my command:
Select sobe.Id, sobe.Naziv, sobe.Opis, sobe.Kat, (Select Group_CONCAT(studenti.Ime,studenti.Prezime) ImePrezime FROM studentsoba LEFT JOIN studenti ON studentsoba.Id_Sobe=sobe.Id AND studenti.JMBAG = studentsoba.JMBAG) AS ImePrezime from Sobe
This gives me this error:
1054 - Unknown column 'sobe.Id' in 'on clause'
I see what the problem is but I cant figure out how to fix it.
I want to pass sobe.Id inside of this subquery:
(Select Group_CONCAT(studenti.Ime,studenti.Prezime) ImePrezime FROM studentsoba LEFT JOIN studenti ON studentsoba.Id_Sobe=sobe.Id AND studenti.JMBAG = studentsoba.JMBAG)
I want to check which students are in that room.
Word soba means room and JMBAG is like personal number for each student
Try moving it to a WHERE clause:
Select s.Id, sobe.Naziv, s.Opis, s.Kat,
(Select Group_CONCAT(si.Ime, si.Prezime) as ImePrezime
from studentsoba ss LEFT JOIN
studenti si
on si.JMBAG = ss.JMBAG
where ss.Id_Sobe = s.Id
) AS ImePrezime
from Sobe s;
The correlated subquery should be fine. I suppose the correlation clause cannot be in the on clause -- I normally put it in the where clause anyway.
Also note that I introduced table aliases so the query is easier to write and to read.
Related
I am trying to get a field which is calculated by a subquery. I found about 400 posts at SO that state that you can use the outer ID in a select subquery clause unless you are trying to use it in a join (what I don't).
Here's my query:
SELECT (SELECT group_concat(ct.NAME)
FROM core_tagobject cto
JOIN core_tag ct ON ct.id=cto.tag_id
AND cto.context="tags_working_on"
AND cto.object_id=u.id) AS "tag_list"
FROM auth_user u
I always get back SQL error (1054) - unknown column 'u.id' in 'on clause'.
What am I doing wrong?
Thx!
I guess you want below sql
SELECT group_concat(ct.NAME) AS `tag_list`
FROM core_tagobject cto JOIN core_tag ct ON ct.id=cto.tag_id
JOIN auth_user u ON cto.object_id=u.id
WHERE cto.context="tags_working_on"
With some data examples would be better to produce a proper solution, but could you try:
SELECT tag_list.*
FROM auth_user u
INNER JOIN (
SELECT group_concat(ct.NAME)
FROM core_tagobject cto
JOIN core_tag ct ON ct.id=cto.tag_id
AND cto.context="tags_working_on"
) AS tag_list on tag_list.object_id=u.id ;
Can you assist me with my query? I keep receiving an error that states "Error Code: 1054. Unknown column 'cdata.customerid' in 'on clause'"
If I want to attach the left join data where the customer id's match from customerdata table and order table, how can I achieve this? I must not understand at what point SQL allows data to become accessible by different parts of the query.
select
cdata.customerid,
cdata.affiliate,
cdata.firstname,
cdata.address1,
cdata.address2,
cdata.city,
cdata.state,
cdata.postalcode,
cdata.emailaddress,
cdata.active
from customerdata cdata, order a
left join
(select
a.transactiondate,
sum(a.TransactionAmount),
a.id
from order a
group by a.id)
txns on a.id = cdata.customerid
where cdata.active = "A";
In on clause you have to specify fields that belong to the tables which are taking part in join clause. So, if you are joining cdata with the txns subquery, you have to probably join on txns.id and cdata.customerid. You probably also wanted to get your sum out of your subquery, so you have to include this field in your main SELECT clause. And you probably have to specify transactiondate field in your group by clause, at least this is necessary for ORACLE DB, I am not sure if this is the case for MySQL:
select
cdata.customerid,
cdata.affiliate,
cdata.firstname,
cdata.address1,
cdata.address2,
cdata.city,
cdata.state,
cdata.postalcode,
cdata.emailaddress,
cdata.active,
txns.tsum,
txns.transactiondate
from customerdata cdata
left join
(select
a.transactiondate,
sum(a.TransactionAmount) tsum,
a.id
from order a
group by a.id, a.transactiondate) txns
on txns.id = cdata.customerid
where cdata.active = "A";
The JOIN references the table 'order' and the table 'txns', 'cdata' is not involved here, so within the context of the join cdata.customerid does not exist.
