What is wrong with this bash script [duplicate] - json

Question

This question already has answers here:
Passing bash variable to jq
(10 answers)
Closed 1 year ago.
#!/bin/bash
filename='delete'
while read p; do
jq 'if .tweet | test('\"$p\"'; "i") then . |= . + {vendor: '\"$p\"'} else empty end' sfilter.json
done < $filename
I keep getting this error, when I use variable = "hello world" but not "hello"
Inshort whenever there is a space in letter it causes this error.
But while executing directly on shell there seems to be no error.
jq: error: syntax error, unexpected $end, expecting QQSTRING_TEXT or QQSTRING_INTERP_START or QQSTRING_END (Unix shell quoting issues?) at <top-level>, line 1:
if .tweet | test("sdas
jq: 1 compile error
But when I run the command on shell it works perfectly. Any ideas?
Edit:
Input delete file
sdas adssad

Answer 1

Don't generate a dynamic jq filter using string interpolation. Pass the value via the --arg option.
#!/bin/bash
filename='delete'
while IFS= read -r p; do
jq --arg p "$p" 'if .tweet | test($p; "i") then . |= . + {vendor: $p} else empty end' sfilter.json
done < "$filename"

Answer 2

pass the value of p to your jq program like this:
while read p; do
jq --arg p "$p" 'if .tweet | test($p; "i") then . |= . + {vendor: $p} else empty end' sfilter.json
done < $filename
The shell error occurs because you concatenated the string incorrectly.
Try this:
p=value
JQ_program='if .tweet | test("'"$p"'"; "i") then . |= . + {vendor: "'"$p"'"} else empty end'
echo "$JQ_program"
# result
# if .tweet | test("value"; "i") then . |= . + {vendor: "value"} else empty end