I have a numeric column in my 'daily call' dataset which has a numeric format that I would like to convert into a DATE format.
The problem is, the column has a single data of '81121' (INT) which basically should convert to Aug 11, 2021. however when I use DATE(column name), it converts it to Nov 21, 2008 (CAST gives me the same result).
I have tried CONVERT as well but no luck.
Can someone please advise?
Note: The '11' part in 81121 is the date which changes everyday (looking for something scalable)
Regards,
S
This should do it:
SELECT STR_TO_DATE(LPAD(81121, 6, '0'), '%m%d%y')
-- note that %m expects 2 digits so LPAD is necessary
However I would suggest storing dates using the date datatype.
Related
As title, I'm trying to convert a VARCHAR column in a DATE column, and data is populated in that format "DDMMYYYY" ex. XMAS is "25122022" and in this case the correct formula should be STR_TO_DATE(column, '%d%m%Y')Well, when I execute this query I get an error since in some cases I have values with a "missing" char, I mean, for example, "1012023" when the day is <10 the query fails, cause it checks for "01122023" instead.I could solve this easily by adding a 0 to all fields having length 7, but I'd like to make it more clean.Reading better the usage of STR_TO_DATE I noticed that I could replace %d with %e since the second choice should theorically consider days from 0 to 31 instead of 01 to 31.Unexpectedly the query didn't work and gave me the same erorr at the first instance of a length 7 string.Am I doing something wrong?Thanks in advance.
We can try left padding your date string with zero to a length of 8:
WITH yourTable AS (
SELECT '1012023' AS dt
)
SELECT STR_TO_DATE(LPAD(dt, 8, '0'), '%d%m%Y') AS dt_out -- 2023-01-01
FROM yourTable;
Demo
I have a MySQL table that contains column representing a date and is stored as a string.
The dates in this column (date) are not standard (dirty) and can range from
"Jan 5, 2004" or "Jun 22 2:45 AM"
For the records that are missing the year I have another column (OpeningDate) that can be null or "22 June 2005" and "Deadline" which is a dirty column with values like ("26 January 2004", "01 July 2005, 6 pm
ABOUT: BearingPoint, Inc. Commercial Law and Economic Regulation
Program")
How do I go about to get a normalized representation of the values in the date field.
For other tables I've been able to normalize the date field by using the following queries but for this table the solutions I come up with are too convoluted and not even close to accurate.
SELECT DATE_FORMAT(STR_TO_DATE(DATE,'%M %d, %Y'), '%Y-%m-%d') FROM `data job posts`
I'm not sure there is a clean way to do this since strings are very much non normalized. The cleanest approach would likely be to chunk the data being modified and identify patterns that are identifiable so that you can reduce the size of the dataset to a smaller group of highly unnormalized strings.
As an example something similar to this:
UPDATE table
SET DATE = CASE WHEN DATE LIKE '^alnum+, digit+$' THEN DATE_FORMAT(STR_TO_DATE(DATE,'%M %d, %Y'), '%Y-%m-%d') ELSE DATE END,
DATE = CASE WHEN DATE LIKE '^alnum+:alnum+$' THEN DATE_FORMAT(STR_TO_DATE(DATE,'%M %d %l:%i %p'), '%m-%d') ELSE DATE END;
It might help to create this as a new column and rename the new column when dropping the old one once the operation is complete or creating this as a new table if the current table is live and needs to be queryable as updating records may lock the table.
i have a table like this
|id| date |name|
1 23/11/20 jake
2 01/07/20 jhon
3 23/05/20 blake
4 11/02/20 drake
5 1/03/14 crake
i ran a query like this
WHERE date >= '1/07/20' AND date <= '23/11/20'
i expected a result where i would get only the results between those dates
but i got some results which were from 2014
the data type for the date column is varchar
#note i can not change the datatype
how can i only get dates between the two ?
String-wise comparison is the problem: typically, '10/01/19' (Janurary 10th, 2019) is greater than '01/01/20' (January 1st, 2020), because the former starts with 1, and the later with 0.
You need to turn these strings to dates before you can compare them:
where str_to_date(date, '%d/%m/%y') between '2020-07-01' and '2020-66-23'
This is inefficient, because the entire column needs to be converted before the filtering can happen. I would warmly recommend fixing your data model, and store dates as dates.
Side note: your strings need to be consistently formatted as mm/dd/yy for this to work; if you have varying formats - or strings that do not map to valid dates - then you have a bigger problem than what you have asked here.
I have a field that is a bunch of integers formatted like so:
92014
102014
I would like to convert the field into a datetime of the first of each month. So the newly formated field would be:
9/01/2014 00:00:00
10/01/2014 00:00:00
(or however datetimes would actually get formatted). Can anyone help?
This is how you can accomplish this in an expression:
DateTime.ParseExact(IIF(LEN(Trim(Fields!StringDate.Value)) < 6, "0" & Fields!StringDate.Value,Fields!StringDate.Value),"Myyyy",System.Globalization.CultureInfo.InvariantCulture)
I have a mySQL query which is outputting decimal fields with a comma.
SELECT Metals.Metal, FORMAT(Fixes.GBPam, 3) AS AM, FORMAT(Fixes.GBPpm, 3) AS PM,
DATE_FORMAT(Fixes.DateTime, '%d-%m-%y') AS Date
FROM Fixes, Metals
WHERE Metals.Id = Fixes.Metals_Id
Fields GBPam and GBPpm are both of type decimal(10,5)
Now I want columns AM and PM to be formatted to 3 decimal places in my sql query - Correct
I want values in the thousands to be formatted as xxxx.xxx and not x,xxx.xxx - Incorrect
Example output from mysql query:
Metal AM PM Date
Gold 1,081.334 NULL 11-09-12
Silver 21.009 NULL 10-09-12
Platinum 995.650 NULL 11-09-12
Palladium 416.700 NULL 11-09-12
Can you see that output for Gold AM is 1,081.334? How can I get it to output 1081.334?
This is a pain in the ass for me because I have to then muck about in PHP to remove the comma. I would prefer to just get mysql to format it correctly.
Just use ROUND, this is a numeric function. FORMAT is a string function
ROUND(Fixes.GBPam, 3)
you can use replace command for this purpose.
REPLACE(Fixes.GBPam,',','')
EDIT:
With respect to your question you could do something like this:
SELECT Metals.Metal, ROUND(REPLACE(Fixes.GBPam,',',''),3) AS AM,
ROUND(REPLACE(Fixes.GBPpm,',',''),3) AS PM,
DATE_FORMAT(Fixes.DateTime, '%d-%m-%y') AS Date
FROM Fixes, Metals
WHERE Metals.Id = Fixes.Metals_Id
Use replace function. Whether the field is integer or varchar, it will work.
select replace(Fixes.GBPam,',','.');