How to make skew not affect gradient css - html

i'm trying to apply a gradient to a skewed div but the gradient starts where the skew starts and it doesn't apply the gradient i'm looking for no matter what angle i use.
This is the gradient i'm trying to replicate
but I get a very different result...the colors are off and it's too green on the right side of mine. You can notice that on the image above, the gradient starts at the little wedge at the bottom but mine starts on the entire bottom part.
.main {
height: 80vh;
background-color: white;
}
.skew-div {
height: 100%;
width: 100%;
position: absolute;
top: 0;
background: linear-gradient(180deg, #1D2345 0%, #242766 27.88%, #294B7C 52.91%, #2E6E92 76.86%, #40CE9C 104.51%);;
transform: skewY(-12deg);
transform-origin: 0;
}
<div class="main">
<div class="skew-div">
</div>
</div>
is this possible without just placing the image as a background?

Use clip-path
.main {
height: 80vh;
background-color: white;
position:relative;
}
.skew-div {
height: 100%;
width: 100%;
position: absolute;
top: 0;
background: linear-gradient(180deg, #1D2345 0%, #242766 27.88%, #294B7C 52.91%, #2E6E92 76.86%, #40CE9C 104.51%);
clip-path: polygon(0 0, 100% 0, 100% 70%, 0 100%);
}
<div class="main">
<div class="skew-div">
</div>
</div>

You can use clip-path property
.main {
height: 80vh;
background-color: white;
}
.skew-div {
height: 100%;
width: 100%;
position: absolute;
top: 0;
background: linear-gradient(180deg, #1D2345 0%, #242766 27.88%, #294B7C 52.91%, #2E6E92 76.86%, #40CE9C 104.51%);
;
clip-path: polygon(0 0, 100% 0, 100% 75%, 0% 100%);
}
<div class="main">
<div class="skew-div">
</div>
</div>

Instead of using transform: skewY() you may use clip-path property. transform sometimes creates some sudden confusing problems. That's why you should sometimes escape using that property. Else use it using proper Browser Vendor Prefixes.
If you feel any difficulty configuring clip-path property then you may use this 3rd party website for clip-path value generation =>
https://bennettfeely.com/clippy/

Related

How to hide an element as page is scrolled?

I'm trying to hide an element as I'm scrolling up in the page. I'm using clip-path and position:fixed to try achieve this. This is what I have so far. The text is hidden as I'm scrolling as intended. Wondering if it would be possible to start clipping it from the top as I'm scrolling vs the bottom as it is working right now.
I want the element to be clipped from the top as I'm scrolling down.
One idea I had was to rotate the text 180 degrees, and then rotate the clipped element back 180 degrees but I'm not too sure if that would work/how to implement it. Since transform creates a containing block I don't know how to get the scrolling to work.
#main-container {
position: relative;
height: 100px;
width: 100vw;
}
#clip-container {
position: absolute;
height: 80px;
width: 100vw;
-webkit-clip-path: polygon(0 0, 100% 0, 100% 100%, 0 100%);
clip-path: polygon(0 0, 100% 0, 100% 100%, 0 100%);
overflow: hidden;
background-color: rgba(255, 165, 0, 0.5);
margin-top: 10px;
}
.filler-div {
background-color: blue;
width: 100vw;
height: 100px;
}
#text {
position: fixed;
}
<div class="filler-div"></div>
<div id="main-container">
<div id="clip-container">
<div id="text">
<h1>TEXT GOES HERE</h1>
</div>
</div>
</div>
<div class="filler-div"></div>
Learn any of the javascript libraries below
scrollrevealjs.org
scrollmagic.io

Parallax div sections with a slant

How would I go about create several homepage sections, all with parallax background images and a slanted edge?
This is the design I'm trying to create: http://prnt.sc/ea0avx
If it helps, I'm building within Wordpress using Avada theme as my base.
https://www.viget.com/articles/angled-edges-with-css-masks-and-transforms
The Author details how to write css such that the sections have angled borders.
You can just transform the angled divs and over lap them off the screen.
<style>
body {
margin: 0;
}
.angle {
margin: -75px;
top: 350px;
height: 400px;
background: green;
transform: rotate(-5deg);
z-index: 5;
}
.revAngle {
margin: -75px;
width: 150%;
height: 400px;
background: green;
transform: rotate(5deg);
z-index: 5;
}
.strait {
height: 500px;
background: pink;
}
</style>
<html>
<div class="strait"></div>
<div class="angle"></div>
<div class="strait"></div>
<div class="revAngle"></div>
<div class="strait"></div>
</html>
http://codepen.io/kevinlbatchelor/pen/ggJmYK
To achieve a parallax background effect use something along these lines of code.
Example:
.parallaxdiv {
/* The image used */
background-image: url("img_parallax.jpg");
/* The Full height */
height: 100%;
/* Create the parallax scrolling effect */
background-attachment: fixed;
background-position: center;
background-repeat: no-repeat;
background-size: cover;
}
I am not exactly sure what you mean by a slanted edge , but you can try to use CSS clip-paths to achieve a slanted affect.
An example:
.img {
-webkit-clip-path: polygon(0 0, 100% 0, 100% 96%, 0 100%);
clip-path: polygon(0 0, 100% 0, 100% 96%, 0 100%);
}
Please vote up if it helps !

