Compare number of credits users using two different tables in MySql 8 - mysql

Question

On my MySql version 8.0.17 database I have two different tables.
In the table table_credits_used I stored for each user the number of access in shared area for current date.
mysql> SELECT
COUNT(*) tCount,
tNameUser
FROM
`table_credits_used`
WHERE
tDate = CURDATE()
GROUP BY
tDate,
tNameUser;
+--------+-----------+
| tCount | tNameUser |
+--------+-----------+
| 1 | Chenoa |
| 6 | Kimi |
| 1 | Aponi |
| 1 | Imala |
| 6 | Doba |
| 1 | Elsu |
| 1 | Jair |
| 2 | Nova |
| 1 | Aarav |
| 1 | Aarush |
| 1 | Aaryan |
| 1 | Aayansh |
| 1 | Aayush |
| 5 | Abeer |
| 1 | Adhrit |
| 2 | Adi |
| 1 | Aditya |
| 1 | Advaith |
| 6 | Advay |
| 6 | Advik |
| 6 | Agastya |
+--------+-----------+
21 rows in set (0.04 sec)
In the table table_credit_to_use is stored for each user the maximum number of access in shared area for current date.
mysql> SELECT * FROM `table_credit_to_use`;
+--------+-----------+-----+
| tCount | tNameUser | tID |
+--------+-----------+-----+
| 1 | Chenoa | 1 |
| 6 | Kimi | 2 |
| 1 | Aponi | 3 |
| 1 | Imala | 4 |
| 6 | Doba | 5 |
| 1 | Elsu | 6 |
| 1 | Jair | 7 |
| 2 | Nova | 8 |
| 1 | Aarav | 9 |
| 1 | Aarush | 10 |
| 1 | Aaryan | 11 |
| 1 | Aayansh | 12 |
| 1 | Aayush | 13 |
| 6 | Abeer | 14 |
| 1 | Adhrit | 15 |
| 2 | Adi | 16 |
| 1 | Aditya | 17 |
| 1 | Advaith | 18 |
| 6 | Advay | 19 |
| 6 | Advik | 20 |
| 6 | Agastya | 21 |
+--------+-----------+-----+
21 rows in set (0.04 sec)
I need to show users who have not consumed the maximum number of logins for the current date.
In this example, I need this output:
+--------+-----------+-----+
| tCount | tNameUser | tID |
+--------+-----------+-----+
| 5 | Abeer | 14 |
+--------+-----------+-----+
Because the user Abeer has the right to 6 total accesses, but today he has used only 5.
Any suggestion?
My table structure below on db-fiddle.com, which offers MySQL 8.0

Answer 1

Make sure you have you have ONLY_FULL_GROUP_BY disabled in MySQL.
mysql> SET GLOBAL sql_mode=(SELECT REPLACE(##sql_mode,'ONLY_FULL_GROUP_BY',''));
The following SQL should do the trick:
SELECT cu.tCount, cu.tNameUser, cu.tID FROM table_credits_used cu
INNER JOIN table_credit_to_use ctu ON (ctu.tID = cu.tID)
WHERE cu.tCount < ctu.tCount
AND cu.tDate = CURDATE()
GROUP BY cu.tDate, cu.tNameUser;
Note: The ONLY_FULL_GROUP_BY is enabled on the dbfiddle hence I couldn't try the above full query. The one that worked in db fiddle is the following without the group by clause:
SELECT cu.tCount, cu.tNameUser, cu.tID FROM table_credits_used cu
INNER JOIN table_credit_to_use ctu ON (ctu.tID = cu.tID)
WHERE cu.tCount < ctu.tCount;

Answer 2

Your sample data has no tdate
But you can join the table with the subselect
SELECT
t1.tNameUser,t1.tCount,t2.tCount current_count
FROM `table_credit_to_use` t1
INNER JOIN ( SELECT
COUNT(*) tCount,
tNameUser
FROM
`table_credits_used`
WHERE
tDate = CURDATE()
GROUP BY
tDate,
tNameUser) t2 ON t1.tNameUser = t2.tNameUser