mysql update command example two tables - SPEED UP - mysql

Say you have 2 tables with email in common between them and you want to set an binary value of 1 to the match field - this query works just fine
...but it is very SLOW and puts a huge load on the server if you're dealing with a large number of records (and we are)
UPDATE table1 a
INNER JOIN table2 b
ON a.email = b.email
SET a.match = 1;
Does anyone know of the exact same functionality but written with syntax that would put less load on the server and process the query faster?
Thanks!

Before running the query be sure to index both tables. In our case Table 1 has unique values whereas Table 2 has multiple records with the same email (i.e. different websites)
CREATE UNIQUE INDEX email ON table1 ( email );
CREATE INDEX email ON table2 ( email );
Once these indexes were created on those two tables, the query runs very fast.

Related

Best way to write SQL delete statement, deleting pairs of records

I have a MySQL database with just 1 table:
Fields are: blocknr (not unique), btcaddress (not unique), txid (not unique), vin, vinvoutnr, netvalue.
Indexes exist on both btcaddress and txid.
Data in it looks like this:
I need to delete all "deletable" record pairs. An example is given in red.
Conditions are:
txid must be the same (there can be more than 2 records with same txid)
vinvoutnr must be the same
vin must be different (can have only 2 values 0 and 1, so 1 must be 0 other must be 1)
In a table of 36M records, about 33M records will be deleted.
I've used this:
delete t1
from registration t1
inner join registration t2
where t1.txid=t2.txid and t1.vinvoutnr=t2.vinvoutnr and t1.vin<>t2.vin;
It works but takes 5 hours.
Maybe this would work too (not tested yet):
delete t1
from registration as t1, registration as t2
where t1.txid=t2.txid and t1.vinvoutnr=t2.vinvoutnr and t1.vin<>t2.vin;
Or do I forget about a delete query and try to make a new table with all non-delatables in and then drop the original ?
Database can be offline for this delete query.
Based on your question, you are deleting most of the rows in the table. That is just really expensive. A better approach is to empty the table and re-populate it:
create table temp_registration as
<query for the rows to keep here>;
truncate table registration;
insert into registration
select *
from temp_registration;
Your logic is a bit hard to follow, but I think the logic on the rows to keep is:
select r.*
from registration r
where not exists (select 1
from registration r2
where r2.txid = r.txid and
r2.vinvoutnr = r.vinvoutnr and
r2.vin <> r.vin
);
For best performance, you want an index on registration(txid, vinvoutnr, vin).
Given that you expect to remove the majority of your data it does sound like the simplest approach would be to create a new table with the correct data and then drop the original table as you suggest. Otherwise ADyson's corrections to the JOIN query might help to alleviate the performance issue.

how to compare huge table of mysql

I have a huge table of mysqlwhich contains more than 33 million records .How I could compare my table to found non duplicate records , but unfortunately select statement doesn't work. Because it's huge table.
Please provide me a solution
First, Create a snapshot of your database or the tables you want to compare.
Optionally you can also limit the range of data you want to compare , for example only 3 years of data. This way your select query won't hog all the resources.
Snapshot will be bunch of files each representing a table containg your primary key or business key for each record ( I am assuming you can compare data based on aforementioned key . If thats not the case record all the field in your file)
Next, read each records from the file and do a select against the corresponding table. If there are more than 1 record you know it is a duplicate
Thanks
Look at the explain plan and see if what the DB is actually doing for the NOT IN.
You could try refactoring, with an index on subscriber as Roy suggested if necessary. I'm not familiar enough with MySQL to know whether the optimizer will execute these identically.
SELECT *
FROM contracts
WHERE NOT EXISTS
( SELECT 1
FROM edms
WHERE edms.subscriber=contracts.subscriber
);
-- or
SELECT C.*
FROM contracts AS C
LEFT
JOIN edms AS E
ON E.subscriber = C.subscriber
WHERE E.subscriber IS NULL;

