Hi I am trying to retrieve this data, there are 2 nested dictionaries within it :
{
"metadata": {
"stations": [
{
"id": "S108",
"device_id": "S108",
"name": "Kuala Lumpur",
"location": {
"latitude": 3.1390,
"longitude": 101.6869
}
},
{
"id": "S118",
"device_id": "S118",
"name": "Bukit Bintang",
"location": {
"latitude":3.1468,
"longitude": 101.7113
}
}
],
"reading_type": "DBT 1M F",
"reading_unit": "deg C"
},
"items": [
{
"timestamp": "2021-06-20T15:05:00+08:00",
"readings": [
{
"station_id": "S108",
"value": 32.6
},
{
"station_id": "S118",
"value": 30.3
}
]
}
]
I wanted to get the result like this :
Result
I have tried a few ways :
data = airtemp.json()
df = pd.json_normalize(data,record_path=['metadata', 'stations'])
df
data = airtemp.json()
df1 = pd.json_normalize(data,record_path=['items','readings'])
df1
Is there a way that I can use json_norminalize to form one table with station_id, name, latitude, longtitude, timestamp and value without breaking into 2 tables ?
Many thanks!
You can merge the two dataframes you created:
import pandas as pd
data = {
"metadata": {
"stations": [
{
"id": "S108",
"device_id": "S108",
"name": "Kuala Lumpur",
"location": {
"latitude": 3.1390,
"longitude": 101.6869
}
},
{
"id": "S118",
"device_id": "S118",
"name": "Bukit Bintang",
"location": {
"latitude": 3.1468,
"longitude": 101.7113
}
}
],
"reading_type": "DBT 1M F",
"reading_unit": "deg C"
},
"items": [
{
"timestamp": "2021-06-20T15:05:00+08:00",
"readings": [
{
"station_id": "S108",
"value": 32.6
},
{
"station_id": "S118",
"value": 30.3
}
]
}
]
}
stations = pd.json_normalize(data, record_path=['metadata', 'stations'])
readings = pd.json_normalize(data, record_path=['items', 'readings'])
result = stations.merge(readings, left_on='id', right_on='station_id')
with pd.option_context('display.max_rows', None, 'display.max_columns', None):
print(result)
Outputs:
id device_id name location.latitude location.longitude \
0 S108 S108 Kuala Lumpur 3.1390 101.6869
1 S118 S118 Bukit Bintang 3.1468 101.7113
station_id value
0 S108 32.6
1 S118 30.3
There is only one timestamp in the data you provided so you will have to fetch that separately.
Related
I have the following data frame, df1:
A B C
123 B1 C1
456 B2 C2
And data frame df2:
A
[
{
"id": "123",
"details": {
"id": "123",
"color": null,
"param_1": {
"name": "mike"
},
"location": "US",
"items": [
{
"item_1": "#227858",
"offer_id": null,
"item_details": {
"detials_1": [{ "notes": "other:", "quantity": 1 }]
}
}
],
"version": 1,
}
}
]
[
{
"id": "456",
"details": {
"id": "456",
"color": null,
"param_1": {
"name": "james"
},
"location": "KR",
"items": [
{
"item_1": "#2221",
"offer_id": null,
"item_details": {
"detials_1": [{ "notes": "other", "quantity": 1 }]
}
}
],
"version": 2,
}
}
]
I want to find all values in df1[A] inside the JSON found inside df2[A] under the first instance of the id parameter. Once found, I want to replace the NULL values inside the color parameter with the df1[B] and offer_id with df1[C].
The output should create a new column with the appended values:
df2[B]:
[
{
"id": "123",
"details": {
"id": "123",
"color": B1,
"param_1": {
"name": "mike"
},
"location": "US",
"items": [
{
"item_1": "#227858",
"offer_id": C1,
"item_details": {
"detials_1": [{ "notes": "other:", "quantity": 1 }]
}
}
],
"version": 1,
}
}
]
[
{
"id": "456",
"details": {
"id": "456",
"color": B2,
"param_1": {
"name": "james"
},
"location": "KR",
"items": [
{
"item_1": "#2221",
"offer_id": C2,
"item_details": {
"detials_1": [{ "notes": "other", "quantity": 1 }]
}
}
],
"version": 2,
}
}
]
I just started researching how to approach this, but I need guidance on the most efficient way. Any insight would be greatly appreciated.
using couchbase 5
I need to build a query string from this object
[
{
"_id": 190,
"querystring": [
{
"name": "p1",
"value": "val1"
},
{
"name": "p2",
"value": "val2"
}
]
}
]
the expected output should be
p1=val1&p2=val2
can anyone help here?
after few attempts I think I got closer to the solution I need.
