I need a help to create a view in MySQL.
I have a table in the name of competitions like below:
+---------+-----+-----+-----+
|id| name |rank1|rank2|rank3|
+--+------+-----+-----+-----+
| 1| cmpt1| 4 | 3 | 9 |
| 2| cmpt2| 3 | 7 | 8 |
| 3| cmpt3| 4 | 1 | 2 |
| 4| cmpt4| 5 | 8 | 4 |
| 5| cmpt5| 9 | 3 | 2 |
| 6| cmpt6| 1 | 8 | 2 |
+--+------+-----+-----+-----+
the rank1,2,3 values refer to the player id who has such rank at the end of that competition.
Now I want to create a MySQL view to show each player's total medals. Rank 1, 2, and 3 received gold, silver, and bronze medal respectively.
The output of the view will be like following table:
+------+------------+-------------+-------------+
|player| gold_medals|silver_medals|bronze_medals|
+------+------------+-------------+-------------+
| 1 | 4 | 7 | 1 |
| 2 | 7 | 0 | 9 |
| 3 | 1 | 4 | 6 |
| 4 | 0 | 2 | 8 |
| 5 | 2 | 8 | 0 |
| 6 | 3 | 1 | 1 |
+------+------------+-------------+-------------+
Thanks in advance
I assumed you have another table for list players :
select p.playerid
, count(case when playerid = rank1 then 1 end) gold_medals
, count(case when playerid = rank2 then 1 end) silver_medals
, count(case when playerid = rank3 then 1 end) bronze_medals
from
players p
left join ranks r
on p.playerid in (rank1, rank2, rank3)
group by p.playerid
playerid | gold_medals | silver_medals | bronze_medals
-------: | ----------: | ------------: | ------------:
1 | 1 | 1 | 0
2 | 0 | 0 | 3
3 | 1 | 2 | 0
4 | 2 | 0 | 1
5 | 1 | 0 | 0
6 | 0 | 0 | 0
7 | 0 | 1 | 0
8 | 0 | 2 | 1
9 | 1 | 0 | 1
db<>fiddle here
You can unpivot and aggregate:
select playerid,
sum(ranking = 1) as num_gold,
sum(ranking = 2) as num_silver,
sum(ranking = 3) as num_bronze
from ((select rank1 as playerid, 1 as ranking
from ranks
) union all
(select rank2, 2 as ranking
from ranks
) union all
(select rank3, 3 as ranking
from ranks
)
) p
group by playerid;
Note: This only includes players who have a ranking. Your question doesn't include a source of all players, so that seems sufficient.
Here is a db<>fiddle.
Note that older versions of MySQL (pre-5.7 I think) don't support subqueries in the FROM clause of views. Happily that restriction is no longer in force.
Related
I am designing a database for a web project in which I am trying to collect users' emotional feelings toward art collections. A hybrid dual list on the website allows users to select three options from 12 options and then rank the selected three as 1st, 2nd, and 3rd. There are 1000 data points in this project, which means there are 1000 distinct art collections for the users to vote on, each of the art collections has the same 12 options.
