DATEDIFF to calculate total time interval for the average calculation.
set #start_date = '2016-01-01', #end_date = '2017-01-01';
select
DATE_FORMAT(group_by_date.datetime, '%h:00:00') as hour,
AVG(group_by_date.count) / DATEDIFF(#end_date, #start_date) as average
from (
select
DATE_FORMAT(created_dtm, '%Y-%m-%d %h:00:00') as datetime,
count(id) as count
from table_name
where created_dtm > #start_date
and created_dtm < #end_date
group by datetime
) group_by_date
group by hour;
For each hour,
average sale count per day = total sale count / total days
hour average
01:00:00 0.03841209
02:00:00 0.01653005
03:00:00 0.0306716
04:00:00 0.01147541
05:00:00 0.01179831

SQL return last 12 weeks data, grouped by week, starting last Monday

I've been working on a MySQL query that sorts data into weeks but I just can't figure out how to do it.
I would like to sort the data into weeks for the current and last 11 weeks. Each week will run from Monday 00:00:00 to Sunday 23:59:59.
(Taking todays date as 2014-12-04)...
Week 1: 2014-12-01 > 2014-12-07 - (Last Monday 00:00:00 to next Sunday 23:59:59)
Week 2: 2014-11-24 > 2014-11-30 - (Monday before last 00:00:00 to last Sunday 23:59:59)
Week 3: 2014-11-17 > 2014-11-23 - (Monday before before last 00:00:00 to last last Sunday 23:59:59)
And so on...
For each week the value field data will be totalled.
I need the data returned to be in the format:
datetime: The first date (Always a Monday) of that week.
value: The total of all the values in that week.
For example, the returned data:
Week 1: 2014-12-01 : Totalled value=11
Week 2: 2014-11-24 : Totalled value=3
Week 3: 2014-11-17 : Totalled value=9
Week 4: 2014-11-10 : Totalled value=7
Table_1 data:
table1id datetime value
1 2014-09-01 06:00:00 4
2 2014-09-04 17:00:00 6
3 2014-09-09 18:00:00 9
4 2014-09-15 07:00:00 4
5 2014-09-20 10:00:00 2
6 2014-09-25 10:00:00 3
7 2014-09-30 09:00:00 8
8 2014-10-01 14:00:00 5
9 2014-10-05 10:00:00 7
10 2014-10-09 18:00:00 3
11 2014-10-15 05:00:00 4
12 2014-10-20 07:00:00 8
13 2014-10-24 16:00:00 9
14 2014-10-29 15:00:00 5
15 2014-10-31 16:00:00 7
16 2014-11-05 09:00:00 2
17 2014-11-10 08:00:00 4
18 2014-11-15 16:00:00 3
19 2014-11-20 10:00:00 9
20 2014-11-25 10:00:00 2
21 2014-11-30 10:00:00 1
22 2014-12-01 15:00:00 7
23 2014-12-04 18:00:00 2
I 'could' just pull all the data unsorted for the date range using PHP and sort it from there but I'd rather the MySQL server do it.
Any suggestions would be greatly appreciated. :-)
based on generate days from date range
you can do smething like that:
select mondays.week, mondays.day, sum(value)
from
(select a.a+1 week, curdate() - WEEKDAY(curdate()) - INTERVAL (7*a.a) DAY as day from (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9 union all select 10 union all select 11) as a) as mondays,
Table_1
where Table_1.datetime between mondays.day and (mondays.day + interval(7) day)
group by mondays.week, mondays.day;

time query for vb6 and msaccess

Query for VB6 and MS Access
Table:-
User Id LogDate LogTime
1 1/1/2010 9:00
1 1/1/2010 10:00
1 1/1/2010 11:29
1 2/1/2010 10:00
2 2/1/2010 22:00
2 3/1/2010 11:00
Need to display as:-
User Id LogDate LogTime LogDate LogTime
1 1/1/2010 9:00 1/1/2010 10:00
1 1/1/2010 11:29 2/1/2010 10:00
2 2/1/2010 22:00 3/1/2010 11:00
You need to use a sub-query to find the next date for a user, something like:
SELECT tblStackOverflowTimeQuery.lngUserId, tblStackOverflowTimeQuery.datLogDateTime,
(SELECT TOP 1 tblStackOverflowTimeQuery2.datLogDateTime
FROM tblStackOverflowTimeQuery AS tblStackOverflowTimeQuery2
WHERE tblStackOverflowTimeQuery.lngUserId = tblStackOverflowTimeQuery2.lngUserId
AND tblStackOverflowTimeQuery2.datLogDateTime > tblStackOverflowTimeQuery.datLogDateTime
ORDER BY tblStackOverflowTimeQuery2.datLogDateTime
) AS datEndDateTime
FROM tblStackOverflowTimeQuery
ORDER BY tblStackOverflowTimeQuery.lngUserId, tblStackOverflowTimeQuery.datLogDateTime;
That'll give the following:
lngUserId datLogDateTime datEndDateTime
1 01/01/2010 09:00:00 01/01/2010 10:00:00
1 01/01/2010 10:00:00 01/01/2010 11:29:00
1 01/01/2010 11:29:00 02/01/2010 10:00:00
1 02/01/2010 10:00:00
2 02/01/2010 22:00:00 03/01/2010 11:00:00
2 03/01/2010 11:00:00
which is not exactly what you wanted, but it's a start.
It would be easiest to do these things using code, but that would depend on how you want to use it. Presumably there's nothing in your data to indicate which entry is the start and which is the end.