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ERROR 1111 (HY000): Invalid use of group function
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Closed 1 year ago.
I'm not yet good at MySQL. Please check my sql below and help me understand where I went wrong with it. All I need is just one record for the order.id and the returned record must be the one whose shipped date is the latest.
Database error: Invalid SQL: SELECT orders.id, orders.customer_fk FROM orders INNER JOIN order_details ON order_details.order_fk=orders.id WHERE orders.payment_method IN ('AS','AC') AND ((orders.order_status='SHP' AND order_details.item_status='SHP' AND MAX(order_details.shipped_date) <= '2021-08-07') OR (orders.order_status='CAN' AND orders.order_date <= '2021-08-07 09:56:18')) AND orders.pii_status <> '1'GROUP BY orders.id
MySQL Error: 1111 (Invalid use of group function)
Instead of using MAX alone try to use a subselect
If you don't want the mad for every order.id then you need to add a inner join
SELECT
orders.id, orders.customer_fk
FROM
orders
INNER JOIN
order_details ON order_details.order_fk = orders.id
WHERE
orders.payment_method IN ('AS' , 'AC')
AND ((orders.order_status = 'SHP'
AND order_details.item_status = 'SHP'
AND (SELECT MAX(shipped_date) FROM order_details WHERE order_fk = orders.id) <= '2021-08-07')
OR (orders.order_status = 'CAN'
AND orders.order_date <= '2021-08-07 09:56:18'))
AND orders.pii_status <> '1'
GROUP BY orders.id
To explain it somewhat further
SELECT MAX(shipped_date) FROM order_details WHERE order_fk = orders.id) <= '2021-08-07'
Return true or false for every Order.id as it checks for every row in the outer select what the maximum date is and then checks it against the date.
After selecting all rows you GROUP BY(which i still don't get as you have no aggregation function it) comes for every order.id.
Maybe you should try a DISTINCT
You select both orders.id and orders.customer_fk, but you group by orders.id only. When using group by in SQL, all other columns not present in the group by clause must be aggregate functions, since for example in this current case you group the results by the order id, meaning there can be only one row per unique order id among the results.
And something has to happen with the list of values of the other column that all belong to this one grouped order id, this is where the aggregations come in. If it is a number you can calculate the MIN/MAX/AVG etc. of these, but the simplest aggregate is to just count the matching results.
So if you wanted your query to return the number of order.customer_fk for each unique order.id, just add SELECT orders.id, COUNT(orders.customer_fk).
Otherwise, if you didn't intend to group your results, you can remove the GROUP BY clause, or replace it with an ORDER BY.
If you want to filter using aggregation functions use having. However, I'm guessing that you just want to filter by the date:
SELECT o.id, o.customer_fk
FROM orders o INNER JOIN
order_details od
ON od.order_fk= o.id
WHERE o.payment_method IN ('AS','AC') AND
((o.order_status = 'SHP' AND od.item_status='SHP' AND od.shipped_date <= '2021-08-07') OR
(o.order_status = 'CAN' AND o.order_date <= '2021-08-07 09:56:18')
) AND
o.pii_status <> '1'
GROUP BY o.id
Related
http://sqlfiddle.com/#!9/e6effb/1
I'm trying to get a top 10 by revenue per brand for France on december.
There are 2 tables (first table has date, second table has brand and I'm trying to join them)
I get this error "FUNCTION db_9_d870e5.SUM does not exist. Check the 'Function Name Parsing and Resolution' section in the Reference Manual"
Is my use of Inner join there correct?
It's because you had an extra space after SUM. Please change it from
SUM (o1.total_net_revenue)to SUM(o1.total_net_revenue).
See more about it here.
Also after correcting it, your query still had more error as you were not selecting order_id on your intermediate table i2 so edited here as :
SELECT o1.order_id, o1.country, i2.brand,
SUM(o1.total_net_revenue)
FROM orders o1
INNER JOIN (
SELECT i1.brand, SUM(i1.net_revenue) AS total_net_revenue,order_id
FROM ordered_items i1
WHERE i1.country = 'France'
GROUP BY i1.brand
) i2
ON o1.order_id = i2.order_id AND o1.total_net_revenue = i2.total_net_revenue
AND o1.total_net_revenue = i2.total_net_revenue
WHERE o1.country = 'France' AND o1.created_at BETWEEN '2016-12-01' AND '2016-12-31'
GROUP BY 1,2,3
ORDER BY 4
LIMIT 10`
--EDIT stack Fan is correct that the o2.total_net_revenue exists. My confusion was because the data structure duplicated three columns between the tables, including one that was being looked for.
There were a couple errors with your SQL statement:
1. You were referencing an invalid column in your outer-select-SUM function. I believe you're actually after i2.total_net_revenue.
The table structure is terrible, the "important" columns (country, revenue, order_id) are duplicated between the two tables. I would also expect the revenue columns to share the same name, if they always have the same values in them. In the example, there's no difference between i1.net_revenue and o1.total_net_revenue.