Create a diagonal background image [closed]

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Edit the question to include desired behavior, a specific problem or error, and the shortest code necessary to reproduce the problem. This will help others answer the question.
Closed 6 years ago.
Improve this question
I want to create a diagonal background image as seen in the attached image. I can create a diagonal line using linear-gradient however as I have two different angles this didn't work.
Using Linear Gradients:
This can be done using multiple background images and positioning them accordingly. In the snippet below I've used 3 different layers - one for the top angle (a triangle which is transparent for 50% and is colored for the rest), one for the middle which is essentially nothing but a solid colored rectangle, this is created using linear gradients as it is easier to control the dimensions of an image and finally one for the bottom angle (same approach as the top one but this has a different height and so different angle.)
The output is also responsive as you can see by hovering the element in the below snippet. In the 2nd div, I've set different colors for each image so that you can see how it is formed.
div {
height: 300px;
width: 100%;
background: linear-gradient(to bottom right, transparent 50%, lightblue 51%), linear-gradient(lightblue, lightblue), linear-gradient(to top right, transparent 50%, lightblue 51%);
background-size: 100% 30px, 100% calc(100% - 130px), 100% 100px;
background-position: top left, left 30px, bottom left;
background-repeat: no-repeat;
transition: all 1s ease; /* just for demo */
}
/* just for demo */
div {
margin-bottom: 10px;
}
div:hover {
height: 400px;
}
div:nth-of-type(2) {
background: linear-gradient(to bottom right, transparent 50%, lightblue 51%), linear-gradient(lightpink, lightpink), linear-gradient(to top right, transparent 50%, lightgreen 51%);
background-size: 100% 30px, 100% calc(100% - 130px), 100% 100px;
background-position: top left, left 30px, bottom left;
background-repeat: no-repeat;
}
<div></div>
<div></div>
Using SVG: recommended
This is the approach that I generally recommend and is the best. It involves creating the shape using SVG and then placing it absolutely behind the div element.
div {
position: relative;
height: 300px;
width: 100%;
}
svg {
position: absolute;
height: 100%;
width: 100%;
}
polygon {
fill: lightblue;
}
<div>
<svg viewBox='0 0 300 100' preserveAspectRatio='none'>
<polygon points='0,10 300,0 300,100 0,75z' />
</svg>
</div>
Using Clip-path:
Another approach that can be used is to position a pseudo-element behind the main div and then set a clip-path in the required shape to this pseudo-element.
Note: This snippet will currently work only in WebKit powered browsers. Firefox would need the clip-path to be created via SVG element whereas IE doesn't support it all.
div {
position: relative;
height: 300px;
width: 100%;
}
div:before {
position: absolute;
content: '';
height: 100%;
width: 100%;
background: lightblue;
-webkit-clip-path: polygon(0% 5%, 100% 0%, 100% 100%, 0% 75%);
clip-path: polygon(0% 5%, 100% 0%, 100% 100%, 0% 75%);
}
<div></div>
CSS Perspective
You can use a CSS Perspective Transform to create the shape you want.
div {
margin-top: 25px;
width: 500px;
height: 150px;
transform: perspective( 800px ) rotateY( -25deg );
background: blue;
}
<div></div>
CSS Tricks Docs
Perspective - CSS | MDN
You can apply perspective to the parent container of the rotated div to give it 3-dimensional depth from the front of the viewport.
N.B. For the difference between transform: perspective(value) and perspective: value, see the CSS Tricks Almanac entry on perspective:
Important: Please note the perspective property doesn't affect how the element is rendered; it simply enables a 3D-space for children
elements. This is the main difference between the transform: perspective() function and the perspective property. The first
gives element depth while the latter creates a 3D-space shared by all
its transformed children.
After applying a 3-dimensional depth to the parent container using perspective, you can then apply rotateY to the div you want to rotate.
Working Example:
section {
position: relative;
width: 600px;
perspective: 800px;
transform: translateX(-60px);
}
div:nth-of-type(1) {
position: absolute;
top:30px;
left: 0;
width: 100%;
height: 100px;
background-color: rgb(235,250,255);
transform: rotateY(320deg);
}
div:nth-of-type(2) {
position: absolute;
top: 0;
left: 220px;
width: 120px;
height: 140px;
background-color: rgb(103,201,236);
box-shadow: 6px 6px 6px rgba(127,127,127,0.5);
}
div:nth-of-type(3) {
position: absolute;
top: 24px;
left: 340px;
width: 120px;
height: 140px;
background-color: rgb(255,255,255);
box-shadow: 6px 6px 6px rgba(127,127,127,0.5);
}
<section>
<div></div>
<div></div>
<div></div>
</section>

How to accomplish this shape with angled cuts at the bottom and an image background in CSS?