collection_poll
+-------+--------------------+
| id | collection_name |
+-------+--------------------+
| 1 | collection 1 |
| 2 | collection 2 |
| 3 | collection 3 |
| 4 | collection 4 |
| 5 | collection 5 |
| ... | ... |
+-------+--------------------+
option
+--------------------+--------------------+----------------+
| collection_id | option id | Text |
+--------------------+--------------------+----------------+
| 1 | 1 | Emotion 1 |
| 1 | 2 | Emotion 2 |
| 1 | 3 | Emotion 3 |
| 1 | 4 | Emotion 4 |
| 1 | 5 | Emotion 5 |
| 1 | 6 | Emotion 6 |
| 1 | 7 | Emotion 7 |
| 1 | 8 | Emotion 8 |
| 1 | 9 | Emotion 9 |
| 1 | 10 | Emotion 10 |
| 1 | 11 | Emotion 11 |
| 1 | 12 | Emotion 12 |
| 2 | 1 | Emotion 1 |
| 2 | 2 | Emotion 2 |
| 2 | 3 | Emotion 3 |
| 2 | 4 | Emotion 4 |
| 2 | 5 | Emotion 5 |
| ... | ... | ... |
+--------------------+--------------------+----------------|
vote
+--+-------+-------------+-------------+-------------+-------------+
|id|user_id|collection_id|1st_option_id|2nd_option_id|3rd_option_id|
+--+-------+-------------+-------------+-------------+-------------+
|1 | 1 | 1 | 1 | 8 | 12 |
|2 | 2 | 1 | 3 | 1 | 8 |
|3 | 3 | 1 | 1 | 8 | 3 |
|4 | 1 | 2 | 1 | 8 | 12 |
|5 | 2 | 2 | 3 | 12 | 8 |
|6 | 3 | 2 | 1 | 3 | 12 |
+--+-------+-------------+-------------+-------------+-------------+
This table records each vote and specifies which collection the user votes and the 1st, 2nd, and 3rd options the user ranks.
How do I use MySQL to get this table?
+---------------+-----------+-----------+-----------+-----------+
| collection_id | option_id | 1st_count | 2nd_count | 3rd_count |
+---------------+-----------+-----------+-----------+-----------+
| 1 | 1 | 2 | 1 | 0 |
| 1 | 2 | 0 | 0 | 0 |
| 1 | 3 | 1 | 0 | 1 |
| 1 | 4 | 0 | 0 | 0 |
| ... ... ... ... ... |
| 1 | 8 | 0 | 2 | 1 |
| ... ... ... ... ... |
| 1 | 12 | 0 | 0 | 1 |
| 2 | 1 | 2 | 0 | 0 |
| 2 | 2 | 0 | 0 | 0 |
| 2 | 3 | 1 | 1 | 0 |
| ... ... ... ... ... |
| 2 | 8 | 0 | 1 | 1 |
| ... ... ... ... ... |
| 2 | 12 | 0 | 1 | 2 |
| ... ... ... ... ... |
+---------------+-----------+-----------+-----------+-----------+
which uses collection_poll.id and option.id to get the result from table_vote.
I have
CREATE
OR REPLACE VIEW "public"."poll_results_first_option_count" AS
SELECT
vote.collection_id,
vote.first_option_id,
count(*) AS first_count
FROM
vote
GROUP BY
vote.collection_id,
vote.first_option_id
ORDER BY
vote.collection_id,
vote.first_option_id;
to get the count of each rank but cannot put them together.
The accepted answer does not provide the correct results. You need to be LEFT JOINing, starting from your option table and including option_id in the JOIN criteria:
SELECT `o`.`collection_id`, `o`.`option_id`,
`1st_count`,
`2nd_count`,
`3rd_count`
FROM `option` `o`
LEFT JOIN ( SELECT `collection_id`, `1st_option_id` AS `option_id`, COUNT(*) AS `1st_count` FROM `vote` GROUP BY 1, 2 ) AS `t1` USING (`collection_id`, `option_id`)
LEFT JOIN ( SELECT `collection_id`, `2nd_option_id` AS `option_id`, COUNT(*) AS `2nd_count` FROM `vote` GROUP BY 1, 2 ) AS `t2` USING (`collection_id`, `option_id`)
