generate sequence of (telephone) numbers in table in mySQL - mysql

This is my first post/question since I couldn't find the answer to what I was looking for no matter how I searched. So here it is:
I have a small table of a few hundred rows with four columns (plus id col) as seen on the example below:
| id | phone1 | phone2 | phone3 | phone4 |
| 1 |059374-6| | 065371-7 |023126-8
| 2 | |026372-3| 024353-7 |
| 3 |...
.
.
.
I need to generate the sequence for all the (telephone) numbers of the specific range they belong. In other words, for the first phone number I need to retrieve the numbers:
059374
059375
059376
and consequently for the rest of the phones in the table.
All the number ranges are given in the above mentioned form and do not exceed the total of 10 numbers (max is something like 099500-9). In addition, they are populated through 4 different columns, as shown in the above example, something I have solved so far by using UNION ALL (in order to put them all in one column and finally find all duplicates which is the ultimate goal).
So, is there any elegant way to generate the numbers needed?
I have searched many threads for similar topics but surprisingly none seem to answer my question.
Finally, if there is any better way than combining all cols into one with UNION ALL and then GROUP BY col1 for finding the duplicates would be highly appreciated.

Create a table that contains the numbers from 0 to 9. Extract the starting and ending digits of each number, and join with the number table to find all the numbers in the range.
WITH digits AS (
SELECT 0 AS dig
UNION
SELECT 1 AS dig
...
UNION
SELECT 9 AS dig)
SELECT SUBSTR(phone1, 1, 5) + digits.dig
FROM yourTable
JOIN digits ON dig BETWEEN SUBSTR(phone1, 6, 1) AND SUBSTR(phone1, 8, 1)
WHERE phone1 != ''
This shows how to do it for the phone1 column, you can use UNION to repeat it for the other 3 columns.

Related

Select all rows contains same value in a column

I want to select all package_id that contain product_id 2.
In this case, package_id 1,3,5 has product_id 2
Table: product_package
package_id package_name product_id
---------------------------------------------
1 Gold 1,2,3
2 Platinum 4,5,12
3 Diamond 2,11,5
4 Titanium 3,5
5 Basic 2
I tried:
SELECT
*
FROM
product_package
WHERE product_id IN(2)
It is outputting package_id 3 and 5 only. How do I output this properly?
product_id structure is varchar(256). Should I change the structure or add Foreign keys?
We always recommend not to stored delimited columns see Is storing a delimited list in a database column really that bad?
But you can use FIND_IN_SET but this is always slow
SELECT
*
FROM
product_package
WHERE FIND_IN_SET(2,product_id)
package_id
package_name
product_id
1
Gold
1,2,3
3
Diamond
2,11,5
5
Basic
2
fiddle
First, let me explain what is happening in your query.
You have WHERE product_id IN(2), but product_id is a misnomer and should rather be product_ids, because it is multiple IDs unfortunately stored in a string. IN is made to look up a value in a list. Your list, however, only consists of one element, so you can just as well use the equality operator: WHERE product_id = 2.
What you have is WHERE string = number, so the DBMS has to convert one of the values in order to compare the two. It converts the string to a number (so '2' matches 2 and '002' matches 2, too, as it should). But your strings are not numbers. The DBMS should raise an error on '1,2,3' for instance, because '1,2,3' is not a number. MySQL, however, has a design flaw here and still converts the string, regardless. It just takes as many characters from the left as they still represent a number. '1' does, but then the comma is not considered numerical (yes, MySQL cannot deal with a thousand separator when convertings strings to numbers implicitly). So converting '1,2,3' to a number results in 1. Equally, '2,11,5' results in 2, so rather surprisingly '2,11,5' = 2 in MySQL. This is why you are getting that row.
You ask "Should I change the structure", and the answer to this is yes. So far your table doesn't comply with the first normal form and should thus not exist in a relational database. You'll want two tables instead forming the 1:n relation:
Table: package
package_id
package_name
1
Gold
2
Platinum
3
Diamond
4
Titanium
5
Basic
Table: product_package
package_id
product_id
1
1
1
2
1
3
2
4
2
5
2
12
3
2
3
11
3
5
4
3
4
5
5
2
You ask "or add Foreign keys?", and the answer is and add foreign keys. So with the changed structure you want product_package(product_id) to reference product(product_id) and product_package(package_id) to reference package(package_id).
Disregarding that you should not be storing multiple values in a single field, you can use LIKE operator to achieve what you are looking for. I'm going with assumptions:
all values are delimited with commas
all values are integers
there are no whitespaces (or any other characters besides integers and commas)
select * from product_package
where product_id like '2,%'
or product_id like '%,2,%'
or product_id like '%,2'
or product_id like '2'
Alternatively, you can use REGEXP operator:
select * from product_package
where product_id regexp '^2$|^2,.+|.+,2,.+|.+,2'
References:
MySQL LIKE
MySQL REGEXP

