This question already has answers here:
CSS3 gradient background set on body doesn't stretch but instead repeats?
(13 answers)
Closed 4 years ago.
When using linear-gradient CSS property, the background appears without stripes when using left and right as direction value. But when direction value is given as top or bottom, stripes appears in the background. Is there any way that we can remove the stripes?
Here is the code:
body {
background: linear-gradient(to top, red, yellow);
}
You are facing a complex background propagation that you can read about here. I will try to explain it with simple words.
Your body has a height equal to 0; thus the background won't be visible on it but by default it has 8px of margin which create a height of 8px on the html element.
Why not 16px of height (8px for top + 8px for bottom)?
Since the height of body is 0 we are facing a margin collpasing and both margin will collapse into only one and we have a height of 8px.
Then we have a background propagation from body to html and the linear-gradient will cover the 8px height.
Finally, the background of the html is propagated to the canvas element in order to cover the whole area which explain why the linear gradient is repeating each 8px.
body {
background: linear-gradient(to top, red, yellow);
}
It's also repeated when using left or right direction but you won't see it visually which is logical since it's the same pattern:
body {
background: linear-gradient(to right, red, yellow);
}
You can also remove the repeating and you will see it's covering only 8px
body {
background: linear-gradient(to right, red, yellow) no-repeat;
}
In order to avoid this behavior you can simply set height:100% (or min-height:100%) to the html
html {
height: 100%;
}
body {
background: linear-gradient(to top, red, yellow);
}
It will also work with no-repeat since by default a linear-gradient will cover the whole are:
html {
min-height: 100%;
}
body {
background: linear-gradient(to top, red, yellow) no-repeat;
}
That's because the calculated height of <body> is resulting from the height of its content. When smaller than viewport's height, the background will repeat itself:
body {
background: linear-gradient(to top, red, yellow);
}
To make sure it stretches itself (and the background gradient) across the entire height of the viewport, you need to give <body> a min-height equal with viewport's height (100vw):
body {
background: linear-gradient(to top, red, yellow);
min-height: 100vh;
}
body {
background: linear-gradient(to top, red, yellow);
min-height: 100vh;
margin: 0;
}
As #TemaniAfif pointed out in comments, the technical reason for the above is: there is a difference between the root element, which covers the entire viewport and inherits its background from <body>, and the <body> element, which, as specified, can be smaller than the viewport. As per W3C Recommendation:
The background of the root element becomes the background of the canvas and covers the entire canvas, anchored (for 'background-position') at the same point as it would be if it was painted only for the root element itself. The root element does not paint this background again.
Related
This question already has answers here:
CSS3 gradient background set on body doesn't stretch but instead repeats?
(13 answers)
Closed 4 years ago.
When using linear-gradient CSS property, the background appears without stripes when using left and right as direction value. But when direction value is given as top or bottom, stripes appears in the background. Is there any way that we can remove the stripes?
Here is the code:
body {
background: linear-gradient(to top, red, yellow);
}
You are facing a complex background propagation that you can read about here. I will try to explain it with simple words.
Your body has a height equal to 0; thus the background won't be visible on it but by default it has 8px of margin which create a height of 8px on the html element.
Why not 16px of height (8px for top + 8px for bottom)?
Since the height of body is 0 we are facing a margin collpasing and both margin will collapse into only one and we have a height of 8px.
Then we have a background propagation from body to html and the linear-gradient will cover the 8px height.
Finally, the background of the html is propagated to the canvas element in order to cover the whole area which explain why the linear gradient is repeating each 8px.
body {
background: linear-gradient(to top, red, yellow);
}
It's also repeated when using left or right direction but you won't see it visually which is logical since it's the same pattern:
body {
background: linear-gradient(to right, red, yellow);
}
You can also remove the repeating and you will see it's covering only 8px
body {
background: linear-gradient(to right, red, yellow) no-repeat;
}
In order to avoid this behavior you can simply set height:100% (or min-height:100%) to the html
html {
height: 100%;
}
body {
background: linear-gradient(to top, red, yellow);
}
It will also work with no-repeat since by default a linear-gradient will cover the whole are:
html {
min-height: 100%;
}
body {
background: linear-gradient(to top, red, yellow) no-repeat;
}
That's because the calculated height of <body> is resulting from the height of its content. When smaller than viewport's height, the background will repeat itself:
body {
background: linear-gradient(to top, red, yellow);
}
To make sure it stretches itself (and the background gradient) across the entire height of the viewport, you need to give <body> a min-height equal with viewport's height (100vw):
body {
background: linear-gradient(to top, red, yellow);
min-height: 100vh;
}
body {
background: linear-gradient(to top, red, yellow);
min-height: 100vh;
margin: 0;
}
As #TemaniAfif pointed out in comments, the technical reason for the above is: there is a difference between the root element, which covers the entire viewport and inherits its background from <body>, and the <body> element, which, as specified, can be smaller than the viewport. As per W3C Recommendation:
The background of the root element becomes the background of the canvas and covers the entire canvas, anchored (for 'background-position') at the same point as it would be if it was painted only for the root element itself. The root element does not paint this background again.