I have a select statement that uses inner joins on multiple tables, and I want to get COUNT() from one particular table, however my current statement is throwing an error:
Syntax error: unexpected 'COUNT' (count)
Helpful. I know. Gotta love MySQL's detailed and in-depth error messages.
Here is my select statement:
SELECT SE.SEId, SE.ParentME, SE.ParentSE, SE.Name, SE.Status, SE.Description,
UDC.UDCId, UDC.Code, UDC.Description,
TRM.COUNT(*)
FROM SubEquipment SE
INNER JOIN UserDefinedCode UDC ON UDC.ETId = SE.EquipmentType
INNER JOIN Terminal TRM ON TRM.SEId = SE.SEId
GROUP BY TRM.SEId
WHERE ParentME = #MEId;
What am I doing wrong? Is this possible?
You want to do the following:
SELECT SE.SEId, SE.ParentME, SE.ParentSE, SE.Name, SE.Status, SE.Description,
UDC.UDCId, UDC.Code, UDC.Description,
COUNT(DISTINCT TRM.SEID)
FROM SubEquipment SE
INNER JOIN UserDefinedCode UDC ON UDC.ETId = SE.EquipmentType
INNER JOIN Terminal TRM ON TRM.SEId = SE.SEId
WHERE ParentME = #MEId
GROUP BY 1,2,3,4,5,6,7,8,9
Because Count is an aggregate your single measures must be grouped. Plus the error you're seeing is because COUNT isn't a column in TRM. That's what it thinks you're asking for.
Try COUNT(DISTINCT [the TRM primary key field(s)]); it should count the distinct terminal "id" values, so even if the intermediate JOIN multiples the rows, you'll still get the number of terminals.
In addition to FirebladeDan's answer, (as he suggested) a subquery also cleaned this issue up:
SELECT DISTINCT SE.SEId, SE.ParentME, SE.ParentSE, SE.Name, SE.Status, SE.Description,
UDC.UDCId, UDC.Code, UDC.Description,
--Subquery to get the count
(SELECT COUNT(*) FROM Terminal WHERE TRM.SEId = SE.SEId) AS TerminalCount
FROM SubEquipment SE
INNER JOIN UserDefinedCode UDC ON UDC.ETId = SE.EquipmentType
LEFT JOIN Terminal TRM ON TRM.SEId = SE.SEId
WHERE ParentME = #MEId;
This got rid of the need for grouping the columns.
Subnote: I changed the INNER JOIN on the Terminal table to a LEFT JOIN, because if a SEId did not have any associated terminals, it would not return any information, which also called for a DISTINCT query.
I want to use subquery inside of IFNULL statement
SELECT t.col1
, IFNULL(t.col2, (SELECT an.col_11
FROM another_table an
WHERE an.col1 = t.col5)) as alias_name
, t.col3
FROM table t;
In IFNULL statement second expression should be subquery.
Please give me proper syntax
My actual query is
SELECT u.username, up.gender, d.name, desg.name,
IFNULL(up.creative_lead_id,
(SELECT au.username FROM auth_user au
WHERE au.id=up.creative_lead_id)) as creative_lead, up.image
FROM user_profile up, department d, designation, auth_user
WHERE up.department_id=d.id
AND up.designation_id = desg.id up.auth_uesr_id = u.id;
This query is giving syntax error because of IFNULL statement.