LEFT JOIN ( SELECT `collection_id`, `3rd_option_id` AS `option_id`, COUNT(*) AS `3rd_count` FROM `vote` GROUP BY 1, 2 ) AS `t3` USING (`collection_id`, `option_id`)
ORDER BY `o`.`collection_id`, `o`.`option_id`;
In your question you state:
each of the art collections has the same 12 options
If this is the case, then there is no need to link them in your option table. Instead you can just have the twelve options (and drop collection_id column) and CROSS JOIN to collection_poll to build the full list:
SELECT `cp`.`id`, `o`.`option_id`,
`1st_count`,
`2nd_count`,
`3rd_count`
FROM `collection_poll` `cp`
CROSS JOIN `option` `o`
LEFT JOIN ( SELECT `collection_id`, `1st_option_id` AS `option_id`, COUNT(*) AS `1st_count` FROM `vote` GROUP BY 1, 2 ) AS `t1` ON `cp`.`id` = `t1`.`collection_id` AND `o`.`option_id` = `t1`.`option_id`
LEFT JOIN ( SELECT `collection_id`, `2nd_option_id` AS `option_id`, COUNT(*) AS `2nd_count` FROM `vote` GROUP BY 1, 2 ) AS `t2` ON `cp`.`id` = `t2`.`collection_id` AND `o`.`option_id` = `t2`.`option_id`
LEFT JOIN ( SELECT `collection_id`, `3rd_option_id` AS `option_id`, COUNT(*) AS `3rd_count` FROM `vote` GROUP BY 1, 2 ) AS `t3` ON `cp`.`id` = `t3`.`collection_id` AND `o`.`option_id` = `t3`.`option_id`
ORDER BY cp.id, o.option_id;
Step 1: Do the sums
SELECT collection_id,
1st_option_id,
COUNT(*) AS 1st_count
FROM votes
GROUP BY 1,2
and do similarly for the others
Step 2: Put them together (somewhat like "pivot"):
SELECT collection_id,
1st_count,
2nd_count,
3rd_count
FROM ( ... ) AS t1
JOIN ( ... ) AS t2 USING(collection_id)
JOIN ( ... ) AS t3 USING(collection_id)
ORDER BY collection_id;
where the "..." comes from step 1
From the following game table of sports matches:
+-----+-----------+---------------+----------+-------+-------+---------+---------+
| id_ | date_time | tournament_id | round_id | p1_id | p2_id | p1_stat | p2_stat |
+-----+-----------+---------------+----------+-------+-------+---------+---------+
| 1 | NULL | 1 | 4 | 1 | 3 | 2 | 3 |
| 2 | NULL | 1 | 5 | 1 | 4 | 4 | 6 |
| 3 | NULL | 1 | 9 | 1 | 5 | 6 | 9 |
| 4 | NULL | 1 | 10 | 2 | 1 | 8 | 12 |
| 5 | NULL | 2 | 4 | 1 | 2 | 10 | 15 |
| 6 | NULL | 2 | 5 | 4 | 1 | 12 | 18 |
+-----+-----------+---------------+----------+-------+-------+---------+---------+
I'm trying to get the stats for each player for their previous match. The output should look like this:
+-----+--------------+--------------+
| id_ | prev_p1_stat | prev_p2_stat |
+-----+--------------+--------------+
| 1 | NULL | NULL |
| 2 | 2 | NULL |
| 3 | 4 | NULL |
| 4 | NULL | 6 |
| 5 | 12 | 8 |
| 6 | 6 | 10 |
+-----+--------------+--------------+
However, the date_time column is quite often blank and id_ is not date sequential. The tournament table does have a date_time column which is always populated:
+-----+------------+
| id_ | date_time |
+-----+------------+
| 1 | 1997-01-01 |
| 2 | 1997-01-06 |
+-----+------------+
This means the tournament date_time can be used in conjunction with game round_id to determine the previous match.
I've found the following answers here and here but they both focus on a single table and don't have the added complexity of having to determine whether the p1_stat or the p2_stat should be selected.
