I have recently started working with SQL and I am trying to write a query that will display all cities that has the highest volume and listing on a yearly basis.
this query is able to handle the year 2011 alone
select city, year, month,max(volume),max(listings)
from kaydata
where year = 2011
result
city year month max(volume) max(listings)
0 Abilene 2011 2 6505000.0 746.0
sample data
city year month volume listings
0 modak 2011 1 5380000.0 701.0
1 Abilene 2011 2 6505000.0 746.0
2 ipetu 2010 3 9285000.0 784.0
2 oyog 2010 4 7085000.0 204.0
desired result
city year month max(volume) max(listings)
0 Abilene 2011 2 6505000.0 746.0
1 ipetu 2010 3 9285000.0 784.0
If I understand correctly, this would achieve what you're after:
select city,year,month,volume,maxlisting from (
select * , row_number() over (partition by year order by volume desc) rn
, max(listing) over (partition by year) maxlisting
from kaydata
) t
where rn = 1
Related
I have a table in mysql. How to write the query to find the phone name that has got highest sales(highest number of Sold_out in each year)
--------------------------------------------
Phone Sold_out Month Year
--------------------------------------------
iphone 3 Jan-15 2015
iphone 10 Feb-15 2015
samsung 4 March-15 2015
Lava 14 June-16 2016
Lenova 8 July-16 2016
Lenova 10 Sep-16 2016
Motorola 8 Jan-17 2017
Nokia 7 Jan-17 2017
Nokia 3 Feb-17 2017
--------------------------------------------
The result I need is
-----------------------------
year Phone sales
-----------------------------
2015 iphone 13
2016 lenova 18
2017 Nokia 10
-----------------------------
In the derived table the total sales are calculated at ( year,phone ) combination. Once the total sales are calculated all the top rows( rank = 1 by sales ) should be identified for each year. By using correlated sub-queries and having clause the first row is identified from each group( year ) and displayed as final output.
SELECT year,phone, sales_per_year
FROM
(
SELECT year,phone,SUM(sold_out) AS sales_per_year
FROM sales
GROUP BY year,phone
) o
GROUP BY year,phone
HAVING (
SELECT COUNT(*)
FROM
(
SELECT year,phone,SUM(sold_out) AS sales_per_year
FROM sales
GROUP BY year,phone
) i
WHERE i.year = o.year
AND i.sales_per_year > o.sales_per_year
) < 1
ORDER BY year,phone,sales_per_year DESC
Check the sql fiddle link
http://sqlfiddle.com/#!9/ff096e/14
I have two queries that give respectively the number of working unit bought, and the number of working unit consumed by a client.
I am working on a SQL Server 2014
The WUBought query returns something like this example :
Customer Year Month UnitBought
Cust1 2015 6 50
Cust2 2014 7 100
Cust1 2013 10 30
Cust3 2015 2 40
The other query returns the number that were consumed by a client :
Customer Year Month UnitConsumed
Cust1 2015 2 6
Cust1 2015 5 20
Cust2 2015 3 8
Cust1 2015 4 3
Cust3 2015 2 10
What I am basically trying to do, is a sum of what has been bought for every month, minus what has been consumed. Here is an example of what I want as a result for the first six months for Cust1 :
Customer Year Month Remaining
Cust1 2015 1 30
Cust1 2015 2 24
Cust2 2015 3 24
Cust1 2015 4 21
Cust3 2015 5 1
Cust3 2015 6 51
The query that returns the WU bought with a UNION ALL from a table that lists every month, to get each month even if there is no value :
SELECT Customer, [Year], [Month], SUM(UOBought) AS UORest
FROM WU_Bought
GROUP BY [Customer], [PurchaseDate]
UNION ALL
SELECT '' AS Customer, [Year], [Month], '' AS UORest
FROM Months
GROUP BY [Year], [Month]
Here is the query that sums every bought unit every month, with the same union statement :
SELECT Customer, [Year], [Month], SUM(TotalConsumed) * -1 AS UORest
FROM WUConsumed
GROUP BY Customer, Year, Month
UNION ALL
SELECT '' AS Customer, [Year], [Month], '' AS UORest
FROM EveryMonths
GROUP BY Year, Month
Right now I think I must adjust the first one, forcing it to keep the previous sum, but I am not sure how I can do that.
Does this work for you?
SELECT b.customer_id, b.year, b.month, SUM(b.units_bought) AS units_bought, ISNULL(c.units_consumed,0) AS units_consumed, SUM(b.units_bought) - ISNULL(c.units_consumed,0) AS units_remaining
FROM Bought b
LEFT JOIN Consumed c
ON b.customer_id = c.customer_id AND b.year = c.year AND b.month = c.month
GROUP BY b.customer_id, b.year, b.month
Ok, I got it working.