In your inner join, you didn't reference i1.order_id, which meant that your "on" clause couldn't execute correctly.
PROTIP:
When you run into an issue like this, take all the complicated bits out of your query and get the base query working correctly first. THEN add your functions.
PROTIP:
In your GROUP BY clause, reference the actual columns, NOT the column numbers. It makes your query more robust.
This is the query I ended up with:
SELECT o1.order_id, o1.country, i2.brand,
SUM(i2.total_net_revenue) AS total_rev
FROM orders o1
INNER JOIN (
SELECT i1.order_id, i1.brand, SUM(i1.net_revenue) AS total_net_revenue
FROM ordered_items i1
WHERE i1.country = 'France'
GROUP BY i1.brand
) i2
ON o1.order_id = i2.order_id AND o1.total_net_revenue = i2.total_net_revenue
AND o1.total_net_revenue = i2.total_net_revenue
WHERE o1.country = 'France' AND o1.created_at BETWEEN '2016-12-01' AND '2016-12-31'
GROUP BY o1.order_id, o1.country, i2.brand
ORDER BY total_rev
LIMIT 10
I have a table where I am storing the stored number of barrels inside of many tanks. I am storing values here every night at midnight, and at the beggining and end of any operator initiated transfer.
What I want to return is the number of barrels difference since the previous event record for that specific tank. I have the correct ID for the self join to get the previous record number, however the barrels is incorrect.
Here is what I currently have.
SELECT
inventory.id,
MAX(inventory2.id) AS id2,
inventory.tankname,
inventory.barrels,
inventory.eventstamp,
inventory2.barrels
FROM
inventory
LEFT JOIN
inventory inventory2 ON inventory2.tankname = inventory.tankname AND inventory2.eventstamp < inventory.eventstamp
GROUP BY
inventory.id,
inventory.tankname,
inventory.barrels,
inventory.eventstamp
ORDER BY
inventory.tankname,
inventory.eventstamp
That returns the following
Just use correlated subqueries:
SELECT i.*,
(SELECT i2.id
FROM inventory i2
WHERE i2.tankname = i.tankname AND
i2.eventstamp < i.eventstamp
ORDER BY i2.eventstamp DESC
LIMIT 1
) as prev_id,
(SELECT i2.barrels
FROM inventory i2
WHERE i2.tankname = i.tankname AND
i2.eventstamp < i.eventstamp
ORDER BY i2.eventstamp DESC
LIMIT 1
) as prev_barrels
FROM inventory i
ORDER BY i.tankname, i.eventstamp;
Your query doesn't work because you have columns in the SELECT that are not in the GROUP BY and are not aggregated. That shouldn't be allowed in any database; it is unfortunate that MySQL does allow it.
I'm just starting to learn SQL, and managed to cobble together a couple of working queries, but then when I combine them I am getting a syntax error. The query throwing the error:
SELECT sca_ticket_status.name As Status, AVG(QueueTime)
FROM (SELECT DateDiff (created, now()) as 'QueueTime'
FROM sca_ticket as SubQuery
LEFT JOIN sca_ticket_status
ON sca_ticket.status_id = sca_ticket_status.id
GROUP BY name
ORDER BY sort
For reference, the two working queries that I am attempting to leverage are as follows:
SELECT sca_ticket_status.name As Status, COUNT(sca_ticket.ticket_id) AS Count
FROM sca_ticket
LEFT JOIN sca_ticket_status
ON sca_ticket.status_id = sca_ticket_status.id
WHERE sca_ticket.created between date_sub(now(),INTERVAL 1 WEEK) and now()
GROUP BY name
ORDER BY sort
SELECT AVG(QueueTime)
FROM (SELECT DateDiff (created, now()) as 'QueueTime'
FROM `sca_ticket`
WHERE `status_id` = 1) as SubQuery
Try closing your second select statement
SELECT sca_ticket_status.name As Status, AVG(QueueTime)
FROM (SELECT status_id, DateDiff (created, now()) as 'QueueTime'
FROM sca_ticket) q1
LEFT JOIN sca_ticket_status
ON q1.status_id = sca_ticket_status.id
GROUP BY name
ORDER BY sort
You will also need to expose the status_id column in your inner select list if you want to join on it later.
You do not need a subquery at all. This just slows down the processing in MySQL (the optimizer is not very smart; it materializes subqueries losing index information).
SELECT ts.name As Status, AVG(DateDiff(t.created, now()))
FROM sca_ticket t LEFT JOIN
sca_ticket_status ts
ON t.status_id = ts.id
GROUP BY ts.name
ORDER BY sort
I'm trying to fetch the lowest price per day per hotel, I get multiple results.
I first try to fetch the lowest amount with the MIN() function, then inner join.