I've got as far as this query:
SELECT
g.id_ AS game_id,
CASE
WHEN g.p1_id = sq_p1.p1_id THEN sq_p1.p1_stat
ELSE sq_p1.p2_stat
END AS prev_p1_stat,
CASE
WHEN g.p1_id = sq_p2.p1_id THEN sq_p2.p1_stat
ELSE sq_p2.p2_stat
END AS prev_p2_stat
FROM
test.game AS g
JOIN
test.tournament AS t ON t.id_ = g.tournament_id
LEFT OUTER JOIN
(SELECT
g.id_ AS match_id,
t.date_time AS tournament_date,
g.round_id,
g.p1_id,
g.p2_id,
g.p1_stat,
g.p2_stat
FROM
test.game AS g
JOIN test.tournament AS t ON t.id_ = g.tournament_id) AS sq_p1 ON (sq_p1.p1_id = g.p1_id
OR sq_p1.p2_id = g.p1_id)
AND (sq_p1.tournament_date = t.date_time
AND sq_p1.round_id < g.round_id
OR sq_p1.tournament_date < t.date_time)
LEFT OUTER JOIN
(SELECT
g.id_ AS match_id,
t.date_time AS tournament_date,
g.round_id,
g.p1_id,
g.p2_id,
g.p1_stat,
g.p2_stat
FROM
test.game AS g
JOIN test.tournament AS t ON t.id_ = g.tournament_id) AS sq_p2 ON (sq_p2.p1_id = g.p1_id
OR sq_p2.p2_id = g.p1_id)
AND (sq_p2.tournament_date = t.date_time
AND sq_p2.round_id < g.round_id
OR sq_p2.tournament_date < t.date_time)
ORDER BY t.date_time , g.round_id
But this isn't even close to what I'm looking for :(
I've created a dbfiddle.
One other thing that's perhaps worth mentioning... I intend to use a couple of versions of this query in a union query such that the final result (including all columns for reference) will look like this:
+-----+------------+-----------+-------------+-------------+---------------+------------------+--------------------+
| id_ | player_num | player_id | opponent_id | player_stat | opponent_stat | player_prev_stat | opponent_prev_stat |
+-----+------------+-----------+-------------+-------------+---------------+------------------+--------------------+
| 1 | 1 | 1 | 3 | 2 | 3 | NULL | NULL |
| 1 | 2 | 3 | 1 | 3 | 2 | NULL | NULL |
| 2 | 1 | 1 | 4 | 4 | 6 | 2 | NULL |
| 2 | 2 | 4 | 1 | 6 | 4 | NULL | 2 |
| 3 | 1 | 1 | 5 | 6 | 9 | 4 | NULL |
| 3 | 2 | 5 | 1 | 9 | 6 | NULL | 4 |
| 4 | 1 | 2 | 1 | 8 | 12 | NULL | 6 |
| 4 | 2 | 1 | 2 | 12 | 8 | 6 | NULL |
| 5 | 1 | 1 | 2 | 10 | 15 | 12 | 8 |
| 5 | 2 | 2 | 1 | 15 | 10 | 8 | 12 |
| 6 | 1 | 4 | 1 | 12 | 18 | 6 | 10 |
| 6 | 2 | 1 | 4 | 18 | 12 | 10 | 6 |
+-----+------------+-----------+-------------+-------------+---------------+------------------+--------------------+
Perhaps it makes more sense to do a union and then engineer the previous stats?
For some final info, the actual game table has about 1.5m rows and the actual tournament table has about 30k rows. I'm using MySQL 8.0.26.
Kudos to #Barmer for the direction - here's the query I created using LAG():
WITH union_matches AS (
SELECT
g.id_ AS match_id,
t.date_time AS tournament_date,
g.round_id AS round_id,
1 AS player_num,
g.p1_id AS player_id,
g.p2_id AS opponent_id,
g.p1_stat AS player_stat,
g.p2_stat AS opponent_stat
FROM
game AS g
JOIN
tournament AS t ON t.id_ = g.tournament_id
UNION SELECT
g.id_ AS match_id,
t.date_time AS tournament_date,
g.round_id AS round_id,
2 AS player_num,
g.p2_id AS player_id,
g.p1_id AS opponent_id,
g.p2_stat AS player_stat,
g.p1_stat AS opponent_stat
FROM
game AS g
JOIN
tournament AS t ON t.id_ = g.tournament_id
)
SELECT
match_id,
player_num,
player_id,
opponent_id,
player_stat,
opponent_stat,
LAG(player_stat, 1) OVER (PARTITION BY player_id ORDER BY tournament_date, round_id) AS wrong_player_prev_stat,
LAG(opponent_stat, 1) OVER (PARTITION BY opponent_id ORDER BY tournament_date, round_id) AS wrong_opponent_prev_stat
FROM
union_matches
ORDER BY
tournament_date, round_id, player_num
And a link to the dbfiddle.