SQL Validate a column with the same column

I have the following situation. I have a table with all info of article. I will like to compare the same column with it self. because I have multiple type of article. Single product and Master product. the only way that I have to differences it, is by SKU. for example.
ID | SKU
1 | 11111
2 | 11112
3 | 11113
4 | 11113-5
5 | 11113-8
6 | 11114
7 | 11115
8 | 11115-1-W
9 | 11115-2
10 | 11116
I only want to list or / and count only the sku that are full unique. follow th example the sku that are unique and no have variant are (ID = 1, 2, 6 and 10) I will want to create a query where if 11113 are again on the column not cout it. so in total I will be 4 unique sku and not "6 (on total)". Please let me know. if this are possible.
Assuming the length of master SKUs are 5 characters, try this:
select a.*
from mytable a
left join mytable b on b.sku like concat(a.sku, '%')
where length(a.sku) = 5
and b.sku is null
This query joins master SKUs to child ones, but filters out successful joins - leaving only solitary master SKUs.
You can do this by grouping and counting the unique rows.
First, we will need to take your table and add a new column, MasterSKU. This will be the first five characters of the SKU column. Once we have the MasterSKU, we can then GROUP BY it. This will bundle together all of the rows having the same MasterSKU. Once we are grouping we get access to aggregate functions like COUNT(). We will use that function to count the number of rows for each MasterSKU. Then, we will filter out any rows that have a COUNT() over 1. That will leave you with only the unique rows remaining.
Take that unique list and LEFT JOIN it back into your original table to grab the IDs.
SELECT ID, A.MasterSKU
FROM (
SELECT
MasterSKU = SUBSTRING(SKU,1,5),
MasterSKUCount = COUNT(*)
FROM MyTable
GROUP BY SUBSTRING(SKU,1,5)
HAVING COUNT(*) = 1
) AS A
LEFT JOIN (
SELECT
ID,
MasterSKU = SUBSTRING(SKU,1,5)
FROM MyTable
) AS B
ON A.MasterSKU = B.MasterSKU
Now one thing I noticed from you example. The original SKU column really looks like three columns in one. We have multiple values being joined with hypens.
11115-1-W
There may be a reason for it, but most likely this violates first normal form and will make the database hard to query. It's part of the reason why such a complicated query is needed. If the SKU column really represents multiple things then we may want to consider breaking it out into MasterSKU, Version, and Color or whatever each hyphen represents.

MS Access : multiple queries into one table

Okay I'm still fairly new to MS Access, but have got some of the bases down. My next issue is pulling data from two different queries but still needing them to show.
Here's what I have
I have one query with the following information
| ID Number | Points |
The other query has the following
| ID Number | Points over 1000 |
In this new query I need to do display the following
| ID Number | Points | Points over 1000 | Total Points |
There's going to be some rows where Points over 1000 doesn't exist and needs to be empty or a 0, but I need the ID Number In Points over 1000 to match and check the ID Number in just the points column.
and in the end add them up in the Points total
I hope that makes sense?
Thanks again
In theory this Query should work the way you want it to.
SELECT
tmpQ.ID,
Sum(tmpQ.Points) As ActualPoints,
Sum(tmpQ.PointsOver1000) As Over1000,
[ActualPoints] + [Over1000] As TotalPoints
FROM
(
SELECT
qryA.[ID Number] As ID,
Sum(qryA.Points) As Points,
Sum(0) As PointsOver1000
FROM
qryA
GROUP BY
qryA.[ID Number]
UNION ALL
SELECT
qryB.[ID Number] As ID,
Sum(0) As Points,
Sum(qryB.PointsOver1000) As PointsOver1000
FROM
qryB
GROUP BY
qryB.[ID Number]
) As tmpQ
GROUP BY
tmpQ.ID;
Where qryA and qryB are the two queries you have that will give you the result of two different Points.