You can rewrite your query with join,Correlated query will execute for each row in your table and it might affect the performance
SELECT
t.col1,
IFNULL(t.col2, an.col_11) AS alias_name,
t.col3
FROM
`table` t
LEFT JOIN another_table an
ON an.col1 = t.col5
Don't use a subquery for this situation, try a query like that instead (use of jointure):
SELECT t.col1
,IFNULL(t.col2, an.col_11) AS alias_name
,t.col3
FROM your_table t
LEFT JOIN another_table an ON an.col1 = t.col5
In your full query, your using twice up.creative_lead_id for your IFNULL clause (once as first parameter and then in the subquery). That make no sense because if the first param is NULL, your subquery will return no result!
In order to show you the principe that will solve your problem, i just replaced the first param by a fictive one that i called up.creative_lead. This fictive column is the name of the creative lead stored in your table user_profile and if this value is null, i'm looking to the username of the user corresponding to creative_lead_id.
Here is the full query that'll solve your problem with the correction mentioned above:
SELECT u.username
,up.gender
,d.name
,desg.name
,IFNULL(up.creative_lead, cl.username) AS creative_lead
,up.image
FROM user_profile up
INNER JOIN department d ON d.id = up.department_id
INNER JOIN designation desg ON desg.id = up.designation_id
INNER JOIN auth_user u ON u.id = up.auth_user_id
INNER JOIN auth_user cl ON cl.id = up.creative_lead_id
Notice that i changed the syntax of your query, it's highly recommended to avoid the use of old syntax for jointures (use explicit JOIN clause instead).
Hope this will help you.
This is my mysql query
SELECT tm.MAGAZINE_ID, tm.MAGAZINE_NAME,tm.MAGAZINE_DESCRIPTION,pub.publisher_name,
tmi.COVER_PAGE_THUMB AS COVER_PAGE_VERTICAL,tmi.FROM_DATE AS ISSUE_DATE,
tm.html_flag AS HTML_EXIST,tm.CATEGORY_ID,tm.language_id,tm.is_free,tma.AppUrl,
(SELECT issue_id from tbl_magazine_issue WHERE magazine_id = 141
ORDER BY FROM_DATE DESC LIMIT 1) as temp_issue_id
FROM tbl_magazine_apps as tma
LEFT OUTER JOIN tbl_magazine_code as tmc ON tmc.Code = tma.AppsCode
LEFT OUTER JOIN `tbl_magazine` AS tm ON tmc.magazine_Id = tm.MAGAZINE_ID
JOIN `tbl_magazine_issue` AS tmi ON temp_issue_id = tmi.issue_id
LEFT OUTER JOIN mst_publisher AS pub ON tm.publisher_id=pub.publisher_id
WHERE
tmi.PUBLISH_STATUS IN(1,3)
AND tmi.`OS_SELECT` = '".$osType."'
AND tma.id IN (".$appIds.")
GROUP BY tm.MAGAZINE_ID
ORDER BY tmi.ISSUE_DATE DESC
but i got an error that
#1054 - Unknown column 'temp_issue_id' in 'on clause'
if any one know about this please help me. i am new to this
AFAIK The subquery belongs to the from part:
http://dev.mysql.com/doc/refman/5.7/en/from-clause-subqueries.html
So I would join the subquery.
Like:
SELECT a.a, b.b
FROM table1 as a
JOIN (SELECT b from table2) as b ON a.key = b.key;
As the message suggests, the column temp_issue_id is not in any of the following tables: tbl_magazine_apps, tbl_magazine, or tbl_magazine_issue. It is also not a variable in the environment.
Beyond that, it is pretty much impossible for anyone to figure out how to fix the problem without more knowledge about the data structure.
If I were to hazard a guess, based on the table names, that particular join would be:
JOIN `tbl_magazine_issue` AS tmi ON tm.magazine_id = tmi.magazine_id
because it makes sense to me that a magazine issue would be connect to a magazine. I have no idea what temp_issue_id is, though.
temp_issue_id give alias name for specifying this column i think it should be tm.issue_id
temp_issue_id is column's name as per the query. You need it to convert to table and use subsequent column in your SELECT clause.