I have read up on various methods and played with the Clippy tool, the problem is the browser support just isn't there yet. What would be the best method for accomplishing the look of the image below with CSS? I am trying to add a shape as bottom-border as you can see in the image below right after the blue background image. Is there a way I can do this that most recent major browsers support through CSS?
What I've tried (doesn't seem to work in Chrome and others):
.element {
-webkit-clip-path: polygon(50% 0%, 100% 0, 100% 86%, 75% 100%, 0 85%, 0 0);
clip-path: polygon(50% 0%, 100% 0, 100% 86%, 75% 100%, 0 85%, 0 0);
}
The desired result would look something like:
Both dippas' answer and the demo in misterManSam's comment are good but they would work only if the page background is a solid color (which can then be used as border's color or within the gradient). They would run into problems when the page's background is either an image (or) a gradient and they should show through the cutout portion of the shape.
For such cases I would recommend using SVG instead of CSS because it is so complex to create it with CSS that it is not actually worth the effort. Though you've asked for CSS, I will detail these SVG methods here just in case you want to use them (or atleast some future readers might find it helpful).
With SVG:
With SVG we can either create a path and fill it with the image (or) use a SVG mask for creating the shape. (Note: CSS clip-path using SVG is still a no-go due to lack of support in IE.)
Below snippet uses SVG path element to create the shape and then fill it with the image.
svg {
height: 200px;
width: 100%;
}
path {
fill: url(#image);
}
/* Just for demo */
path:hover{
cursor: pointer;
}
body {
min-height: 100vh;
background-image: radial-gradient(circle, #3F9CBA 0%, #153346 100%);
}
<svg viewBox='0 0 1024 200' preserveAspectRatio='none'>
<defs>
<pattern id='image' height='200' width='1024' patternUnits='userSpaceOnUse'>
<image xlink:href='http://lorempixel.com/1024/200/nature/3' height='200' width='1024' />
</pattern>
</defs>
<path d='M0,0 1024,0 1024,150 716.8,200 0,150z' />
</svg>
The following snippet uses SVG mask. The difference between using a path with an image fill and a mask is the hover area. With a path the hover effects are restricted to the shape boundary whereas with a mask, the image is still a rectangle (or square) and so hover effects are triggered even outside.
svg {
height: 200px;
width: 100%;
}
image {
mask: url(#masker);
}
/* Just for demo */
image:hover{
cursor: pointer;
}
body {
min-height: 100vh;
background-image: radial-gradient(circle, #3F9CBA 0%, #153346 100%);
}
<svg viewBox='0 0 1024 200' preserveAspectRatio='none'>
<defs>
<mask id='masker' x='0' y='0' width='1024' height='200'>
<polygon points='0,0 1024,0 1024,200 0,200z' fill="#fff" />
<path d='M0,150 716.8,200 1024,150 1024,200 0,200z' fill="#000" />
</mask>
</defs>
<image xlink:href='http://lorempixel.com/1024/200/nature/3' height='200' width='1024' />
</svg>
With CSS:
The below option is our best bet with pure CSS but unfortunately it has poor browser support. It uses CSS linear-gradient as mask images to hide the portions that are not required. This method works only in Webkit powered browsers for now and so is a no-go.
.shape {
height: 200px;
width: 100%;
background-image: url(http://lorempixel.com/1200/200/nature/3);
-webkit-mask-image: linear-gradient(to top right, transparent 49.5%, white 50.5%), linear-gradient(to top left, transparent 49.5%, white 50.5%), linear-gradient(white, white);
mask-image: linear-gradient(to top right, transparent 49.5%, white 50.5%), linear-gradient(to top left, transparent 49.5%, white 50.5%), linear-gradient(white, white);
-webkit-mask-size: 70.5% 30%, 30% 30%, 100% 70%;
-webkit-mask-position: bottom left, bottom right, top left;
-webkit-mask-repeat: no-repeat;
}
body {
min-height: 100vh;
background-image: radial-gradient(circle, #3F9CBA 0%, #153346 100%);
}
<div class='shape'></div>
Other attempts to produce a transparent cut run into problems if the shape has to be responsive. For example, the below snippet uses very complex transformations, positioning etc to achieve this shape but it is not responsive (view in full page mode). I wouldn't have recommended this method even if the shape was responsive (due to complexities involved) but the lack of responsiveness means this is a no-go.
.shape {
position: relative;
height: 200px;
width: 100%;
overflow: hidden;
}
.shape-left,
.shape-right,
.shape img {
position: absolute;
height: 100%;
}
.shape-left {
width: 75%;
transform: skewY(5deg);
overflow: hidden;
}
.shape-left img {
top: -7%;
bottom: 0px;
width: 133.3%;
transform: skewY(-5deg);
}
.shape-left,
.shape-left img {
transform-origin: bottom right;
backface-visibility: hidden;
}
.shape-right {
right: 0%;
width: 25%;
transform: skewY(-10deg);
overflow: hidden;
}
.shape-right img {
top: -13.5%;
left: -300%;
width: 400%;
transform: skewY(10deg);
}
.shape-right {
transform-origin: bottom left;
backface-visibility: hidden;
}
/* just for demo */
.reference {
height: 200px;
width: 100%;
}
.reference img {
height: 100%;
width: 100%;
}
* {
box-sizing: border-box;
}
body {
min-height: 100vh;
background-image:radial-gradient(circle, #3F9CBA 0%, #153346 100%);
}
<div class='shape'>
<div class='shape-left'>
<img src='http://lorempixel.com/800/200/nature/3' />
</div>
<div class='shape-right'>
<img src='http://lorempixel.com/800/200/nature/3' />
</div>
</div>
<hr>
<div class='reference'>
<img src='http://lorempixel.com/800/200/nature/3' />
</div>
Note: This may have been the item that misterManSam was referring to in comments but I feel the needs are a bit different here even though both involve creating unusual borders.
you can use a background-image on a div and two shapes using it pseudo-selectors :before/:after
Something like this:
.bg {
background: url(http://lorempixel.com/1600/900) no-repeat center top;
min-height: 100px;
min-width: 200px;
position: relative
}
.bg:before {
content: "";
border-bottom: 65px solid white;
border-right: 575px solid rgba(0, 0, 0, 0);
position: absolute;
left: 0;
bottom: 0;
}
.bg:after {
content: "";
border-bottom: 65px solid white;
border-left: 200px solid rgba(0, 0, 0, 0);
position: absolute;
right: 0;
bottom: 0;
}
<div class="bg"></div>
I think the easiest way to do it is with pseudo elements on the parent div element. This is basic CSS knowledge and can be implemented very easily. The parent div needs to have the position: relative; property set and the rest is done by the ::before and ::after elements.
.background::before {
transform: rotate(10deg);
position: absolute;
}
Example
Hope this helps.