MySQL copy row from one table to another with multiple NOT IN criteria

We have an old FoxPro DB that still has active data being entered into it. I am in the process of writing a series of .bat files that will update a MySQL database for our web applications that I'm working on.
Our FoxPro databases were never set up with unique IDs or anything useful like that so I'm having to have the query look at a few different fields.
Here's my query thus far:
//traininghistory = MySQL DB
//traininghistory_test = FoxPro DB
INSERT INTO traininghistory
WHERE traininghistory_test.CLASSID NOT IN(SELECT CLASSID FROM traininghistory)
AND traininghistory_test.EMPID NOT IN(SELECT EMPID FROM traininghistory)
What I'm After is this:
I need an query that looks at the 600,000+ entries in the FoxPro DB (traininghistory_test in my code) and compares to the 600,000+ entries in the MySQL DB (traininghistory in my code) and only inserts the ones where the columns CLASSID and EMPID are new- that is, they are NOT in the traininghistory table.
Any thoughts on this (or if you know a simpler/more efficient way to execute this query in MySQL) are greatly appreciated.
One option is to use a outer join / null check:
insert into traininghistory
select values
from traininghistory_test tht
left join traininghistory th on tht.empid = th.empid
and tht.classid = th.classid
where th.empid is null
It's also worth noting, your current query may leave out records since it's not comparing empid and classid in the same records.
One way ist.
CREATE ONE UNIQUE INDEX ON THE COLUMS (CLASSID, EMPID),
THEN
INSERT IGNORE INTO traininghistory SELECT * or fieldlist FROM traininghistory_test;
Thats all

MySQL : updating a table from another table by leftjoin vs iterating

I have two tables T1 and T2 and want to update one field of T1 from T2 where T2 holds massive data.
What is more efficient?
Updating T1 in a for loop iteration over the values
or
Left join it with T2 and update.
Please note that i'm updating these tables in a shell script
In general, the JOIN will always work much better than a loop. The size should not be an issue if it is properly indexed.
There is no simple answer which will be more effective, it will depend on table size and data size to which you are going to update in one go.
Suppose you are using innodb engine and trying to update 1,000 or more rows in one go with 2 heavy tables join and it is quite frequent then it will not be good idea on production server as it will lock your table for some time and due to this locking some other operations also can be hit on your production server.
Option1: If you are trying to update few rows and based on proper indexed fields (preferred based on primary key) then you can go with join.
Option2: If you are trying to update a large amount of data based on multiple tables join then below option will be better:
Step1: Create a stored procedure.
Step2: Keep below query results in a cursor.
suppose you want TO UPDATE corresponding field2 DATA of TABLE table2 IN field1 of TABLE table1:
SELECT a.primary_key,b.field2 FROM table1 a JOIN table2 b ON a.primary_key=b.foreign_key WHERE [place CONDITION here IF any...];
Step3: Now update all rows one by one based on primary key using stored values in cursor.
Step4: You can call this stored procedure from your script.

