Mysql query to get created and resolved defect group by month - mysql

The table I am using is like bellow:
CREATE TABLE IF NOT EXISTS `tickets` (
`id` int(6) unsigned NOT NULL,
`created` timestamp ,
`resolved` timestamp ,
PRIMARY KEY (`id`)
) DEFAULT CHARSET=utf8;
INSERT INTO `tickets` (`id`, `created`, `resolved`) VALUES
('1', '2021-01-01', '2021-01-12'),
('2', '2021-02-25', '2021-01-15'),
('3', '2021-03-10', '2021-03-22'),
('4', '2021-03-10', '2021-03-22'),
('5', '2021-03-10', '2021-03-22'),
('6', '2021-03-11', '2021-03-22'),
('7', '2021-03-13', '2021-03-22'),
('8', '2021-03-13', '2021-03-22'),
('9', '2021-04-01', '2021-03-12');
Now I want a query to show me the table with columns like
Month, NumberOfticketsCreated, NumberOfTicketsResolved.
Here is what I tried so far but it does not return what I expect:
SELECT
YEAR(`created`) AS y
, MONTH(`created`) AS m
, COUNT(`created`) as NumberOfticketsCreated
, count(`resolved`) as NumberOfTicketsResolved
FROM tickets
GROUP BY y, m;

Create table t1 with group by 'created'
Create table t2 with group by 'resolved'
then left join above two tables.
select t1.y, t1.m, t1.NumberOfticketsCreated, t2.NumberOfTicketsResolved
from
(SELECT
YEAR(`created`) AS y
, MONTH(`created`) AS m
, MONTH(`resolved`) AS n
, COUNT(`created`) as NumberOfticketsCreated
, count(`resolved`) as NumberOfTicketsResolved
FROM tickets
GROUP BY m) as t1
left join
(SELECT
YEAR(`created`) AS y
, MONTH(`created`) AS m
, MONTH(`resolved`) AS n
, COUNT(`created`) as NumberOdticketsCreated
, count(`resolved`) as NumberOfTicketsResolved
FROM tickets
GROUP BY n) as t2
on t1.m = t2.m

Related

How to get difference or delta of counts entries of each days with window functions?

I have a table with few fields like id, country, ip, created_at. Then I am trying to get the deltas between total entry of one day and total entry of the next day.
CREATE TABLE session (
id int NOT NULL AUTO_INCREMENT,
country varchar(50) NOT NULL,
ip varchar(255),
created_at TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (id)
);
INSERT INTO `session` (`id`, `country`, `ip`, `created_at`) VALUES
('1', 'IN', '10.100.102.11', '2021-04-05 20:26:02'),
('2', 'IN', '10.100.102.11', '2021-04-05 19:26:02'),
('3', 'US', '10.120.102.11', '2021-04-17 10:26:02'),
('4', 'US', '10.100.112.11', '2021-04-16 12:26:02'),
('5', 'AU', '10.100.102.122', '2021-04-12 19:36:02'),
('6', 'AU', '10.100.102.122', '2021-04-12 18:20:02'),
('7', 'AU', '10.100.102.122', '2021-04-12 23:26:02'),
('8', 'US', '10.100.102.2', '2021-04-16 21:33:01'),
('9', 'AU', '10.100.102.122', '2021-04-18 20:46:02'),
('10', 'AU', '10.100.102.111', '2021-04-04 13:19:12'),
('11', 'US', '10.100.112.11', '2021-04-16 12:26:02'),
('12', 'IN', '10.100.102.11', '2021-04-05 15:26:02'),
('13', 'IN', '10.100.102.11', '2021-04-05 19:26:02');
Now I have written this query to get the delta
SELECT T1.date1 as date, IFNULL(T1.cnt1-T2.cnt2, T1.cnt1) as delta from (
select TA.dateA as date1, MAX(TA.countA) as cnt1 from (
select DATE(created_at) AS dateA, COUNT(*) AS countA
FROM session
GROUP BY DATE(created_at)
UNION
select DISTINCT DATE(DATE(created_at)+1) AS dateA, 0 AS countA
FROM session
) as TA
group by TA.dateA
) as T1
LEFT OUTER JOIN (
select DATE(DATE(created_at)+1) AS date2,
COUNT(*) AS cnt2
FROM session
GROUP BY DATE(created_at)
) as T2
ON T1.date1=T2.date2
ORDER BY date;
http://sqlfiddle.com/#!9/4f5fd26/60
Then I am getting the results as
date delta
2021-04-04 1
2021-04-05 3
2021-04-06 -4
2021-04-12 3
2021-04-13 -3
2021-04-16 3
2021-04-17 -2
2021-04-18 0
2021-04-19 -1
Now, is there any place of improvements/optimizes on it with/or window functions? (I am zero with SQL, still playing around).
Try a shorter version
with grp as (
SELECT t.dateA, SUM(t.cnt) AS countA
FROM session,
LATERAL (
select DATE(created_at) AS dateA, 1 as cnt
union all
select DATE(DATE(created_at)+1), 0 as cnt
) t
GROUP BY dateA
)
select t1.dateA as date, IFNULL(t1.countA-t2.countA, t1.countA) as delta
from grp t1
left join grp t2 on DATE(t2.dateA + 1) = t1.dateA
order by t1.dateA
db<>fiddle

