I would like to do the following and it is not working. I would like to left join the result of a subquery.
select result1.id, result.name from (select cust.id as id, cust.name as name, ss.sold_date as soldDate, pp.product_name as productName from customers cust
left join sales ss on ss.customer_id = cust.id
left join products pp on pp.id = ss.product_id) as result
left join result as result1 on result.id = result1.id
When I do this, it says table 'result' does not exist. How do I left join the result alias?
As per your comment you're trying to join the subquery result with itself.
In this particular case it does not make any sense because you'll just get the same data twice. So, using the subquery once will work
select result1.id, result.name
from (select cust.id as id, cust.name as name, ss.sold_date as soldDate, pp.product_name as productName
from customers cust
left join sales ss on ss.customer_id = cust.id
left join products pp on pp.id = ss.product_id) as result
left join result as result1 on result.id = result1.id
I general, if you need to use same sub-query twice, you may use a CTE (common-table-expression):
with sub_q as (select cust.id as id, cust.name as name, ss.sold_date as soldDate, pp.product_name as productName
from customers cust
left join sales ss on ss.customer_id = cust.id
left join products pp on pp.id = ss.product_id)
select *
from sub_q res
left join sub_q res1
on res.id = res1.id
The CTE (the "with" part of the query above) is like a variable. In "usual" programming languages variable is being used to store values, whereas in query language it's job to store queries
UPD. The OP appeared to be on mysql version prior to 8.0 and the db OP is on doesn't support CTEs
So, here you may end up using views for example
First, a script to creaate a view
create view sub_q as select cust.id as id, cust.name as name, ss.sold_date as soldDate, pp.product_name as productName
from customers cust
left join sales ss on ss.customer_id = cust.id
left join products pp on pp.id = ss.product_id;
Second, run the query
select *
from sub_q res
left join sub_q res1
on res.id = res1.id;
Alternatively you may repeat subquery twice in the select statement
Related
I've been given a question using AdventureWorks to list all the vendors with no products. When I run my SELECT statement nothing is returned. What am I doing wrong? (Answer can only be done using Joins and Unions - No Subqueries)
SELECT DISTINCT pv.Name AS 'Vendors'
FROM Purchasing.Vendor pv
INNER JOIN Purchasing.ProductVendor ppv
ON pv.BusinessEntityID = ppv.BusinessEntityID
INNER JOIN Production.Product pp
ON pp.ProductID = ppv.ProductID
WHERE pp.ProductID != ppv.ProductID;
You're looking at one too many tables, all ProductVendors have Products. Not all Vendors have ProductVendors.
From there you can simply use a LEFT JOIN and look for null records.
SELECT DISTINCT v.Name
FROM Purchasing.Vendor v
LEFT JOIN Purchasing.ProductVendor pv ON pv.BusinessEntityID = v.BusinessEntityID
WHERE pv.BusinessEntityID IS NULL
Use left join to include cases where there is no product for a "vendor". Inner join will consider only those cases, where a product id exists for a vendor.
Now, do grouping on a "Vendor" and count the number of products using COUNT() function.
Finally, filter out those vendors where count is zero, using HAVING clause
Try the following:
SELECT pv.Name AS 'Vendors',
Count(pp.ProductID) AS count_products
FROM Purchasing.Vendor pv
LEFT JOIN Purchasing.ProductVendor ppv
ON pv.BusinessEntityID = ppv.BusinessEntityID
LEFT JOIN Production.Product pp
ON pp.ProductID = ppv.ProductID
GROUP BY pv.Name
HAVING count_products = 0;
SELECT DISTINCT pv.Name AS 'Vendors'
FROM Purchasing.Vendor pv
INNER JOIN Purchasing.ProductVendor ppv
ON pv.BusinessEntityID = ppv.BusinessEntityID
where not exists (SELECT 1 Production.Product pp Where pp.ProductID = ppv.ProductID)
Return all vendors wich donot have any product
We are maintaining a history of Content. We want to get the updated entry of each content, with create Time and update Time should be of the first entry of the Content. The query contains multiple selects and where clauses with so many left joins. The dataset is very huge, thereby query is taking more than 60 seconds to execute. Kindly help in improving the same. Query:
select * from (select * from (
SELECT c.*, initCMS.initcreatetime, initCMS.initupdatetime, user.name as partnerName, r.name as rightsName, r1.name as copyRightsName, a.name as agelimitName, ct.type as contenttypename, cat.name as categoryname, lang.name as languagename FROM ContentCMS c
left join ContentCategoryType ct on ct.id = c.contentType
left join User user on c.contentPartnerId = user.id
left join Category cat on cat.id = c.categoryId
left join Language lang on lang.id = c.languageCode
left join CopyRights r on c.rights = r.id
left join CopyRights r1 on c.copyrights = r1.id
left join Age a on c.ageLimit = a.id
left outer join (
SELECT contentId, createTime as initcreatetime, updateTime as initupdatetime from ContentCMS cms where cms.deleted='0'
) as initCMS on initCMS.contentId = c.contentId WHERE c.deleted='0' order by c.id DESC
) as temp group by contentId) as c where c.editedBy='0'
Any help would be highly appreciated. Thank you.