When i later try to group by outside the subquery, it just groups by the lowest id.
The SQL itself:
SELECT mt.id, mt.amount, mt.fk_hotel, mt.start_date
FROM price mt
INNER JOIN
(
SELECT price.id, MIN(price.amount) minAmount
FROM price
WHERE 1=1 AND price.start_date >= '2014-10-08' AND price.start_date <= '2014-10-10' AND price.active = 1 AND price.max_people = 2
GROUP BY id
) t
ON mt.id = t.id AND mt.amount = t.minAmount
ORDER BY mt.fk_hotel, mt.amount;
And the results looks like this:
http://jsfiddle.net/63mg3b2j/
I want to group by the start date and fk_hotel so that it groups by the lowest amount value, can anybody help me? Am I being clear?
Edit: I also need a field fk_room from the corresponding row, so i can inner join
Try this:
SELECT MIN(mt.amount) AS min_amount, mt.fk_hotel, mt.start_date
FROM price mt
WHERE
mt.active = 1 AND
mt.max_people = 2 AND
mt.start_date >= '2014-10-08' AND mt.start_date <= '2014-10-10'
GROUP BY mt.fk_hotel, mt.start_date
ORDER BY mt.fk_hotel, min_amount;
Well first of all get a table with minimum value in top row using ORDER BY and then GROUP BY for your required result
SELECT mt.id, mt.amount, mt.fk_hotel, mt.start_date
FROM
(SELECT id, amount, fk_hotel, start_date
FROM price
WHERE start_date >= '2014-10-08' AND start_date <= '2014-10-10'
AND active = 1 AND max_people = 2
ORDER BY amount DESC) AS mt
GROUP BY mt.id
Well I had to still go with a subquery, cause i needed some additional foreign key fields from the corresponding row to inner join some other stuff. It isn't a great solution, cause it fetches too much stuff, the rest is filtered out programmatically.
The most annoying thing here, when I try to use MIN() or MAX() function and get the appropriate fields to that row, it fetches the first results from the DB, which are incorrect and so i have to use a subquery to inner join to get the other fields, I can use grouping, but I had too many fields to group. Maybe I'm missing something. The amount of data doesn't grow in time, so I guess it works for me. So this is the final SQL i came up with, for future reference..
SELECT mt.*, roomtype.name roomname, hotel.name hotelname
FROM booking.price mt
INNER JOIN roomtype ON roomtype.id = mt.fk_roomtype
INNER JOIN hotel ON hotel.id = mt.fk_hotel
INNER JOIN(
SELECT price.id, MIN(price.amount) minAmount
FROM booking.price WHERE 1=1 AND price.start_date >= '2014-10-22' AND price.start_date <= '2014-10-31' AND price.max_people = 2 AND price.active = 1
GROUP BY id
) t
ON mt.id = t.id AND mt.amount = t.minAmount
ORDER BY mt.start_date, mt.amount
I need a SQL query to list all the customers who have joined in last 6 months.
This is my SQL for that.
select
c.company_name,
c.phone1,
c.sprovince,
c.scountry,
sum(order_total_amount) as amt_sold,
max(o.order_date) as last_order_date,
customersince
from
tbl_company c
join
tbl_order o
on c.companyid = o.company_id
where
c.companytype like 'Customer'
and
(PERIOD_DIFF(c.customersince,curdate())<6)
group by company_name
order by amt_sold desc
Now I need one more or condition so that if there is null in customersince column then I should check the first order of the customer. If it is in last 6 months I should display that user also.
order_date is available in tbl_order table. The first order of the customer is min(order_date) group by customer_id
How can I do this?
SELECT c.company_name,
c.phone1,
c.sprovince,
c.scountry,
SUM(order_total_amount) as amt_sold,
MAX(o.order_date) as last_order_date,
COALESCE(customersince, MIN(o.order_date)) AS customersince
FROM tbl_order o
JOIN tbl_company c
ON c.companyid = o.company_id
WHERE c.companytype like 'Customer'
AND (c.customersince >= NOW() - INTERVAL 6 MONTH OR c.customersince IS NULL)
GROUP BY
companyid
HAVING customersince >= NOW() - INTERVAL 6 MONTH
ORDER BY
amt_sold DESC
Note the double condition on customersince: one in the WHERE clause, another one in the HAVING clause.
If you have an index on tbl_customer (customersince), this index will be used to filter the appropriate records early (and fine-filter them later).
PERIOD_DIFF(ifnull(c.customersince, `first_order`),curdate())<6)
you should include your table schema, your first order is refer to which table?
I don't have mysql to test, but this where clause might work for you:
where c.companytype like 'customer'
and (
(PERIOD_DIFF(c.customersince, curdate())<6)
OR
(c.customersince is null AND (PERIOD_DIFF(o.order_date, curdate())<6)
)
Also, you will have to add things you don't have in an aggregate function (max, sum, etc) to your group by clause.