I'm trying to truncate a column that I have created in my query to display only 15 characters, however I don't know how to. In a table (yes), in a query (no).
How would I write my code to do this? Here's the code:
(SELECT CONCAT(StudLName, ',',UPPER(StudFName)) AS StudentName FROM STUDENT);
Current result:
I think this is what you want:
(SELECT LEFT(CONCAT(StudLName, ',',UPPER(StudFName)),15) AS StudentName FROM STUDENT);
Just wrap the CONCAT function in a LEFT function
An alternative to LEFT, using a cast:
SELECT CAST(CONCAT(StudLName, ',', UPPER(StudFName)) AS CHAR(15)) AS StudentName
FROM STUDENT;
Related
I m trying to get number in between "sims_7009_alaira", i want 7009.
SELECT sno,dbase, SUBSTRING_INDEX(dbase, 'sims_', -1)temp
FROM school
How should i do that in SQL
Give this a try:
select substring_index(SUBSTRING_INDEX(dbase, '_', 2),'_',-1) from school;
Check this here:
SQL Fiddle
Just use substring_index() two times:
SELECT sno, dbase, substring_index(substring_index(dbase, 'sims_', -1), '_alaira', 1) as number FROM school
Do this instead:
SELECT sno,dbase, SUBSTRING_INDEX(SUBSTRING_INDEX(dbase, "_", 2),'_',-1) temp
FROM school;
For more insight see this.
just as the question can we do something to get the length and first 3 characters of the employee name of one column
Please do not mark as answered or duplicate
i have the test tomorrow Advance SQL so I am trying to solve some imp question..
Please answer the problem
thanks again
Hi Shanu, You can use LEN() or LENGTH()(in case of oracle sql) function to get the length of a column.
SELECT LEN(column_name) FROM table_name;
And you can use SUBSTRING or SUBSTR() function go get first three characters of a column.
SUBSTRING( string, start_position, length );
SELECT SUBSTRING( column_name, 1, 3 ) FROM table_name;
To get both together use concatenation operator,
SELECT LEN(column_name)||SUBSTRING( column_name, 1, 3 ) FROM table_name;
Hope you got what you need. Any issues, feel free to ask
We can use SUBSTRING or SUBSTR() function, go get first three characters of a column.
And then try this particular query:
SELECT SUBSTRING(ename,1,3)
FROM emp;
Select len(ename) as Column_Length, left(ename,3) first_three_char from employee; ---------need to code your query. Should not use test format, will be confusing
You can also use substring function instead of left. Query will look like
Select len(ename) as Column_Length,substring(ename,1,3) first_three_char from employee;
SELECT LEN(EMPLOYEE_NAME),LEFT(EMPLOYEE_NAME,3) FROM EMPLOYEE_TABLE;
I try make search for my site. Example: have field name = city, if city is empty my query looks: SELECT * FROM TABLE WHERE CITY = ALL;
I don't know how to write: CITY = ALL correct, expression CITY is not null will be complicated because I should be remove =
Try this:
SELECT *
FROM Table
WHERE #SearchParam IS NULL OR City = #SearchParam
If his parameter #SearchParam is passed to the query with a NULL value then it will return all the data in the table, otherwise it will search for the cities with this parameter.
remove the where completely
SELECT * FROM TABLE
or
SELECT * FROM TABLE WHERE CITY = #searchstring or #searchstring is null;
If you don't care about very optimized queries, you can use a like operator compare with
City like '%#exp'
If exp is empty the query returns all Cities.
I personally do not recommend this :)
All the best
If you are getting them all, why have the WHERE clause in at all?
SELECT * FROM TABLE
Note, you should avoid using SELECT * whenever possible. As it is a waste of resources, always be explicit with your columns returned.
Maybe something like this?
