I would like to perform a left join on the following tables:
Vehicles.boats,
vehicle_details.colors
With columns
vehicles.boats.yacht
color_id
where color_id is computed from vehicle_details.colors in a calculation that involves
vehicle_details.colors.sequence
and
vehicle_details.colors.name
I assume the following would serve as my skeleton, but I am unsure of where to put the calculations that define color_id:
SELECT vehicles.boats.yacht, vehicle_details.colors.sequence
FROM vehicles.boats
LEFT JOIN vehicle_details.colors
ON vehicle.boats.colorIdentifier = color_id;
Would it be something like the following, where the calculation is used in the ON portion?
SELECT vehicles.boats.yacht, vehicle_details.colors.sequence
FROM vehicles.boats
LEFT JOIN vehicle_details.colors
ON vehicle.boats.colorIdentifier = *calculations* AS color_id;
In that format you need to do the calculation twice, once for the join condition, once for the display.
SELECT vehicles.boats.yacht, vehicle_details.colors.sequence,*calculations* AS color_id;
FROM vehicles.boats
LEFT JOIN vehicle_details.colors
ON vehicles.boats.colorIdentifier = *calculations*;
You could use a subquery and do it once, something like:
SELECT vehicles.boats.yacht, vehicle_details.colors.sequence, color_id;
FROM vehicles.boats
LEFT JOIN ( Select vehicle_details.colors, *calculations* as colour_id from vehicle_details) as Details_subquery
ON vehicles.boats.colorIdentifier = colour_id ;
Related
I'm populating a table which is fetching the ids from 2 other tables to display their information, for example, delivery has a Hamburguer and the box, but the user might register the delivery with out the box, only with the hamburguer.
When I make a INNER JOIN SELECT to get the data from the DB it will return 0 results since there is no box and I'm trying to compare the ids that don't exist. It doesn't populate the table then.
SELECT
entrega_telemovel.*,
telemovel.id_telemovel,
telemovel.nroserie,
nro_telemovel.numero_telemovel,
nro_telemovel.id_nrotelemovel,
funcionarios.id_funcionario,
funcionarios.nome
FROM entrega_telemovel
INNER JOIN telemovel
ON entrega_telemovel.telemovel = telemovel.id_telemovel
INNER JOIN nro_telemovel
ON nro_telemovel.id_nrotelemovel = entrega_telemovel.numero_telemovel
INNER JOIN funcionarios
ON funcionarios.id_funcionario = entrega_telemovel.funcionario_entrega
ORDER BY funcionarios.nome;
In this query above entrega_telemovel.telemovel=telemovel.id_telemovel the value in entrega_telemovel.telemovel is null like the example I gave above. So 0 results are returned from the query.
How can I solve this ?
You are looking for a LEFT JOIN.
INNER JOIN only combines rows, that exist in both tables. A LEFT JOIN on the other hand always produces at least one row. If on table does not have a match for it, all columns are set to NULL.
SELECT
entrega_telemovel.*,
telemovel.id_telemovel,
telemovel.nroserie,
nro_telemovel.numero_telemovel,
nro_telemovel.id_nrotelemovel,
funcionarios.id_funcionario,
funcionarios.nome
FROM entrega_telemovel
LEFT JOIN telemovel
ON entrega_telemovel.telemovel = telemovel.id_telemovel
LEFT JOIN nro_telemovel
ON nro_telemovel.id_nrotelemovel = entrega_telemovel.numero_telemovel
LEFT JOIN funcionarios
ON funcionarios.id_funcionario = entrega_telemovel.funcionario_entrega
ORDER BY funcionarios.nome;
You want to show all entrega_telemovel entries, no matter whether they have a match in entrega_telemovel or not. This is what an outer join does.
SELECT ...
FROM entrega_telemovel et
LEFT OUTER JOIN telemovel t ON et.telemovel = t.id_telemovel
...
I'm trying to create a SQL query that uses one table to count the number of blade servers our company has in each chassis and groups those, while joining it with chassis information from another table.
However, one of the chassis has no blades in it, so the name does not appear in the blade inventory table. Using an INNER JOIN creates a table that doesn't contain that blade in any capacity. A LEFT JOIN achieves the same effect, but a RIGHT JOIN gives me an extra row with a null value for the chassis name.