How to achieve glow element using CSS in plain div like described below?

I am trying to convert PSD into HTML using CSS.
I have a plain rectangle like this :
Now a oval shape glow element : ( As in PSD )
Because of this if you look at only rectangle , With a glow at top it looks like below :
How to achieve the same ? Any lead is appreciated :)
Using Radial Gradients:
You can sort of achieve that by placing a radial-gradient image on top of your rectangle with the solid color. The positioning and size of the gradient may need to be modified to suit your needs.
The radial-gradient that I had used is very similar to the one in your PSD image. That is is starts from a bluish color and then gradually moves to transparent. This gradient is then positioned such that its center point is at 75% width of the parent and a distance that is 25% of the parent's height above it.
div {
height: 200px;
width: 400px;
background-color: rgb(17, 45, 67);
background-image: radial-gradient(ellipse at 75% -25%, rgb(14, 102, 150) 0%, transparent 50%);
background-size: 100% 100%;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/prefixfree/1.0.7/prefixfree.min.js"></script>
<div></div>
The main thing to worry with using radial-gradient is the relatively poor browser support.
Using Box Shadow:
Below is a slightly different approach using a pseudo-element and box-shadow. The box-shadow has a very high spread radius which produces a glow like effect.
This has better browser support than radial-gradient (even as low as IE8) but box-shadow cannot take values in percentage and hence this solution wouldn't be very useful for dynamic sized containers.
div {
position: relative;
width: 1280px;
height: 480px;
background-color: rgb(17, 45, 67);
overflow: hidden;
}
div:after {
position: absolute;
content: '';
right: 150px;
top: -250px;
height: 250px;
width: 300px;
border-radius: 50%;
background: rgb(14, 102, 150);
box-shadow: 25px 25px 150px 250px rgba(14, 102, 150, 0.5);
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/prefixfree/1.0.7/prefixfree.min.js"></script>
<div></div>
The only way I can see is to use a pseudo element and put a gradient background on it. I've made this quickly to show you but it does not reproduce exactly your image :
.rectangle {
position: relative;
width: 300px;
height: 100px;
background-color: #112D43;
}
.rectangle:after {
content: "";
display: block;
position: absolute;
top: 0;
right: 0;
width: 100px;
height: 40px;
background: radial-gradient(ellipse at center, #094567 0%, rgba(0, 0, 0, 0) 50%);
}
<div class="rectangle"></div>