I have two distinct queries which return single values and I would like to combine them into one single value. See below:
Query 1:
select sum(value)
from table.trans as transactions
where country= 'UK'
and transactions.from = 'Angela'
Query 2:
select sum(value)
from table.trans as transactions
where country= 'UK'
and transactions.to= 'Angela'
I now want to get:
Value from query 1 - Value from query 2
You can use conditional aggregation:
select sum(case when t.to = 'Angela' then value end) as to_value,
sum(case when t.from = 'Angela' then value end) as from_value
from table.trans t
where country = 'UK' and 'Angela' in (t.to, t.from);
For the difference:
select sum(case when t.to = 'Angela' then value
when t.from = 'Angela' then - value
end) as diff
from table.trans t
where country = 'UK' and 'Angela' in (t.to, t.from);
You can use IF as well
select SUM(if(transactions.from = 'Angela',ifnull(value,0),0)+ if(transactions.to = 'Angela',ifnull(-value,0),0)) diff
from table.trans as transactions
where country= 'UK'
and 'Angela' in (transactions.from,transactions.to)
Related
Can you advice in whats the best way to combine multiple select and count into the one query
For example here are some queries that are from a test_table and work perfect on their own
SELECT name, count(*) AS 'Overall' FROM test_test WHERE country_prefix = '44' AND area_code = '203' GROUP BY `city_name`;
SELECT name, count(*) AS 'unallocated' FROM test_tab le WHERE country_prefix = '44' AND area_code = '203' AND removed != '1' AND destination-value = '1234' GROUP BY `city_name`;
There's a few more queries i'll be running but I think if I get two working together ill be able to do the rest
I was thinking something like this:
SELECT name, (SELECT count(*) FROM test_table WHERE country_prefix = '44' AND area_code = '203' GROUP BY `city_name') AS "Overall", (SELECT count(*) AS 'unallocated' FROM test_table WHERE country_prefix = '44' AND city_code = '203' AND removed != '1' AND destination-value = '1234' GROUP BY 'city_name')
But unfortunately doesn't work
Would the best way to do this be using sum case when, something like this:
sum(case when destination-value = '1234' then 1 else 0 end) AS unallocated
You can do it with conditional aggregation:
SELECT city_name,
COUNT(CASE WHEN country_prefix = '44' AND area_code = '203' THEN 1 END) AS Overall,
COUNT(CASE WHEN country_prefix = '44' AND area_code = '203' AND removed != '1' AND destination-value = '1234' THEN 1 END) AS unallocated
FROM tablename
GROUP BY city_name;
or since the 2 cases contain common conditions, these conditions can be moved to a WHERE clause:
SELECT city_name,
COUNT(*) AS Overall,
COUNT(CASE WHEN removed != '1' AND destination-value = '1234' THEN 1 END) AS unallocated
FROM tablename
WHERE country_prefix = '44' AND area_code = '203'
GROUP BY city_name;
In Mysql it's possible to simplify the code with the function SUM() instead of COUNT():
SELECT city_name,
COUNT(*) AS Overall,
SUM(removed != '1' AND destination-value = '1234') AS unallocated
FROM tablename
WHERE country_prefix = '44' AND area_code = '203'
GROUP BY city_name;
With this example iformation table:
How can i output this information?
I'm trying this query,
but it's just returning me the total number of 'PART' rows for each 'NAMES'.
SELECT
NAMES
, SUM(PART = "F001") AS SUM_F001
, SUM(PART = "F002") AS SUM_F002
, SUM(PART = "F003") AS SUM_F003
FROM
MY_TABLE
GROUP BY NAMES ASC
You are pretty close with your current query.
But you need to use the query below to correctly pivot.