[
{
"_id": 190,
"res": [
"company_id=$PREFIJO&",
"user_country=$COUNTRY&",
"offer_unique_code=$PIXEL&",
"pub_id=$PUBID&"
]
}
]
now, how can I convert "res" to a concatenated string of all the array elements?
WITH obj AS ({ "_id": 190, "querystring": [ { "name": "p1", "value": "val1" }, { "name": "p2", "value": "val2" } ] })
SELECT obj._id, CONCAT2("&", ARRAY CONCAT2("=",v.name,v.`value`) FOR v IN obj.querystring END) AS res;
Array of objects
WITH objs AS ([{ "_id": 190, "querystring": [ { "name": "p1", "value": "val1" }, { "name": "p2", "value": "val2" } ] },
{ "_id": 191, "querystring": [ { "name": "p3", "value": "val1" }, { "name": "p4", "value": "val2" } ] }
])
SELECT obj._id, CONCAT2("&", ARRAY CONCAT2("=",v.name,v.`value`) FOR v IN obj.querystring END) AS res FROM objs AS obj ;
Older version where CONCAT2() not available, get array of strings (name=val) and do in application or use the following technique. Assume your name/val doesn't have any replace characters.
WITH objs AS ([{ "_id": 190, "querystring": [ { "name": "p1", "value": "val1" }, { "name": "p2", "value": "val2" } ] },
{ "_id": 191, "querystring": [ { "name": "p3", "value": "val1" }, { "name": "p4", "value": "val2" } ] }
])
SELECT obj._id, replace(replace(replace(encode_json(ARRAY CONCAT(v.name,"=",v.`value`) FOR v IN obj.querystring END),"\",\"","&"),"[\"",""),"\"]","") AS res FROM objs AS obj ;
If single document then have ARRAY of objects then use UNNEST
If there is number , convert to string using TO_STR() before CONCAT operation
https://docs.couchbase.com/server/current/n1ql/n1ql-language-reference/stringfun.html#fn-str-concat2
In the following JSON, I want to extract a list of all the nested JSON objects (nested dictionaries) which have the same value for the account_id key.
data =
[
{
"index": 1,
"timestamp": 1637165214.7020836,
"transactions": []
},
{
"index": 2,
"timestamp": 1489565214.7018296,
"transactions": [
{
"account_id": "12",
"device_id": "42",
}
]
},
{
"index": 3,
"timestamp": 1644585214.7012236,
"transactions": [
{
"account_id": "13",
"device_id": "43",
}
]
},
{
"index": 4,
"timestamp": 1644752214.7012756,
"transactions": [
{
"account_id": "13",
"device_id": "44",
}
]
}
]
For the above example, I expect to get the following:
[
{
"index": 3,
"timestamp": 1644585214.7012236,
"transactions": [
{
"account_id": "13",
"device_id": "43",
}
]
},
{
"index": 4,
"timestamp": 1644752214.7012756,
"transactions": [
{
"account_id": "13",
"device_id": "44",
}
]
}
]
Tried iterating over each dictionary but failed to get the desired outcome:
l = []
for entry in data:
l = l + entry['transactions']
print(transaction['ticket_id' for transaction in l if 'ticket_id' in transaction]) # which only lists all the ticket id values
Surely there must be an 'easy' way, perhaps via the json module?
H
for d in data:
if not len(d['transactions']):
continue
acc_id=d['transactions'][0]['account_id']
if acc_id in group_by_id:
group_by_id[acc_id].append(d)
else:
group_by_id[acc_id]=[d]
print(group_by_id)
this would group every entry according to their account_id. Rest you can process according to the use case
I have a single table in database like database table. I want to search a child from database and return a hierarchical JSON to a front end in order to create a tree. How can I do that in FLASK.