This is my table
ID | Name | enabled1 | count1 | enabled2 | count2
1 | John | 1 | 3 | 0 | 4
2 | John | 1 | 2 | 1 | 2
3 | Mike | 0 | 7 | 0 | 3
4 | Simon | 1 | 3 | 1 | 2
5 | John | 0 | 2 | 1 | 7
6 | Mike | 0 | 2 | 0 | 1
7 | Marco | 1 | 6 | 1 | 6
8 | John | 1 | 9 | 0 | 2
9 | Marco | 0 | 4 | 0 | 1
And this is my doctrine function:
public function countCombined() : array
{
$qb = $this->createQueryBuilder('u');
$qb->select('u.name, COUNT(u.id), SUM(u.count1) as count1, SUM(u.count2) as count2');
$qb->where(
$qb->expr()->andX(
$qb->expr()->eq('u.enabled1', ':enabled'),
$qb->expr()->eq('u.enabled2', ':enabled'), // this should not be here
)
);
$qb->setParameter('enabled', '1');
$qb->groupBy('u.name');
return $qb->getQuery()->getResult();
}
the function should give me an array of grouped names with sum of count1 if enabled1 is active, the same is for count2 and enabled2. But my idea is if it is possiable to make it in one function or do i need to make another one?
it should give me something like this back:
Name | count1 | count2 | NamesCounted
John | 14 | 8 | 4
Mike | 0 | 0 | 2
Simon | 3 | 2 | 1
Marco | 6 | 6 | 2
counts all of the grouped named, and counts1 when enabled1 is active, counts2 if enabled2 is active.
Thank you.
Here is what you are looking for :
select
Name,
sum(case when enabled1=1 then count1 end) as count1,
sum(case when enabled2=1 then count2 end) as count2,
count(id) as NamesCounted
from myTable
group by Name
DEMO HERE
I currently have the following simplified tables in my database. The points table contains rows of points awarded to each user for every bid form they have voted in.
I would like to add a column to this table that for each row, it shows the AVERAGE of the previous TWO points awarded to THAT user.
Users
+----+----------------------+
| id | name |
+----+----------------------+
| 1 | Flossie Schamberger |
| 2 | Lawson Graham |
| 3 | Hadley Reilly |
+----+----------------------+
Bid Forms
+----+-----------------+
| id | name |
+----+-----------------+
| 1 | Summer 2017 |
| 2 | Winter 2017 |
| 3 | Summer 2018 |
| 4 | Winter 2019 |
| 5 | Summer 2019 |
+----+-----------------+
Points
+-----+---------+--------------------+------------+------------+
| id | user_id | leave_bid_forms_id | bid_points | date |
+-----+---------+--------------------+------------+------------+
| 1 | 1 | 1 | 6 | 2016-06-19 |
| 2 | 2 | 1 | 8 | 2016-06-19 |
| 3 | 3 | 1 | 10 | 2016-06-19 |
| 4 | 1 | 2 | 4 | 2016-12-18 |
| 5 | 2 | 2 | 8 | 2016-12-18 |
| 6 | 3 | 2 | 4 | 2016-12-18 |
| 7 | 1 | 3 | 10 | 2017-06-18 |
| 8 | 2 | 3 | 12 | 2017-06-18 |
| 9 | 3 | 3 | 4 | 2017-06-18 |
| 10 | 1 | 4 | 4 | 2017-12-17 |
| 11 | 2 | 4 | 4 | 2017-12-17 |
| 12 | 3 | 4 | 2 | 2017-12-17 |
| 13 | 1 | 5 | 16 | 2018-06-17 |
| 14 | 2 | 5 | 12 | 2018-06-17 |
| 15 | 3 | 5 | 10 | 2018-06-17 |
+-----+---------+--------------------+------------+------------+
For each row in the points table I would like an average_points column to be calculated like follows.
