The question is how is it possible to get difference in days from before to today and knowing this difference is happened in the past?
Yes its possible to get difference in days from before to today, all you need is the dates. for the example this is some check in and check out date diff.
// Params in date
public static function getDateDifference($check_in, $check_out)
{
$check_in = strtotime($check_in);
$check_out = strtotime($check_out);
$date_difference = $check_out - $check_in;
$date_difference = round($date_difference / (60 * 60 * 24));
return $date_difference;
}
Related
I use a primefaces extension timer with the following code :
<pe:timer
style="color:darkgrey;"
timeout="1000"
forward="false"
format="HH:mm:ss"/>
But I have a start value. The previous code start from the value 00:00:00, but I have a start time from a Java bean. I have a Date object, or date as long type (from 1970) which is the value from I want to start.
For example I got 1548434800083 or 17:47 25/01/2019 and I want to display the time between this date and now. So how I can set my start value with this date ? I got milliseconds but I can get seconds instead of.
The solution is the following, I have a Java bean, that contain a date in millisecond. I get it with the function getTime() from the Java class Date.
I display my counter, chronometer with the primefaces code :
<pe:timer
style="color:grey;"
forward="true"
formatFunction="return displayElapsedTime('#{synopticBean.longEnteredTime}');"/>
That code call a javascript function, that return a format counter/chronometer :
function displayElapsedTime(longEnteredTime){
var now = new Date();
var elapsedTime = now.getTime() - longEnteredTime;
var numHours = Math.floor(elapsedTime / 3600000);
var minutesAndSecondMS = elapsedTime - numHours;
var minutes = Math.floor((minutesAndSecondMS % (1000 * 60 * 60)) / (1000 * 60));
var seconds = Math.floor((minutesAndSecondMS % (1000 * 60)) / 1000);
var innerHtmlText = (('0' + (numHours)).slice(-2) + ":" +('0' + (minutes)).slice(-2) + ":" + ('0' + (seconds)).slice(-2));
return innerHtmlText;
}
It display a duration, the number of hours. I only count with hours, no day.
Best solution for your case is formatting. But sometime we need to set start value of primefaces timer:
Run javascript:
PF('timer').currentTimeout = 100;
I checked several older questions regarding this topic like this one: Calendar Recurring/Repeating Events - Best Storage Method however, the answers are pretty bad performance-wise and cumbersome in implementation. From another answer, it's easy to tell why the accepted answer is a bad idea: a month of events takes 90 queries. Which is unacceptable.
Anyways, here's the issue I'm facing so that you don't have re-read those questions:
Storing events in such a way to allow them to recur. Think Google Calendar where you can specify patterns like "happens on the 1st of the month, every month" or "happens every 2nd monday of the month" (the latter is less important to me.
Querying a list of events for a time period. For example, I want to show someone a list of events for the next 2 months and I don't want to query for every single day of the month. Doing that would just kill the server (per user among thousands of rows of events)
DB agnostic. I use PgSQL and saw many answers for this question on other forums using either MS SQL-specific stuff or Oracle.
I'd appreciate any help! I read a couple of papers on the topic and still can't find something I can make work in SQL specifically.
The solution I have come up with is that I have an event table that has five fields defining the recurrence of the event, as defined below. I then also have a schedule table which I populate with the actual occurrence of the events. I do require an end date, and even when they specify something to go out to a couple years out, it is a monthly type event which does not create that many entries into the schedule table.
So, the event is stored in an event table, with a startDateTime and an endDateTime that describe the entire duration of the event if there is no recurrence. These two datetime fields also define the overall start and end of the event if it is a recurring event. In that same event table, we have the five fields defining recurrence, as laid out below.
The Schedule table stores individual occurrences of each event. So it has an eventId, startDateTime, and endDateTime. This start and end refer only to each occurrence, not the overall span.