SELECT
NAMES
, MAX(CASE WHEN PART = 'F001' THEN QTY ELSE 0 END) AS F001
, MAX(CASE WHEN PART = 'F002' THEN QTY ELSE 0 END) AS F002
, MAX(CASE WHEN PART = 'F003' THEN QTY ELSE 0 END) AS F003
, SUM(QTY) AS alias
FROM
FROM
MY_TABLE
GROUP BY
NAMES # Don't use ASC OR DESC on GROUP BY because it's deprecated
ORDER BY
NAMES ASC
U can use the query as follows
SELECT NAMES , SUM(CASE WHEN PART = 'F001' THEN 1 ELSE 0 END) AS F001 , SUM(CASE WHEN PART = 'F002' THEN 1 ELSE 0 END) AS F002 , SUM(CASE WHEN PART = 'F003' THEN 1 ELSE 0 END) AS F003 , SUM(QTY) AS alias FROM FROM MY_TABLE GROUP BY NAMES ORDER BY NAMES ASC
In my current query:
SELECT COUNT(WC.ID) AS "Regions"
FROM WHOLE_FEATURES_PDB_CHAINS AS WC
;
I COUNT(WC.ID) AS "Regions" .
However, we have multiple regions with WC.Type can be 1,2,3,4. I need to count each type occurrence into COUNT(WC.ID) AS "Region_1", COUNT(WC.ID) AS "Region_2" ... depending on WC.Type.
Is there any way to solve this in one query? I am looking at MySQL IF, yet do not know how to integrate it into the count function.
I need it to be in one row (the shown query here is reduced, it's a larger query)
SELECT COUNT(WC.ID) AS "Region_1" , COUNT(WC.ID) AS "Region_2" ...
Here is the complete query if anyone is interested:
SELECT PCS.PDB_id, PCS.Chain, PPA.ENSEMBL_start, PPA.ENSEMBL_end, PPA.eValue, PIN.TITLE AS "pdbTitle", COUNT(WC.ID) AS "Regions"
FROM PDB_Chains AS PCS
LEFT JOIN WHOLE_FEATURES_PDB_CHAINS AS WC ON WC.PDB_CHAIN_ID = PCS.idPDB_chains, PDB_protein_alignment PPA, PDB_INFOS PIN
WHERE PCS.idPDB_chains = PPA.idPDB_Chains
AND PCS.PDB_id = PIN.PDB_ID
AND PPA.idProteins = (SELECT idProteins from Proteins WHERE ENSEMBL_protein_id = "'+submittedID+'")
GROUP BY PCS.PDB_id, PCS.Chain ORDER BY PCS.PDB_id;
Here's the working solutin based on your kind answers
SELECT PIN.TITLE AS "pdbTitle", COUNT(CASE WHEN WC.STRUCTURAL_FEATURES_ID = 1 then 1 end) AS "PPInterface" , COUNT(CASE WHEN WC.STRUCTURAL_FEATURES_ID = 4 then 1 end) AS "flexibleRegions"
FROM PDB_Chains AS PCS LEFT JOIN WHOLE_FEATURES_PDB_CHAINS AS WC ON WC.PDB_CHAIN_ID = PCS.idPDB_chains, PDB_protein_alignment PPA, PDB_INFOS PIN
WHERE PCS.idPDB_chains = PPA.idPDB_Chains
AND PCS.PDB_id = PIN.PDB_ID
AND PPA.idProteins = (SELECT idProteins from Proteins WHERE ENSEMBL_protein_id = "ENSP00000256078.4")
GROUP BY PCS.PDB_id, PCS.Chain ORDER BY PCS.PDB_id;
You can use case when statement inside your aggregate function.
Try this .
count(case when WC.type = 1 then 1 end) as region_1, similarly repeat for another column.
Select
...
...
sum(if WC.ID = 1 then 1 else 0) as Region1,
sum(if WC.ID = 2 then 1 else 0) as Region2,
sum(if WC.ID = 3 then 1 else 0) as Region3,
sum(if WC.ID = 4 then 1 else 0) as Region4
Might do what you want.
