How do I add dynamic data to a database table? - mysql

I am trying to create a database for gym workout plans. This would have each member's workout plan, which comprises multiple exercises.
My question is: given that one member might have 5 exercises, another member 3, another 6, and so on, how can I store this in the database?
My thought process has been around hardcoding a set number of exercises in the table, and give the possibility of them being null (for exemple 10 exercises, but if you only use 5 exercises, everything else can be stored with nothing). But this doesn't feel very correct.
I am using MySQL for this.

Like #Sami pointed out, you are going to work on whats called a relational database.
Below is a simple database structure that will help you get started.
Members table
Table Name: tbl_members
Table Structure:
|member_id|member_name|member_contact|
Exercise or schedule table
Table Name: tbl_member_schedule
Table Structure:
|schedule_id|member_id|assigned_date|Schedule
In the tbl_member_schedule you can store the entire schedule as a JSON structure or you can further normalize. Since this is an example I am storing the entire schedule in JSON format inside the Schedule field.
Now when you want to retrieve the schedule of a specific member (member id: 1) you can query the database as follows:
select
tbl_members.member_id, tbl_members.member_name,
tbl_member_schedule.Schedule
from
tbl_members join
tbl_member_schedule on tbl_members.member_id = tbl_member_schedule.member_id
where
tbl_members.member_id = 1;
So you JSON structure for your schedule could be
{
day1: [
{exerciseName: 'dumbbell curls', reps: '8 x 4'},
{exerciseName: 'leg extension', reps: '8 x 3'}
],
day2: [
{exerciseName: 'dumbbell curls', reps: '8 x 4'},
{exerciseName: 'leg extension', reps: '8 x 3'}
]
}

Related

writing script in scala to join two mysql tables and create one object (quill)

I have two mysql tables: Owners & Pets
Owner case class:
Owner(id: Int, name: String, age: Int)
Pet case class:
Pet(id: Int, ownerId: Int, type: String, name: String)
I want to create out of those tables list of OwnerAndPets:
case class OwnerAndPets(ownerId: Int,
name: String,
age: String,
pets: List[Pet])
(its for migrations purposes, I want to move those tables to be a collection of mongodb, which the collection documents would be OwnerAndPets objects)
I have two issues:
when I use join with quill on Owner & Pet I get list of tuples [(Owner, Pet)]
and if I have few pets for an owner I will get:
[(Owner(1, "john", 30), Pet(3,1,"dog","max")),
(Owner(1, "john", 30), Pet(4,1,"cat","snow"))]
I need it as (Owner(1, "john", 30), [Pet(3,1,"dog","max"), Pet(4,1,"cat","snow")])
how can I make it like this?
when I use join with quill on Owner & Pet I will not get owners that dont have pets and its fine cause this is what it supposed to be, but in my script in this case I would want to create object like:
OwnerAndPets(Owner(2, "mark", 30), List[])
Would appreciate any help, thanks
this is my join query:
query[Owner].join(query[Pet]).on((o, p) => o.id == p.o_id)
Your question highlights one of the major differences between FRM (Functional Relational Mapping) systems like Quill and Slick as opposed to ORMs like Hibernate. The purpose of FRM systems is not to build a particular domain-specific object hierarchy e.g. OwnersAndPets, but rather, to be able translate a single database query into some set of objects that can reasonably be pulled out of that single query's result set - this is typically a tuple. This means it is up to you to join the tuples (Owner_N, Pet_1-N) object into a single OwnersAndPets object in memory. Typically this can be done via groupBy and map operators:
run(query[Owner].join(query[Pet]).on((o, p) => o.id == p.o_id))
.groupBy(_._1)
.map({case (owner,ownerPetList) =>
OwnerAndPets(
owner.id,owner.name,owner.age+"", // Not sure why you made 'age' a String in OwnerAndPets
ownerPetList.map(_._2))
})
That said, there are some database vendors (e.g. Postgres) that internally implement array types so in some cases you can do the join on the database-level but this is not the case for MySQL and many others.