SQL: Select Keys that doesn't exist in one table

I got a table with a normal setup of auto inc. ids. Some of the rows have been deleted so the ID list could look something like this:
(1, 2, 3, 5, 8, ...)
Then, from another source (Edit: Another source = NOT in a database) I have this array:
(1, 3, 4, 5, 7, 8)
I'm looking for a query I can use on the database to get the list of ID:s NOT in the table from the array I have. Which would be:
(4, 7)
Does such exist? My solution right now is either creating a temporary table so the command "WHERE table.id IS NULL" works, or probably worse, using the PHP function array_diff to see what's missing after having retrieved all the ids from table.
Since the list of ids are closing in on millions or rows I'm eager to find the best solution.
Thank you!
/Thomas
Edit 2:
My main application is a rather easy table which is populated by a lot of rows. This application is administrated using a browser and I'm using PHP as the intepreter for the code.
Everything in this table is to be exported to another system (which is 3rd party product) and there's yet no way of doing this besides manually using the import function in that program. There's also possible to insert new rows in the other system, although the agreed routing is to never ever do this.
The problem is then that my system cannot be 100 % sure that the user did everything correct from when he/she pressed the "export" key. Or, that no rows has ever been created in the other system.
From the other system I can get a CSV-file out where all the rows that system has. So, by comparing the CSV file and my table I can see if:
* There are any rows missing in the other system that should have been imported
* If someone has created rows in the other system
The problem isn't "solving it". It's making the best solution to is since there are so much data in the rows.
Thanks again!
/Thomas
We can use MYSQL not in option.
SELECT id
FROM table_one
WHERE id NOT IN ( SELECT id FROM table_two )
Edited
If you are getting the source from a csv file then you can simply have to put these values directly like:
I am assuming that the CSV are like 1,2,3,...,n
SELECT id
FROM table_one
WHERE id NOT IN ( 1,2,3,...,n );
EDIT 2
Or If you want to select the other way around then you can use mysqlimport to import data in temporary table in MySQL Database and retrieve the result and delete the table.
Like:
Create table
CREATE TABLE my_temp_table(
ids INT,
);
load .csv file
LOAD DATA LOCAL INFILE 'yourIDs.csv' INTO TABLE my_temp_table
FIELDS TERMINATED BY ','
LINES TERMINATED BY '\n'
(ids);
Selecting records
SELECT ids FROM my_temp_table
WHERE ids NOT IN ( SELECT id FROM table_one )
dropping table
DROP TABLE IF EXISTS my_temp_table
What about using a left join ; something like this :
select second_table.id
from second_table
left join first_table on first_table.id = second_table.id
where first_table.is is null
You could also go with a sub-query ; depending on the situation, it might, or might not, be faster, though :
select second_table.id
from second_table
where second_table.id not in (
select first_table.id
from first_table
)
Or with a not exists :
select second_table.id
from second_table
where not exists (
select 1
from first_table
where first_table.id = second_table.id
)
The function you are looking for is NOT IN (an alias for <> ALL)
The MYSQL documentation:
http://dev.mysql.com/doc/refman/5.0/en/all-subqueries.html
An Example of its use:
http://www.roseindia.net/sql/mysql-example/not-in.shtml
Enjoy!
The problem is that T1 could have a million rows or ten million rows, and that number could change, so you don't know how many rows your comparison table, T2, the one that has no gaps, should have, for doing a WHERE NOT EXISTS or a LEFT JOIN testing for NULL.
But the question is, why do you care if there are missing values? I submit that, when an application is properly architected, it should not matter if there are gaps in an autoincrementing key sequence. Even an application where gaps do matter, such as a check-register, should not be using an autoincrenting primary key as a synonym for the check number.
Care to elaborate on your application requirement?
OK, I've read your edits/elaboration. Syncrhonizing two databases where the second is not supposed to insert any new rows, but might do so, sounds like a problem waiting to happen.
Neither approach suggested above (WHERE NOT EXISTS or LEFT JOIN) is air-tight and neither is a way to guarantee logical integrity between the two systems. They will not let you know which system created a row in situations where both tables contain a row with the same id. You're focusing on gaps now, but another problem is duplicate ids.
For example, if both tables have a row with id 13887, you cannot assume that database1 created the row. It could have been inserted into database2, and then database1 could insert a new row using that same id. You would have to compare all column values to ascertain that the rows are the same or not.
I'd suggest therefore that you also explore GUID as a replacement for autoincrementing integers. You cannot prevent database2 from inserting rows, but at least with GUIDs you won't run into a problem where the second database has inserted a row and assigned it a primary key value that your first database might also use, resulting in two different rows with the same id. CreationDateTime and LastUpdateDateTime columns would also be useful.
However, a proper solution, if it is available to you, is to maintain just one database and give users remote access to it, for example, via a web interface. That would eliminate the mess and complication of replication/synchronization issues.
If a remote-access web-interface is not feasible, perhaps you could make one of the databases read-only? Or does database2 have to make updates to the rows? Perhaps you could deny insert privilege? What database engine are you using?
I have the same problem: I have a list of values from the user, and I want to find the subset that does not exist in anther table. I did it in oracle by building a pseudo-table in the select statement Here's a way to do it in Oracle. Try it in MySQL without the "from dual":
-- find ids from user (1,2,3) that *don't* exist in my person table
-- build a pseudo table and join it with my person table
select pseudo.id from (
select '1' as id from dual
union select '2' as id from dual
union select '3' as id from dual
) pseudo
left join person
on person.person_id = pseudo.id
where person.person_id is null