The average point column is the average of that users PREVIOUS 2 points. So for the first entry in the table for each user, the average is obviously 0 because there were no previous points awarded to them.
The previous 2 points for each user should be determined using the date column.
The table below is what I would like to have as the final output.
For clarity, to the side of the table, I have added the calculation and numbers used to arrive at the value in the averaged_points column.
+-----+---------+--------------------+------------+-----------------+
| id | user_id | leave_bid_forms_id | date | averaged_points |
+-----+---------+--------------------+------------+-----------------+
| 1 | 1 | 1 | 2016-06-19 | 0 | ( 0 + 0 ) / 2
| 2 | 2 | 1 | 2016-06-19 | 0 | ( 0 + 0 ) / 2
| 3 | 3 | 1 | 2016-06-19 | 0 | ( 0 + 0 ) / 2
| 4 | 1 | 2 | 2016-12-18 | 3 | ( 6 + 0 ) / 2
| 5 | 2 | 2 | 2016-12-18 | 4 | ( 8 + 0 ) / 2
| 6 | 3 | 2 | 2016-12-18 | 5 | ( 10 + 0) / 2
| 7 | 1 | 3 | 2017-06-18 | 5 | ( 4 + 6 ) / 2
| 8 | 2 | 3 | 2017-06-18 | 8 | ( 8 + 8 ) / 2
| 9 | 3 | 3 | 2017-06-18 | 7 | ( 4 + 10) / 2
| 10 | 1 | 4 | 2017-12-17 | 7 | ( 10 + 4) / 2
| 11 | 2 | 4 | 2017-12-17 | 10 | ( 12 + 8) / 2
| 12 | 3 | 4 | 2017-12-17 | 4 | ( 4 + 4 ) / 2
| 13 | 1 | 5 | 2018-06-17 | 7 | ( 4 + 10) / 2
| 14 | 2 | 5 | 2018-06-17 | 8 | ( 4 + 12) / 2
| 15 | 3 | 5 | 2018-06-17 | 3 | ( 2 + 4 ) / 2
+-----+---------+--------------------+------------+-----------------+
I've been trying to use subqueries to solve this issue as AVG doesn't seem to be affected by any LIMIT clause I have.
So far I have come up with
select id, user_id, leave_bid_forms_id, `date`,
(
SELECT
AVG(bid_points)
FROM (
Select `bid_points`
FROM points as p2
ORDER BY p2.date DESC
Limit 2
) as thing
) AS average_points
from points as p1
This is in this sqlfiddle but to be honest I'm out of my depth here.
Am I on the right path? Wondering if someone would be able to show me where I need to tweak things please!
Thanks.
EDIT
Using the the answer below as a basis I was able to tweak the sql to work with the tables provided in the original sqlfiddle.
I have added that to this sqlfiddle to show it working
The corrected sql to match the code above is
select p.*,
IFNULL(( (coalesce(points_1, 0) + coalesce(points_2, 0)) /
( (points_1 is not null) + (points_2 is not null) )
),0) as prev_2_avg
from (select p.*,
(select p2.bid_points
from points p2
where p2.user_id = p.user_id and
p2.date < p.date
order by p2.date desc
limit 1
) as points_1,
(select p2.bid_points
from points p2
where p2.user_id = p.user_id and
p2.date < p.date
order by p2.date desc
limit 1, 1
) as points_2
from points as p
) p;
Although I am about to ask another question about the best way to make this dynamic with the number of previous poingt that need to be averaged.