Just a partial eval and suggestion because your query seems non properly formed
This left join seems unuseful
FROM ContentCMS c
......
left join (
SELECT contentId
, createTime as initcreatetime
, updateTime as initupdatetime
from ContentCMS cms
where cms.deleted='0'
) as initCMS on initCMS.contentId = c.contentId
same table
the order by (without limit) in a subquery in join is unuseful because join ordered values or unordered value produce the same result
the group by contentId is strange beacuse there aren't aggregation function and the sue of group by without aggregation function is deprecated is sql
and in the most recente version for mysql is not allowed (by deafult) if you need distinct value or just a rows for each contentId you should use distinct or retrive the value in a not casual manner (the use of group by without aggregation function retrive casual value for not aggregated column .
for a partial eval your query should be refactored as
SELECT c.*
, c.initcreatetime
, c.initupdatetime
, user.name as partnerName
, r.name as rightsName
, r1.name as copyRightsName
, a.name as agelimitName
, ct.type as contenttypename
, cat.name as categoryname
, lang.name as languagename
FROM ContentCMS c
left join ContentCategoryType ct on ct.id = c.contentType
left join User user on c.contentPartnerId = user.id
left join Category cat on cat.id = c.categoryId
left join Language lang on lang.id = c.languageCode
left join CopyRights r on c.rights = r.id
left join CopyRights r1 on c.copyrights = r1.id
WHERE c.deleted='0'
) as temp
for the rest you should expiclitally select the column you effectively need add proper aggregation function for the others
Also the nested subquery just for improperly reduce the rows don't help performance ... you should also re-eval you data modelling and design.
I have a database structure with the following setup:
po: id, stockNumber, factoryId, other columns
order: id, stockNumber, factoryId, other columns
stock_number: id, stockNumber, groupId
factory: id, name, groupId
The important part here is the stock_number/factory tables. The groupId column is just an integer and if two or more rows in the table have the same value then their stock numbers/factory are considered the same. Typically this is used for different sizes of the same product.
What I'd like to do is write a query that will join "order" to "po" through the group of stock_number and factory so I can find orders with no matching po. Also the factory has to match the same way.
I have this query if I have a specific stock number/factory in mind but I'd like to update it to query the whole orders table for me:
SELECT id
FROM order
WHERE
styleNumber IN (SELECT a.stockNumber FROM stock_number a INNER JOIN stock_number b ON a.groupId = b.groupId or a.id = b.id WHERE b.stockNumber = '123')
AND factoryId IN (SELECT a.submitter_id FROM submitter a INNER JOIN submitter b ON a.groupId = b.groupId OR a.submitter_id = b.submitter_id WHERE b.SUBMITTER_ID = 'alpha');
EDIT: I came up with this query which I think might be on the right track. It only joins in the stock number so it doesn't do factory yet. Can anyone confirm if I'm going in the correct direction:
SELECT *
FROM order o
LEFT JOIN stock_number s_o ON o.stockNumber = s_o.stockNumber
LEFT JOIN stock_number s_p ON s_o.groupId = s_p.groupId
LEFT JOIN po p ON s_p.stockNumber = p.stockNumber
WHERE p.id IS NULL;
Just join all the tables.
select o.id
FROM order AS o
JOIN stock_number AS sn ON sn.stockNumber = o.stockNumber
JOIN submitter AS su ON ON o.factoryId = su.submitter_id
You could use an anti-join pattern. In this example, it looks complicated because of the two relationship tables. But a query something like this:
SELECT o.id
, o.stockNumber
, o.factoryId
FROM `order` o
LEFT
JOIN `stock_number` s
ON s.stockNumber = o.stockNumber
LEFT
JOIN `factory` f
ON f.id = o.factoryId
AND f.groupId = s.groupId
LEFT
JOIN `po` p
ON p.stockNumber = s.stockNumber
AND p.factoryId = f.id
WHERE p.id IS NULL
The anti-join pattern is easier to visualize with a simpler example. Say you had the order table (as in your example), and an order_line table, with rows related to the order table by the order_id column.
order_line: id, order_id, othercolumns
To get order along with matching order_line rows:
SELECT o.id AS order_id
, l.id AS line_id
FROM `order` o
JOIN `order_line` l
ON l.order_id = o.id
To include rows from order that don't have any matching rows in order_line, we can use an outer join. We add the LEFT keyword:
SELECT o.id AS order_id
, l.id AS line_id
FROM `order` o
LEFT
JOIN `order_line` l
ON l.order_id = o.id
That gets all rows from order, including rows that don't have a matching row in order_line. The trick now is to exclude all the rows that have a matching row. For any rows that didn't have a match, the columns from order_line will be NULL. So we can add a test in the WHERE clause, to exclude rows that had a match.