For querying for all the scheduled occurrences happening in a period of time, I just query the schedule table checking for any occurrences that match this condition:
select * from schedule where schedule.startDateTime < #queryPeriodEnd and schedule.endDateTime > #queryPeriodStart
This query gives me only the schedule entries that happen partially or wholly within my query period. For getting the event data, it's a simple matter of joining to the event table.
The interesting part is calculating something like the second thursday of the month. That happens in the actual code for figuring out all the scheduled occurrences for a given event. I am also enclosing my code for that below.
EVENT RECURRENCE FIELDS
recurs
0=no recurrence
1=daily
2=weekly
3=monthly
recurs_interval
this is how many of the periods between recurrences. If the event recurs every 5 days, recurs_interval will have a 5 and recurs will have 1. If the event recurs every 3 weeks, recurs_interval will have a 3 and recurs will have a 2.
recurs_day
If the user selected monthly type recurrence, on a given day of the month (ex: 10th or the 14th). This has that date. The value is 0 if the user did not select monthly or specific day of month recurrence. The value is 1 to 31 otherwise.
recurs_ordinal
if the user selected a monthly type recurrence, but an ordinal type of day (ex: first monday, second thursday, last friday). This will have that ordinal number. The value is 0 if the user did not select this type of recurrence.
1=first
2=second
3=third
4=fourth
5=last
recurs_weekdays
for weekly and monthly-ordinal recurrence this stores the weekdays where the recurrence happens. 1=Sunday
2=Monday
4=Tuesday
8=Wednesday
16=Thursday
32=Friday
64=Saturday
So, every 4 weeks on Saturday and Sunday would be
recurs=2, recurs_interval=4, recurs_weekdays=65 (64 + 1)
Similarly, Every three months on the first Friday of the month would be
recurs=3, recurs_interval=3, recurs_ordinal=1, recurs_weekdays=32
CODE
thisEvent.occurrences = new List<ScheduleInstance>();
DateTime currentDateTime = (DateTime) thisEvent.start;
DateTime currentEndTime;
BitArray WeekDayRecurrenceBits = new BitArray(new Byte[] {(Byte) thisEvent.recursWeekdays});
while (currentDateTime < thisEvent.end)
{
currentEndTime = new DateTime(currentDateTime.Year, currentDateTime.Month, currentDateTime.Day,
thisEvent.end.Value.Hour, thisEvent.end.Value.Minute, thisEvent.end.Value.Second);
switch (thisEvent.recurs)
{
case (RecurrenceTypeEnum.None):
AddOccurrenceToRooms(thisEvent, currentDateTime, currentEndTime);
currentDateTime = (DateTime)thisEvent.end;
break;
case (RecurrenceTypeEnum.Daily):
AddOccurrenceToRooms(thisEvent, currentDateTime, currentEndTime);
currentDateTime = currentDateTime.AddDays(thisEvent.recursInterval);
break;
case (RecurrenceTypeEnum.Weekly):
int indexIntoCurrentWeek = (int) currentDateTime.DayOfWeek;
while ((indexIntoCurrentWeek < 7) && (currentDateTime < thisEvent.end))
{
if (WeekDayRecurrenceBits[(int) currentDateTime.DayOfWeek])
{
AddOccurrenceToRooms(thisEvent, currentDateTime, currentEndTime);
}
currentDateTime = currentDateTime.AddDays(1);
currentEndTime = currentEndTime.AddDays(1);
indexIntoCurrentWeek++;
}
currentDateTime = currentDateTime.AddDays(7 * (thisEvent.recursInterval - 1));
break;
case (RecurrenceTypeEnum.Monthly):
if (thisEvent.recursDay == 0)
{
DateTime FirstOfTheMonth = new DateTime(currentDateTime.Year, currentDateTime.Month, 1);
int daysToScheduleOccurrence = ((thisEvent.recursWeekdays - (int)FirstOfTheMonth.DayOfWeek + 7) % 7)
+ ((thisEvent.recursOrdinal - 1) * 7)
- currentDateTime.Day + 1;
if (daysToScheduleOccurrence >= 0)
{
currentDateTime = currentDateTime.AddDays(daysToScheduleOccurrence);
currentEndTime = currentEndTime.AddDays(daysToScheduleOccurrence);
if (currentDateTime < thisEvent.end)
{
AddOccurrenceToRooms(thisEvent, currentDateTime, currentEndTime);
}
}
}
else
{
if (currentDateTime.Day <= thisEvent.recursDay && thisEvent.recursDay <= DateTime.DaysInMonth(currentDateTime.Year, currentDateTime.Month) )
{
currentDateTime = currentDateTime.AddDays(thisEvent.recursDay - currentDateTime.Day);
currentEndTime = currentEndTime.AddDays(thisEvent.recursDay - currentEndTime.Day);
AddOccurrenceToRooms(thisEvent, currentDateTime, currentEndTime);
}
}
currentDateTime = currentDateTime.AddDays((currentDateTime.Day - 1) * -1).AddMonths(thisEvent.recursInterval);
break;
default:
break;
}
}
I'm trying to make a countdown timer, where I could easily set the endDate variable in html...