You can use window functions, which were introduced in MySQL 8.
select p.*,
avg(points) over (partition by user_id
order by date
rows between 2 preceding and 1 preceding
) as prev_2_avg
from p;
In earlier versions, this is a real pain, because MySQL does not support nested correlation clauses. One method is with a separate column for each one:
select p.*,
( (coalesce(points_1, 0) + coalesce(points_2, 0)) /
( (points_1 is not null) + (points_2 is not null) )
) as prev_2_avg
from (select p.*,
(select p2.points
from points p2
where p2.user_id = p.user_id and
p2.date < p.date
order by p2.date desc
limit 1
) as points_1,
(select p2.points
from points p2
where p2.user_id = p.user_id and
p2.date < p.date
order by p2.date desc
limit 1, 1
) as points_2
from p
) p;
I'm building a website for our ball team for the fun of it and keeping track of stats using PHP and SQL for the database. I've learned both by reading the manuals and through forums. I'm working on building a query that will display the current longest hitting streak. I stumbled across a page about detecting runs and streaks and am trying to work with that. I'm really new to all this stuff, so maybe I've structured my tables incorrectly.
Table "games"
+--------+------------+------+
| GameID | Date | Time |
+--------+------------+------+
| 1 | 2015/08/19 | 6:30 |
| 2 | 2015/08/20 | 6:30 |
| 3 | 2015/08/22 | 6:30 |
| 4 | 2015/08/24 | 8:00 |
| 5 | 2015/08/24 | 6:30 |
| 6 | 2015/07/15 | 8:00 |
+--------+------------+------+
Table "player"
+--------+----+---+
| GameID | AB | H |
+--------+----+---+
| 1 | 3 | 1 |
| 2 | 4 | 2 |
| 3 | 2 | 0 |
| 4 | 3 | 0 |
| 5 | 2 | 1 |
| 6 | 3 | 0 |
+--------+----+---+
Code
SELECT games.GameID, GR.H,
(SELECT COUNT(*)
FROM player G
WHERE (CASE WHEN G.H > 0 THEN 1 ELSE 0 END) <> (CASE WHEN GR.H > 0 THEN 1 ELSE 0 END)
AND G.GameID <= GR.GameID) as RunGroup
FROM player GR
INNER JOIN games
ON GR.gameID = games.GameID
ORDER BY Date ASC, Time ASC
Basically in order to correctly get the hit streak right, I need to reorder the GameIDs on the "player" table based on the Date (ASC) and Time (ASC) on the "games" table before executing the RunGroup part of the code. Obviously by adding the ORDER BY, everything gets sorted only after the RunGroup has finished querying and results in incorrect data. I've been stuck here for a few days and now need some help.