I'm guessing this is because the non-existence of that blade name in the first table is being given precedence over the second, but not sure how to correct that. My query, as of now, looks like this:
SELECT e.EnclosureName, e.PDUName, q.Blades, r.Serial#
FROM bladeinventory.table e JOIN
(
SELECT EnclosureName,COUNT(*) Blades
FROM bladeinventory.table
GROUP BY EnclosureName
) q ON e.EnclosureName = q.EnclosureName
LEFT JOIN chassisinventory.table r
ON e.EnclosureName = r.EnclosureName
GROUP BY e.EnclosureName, e.PDUName, q.Blades, r.Serial#
Is it possible to edit this in such a way that the name of the chassis with 0 blades is actually generated by the query?
Just pull the name from the chassisinventory table. I'll use coalesce(), just in case you switch the order of the joins (again):
SELECT COALESCE(r.EncloseName, e.EnclosureName) as EnclosureName, e.PDUName, q.Blades, r.Serial#
FROM bladeinventory.table e JOIN
(SELECT EnclosureName,COUNT(*) Blades
FROM bladeinventory.table
GROUP BY EnclosureName
) q
ON e.EnclosureName = q.EnclosureName LEFT JOIN
chassisinventory.table r
ON e.EnclosureName = r.EnclosureName
GROUP BY COALESCE(r.EncloseName, e.EnclosureName), e.PDUName, q.Blades, r.Serial#;
You can also use below code where case is being used which is much simpler and effective
SELECT e.EnclosureName, r.PDUName,
case when q.Blades IS NULL then 0
else q.Blades end Blades,
e.Serial#
FROM chassisinventory.table e
LEFT OUTER JOIN bladeinventory.table r on e.EnclosureName = r.EnclosureName
LEFT OUTER JOIN (SELECT EnclosureName,COUNT(*) Blades
FROM bladeinventory.table
GROUP BY EnclosureName
) q on e.EnclosureName = q.EnclosureName
I have a select query which selects all products from my inventory table and joins them with two other tables (tables l_products and a_products)
SELECT
i.*,
b.title,
ROUND((i.price/100*80) - l.price,2) AS margin,
l.price AS l_price,
a.price AS a_price,
ROUND((a.price/100*80) - l.price, 2) AS l_margin
FROM inventory i
LEFT JOIN products b ON i.id = b.id
LEFT JOIN a_products a ON i.id = a.id
LEFT JOIN l_products l ON i.id = l.id
WHERE
a.condition LIKE IF(i.condition = 'New', 'New%', 'Used%')
AND l.condition LIKE IF(i.condition = 'New', 'New%', 'Used%')
This select query will normally give me a table such as...
id, title, condition, margin, l_price, a_price ...
001-new ... new 10 20 10
001-used ... used 10 25 20
002....
Now I need a condition in the query which will ignore all used products that are more expensive (have a higher a_price) than their 'new' counterparts, such as in the example above you can see that 001-used has a higher a_price than 001-new.
How can I achieve this with out having to resolve to using php
FULL JOIN this query with it self on a column which has a uniquely same value for each id prefix.
You may achieve this effect by adding another field to your SELECT call which produces same unique value for 001-new and 001-used, 002-new and 002-used...
Such value generation can be done by defining your own SQL Routine to extract first 3 characters from a column.
I want to replace the subquery with a join, if possible.
SELECT `fftenant_farmer`.`person_ptr_id`, `fftenant_surveyanswer`.`text_value`
FROM `fftenant_farmer`
INNER JOIN `fftenant_person`
ON (`fftenant_farmer`.`person_ptr_id` = `fftenant_person`.`id`)
LEFT OUTER JOIN `fftenant_surveyanswer`
ON fftenant_surveyanswer.surveyquestion_id = 1
AND fftenant_surveyanswer.`surveyresult_id` IN (SELECT y.`surveyresult_id` FROM `fftenant_farmer_surveyresults` y WHERE y.farmer_id = `fftenant_farmer`.`person_ptr_id`)
I tried:
SELECT `fftenant_farmer`.`person_ptr_id`, `fftenant_surveyanswer`.`text_value`#, T5.`text_value`
FROM `fftenant_farmer`
INNER JOIN `fftenant_person`
ON (`fftenant_farmer`.`person_ptr_id` = `fftenant_person`.`id`)
LEFT OUTER JOIN `fftenant_farmer_surveyresults`
ON (`fftenant_farmer`.`person_ptr_id` = `fftenant_farmer_surveyresults`.`farmer_id`)
LEFT OUTER JOIN `fftenant_surveyanswer`
ON (`fftenant_farmer_surveyresults`.`surveyresult_id` = `fftenant_surveyanswer`.`surveyresult_id`)
AND fftenant_surveyanswer.surveyquestion_id = 1
But that gave me one record per farmer per survey result for that farmer. I only want one record per farmer as returned by the first query.