I can send strings to AS3 with flashvars="endDate=123", but how do I make it to be date (for example christmas)? - I need it to be date because then in AS3 I have something like endDate - todayDate = timeRemaining
Just pass date to flash vars using formats specified here and parse that string in AS3 using Date.parse() method.
In this example you get a countdown in days to Xmas.
var dateFromFlashVar : String = "2013/12/25 15:30:20 GMT+0300";
trace( new Date( new Date( Date.parse( dateFromFlashVar ) ).time - new Date().time ).getDate().toString() );
to transfrom a unix_timestamp date to as3 Date, you can do:
// unixTimeStamp is in seconds so we multiply by 1000 because flash Date take miliseconds
var date:Date = new Date( unixTimeStamp*1000 );
to get back unix timestamp of a date you can do:
// divide by 1000 to get seconds instead of miliseconds
var timeStamp:int = date.time / 1000;
i hope this is what you where searching for
Perhaps a stupid question, but i really dont know the answer :(
lets say i have a date object, how can i change its AM date to PM, or vice verca?
Thanks
seems like you can
var currentTime = new Date();
var hours:uint = currentTime.getHours();
then you can say, if hours is greater than or equal to 12, then subtract by 12, otherwise, add 12 to it, for example, by
public static const millisecondsPerHour:int = 1000 * 60 * 60;
var reversedAMPM = new Date(currentTime.getTime() + (12 * millisecondsPerHour));
Although Jian's version should work, here's an alternative.
Assuming var date:Date is initialized, you may literally change it:
date.hours += (date.hours > 12) ? -12:12;
Is there any ActionScript class which represents "durations of time", similar to the TimeDelta class in Python?
Edit: Thanks for the responses. I should clarify a bit, though: I want be able to ask questions like "how many weeks are between date0 and date1" or "let x represent "one day". What is date2 + x?"
I know I can do all this by representing dates as timestamps... But I'm hoping to find something nicer.
I posted a full AS3 port of the .NET TimeSpan class on this question, which sounds exactly like what you need.
// 5 days from new
var ts : TimeSpan = TimeSpan.fromDays(5);
var now : Date = new Date();
var fiveDaysTime : Date = ts.add(now);
// Diff between dates
var d1 : Date = new Date(2009, 1, 1);
var d2 : Date = new Date(2009, 1, 6);
var ts : TimeSpan = TimeSpan.fromDates(d1, d2);
You can use time() in the Date class to get unix era milliseconds and use that for time delta.
If you subtract two dates:
var dateDiff = date1 - date2;
dateDiff will hold the number of milliseconds between the two dates. You can then convert from milliseconds to whatever useful number you like.
I don't think there is a class which measures change in time in Actionscript 3. According to this blog post on Adventures in Actionscript, timing is very inaccurate in the Flash player on the web. That post is pretty informative and has a class called SuperTimer that might help you. You might want to keep this inaccuracy in mind if using solutions posed by Justin Niessner and toastie.