SELECT o.id AS order_id
, l.id AS line_id
FROM `order` o
LEFT
JOIN `order_line` l
ON l.order_id = o.id
WHERE l.order_id IS NULL
That gets us rows from order that don't have a matching row in order_line.
We can use this same pattern in a more complicated query. We use outer join operations, and rows from order that don't have a matching row in po will have NULL values for the columns from po.
Oke guys, the following has been bugging me all day:
I use the query below to select an overview of products and prices including the latest result-price based on field StartTime from another table (tresults). To do this I thought I would need a subselect in the join.
The problem is that the EXPLAIN function is telling me that MySQL is scanning ALL result rows (225000 rows) not using any index.
Is there some way I can speed this up? Preferably by adding a WHERE statement to have mysql look only at the rows with the corresponding pID's.
select p.pID, brandname, description, p.EAN, RetailPrice, LowestPrice, min(price), min(price)/lowestprice-1 as afwijking
from tproducts p
join (
select Max(tresults.StartTime) AS maxstarttime, tresults.pID
from tresults
-- maybe adding a where clause here?
group by tresults.pID
) p_max on (p_max.pID = p.pID)
join tresults res on (res.starttime = p_max.maxstarttime and p.pID = res.pID and res.websiteID = 1)
join tsupplierproducts sp on (sp.pID = p.pID AND supplierID = 1)
join tbrands b on (b.brandID = p.BrandID)
group by p.pID, brandname, description, p.EAN, RetailPrice, LowestPrice
Indexes are on all columns that are part of joins or where clauses.
Any help would be appreciated. Thanks!
From your SQL I assume that you are listing product based on 1 supplier (supplierID = 1) only.
Best practice is do your known filter at begin of sql to eliminate record, then use inner join to join other without filter table.
select p.pID, brandname, description, p.EAN, RetailPrice, LowestPrice, min(price), min(price)/lowestprice-1 as afwijking
from
(select p.pID, p.BrandID p.EAN, Max(t.StartTime) AS maxstarttime
FROM tproducts p INNER JOIN tresults t on supplierID=1 and p.pID=t.pID
group by tresults.pID
) p
inner join tresults res on (res.websiteID = 1 and p.pID = res.pID and res.starttime = p_max.maxstarttime)
inner join tsupplierproducts sp on (sp.pID = p.pID)
inner join tbrands b on (b.brandID = p.BrandID)
group by p.pID, brandname, description, p.EAN, RetailPrice, LowestPrice
from above code, I eliminate all supplierID != 1 from tproducts before join tresults.
let me know if the above sql help, and what is the EXPLAIN function result
:-)
I currently have the following:
Table Town:
id
name
region
Table Supplier:
id
name
town_id
The below query returns the number of suppliers for each town:
SELECT t.id, t.name, count(s.id) as NumSupplier
FROM Town t
INNER JOIN Suppliers s ON s.town_id = t.id
GROUP BY t.id, t.name
I now wish to introduce another table in to the query, Supplier_vehicles. A supplier can have many vehicles:
Table Supplier_vehicles:
id
supplier_id
vehicle_id
Now, the NumSupplier field needs to return the number of suppliers for each town that have any of the given vehicle_id (IN condition):
The following query will simply bring back the suppliers that have any of the given vehicle_id:
SELECT * FROM Supplier s, Supplier_vehicles v WHERE s.id = v.supplier_id AND v.vehicle_id IN (1, 4, 6)
I need to integrate this in to the first query so that it returns the number of suppliers that have any of the given vehicle_id.
SELECT t.id, t.name, count(s.id) as NumSupplier
FROM Town t
INNER JOIN Suppliers s ON s.town_id = t.id
WHERE s.id IN (SELECT sv.supplier_id
FROM supplier_vehicles sv
WHERE sv.vehicle_id IN (1,4,6))
GROUP BY t.id, t.name
Or you could do an INNER JOIN (as your supplier join is INNER, but this will remove towns with no suppliers with those vehicles) and change the COUNT(s.id) TO COUNT(DISTINCT s.id)
If I remember correctly, you can put your second query inside the LEFT OUTER JOIN condition.
So for example, you can do something like
...
LEFT OUTER JOIN (SELECT * FROM Suppler s, Supplier_vehicles ......) s ON s.town_id=t.id
In that way you are "integrating" or combining the two queries into one. Let me know if this works.
SELECT t.name, count(s.id) as NumSupplier
FROM Town t
LEFT OUTER JOIN Suppliers s ON t.id = s.town_id
LEFT OUTER JOIN Supplier_vehicles v ON s.id = v.supplier_id
WHERE v.vehicle_id IN (1,4,6)
GROUP BY t.name