MySql SELECT by Spliting multiple values separated by ||

Below is the result set from SELECT query,
mysql> select * from mytable where userid =242 ;
+--------+-----------------------------+------------+---------------------+---------------------+
| UserId | ActiveLinks | ModifiedBy | DateCreated | DateModified |
+--------+-----------------------------+------------+---------------------+---------------------+
| 242 | 1|2|4|6|9|15|22|33|43|57|58 | 66 | 2013-11-28 16:17:25 | 2013-11-28 16:17:25 |
+--------+-----------------------------+------------+---------------------+---------------------+
What I want is to SELECT the records by splitting the Active links columns and associating it with UserId in the below format,
eg,
UserId ActiveLinks
242 1
242 2
242 4
242 6
Can anyone help me with this query , as of now nothing coming to my mind. Thanks
Dealing with lists stored in data is a pain. In MySQL, you can use substring_index(). The following should do what you want:
SELECT userid,
substring_index(substring_index(l.ActiveLinks, '||', n.n), '|', -1) as link
FROM (select 1 as n union all select 2 union all select 3 union all select 4) n join
ipadminuserslinks l
on length(l.ActiveLinks) - length(replace(l.ActiveLinks, '||', '')) + 1 <= n.n
WHERE userid = 242;
The first subquery generates a bunch of numbers, which you need. You may have to increase the size of this list.
The on clause limits the numbers to the number of elements in the list.
As you can probably tell, this is rather complicated. It is much easier to use a junction table, which is the relational way to store this type of information.
I would create a routine which will have the delimiter as an argument.
Another in_var would be the correspondent line.
Every time you call it, it will return the set of values for the UserId called.
It will basically use a loop based on the count of '|' (we call this pipeline)
This way you can implement the solution proposed by #Gordon Linoff without the need to know how many active links you have.
If this is just a list of values that do not relate to anything on another table I would do it the same way as Gordon (if needs be you can cross join the sub query that gets the lists of numbers to easily generate far larger ranges of numbers). One minor issue is that if the range of number is bigger than the number of delimited values on a row then the last value will be repeated (easily removed using DISTINCT in this case, more complicated when there are duplicate values in there that you want to keep).
However if the list of delimited values are related to another table (such as being the id field of another table then you could do it this way:-
SELECT a.UserId, b.link_id
FROM mytable a
LEFT OUTER JOIN my_link_table b
ON FIND_IN_SET(b.link_id, replace(a.ActiveLinks, '|', ','))
Ie, use FIND_IN_SET to join your table with the related table. In this case converting any | symbols used as delimiters to commas to allow FIND_IN_SET to work.

MySQL, how to repeat same line x times

I have a query that outputs address order data:
SELECT ordernumber
, article_description
, article_size_description
, concat(NumberPerBox,' pieces') as contents
, NumberOrdered
FROM customerorder
WHERE customerorder.id = 1;
I would like the above line to be outputted NumberOrders (e.g. 50,000) divided by NumberPerBox e.g. 2,000 = 25 times.
Is there a SQL query that can do this, I'm not against using temporary tables to join against if that's what it takes.
I checked out the previous questions, however the nearest one:
is to be posible in mysql repeat the same result
Only gave answers that give a fixed number of rows, and I need it to be dynamic depending on the value of (NumberOrdered div NumberPerBox).
The result I want is:
Boxnr Ordernr as_description contents NumberOrdered
------+--------------+----------------+-----------+---------------
1 | CORDO1245 | Carrying bags | 2,000 pcs | 50,000
2 | CORDO1245 | Carrying bags | 2,000 pcs | 50,000
....
25 | CORDO1245 | Carrying bags | 2,000 pcs | 50,000
First, let me say that I am more familiar with SQL Server so my answer has a bit of a bias.
Second, I did not test my code sample and it should probably be used as a reference point to start from.
It would appear to me that this situation is a prime candidate for a numbers table. Simply put, it is a table (usually called "Numbers") that is nothing more than a single PK column of integers from 1 to n. Once you've used a Numbers table and aware of how it's used, you'll start finding many uses for it - such as querying for time intervals, string splitting, etc.
That said, here is my untested response to your question:
SELECT
IV.number as Boxnr
,ordernumber
,article_description
,article_size_description
,concat(NumberPerBox,' pieces') as contents
,NumberOrdered
FROM
customerorder
INNER JOIN (
SELECT
Numbers.number
,customerorder.ordernumber
,customerorder.NumberPerBox
FROM
Numbers
INNER JOIN customerorder
ON Numbers.number BETWEEN 1 AND customerorder.NumberOrdered / customerorder.NumberPerBox
WHERE
customerorder.id = 1
) AS IV
ON customerorder.ordernumber = IV.ordernumber
As I said, most of my experience is in SQL Server. I reference http://www.sqlservercentral.com/articles/Advanced+Querying/2547/ (registration required). However, there appears to be quite a few resources available when I search for "SQL numbers table".