My background output is not coming as it should be.
I was expecting this
only the code that I used is html with external css with empty body tag
<body></body>
css code is:
body{ background: linear-gradient(to bottom right, red, blue); }
but the output came like this.
i am unable to detect any problem accept for the fact that you have written <body></boyd> instead of <body></body>
If your body has no content, it will have no height and the gradient will be shown as a small line (based on the default padding/margin on the body element) and repeated by default. You can see what's being repeated by disabling the repeat like this:
body {
background: linear-gradient(to bottom right, red, blue);
background-repeat: no-repeat;
}
To work around this, add a min-height to the body:
body {
background: linear-gradient(to bottom right, red, blue);
min-height: 100vh;
}
How can I create a CSS background consisting of an image covering the top x pixels of the body and a solid color or gradient below (also spanning behind the top bg picture if it is transparent)?
A gradient can be stacked placed on top of a solid color, so that the gradient fills the entire height of the screen. How can I change the gradient to a picture and only make it x pixels high?
background: linear-gradient(0deg, rgba(239,237,224,1) 30%, rgba(255,255,255,1) 100%) top/100% 100vh no-repeat rgba(239,237,224,1);
Use a pseudo element for the image:
body {
min-height:100vh;
margin:0;
position:relative;
background:linear-gradient(red,blue);
}
body::before {
content:"";
position:absolute;
height:100px; /* update this */
inset: 0 0 auto;
background:url(https://picsum.photos/id/1069/800/600) center/cover;
}
You can have multiple background images - with a mixture of actual images and gradient images.
The first image in the list is rendered on top of the others and so on down the list. You can set the size and positioning and repetition of each separately or together.
In this snippet the individual settings are separated out to make it clearer what is going on:
.bg {
width: 100vw;
height: 100vh;
background-image: url(https://i.stack.imgur.com/ew6J2.png), linear-gradient(to bottom, red,blue);
background-size: 30vw auto, 100% 100%;
background-position: center top, 0 0;
background-repeat: no-repeat;
}
<div class="bg"></div>
For a client I am trying to implement a background on an HTML element, which contains 2 radial gradients. One is located in the top right, one is located in the bottom left. My CSS only renders one of the radial gradients.
I have tried putting two radial gradient elements as a background:
body {
width: 100vw;
height: 100vh;
background-color: green;
background:
radial-gradient(
circle at top right,
red,
black 20%
),
radial-gradient(
circle at bottom left,
yellow,
orange 20%
);
}
Only the first radial-gradient appears, but the second one doesn't. When I switch the position of both gradients in de CSS markup, the colors change. So it appears as if only the first gradient is recognised.
I'm not sure which amount of color you want to see in the result, but my guess is you are after something like this.
body {
width: 100vw;
height: 100vh;
margin:0;
background-color: green;
background-image:
radial-gradient(
circle at top right,
red,
black 20%,
transparent 40%
),
radial-gradient(
circle at bottom left,
yellow,
orange 20%,
transparent 40%
);
}
One problem with your code was that you used the background shorthand for the background images, which resets the background color, so the green was no longer there. Use background-image instead.
Another was that both gradients covered the whole page, while you apparently want them to take up only the top right corner and bottom left corner instead. I solved this by giving them both transparent from 40%.
And I took the liberty of giving the body 0 margin, to get rid of the scrollbars.
My CSS only renders one of the radial gradients.
Simply because you are using opaque colors and by default a gradient will cover all the element so your will only see the top layer.
In addition to the answer of Mr Lister, you can adjust background-size to control the space each gradient should take:
body {
margin:0;
height: 100vh;
background:
radial-gradient(circle at top right, red, black 40%) right,
radial-gradient(circle at bottom left, yellow, orange 40%) left;
background-size:50% 100%;
background-repeat:no-repeat;
}
This looks a bit ugly but if you want to have a continuous background make sure both end color are the same:
body {
margin:0;
height: 100vh;
background:
radial-gradient(circle at top right , red, black 40%, green 60%) right,
radial-gradient(circle at bottom left, yellow, orange 40%, green 60%) left;
background-size:50.5% 100%;
background-repeat:no-repeat;
}
I am trying to make a design in Boostrap 4 (alpha 5), and making one third of the screen having a pink background color. The background color should extend all the way from the left margin of my right column and to the right margin. The result should be a bit like:
Does anybody have any recommandations of best way of doing this?
What if you use an gradient on the background for this?
See this example:
body {
background: linear-gradient(
to right,
lightgrey 0%,
lightgrey 70%,
hotpink 70%,
hotpink 100%
);
}
your code
You can use div on background with width set using vw, which is viewport width.
For example:
.background{
z-index: -1; // prevent "background" from covering anything
width: 33vw; //give background width of one third of page
height: 100%;
position: fixed; /* or absolute? I don't know what will be better for you */
right: 0; /* stick to the right side */
background-color: pink;
}