The Result I currently get is:
+--------+---+----------+
| GameID | H | RunGroup |
+--------+---+----------+
| 6 | 0 | 3 |
| 1 | 1 | 0 |
| 2 | 2 | 0 |
| 3 | 0 | 2 |
| 5 | 1 | 2 |
| 4 | 0 | 2 |
+--------+---+----------+
This is what I'm trying to achieve:
+--------+---+----------+
| GameID | H | RunGroup |
+--------+---+----------+
| 6 | 0 | 0 |
| 1 | 1 | 1 |
| 2 | 2 | 1 |
| 3 | 0 | 2 |
| 5 | 1 | 2 |
| 4 | 0 | 3 |
+--------+---+----------+
Thanks
Consider the following:
DROP TABLE IF EXISTS games;
CREATE TABLE games
(game_id INT NOT NULL AUTO_INCREMENT PRIMARY KEY
,date_played DATETIME NOT NULL
);
INSERT INTO games VALUES
(1,'2015/08/19 18:30:00'),
(2,'2015/08/20 18:30:00'),
(3,'2015/08/22 18:30:00'),
(4,'2015/08/24 20:00:00'),
(5,'2015/08/24 18:30:00'),
(6,'2015/07/15 20:00:00');
DROP TABLE IF EXISTS stats;
CREATE TABLE stats
(player_id INT NOT NULL
,game_id INT NOT NULL
,at_bat INT NOT NULL
,hits INT NOT NULL
,PRIMARY KEY(player_id,game_id)
);
INSERT INTO stats VALUES
(1,1,3,1),
(1,2,4,2),
(1,3,2,0),
(1,4,3,0),
(1,5,2,1),
(1,6,3,0),
(2,1,2,1),
(2,2,3,2),
(2,3,3,0),
(2,4,3,1),
(2,5,2,1),
(2,6,3,0);
SELECT x.*
, SUM(y.at_bat) runningAB
, SUM(y.hits) runningH
, SUM(y.hits)/SUM(y.at_bat) BA
FROM
(
SELECT s.*, g.date_played FROM stats s JOIN games g ON g.game_id = s.game_id
) x
JOIN
(
SELECT s.*, g.date_played FROM stats s JOIN games g ON g.game_id = s.game_id
) y
ON y.player_id = x.player_id
AND y.date_played <= x.date_played
GROUP
BY x.player_id
, x.date_played;
+-----------+---------+--------+------+---------------------+-----------+----------+--------+
| player_id | game_id | at_bat | hits | date_played | runningAB | runningH | BA |
+-----------+---------+--------+------+---------------------+-----------+----------+--------+
| 1 | 6 | 3 | 0 | 2015-07-15 20:00:00 | 3 | 0 | 0.0000 |
| 1 | 1 | 3 | 1 | 2015-08-19 18:30:00 | 6 | 1 | 0.1667 |
| 1 | 2 | 4 | 2 | 2015-08-20 18:30:00 | 10 | 3 | 0.3000 |
| 1 | 3 | 2 | 0 | 2015-08-22 18:30:00 | 12 | 3 | 0.2500 |
| 1 | 5 | 2 | 1 | 2015-08-24 18:30:00 | 14 | 4 | 0.2857 |
| 1 | 4 | 3 | 0 | 2015-08-24 20:00:00 | 17 | 4 | 0.2353 |
| 2 | 6 | 3 | 0 | 2015-07-15 20:00:00 | 3 | 0 | 0.0000 |
| 2 | 1 | 2 | 1 | 2015-08-19 18:30:00 | 5 | 1 | 0.2000 |
| 2 | 2 | 3 | 2 | 2015-08-20 18:30:00 | 8 | 3 | 0.3750 |
| 2 | 3 | 3 | 0 | 2015-08-22 18:30:00 | 11 | 3 | 0.2727 |
| 2 | 5 | 2 | 1 | 2015-08-24 18:30:00 | 13 | 4 | 0.3077 |
| 2 | 4 | 3 | 1 | 2015-08-24 20:00:00 | 16 | 5 | 0.3125 |
+-----------+---------+--------+------+---------------------+-----------+----------+--------+
I rebuilt my database to have only one table to contain the stats from all players. From there i was able to use this query to find my longest current hitting streak for a certain player.
SELECT *
FROM (SELECT (CASE WHEN h > 0 THEN 1 ELSE 0 END) As H, MIN(date_played) as StartDate,
MAX(date_played) as EndDate, COUNT(*) as Games
FROM (SELECT date_played, (CASE WHEN h > 0 THEN 1 ELSE 0 END) as H, (SELECT COUNT(*)
FROM stats G WHERE ((CASE WHEN G.h > 0 THEN 1 ELSE 0 END) <> (CASE WHEN GR.h > 0 THEN 1 ELSE 0 END))
AND G.date_played <= GR.date_played AND player_id = 13) as RunGroup
FROM stats GR
WHERE player_id = 13) A
GROUP BY H, RunGroup
ORDER BY Min(date_played)) A
WHERE H = 1
ORDER BY Games DESC
LIMIT 1