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here is my query
SELECT distinct(DESIG_NAME)
FROM employees
WHERE GRADE like ("L0007", "L0008", "L0009");
I want to find grade of employee in one single statement
grade are level e.g., level7, level8, etc something like this
DISTINCT is not a function, and also you want WHERE IN (...):
SELECT DISTINCT DESIG_NAME
FROM employees
WHERE GRADE IN ('L0007', 'L0008', 'L0009');
SELECT distinct(DESIG_NAME) FROM employees where GRADE like 'L0007' or like 'L0008' or like 'L0009'
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As the title suggests, trying to take the count or possibly distinct count of a column, we call it year, to count the number of a years for an individual or populated ID and place it another column in the same table. Here is an idea of what I have so far and we want to update the table. Thank you.
Join group table to updated table directly:
UPDATE outputtable O JOIN
(SELECT personID, COUNT(DISTINCT year) AS countYear
FROM outputtable GROUP BY personID) temp ON O.personID=temp.personID
SET O.N=temp.countYear
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Here is the MySQL code
select id, name, code, batch_id from subjects where batch_id=18;
In this query i want name to be subject name during the execution. So this is the whole problem.
Do you want a column alias in the resultset?
select id, name as subject_name, code, batch_id
from subjects
where batch_id = 18
This changes the name of column name to subject_name in the result of the query.
I don't see what your question has to do with the where clause.
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Write Mysql query with average age counting
Try the following
select
ReportsTo,
count(*) as Members,
avg(age) as Average_Age
from yourTable
where ReportsTo is not null
group by
ReportsTo
This is actually quite easy. This may work for you!
SELECT ReportsTo, COUNT(Members) as Members, AVG(Age) as average
FROM table
GROUP BY ReportsTo
ORDER BY ReportsTo
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SELECT location,special,price FROM `tickets`
WHERE event = 'food' GROUP BY location
I think you want, (assuming its mysql) the following:
SELECT location, ANY_VALUE(special) special, ANY_VALUE(price) price
FROM tickets
WHERE event='food'
GROUP BY location ;
ANY_VALUE is strange aggregate function out of normal db standards that returns one of the values arbitarily.
If you wish to not have duplicate results in your rows you can choose only distinct result set.
SELECT DISTINCT location,special,price FROM tickets WHERE event = 'food' GROUP BY location
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I am having a database with 2 columns employee and job.Job column contains character in each record.In that,I have to list the employees whose job is having last 3 characters as 'man'.I have to use only functions in SQL Query.
Use LIKE with wildcard:
SELECT *
FROM your_table
WHERE job_column_name LIKE '%man'
or using RIGHT
SELECT *
FROM your_table
WHERE RIGHT(job_column_name, 3) = 'man'
Answer For Question 4 is
SELECT *
FROM emp
WHERE SUBSTR(job,-3,3)='MAN';