Convert order by additional operator to sequelize - mysql

Question

I want to convert query MySQL into sequelize, but i don't know
SELECT * FROM `RewardEntries`
ORDER BY `RewardEntries`.`happinessPoint` + `RewardEntries`.`moneyPoint` + `RewardEntries`.`healthyPoint` DESC
Please help me
thanks

Answer 1

There might be a more elegant way to do this. I've tested this with PostgreSQL, although the same would probably work for MySQL, too.
let rewards = await RewardEntry.findAll({
order: [
[ sequelize.literal('happinesspoint + moneypoint + healthypoint'), 'DESC' ]
]
})
Here's a complete sample. The name of the table in the database and all of its columns are all lowercase. That's why the query has just lowercase in it.
let {
Sequelize,
DataTypes,
} = require('sequelize')
async function run () {
let sequelize = new Sequelize('mydb', 'username', 'password', {
host: 'localhost',
port: 5432,
dialect: 'postgres',
logging: console.log
})
let RewardEntry = sequelize.define('RewardEntry', {
id: {
type: DataTypes.INTEGER,
allowNull: false,
primaryKey: true
},
HappinessPoint: {
type: DataTypes.INTEGER,
field: 'happinesspoint'
},
MoneyPoint: {
type: DataTypes.INTEGER,
field: 'moneypoint'
},
HealthyPoint: {
type: DataTypes.INTEGER,
field: 'healthypoint'
}
},
{
tableName: 'rewardentries',
timestamps: false
})
let rewards = await RewardEntry.findAll({
order: [
[ sequelize.literal('happinesspoint + moneypoint + healthypoint'), 'DESC' ]
]
})
console.log(JSON.stringify(rewards, null, 2))
await sequelize.close()
}
run()