SELECT * FROM TABLE WHERE (CITY = SOMETHING) OR (SOMETHING is null);
I have a table named datas and I'm executing a query like this:
SELECT linkurl AS DOWNLOADURL,
lastrevlevel AS VERSION,
code AS DESCRIPTION,
created AS RELEASEDATE,
name AS TYPE
FROM datas
WHERE id IN (SELECT child_id
FROM datas _datas
WHERE parent_id = (SELECT Max(id)
FROM datas
WHERE code = 'AN4307SW'))
It returns results like this:
DOWNLOADURL VERSION DESCRIPTION RELEASEDATE TYPE
/artifacts/download.txt 2.0 images 25/6/12 download.txt
In the Type column I am geting name of the file. I need to get the file extension of the file name in the Type column. How can I achieve this?
Examples:
TYPE
.txt
.pdf
.xls
You can use SUBSTRING_INDEX. Like this:
select linkurl as DOWNLOADURL,lastrevlevel as VERSION,
code as DESCRIPTION,created as RELEASEDATE,
SUBSTRING_INDEX(name,'.',-1) as TYPE
from datas where id in
(select child_id from datas _datas
where parent_id=( select max(id) from datas
where code = 'AN4307SW'))
EDIT
If you see the docs on this function I think this will apply well to you requirements.
Returns the substring from string str before count occurrences of the
delimiter delim. If count is positive, everything to the left of the
final delimiter (counting from the left) is returned. If count is
negative, everything to the right of the final delimiter (counting
from the right) is returned. SUBSTRING_INDEX() performs a
case-sensitive match when searching for delim.
This will also handle a case like this:
select SUBSTRING_INDEX('Test.Document.doc','.',-1);
EDIT2
If you are using oracle. Please tag the question in the correct matter next time. There is no SUBSTRING_INDEX in oracle. But what I can see you can do this quite easy:
SELECT SUBSTR('Test.Document.doc', INSTR('Test.Document.doc', '.',-1))
FROM dual;
Full query like this:
select linkurl as DOWNLOADURL,lastrevlevel as VERSION,
code as DESCRIPTION,created as RELEASEDATE,
SUBSTR(name, INSTR(name, '.',-1)) as TYPE
from datas where id in
(select child_id from datas _datas
where parent_id=( select max(id) from datas
where code = 'AN4307SW'))
Reference here
select linkurl as DOWNLOADURL,lastrevlevel as VERSION,
code as DESCRIPTION,created as RELEASEDATE,reverse(substring(reverse(name), 1,charindex('.', reverse(name))-1)) as TYPE
from datas where id in
(select child_id from datas _datas
where parent_id=( select max(id) from datas
where code = 'AN4307SW'))
think you'll need something like this
SELECT REPLACE(name,SUBSTRING(name ,0, CHARINDEX('.', name )),'')
SELECT REVERSE(SUBSTRING(REVERSE(name),1,LOCATE('.',REVERSE(name),1)));
It can be done like this
SELECT SUBSTRING_INDEX(FILE_NAME,"." ,-1) from TABLE_NAME
SELECT
SUBSTRING(file_name,(LENGTH(file_name)-LOCATE('.',REVERSE(file_name)))+2)
FROM <table name> WHERE file_id=<file_id>;
I'm trying do something like this:
SELECT * FROM table WHERE column IN (1,2,3)
but in place of 1,2,3 I want to use a column from another table that contains a comma-delimited list just like "1,2,3" above.
I have tried to do this:
SELECT
GROUP_CONCAT(a.eating_area SEPARATOR ', ')
FROM table_areas a
WHERE a.eating_area_id IN (
SELECT
o.eating_area_ids
FROM table_offers o WHERE o.rid=1
)
however this only returns the value associated with 1, and not 2 or 3. Can this be done or is there another way to do this?
Many thanks
SELECT * FROM table t
WHERE IF(FIND_IN_SET(column,(SELECT "1,2,3" FROM otherTable WHERE 1))>=1,1,0)
-- FIND_IN_SET will return the position.
I don't know if it's the best way to do it but... i think it could work.
Source: Find_in_set