My expected JSON for mat should be like expected JSON
Since you have tagged your question with flask, this post assumes you are using Python as well. To format your database values in JSON string, you can query the db and then use recursion:
import sqlite3, collections
d = list(sqlite3.connect('file.db').cursor().execute("select * from values"))
def get_tree(vals):
_d = collections.defaultdict(list)
for a, *b in vals:
_d[a].append(b)
return [{'name':a, **({} if not (c:=list(filter(None, b))) else {'children':get_tree(b)})} for a, b in _d.items()]
import json
print(json.dumps(get_tree(d), indent=4))
Output:
[
{
"name": "AA",
"children": [
{
"name": "BB",
"children": [
{
"name": "EE",
"children": [
{
"name": "JJ",
"children": [
{
"name": "EEV"
},
{
"name": "FFW"
}
]
},
{
"name": "KK",
"children": [
{
"name": "HHX"
}
]
}
]
}
]
},
{
"name": "CC",
"children": [
{
"name": "FF",
"children": [
{
"name": "LL",
"children": [
{
"name": "QQY"
}
]
},
{
"name": "MM",
"children": [
{
"name": "RRV"
}
]
}
]
},
{
"name": "GG",
"children": [
{
"name": "NN",
"children": [
{
"name": "SSW"
}
]
}
]
}
]
},
{
"name": "DD",
"children": [
{
"name": "HH",
"children": [
{
"name": "OO",
"children": [
{
"name": "TTZ"
}
]
}
]
},
{
"name": "II",
"children": [
{
"name": "PP",
"children": [
{
"name": "UUW"
}
]
}
]
}
]
}
]
}
]
I'm totally new to python. I want to merge two JSON files who have the same objects but different keys.
Here is a basic example of the result I would love to get :
JSON1 :
{
"json1" : {
"1" : {
"id": 1,
"name": "first_artist",
"imageUrl": "https://1.jpg",
"genre": "Rap "
},
"2" : {
"id": 2,
"name": "second_artist",
"imageUrl": "https://2.jpg",
"genre": "Hip-Hop"
}
}
}
JSON2:
{
"json2" : {
"1" : {
"date": 17/07/19,
"venue": "venue1"
},
"2" : {
"date": 19/07/19,
"venue": "venue2"
}
}
}
Expected JSON:
{
"expected_json" : {
"1" : {
"id": 1,
"name": "first_artist",
"imageUrl": "https://1.jpg",
"genre": "Rap "
"date": 17/07/19,
"venue": "venue1"
},
"2" : {
"id": 2,
"name": "second_artist",
"imageUrl": "https://2.jpg",
"genre": "Hip-Hop"
"date": 19/07/19,
"venue": "venue2"
}
}
}
Can someone give tips and direction to make this possible ? Thanks
You can simplify your input to:
A.json:
{
"1" : {
"id": 1,
"name": "first_artist",
"imageUrl": "https://1.jpg",
"genre": "Rap "
},
"2" : {
"id": 2,
"name": "second_artist",
"imageUrl": "https://2.jpg",
"genre": "Hip-Hop"
}
}
B.json:
{
"1" : {
"date": "17/07/19",
"venue": "venue1"
},
"2" : {
"date": "19/07/19",
"venue": "venue2"
}
}
and you have to change 19/07/19 to "19/07/19" for it to be valid json.
Now you can use the json module:
import json
#from pprint import pprint
# load json from files
with open('A.json') as A_file:
A = json.load(A_file) # returns a dict()
#print('A:')
#pprint(A)
with open('B.json') as B_file:
B = json.load(B_file)
#print('\nB:')
#pprint(A)
# get a list of unique keys -> {'1', '2'}
keys = set()
keys.update(A.keys())
keys.update(B.keys())
#print(f'\nkeys: {keys}')
# for each key merge values from dicts A and B
result = {}
for key in keys:
#print(f'\n{key}:')
merge = {}
if key in A:
merge.update(A[key])
if key in B:
merge.update(B[key])
#pprint(merge)
result[key] = merge
#print('\nresult:')
#pprint(result)
# write the result to expected.json
with open('expected.json', 'w+') as expected_file:
expected_file.write(json.dumps(result, sort_keys=True, indent='\t'))
This writes:
expected.json:
{
"1": {
"date": "17/07/19",
"genre": "Rap ",
"id": 1,
"imageUrl": "https://1.jpg",
"name": "first_artist",
"venue": "venue1"
},
"2": {
"date": "19/07/19",
"genre": "Hip-Hop",
"id": 2,
"imageUrl": "https://2.jpg",
"name": "second_artist",
"venue": "venue2"
}
}