You can use GROUP BY with COUNT to get the required result, e.g.:
SELECT WC.Type, COUNT(WC.ID) AS "Regions"
FROM WHOLE_FEATURES_PDB_CHAINS AS WC
GROUP BY WC.Type;
Update
If you want the counts as pivoted column for each region then you can write inner SELECT queries, e.g.:
SELECT
(SELECT COUNT(ID) FROM WHOLE_FEATURES_PDB_CHAINS WHERE type = 1) AS "Region_1",
(SELECT COUNT(ID) FROM WHOLE_FEATURES_PDB_CHAINS WHERE type = 2) AS "Region_2",
other_column
FROM WHOLE_FEATURES_PDB_CHAINS AS WC
WHERE <some condition>;
In this code its able to alias each case statement separately like,
SELECT
id,
SUM(CASE
WHEN (a.place = 'CHN' AND a.salary = 20000)
THEN '1'
ELSE '0'
END) AS '20K Salary',
SUM(CASE
WHEN (a.place = 'CHN' and a.salary = 35000)
THEN '1'
ELSE '0'
END) AS '35K Salary'
FROM Employee a;
but when nested CASE statement is used,
SELECT
id,
SUM(CASE
WHEN (a.place = 'CHN')
THEN (CASE
WHEN a.salary = 20000
THEN '1'
ELSE '0'
END) AS '20K Salary',
(CASE
WHEN a.salary = 35000
THEN '1'
ELSE '0'
END) AS '35K Salary'
END)
FROM Employee a;
its not possible to execute the query
In the first set of code each case statement is part of the SELECT list (i.e. they are in a comma separated list following SELECT) so each returns a column. In the second set of code there is only one case statement in the SELECT list, the fact that it is nested has no impact on this. Also the syntax for the nested case isn't correct because the THEN part is followed by two expressions separated by commas which is not allowed.
Of course this is possible to do what you want. You want to create two columns, so each needs its own logic and its own alias:
SELECT id,
SUM(CASE WHEN a.place = 'CHN' AND a.salary = 20000 THEN 1 ELSE 0
END) as Salary_20K,
SUM(CASE WHEN a.place = 'CHN' AND a.salary = 35000 THEN 1 ELSE 0
END) as Salary_35K
FROM Employee a;
Note: Don't put numeric constants in single quotes. Only use single quotes for string and date constants.
I am trying to get the count of females and males in the gender field of a table.
Is there a way to get the count of each in one query?
Something like:
select * from table count(where gender = 'm') as total_males, count(where gender = 'f') as total_females;
or will it require two queries?
select count(*) from table where gender = 'm';
select count(*) from table where gender = 'f';
This is basically a PIVOT. MySQL does not have a pivot so you can use an aggregate function with a CASE statement to perform this:
select
sum(case when gender = 'm' then 1 else 0 end) Total_Male,
sum(case when gender = 'f' then 1 else 0 end) Total_Female
from yourtable
See SQL Fiddle with Demo
Or using COUNT:
select
count(case when gender = 'm' then 1 else null end) Total_Male,
count(case when gender = 'f' then 1 else null end) Total_Female
from yourtable;
See SQL Fiddle with Demo
Something like this will work:
SELECT SUM(IF(t.gender='m',1,0)) AS total_males
, SUM(IF(t.gender='f',1,0)) AS total_females
FROM mytable t
The "trick" here is that we are using a conditional test to return either a 0 or a 1 for each row, and then adding up the 0's and 1's. To make this a little more clear, I am using the SUM aggregate function rather than COUNT, although COUNT could be used just as easily, though we'd need to return a NULL in place of the zero.
SELECT COUNT(IF(t.gender='m',1,NULL)) AS total_males
, COUNT(IF(t.gender='f',1,NULL)) AS total_females
FROM mytable t
Consider that the two expressions in the SELECT list of this query:
SELECT COUNT(1)
, SUM(1)
FROM mytable t
Will return the same value.
If you want to avoid the MySQL IF function, this can also be done using the ANSI SQL CASE expression:
SELECT SUM( CASE WHEN t.gender = 'm' THEN 1 ELSE 0 END )) AS total_males
, SUM( CASE WHEN t.gender = 'f' THEN 1 ELSE 0 END )) AS total_females
FROM mytable t
select sum(case when gender='m' then 1 else null end) as total_males, sum(case when gender='f' then 1 else null end) as total_females from ...
Should work just fine!
If your only issue is to avoid two queries, you can always write two queries as subselects of one query.
Select (select 1 from dual) as one, (select 2 from dual) as two from dual
This would work for your scenario, too.