What I did was really "simple", using a SQL Server feature, available since 2012 :
ROWS UNBOUNDED PRECEDING
Here is a pretty clear article about this feature.
I created an other view grouping the results from the queries about consumed and bought units with a UNION ALL clause, called "WU_Closing_View", then used the ROWS UNBOUNDED PRECEDING within it :
SELECT Customer, Year, Month, SUM(Closing) OVER(PARTITION BY Customer ORDER BY Year, Month ROWS UNBOUNDED PRECEDING) AS Closing
FROM WU_Closing_View
GROUP BY Customer, Year, Month, Closing
UNION ALL
SELECT '' AS Customer, Year, Month, '' AS Sum_bought
FROM Months
GROUP BY Year, Month
ORDER BY Customer, Year, Month
Note that I used PARTITION BY, in order to sum by client. Because I wanted to show every month in a SSRS matrix, I added a "UNION ALL" pointing to a table that has every year and month on it for an empty client, from 2010 to 2017. But it is optional if you don't need the evolution for every month.
There may be an easier way, but that's the one I found so far.
I am trying to find a MySQL query that will display the number of occurrences of an ID value within a year.
Table:
a_id year
---- ----
1 2010
1 2011
1 2012
1 2012
1 2013
1 2014
1 2015
2 2010
2 2011
2 2013
2 2014
2 2014
2 2015
3 2010
3 2010
3 2011
Expected output:
a_id year occurrences
---- ----- -----------
1 2010 1
1 2011 1
1 2012 2
1 2013 1
1 2014 1
1 2015 1
2 2010 1
2 2011 1
2 2013 1
2 2014 2
2 2015 1
3 2010 2
3 2011 1
I'm trying with the something along the lines of following sql query, but it gives me nothing like the expected output. It's the 3rd column im struggling with.
SELECT a__id, year, count(distinct a_id) as occurrences
FROM table1
GROUP by year
ORDER by a_id
How can i create that 3rd column?
Scince you are grouping by a_id and year you of course get only 1 distinct value for group. Simply change count(distinct a_id) to count(*).
For example you get group:
1 2012
1 2012
Notice in this group distinct a_id values is 1. But you want count of all rows in group. With distinct you will get 1 as occurence in all groups.
EDIT:
Ok, I have missed that you are grouping only by year, so you should group by a_id also. The rest of the answer stays as is. So you end up with:
SELECT a__id, year, count(*) as occurrences
FROM table1
GROUP by a__id, year
SELECT a__id, year, count(*) as occurrences
FROM table1
GROUP by a__id, year
Using the following will get you what you are looking for.
SELECT a_id, year, count(*)
FROM table1
GROUP BY a_id, year
ORDER BY a_id, year
Although, in previous versions, ORDER BY may have been guaranteed by MySQL, it is deprecated now. If you want to ensure your results come back sorted, add ORDER BY. 'Future you' will thank you for it.
I am having a problem with this query:
SELECT
YEAR(passDate) as Year,
count(*) AS total_amount
FROM
`dsp_drop_pass_details`
WHERE passDate
BETWEEN '2009-01-01'
AND '2012-05-01'
AND batch='DROPOUT'
GROUP BY YEAR(passDate)
ORDER BY YEAR(passDate)
output---
Month total amount
2011 30
2012 20
But my desire out put is
Month total amount
2009 0
2010 0
2011 40
2012 20
I want 0 where count is 0
The easiest way would be to have a table Years, with all the wanted years.
create table Years(yearValue int);
insert into years values (2001), (2002)..., (2020);
then do a left join on your actual table.
SELECT y.yearValue, COALESCE(COUNT(d.id), 0) --assumning you have a field id in dsp_drop_pass_details
FROM years y
LEFT join dsp_drop_pass_details d on y.yearValue = YEAR(d.passDate)
WHERE y.yearValue between 2009 and 2012
GROUP BY y.yearValue
ORDER BY y.yearValue;
I have a database table with following columns
Id, Name, Date (FORMAT: Y-m-d H:i:s)
Now I want to retrieve data of following form
Count Year
3 2013
5 2014
It is showing total no of records generated in different years
For example If I have following data:
1 Manish 2013-10-01 23:12:12
2 Tarun 2013-10-02 23:12:12
3 Pankaj 2014-10-02 23:12:12
4 Pankaj 2015-10-02 23:12:12,
Then it will return me following data:
Count Year
2 2013
1 2014
1 2015
Is it possible?
select count(*) as cnt,
year(date) year_of_date
from your_table
group by year_of_date
select year(date) as Year,count(*) as Total
from my_table
group by year(date)