A join may be faster on most RDBMs, but the real reason I asked this question is I just can't seem to formulate a join to replace the subquery and I want to know if it's even possible.
You could use DISTINCT or GROUP BY, as mvds and Brilliand suggest, but I think it's closer to the query's design intent if you change the last join to an inner-join, but elevating its precedence:
SELECT farmer.person_ptr_id, surveyanswer.text_value
FROM fftenant_farmer AS farmer
INNER
JOIN fftenant_person AS person
ON person.id = farmer.person_ptr_id
LEFT
OUTER
JOIN
( fftenant_farmer_surveyresults AS farmer_surveyresults
INNER
JOIN fftenant_surveyanswer AS surveyanswer
ON surveyanswer.surveyresult_id = farmer_surveyresults.surveyresult_id
AND surveyanswer.surveyquestion_id = 1
)
ON farmer_surveyresults.farmer_id = farmer.person_ptr_id
Broadly speaking, this will end up giving the same results as the DISTINCT or GROUP BY approach, but in a more principled, less ad hoc way, IMHO.
Use SELECT DISTINCT or GROUP BY to remove the duplicate entries.
Changing your attempt as little as possible:
SELECT DISTINCT `fftenant_farmer`.`person_ptr_id`, `fftenant_surveyanswer`.`text_value`#, T5.`text_value`
FROM `fftenant_farmer`
INNER JOIN `fftenant_person`
ON (`fftenant_farmer`.`person_ptr_id` = `fftenant_person`.`id`)
LEFT OUTER JOIN `fftenant_farmer_surveyresults`
ON (`fftenant_farmer`.`person_ptr_id` = `fftenant_farmer_surveyresults`.`farmer_id`)
LEFT OUTER JOIN `fftenant_surveyanswer`
ON (`fftenant_farmer_surveyresults`.`surveyresult_id` = `fftenant_surveyanswer`.`surveyresult_id`)
AND fftenant_surveyanswer.surveyquestion_id = 1
the real reason I asked this question is I just can't seem to formulate a join to replace the subquery and I want to know if it's even possible
Then consider a much simpler example to begin with e.g.
SELECT *
FROM T1
WHERE id IN (SELECT id FROM T2);
This is known as a semi join and if desired may be re-written using (among other possibilities) a JOIN with a SELECT clause to a) project only from the 'outer' table, and b) return only DISTINCT rows:
SELECT DISTINCT T1.*
FROM T1
JOIN T2 USING (id);
I am trying to perform a query which groups a set of data by an attribute called type_id.
SELECT
vt.id AS voucher_type,
COALESCE(COUNT(v.id), 0) AS vouchers_remaining
FROM
vouchers v
INNER JOIN voucher_types vt
ON vt.id = v.type_id
WHERE
v.sold = 0
GROUP BY vt.id
What I want in the result is the type_id and the number of unsold products remaining for each type. This is working OK provided that there is at least one left, however if there is a zero count row, it is not returned in the result set.
How can I set up a dummy row for those types which do not have any corresponding rows to count?
Any advice would be greatly appreciated.
Thanks
You'll have to use a LEFT JOIN instead of an INNER JOIN. You start by selecting all voucher_types and then left join to find the count.
SELECT
voucher_types.id AS voucher_type,
IFNULL(vouchers_count.vouchers_remaining, 0) AS vouchers_remaining
FROM
voucher_types
LEFT JOIN
(
SELECT
v.type_id AS voucher_type,
COUNT(v.id) AS vouchers_remaining
FROM
vouchers v
WHERE
v.sold = 0
GROUP BY v.type_id
) AS vouchers_count
ON vouchers_count.voucher_type = voucher_types.id
You want an OUTER JOIN (or LEFT JOIN, same difference) instead of an INNER JOIN. That should already do the trick.
Because you're doing an INNER JOIN you automatically exclude types with no corresponding vouchers. You need a RIGHT OUTER JOIN.
Also, as far as I can remember, COUNT will always give you an integer, so there is no need for the COALESCE.
Good luck,
Alin