SQLite3::SQLException: no such column: parameters.user:

I am saving a list of followed users to the db and then trying to get the records where the current user is a part of that list but keep getting this exception.
SQLite3::SQLException: no such column: parameters.user: SELECT "activities".* FROM "activities" WHERE "parameters"."user" = 3
This is a record in the db
=> #<PublicActivity::Activity id: 107, trackable_id: 16, trackable_type: "Shout", owner_id: 1, owner_type: "User", key: "shout.shout", parameters: {:user=>[3]}, recipient_id: nil, recipient_type: nil, created_at: "2015-10-20 21:44:41", updated_at: "2015-10-20 21:44:41", read: false>
These are the queries I've tried that give me this. current_user.id = 3
PublicActivity::Activity.where({'parameters.user' => current_user.id})
PublicActivity::Activity.where(parameters: {user: current_user.id})
So. How do I get the records where the current user is a part of that list of users? Also, would the I be able to use the same query in Mysql?
Might seem like a silly question, but is the parameters column defined as a serialized column in the model? With adapters like MySQL and (I believe) SQLite you can't query serialized fields. So If it's something that you'd like to query, you need to save it separately from the serialized field.
That being said, with PostgreSQL and their rails adapter, you can query serialized fields.
You should check out this SO question and this anser

Using N1QL with document keys

I'm fairly new to couchbase and have tried to find the answer to a particular query I'm trying to create with not much success so far.
I've debated between using a view or N1QL for this particular case and settled with N1QL but haven't managed to get it to work so maybe a view is better after all.
Basically I have the document key (Group_1) for the following document:
Group_1
{
"cbType": "group",
"ID": 1,
"Name": "Group Atlas 3",
"StoreList": [
2,
4,
6
]
}
I also have 'store' documents, their keys are listed in this document's storelist. (Store_2, Store_4, Store_6 and they have a storeID value that is 2, 4 and 6) I basically want to obtain all 3 documents listed.
What I do have that works is I obtain this document with its id by doing:
var result = CouchbaseManager.Bucket.Get<dynamic>(couchbaseKey);
mygroup = JsonConvert.DeserializeObject<Group> (result.ToString());
I can then loop through it's storelist and obtain all it's stores in the same manner, but i don't need anything else from the group, all i want are the stores and would have prefered to do this in a single operation.
Does anyone know how to do a N1QL directly unto a specified document value?
Something like (and this is total imaginary non working code I'm just trying to clearly illustrate what I'm trying to get at):
SELECT * FROM mycouchbase WHERE documentkey IN
Group_1.StoreList
Thanks
UPDATE:
So Nic's solution does not work;
This is the closest I get to what I need atm:
SELECT b from DataBoard c USE KEYS ["Group_X"] UNNEST c.StoreList b;
"results":[{"b":2},{"b":4},{"b":6}]
Which returns the list of IDs of the Stores I want for any given group (Group_X) - I haven't found a way to get the full Stores instead of just the ID in the same statement yet.
Once I have, I'll post the full solution as well as all the speed bumps I've encountered in the process.
I apologize if I have a misunderstanding of your question, but I'm going to give it my best shot. If I misunderstood, please let me know and we'll work from there.
Let's use the following scenario:
group_1
{
"cbType": "group",
"ID": 1,
"Name": "Group Atlas 3",
"StoreList": [
2,
4,
6
]
}
store_2
{
"cbType": "store",
"ID": 2,
"name": "some store name"
}
store_4
{
"cbType": "store",
"ID": 4,
"name": "another store name"
}
store_6
{
"cbType": "store",
"ID": 6,
"name": "last store name"
}
Now lets say you wan't to query the stores from a particular group (group_1), but include no other information about the group. You essentially want to use N1QL's UNNEST and JOIN operators.
This might leave you with a query like so:
SELECT
stores.name
FROM `bucket-name-here` AS groups
UNNEST groups.StoreList AS groupstore
JOIN `bucket-name-here` AS stores ON KEYS ("store_" || groupstore.ID)
WHERE
META(groups).id = 'group_1';
A few assumptions are made in this. Both your documents exist in the same bucket and you only want to select from group_1. Of course you could use a LIKE and switch the group id to a percent wildcard.
Let me know if something doesn't make sense.
Best,
Try this query:
select Name
from buketname a join bucketname b ON KEYS a.StoreList
where Name="Group Atlas 3"
Based on your update, you can do the following:
SELECT b, s
FROM DataBoard c USE KEYS ["Group_X"]
UNNEST c.StoreList b
JOIN store_bucket s ON KEYS "Store_" || TO_STRING(b);
I have a similar requirement and I got what I needed with a query like this:
SELECT store
FROM `bucket-name-here` group
JOIN `bucket-name-here` store ON KEYS group.StoreList
WHERE group.cbType = 'group'
AND group.ID = 1

