Extract the number of invoices of the current year in mysql - mysql

Question

Goodmorning everyone.
I'm going crazy
I need to extract the number of invoices from the current year per customer.
in my table tbl_preventivi I have the field anagrafica_id for the customer and date_prev for the date of the invoice.
this is my code.
$anno = date('Y');
SELECT tbl_preventivi.anagrafica_id, Count(tbl_preventivi.preventivo_id) AS totale
FROM tbl_preventivi
GROUP BY tbl_preventivi.anagrafica_id, Year(tbl_preventivi.data_prev)
HAVING ((Year(tbl_preventivi.data_prev) = ".$anno.") AND (tbl_preventivi.anagrafica_id=".$_GET['anagrafica_id']."))
i am sure that in the test i am doing the result must be 1, instead the query is null.
if I remove
(Year(tbl_preventivi.data_prev) = ".$anno.") AND the query works and returns 6 (which is the number of invoices made even in previous years).
where am i wrong?

Answer 1

The simplest solution would be something like:
SELECT p.`anagrafica_id`,
COUNT(p.`preventivo_id`) as `totale`
FROM `tbl_preventivi` p
WHERE p.`anagrafica_id` = 12345 and YEAR(p.`data_prev`) = 9999
GROUP BY p.`anagrafica_id`;
Note: 12345 should be replaced with a sanitized customer number, and 9999 should be replaced with a sanitized and logical year. Prepared statements are your friend here.
If you wish to see all invoices for a customer across all years, you can do this:
SELECT p.`anagrafica_id`,
YEAR(p.`data_prev`) as `year`,
COUNT(p.`preventivo_id`) as `totale`
FROM `tbl_preventivi` p
WHERE p.`anagrafica_id` = 12345
GROUP BY p.`anagrafica_id`, `year`
ORDER BY `year` DESC;
Again, be sure to sanitize your inputs. In the famous words of Fox Mulder: Trust no one.