Store a big array in the MySQL table

I want to create tablestopsfor all stops with these columns id, stop_name, stop_lat, stop_long, route, arrivaltime but I dont know how can I store the arrivaltime into the table since this column is a big array
Like this:
{
"id": 1
"stops_name": "Amersham ",
"arrival_time": {
"mon-fri": [ "05:38", "06:07","06:37",.....50 entries],
"sat": ["05:34","06:01","06:31",...........50 entries],
"son": ["06:02","06:34","07:04",...........50 entries]
},
"stops_lat": 83.837994,
"stops_long": 18.700423
}
Is that to manage with mysql?
Generally speaking you would split the "arrival times" out into a new table, referencing back to the table of stops. You would also generally store each time as a single row, and then select the entire collection of rows.
This works best because it lets you query on the 'time' column and search for time ranges, etc and only get the relevant rows.
For the "day", I would most likely use a Set to have a column that can be 1 or more values. Also consider that likely you may need to store info on public holidays or other special dates as well:
https://dev.mysql.com/doc/refman/5.6/en/set.html
Stops: id, stops_name, stops_lat, stops_long (1, "Amersham", 83.837994, 18.700423)
Stops_arrivals: id, stops_id, day, time (1, 1, "Mon", "05:38"), (2, 1, "Mon", "06:07"), etc

How to enter multiple table data in mongoDB using json

I am trying to learn mongodb. Suppose there are two tables and they are related. For example like this -
1st table has
First name- Fred, last name- Zhang, age- 20, id- s1234
2nd table has
id- s1234, course- COSC2406, semester- 1
id- s1234, course- COSC1127, semester- 1
id- s1234, course- COSC2110, semester- 1
how to insert data in the mongo db? I wrote it like this, not sure is it correct or not -
db.users.insert({
given_name: 'Fred',
family_name: 'Zhang',
Age: 20,
student_number: 's1234',
Course: ['COSC2406', 'COSC1127', 'COSC2110'],
Semester: 1
});
Thank you in advance
This would be a assuming that what you want to model has the "student_number" and the "Semester" as what is basically a unique identifier for the entries. But there would be a way to do this without accumulating the array contents in code.
You can make use of the upsert functionality in the .update() method, with the help of of few other operators in the statement.
I am going to assume you are going this inside a loop of sorts, so everything on the right side values is actually a variable:
db.users.update(
{
"student_number": student_number,
"Semester": semester
},
{
"$setOnInsert": {
"given_name": given_name,
"family_name": family_name,
"Age": age
},
"$addToSet": { "courses": course }
},
{ "upsert": true }
)
What this does in an "upsert" operation is first looks for a document that may exist in your collection that matches the query criteria given. In this case a "student_number" with the current "Semester" value.
When that match is found, the document is merely "updated". So what is being done here is using the $addToSet operator in order to "update" only unique values into the "courses" array element. This would seem to make sense to have unique courses but if that is not your case then of course you can simply use the $push operator instead. So that is the operation you want to happen every time, whether the document was "matched" or not.
In the case where no "matching" document is found, a new document will then be inserted into the collection. This is where the $setOnInsert operator comes in.
So the point of that section is that it will only be called when a new document is created as there is no need to update those fields with the same information every time. In addition to this, the fields you specified in the query criteria have explicit values, so the behavior of the "upsert" is to automatically create those fields with those values in the newly created document.
After a new document is created, then the next "upsert" statement that uses the same criteria will of course only "update" the now existing document, and as such only your new course information would be added.
Overall working like this allows you to "pre-join" the two tables from your source with an appropriate query. Then you are just looping the results without needing to write code for trying to group the correct entries together and simply letting MongoDB do the accumulation work for you.
Of course you can always just write the code to do this yourself and it would result in fewer "trips" to the database in order to insert your already accumulated records if that would suit your needs.
As a final note, though it does require some additional complexity, you can get better performance out of the operation as shown by using the newly introduced "batch updates" functionality.For this your MongoDB server version will need to be 2.6 or higher. But that is one way of still reducing the logic while maintaining fewer actual "over the wire" writes to the database.
You can either have two separate collections - one with student details and other with courses and link them with "id".
Else you can have a single document with courses as inner document in form of array as below:
{
"FirstName": "Fred",
"LastName": "Zhang",
"age": 20,
"id": "s1234",
"Courses": [
{
"courseId": "COSC2406",
"semester": 1
},
{
"courseId": "COSC1127",
"semester": 1
},
{
"courseId": "COSC2110",
"semester": 1
},
{
"courseId": "COSC2110",
"semester": 2
}
]
}