Maria DB - update row with value of previous row + constant

I have table called dobridol with several column.
CREATE TABLE IF NOT EXISTS `dobridol` (
`id` int(6) unsigned NOT NULL,
`dt` varchar(200) NOT NULL,
`p2` int(6) NOT NULL,
`p6` int(6) NOT NULL,
PRIMARY KEY (`id`)
) DEFAULT CHARSET=utf8;
INSERT INTO `dobridol` (`id`, `dt`, `p2`,`p6`) VALUES
('1', '2021-02-28 23:50:00', '100', '600'),
('2', '2021-02-28 23:55:00', '200', '700'),
('3', '2021-03-01 00:00:00', '300', '800'),
('4', '2021-03-01 00:05:00', '400', '900'),
('5', '2021-03-01 00:10:00', '400', '900'),
('6', '2021-03-01 00:15:00', '400', '900'),
('7', '2021-03-01 00:20:00', '500', '1000'),
('8', '2021-03-01 00:25:00', '600', '1100');
The table has values for January and March also.
I want to be able to UPDATE table like that:
I select period as month, then I add constant value (in this case I added 39) to p6 ONLY WHEN p2 value is different than previous row p2.
If this is the case I have to add 39 to PREVIOUS row p6 value.
update dobridol join
(select tt.*,
sum(case when p2 <> prev_p2 then 1 else 0 end) over (order by dt) as cnt
from (select tt.*,
lag(p2) over (order by dt) as prev_p2
from dobridol tt
) tt
) tt
on tt.id = dobridol.id
set dobridol.p6 = cnt * 39 + <PREVIOUS_ROW_p6_VALUE_HAS_TO_BE_HERE>
where cnt > 0
The query should look-like this but I have to replace this <PREVIOUS_ROW_VALUE_HAS_TO_BE_HERE> with the right syntax of picking last row p6. How can I pick it?
Also where to add clause
dobridol.dt BETWEEN '2021-03-01' AND '2021-03-30'
in the SQL query?
If I understand correctly, you can use lag():
update dobridol join
(select tt.*,
lag(p6) over (order by dt) as prev_p6,
sum(case when p2 <> prev_p2 then 1 else 0 end) over (order by dt) as cnt
from (select tt.*,
lag(p2) over (order by dt) as prev_p2
from dobridol tt
) tt
) tt
on tt.id = dobridol.id
set dobridol.p6 = tt.cnt * 39 + tt.prev_p6
where cnt > 0 ;
Here is a db<>fiddle.

inner join with subquery results differs for these data sets

CREATE TABLE IF NOT EXISTS `wcd` (
`id` int(6) unsigned NOT NULL,
`wid` int(11) unsigned NOT NULL,
PRIMARY KEY (`id`)
) DEFAULT CHARSET=utf8;
INSERT INTO `wcd` (`id`, `wid`) VALUES
('168', '5685'),
('167', '5685'),
('166', '5685'),
('165', '5685'),
('164', '5685'),
('163', '5685'),
('162', '5684'),
('161', '5684');
CREATE TABLE IF NOT EXISTS `cases` (
`id` int(6) unsigned NOT NULL,
`wcd_id` int(11) unsigned NOT NULL,
`reason_id` int(11) unsigned NOT NULL,
PRIMARY KEY (`id`)
) DEFAULT CHARSET=utf8;
INSERT INTO `cases` (`id`, `wcd_id`, `reason_id`) VALUES
('20', '168', '4'),
('19', '168', '1'),
('18', '167', '6'),
('17', '167', '5'),
('16', '166', '4'),
('15', '166', '1'),
('14', '165', '4'),
('13', '165', '1'),
('12', '164', '1'),
('11', '163', '4'),
('10', '162', '1'),
('9', '162', '4'),
('8', '162', '5'),
('7', '161', '5'),
('6', '161', '6');
the above two table has foreignkey relation with wcd.id = cases.wcd_id,
Lets consider the records related to wcd.wid 5865. The result should be grouped by reason_id with the condition max(cases.id)
I used the query below to achieve this and got the result as expected.
SELECT d.id, d.wid, c.* FROM wcd d
LEFT JOIN cases c ON c.wcd_id = d.id
inner JOIN (SELECT MAX(id) AS max_id FROM cases GROUP BY reason_id) c2
ON c2.max_id = c.id
WHERE d.wid = 5685;
Result:
id wid id wcd_id reason_id
168 5685 19 168 1
168 5685 20 168 4
167 5685 17 167 5
167 5685 18 167 6
with the same query for 5684, the query returns 0 rows though there is data available for it. but I'm expecting the rows below.
id wid id wcd_id reason_id
162 5684 10 162 1
162 5684 9 162 4
162 5684 8 162 5
161 5684 6 161 6
What the issue with the query and what needs to be changed to get the result above for 5684.?
here is the sqlfiddle link
You need to look back at the wcd table to propery correlate, since you need the id of the row that has the "latest" reason per wid - and that column is not available in cases.
In MySQL 8.0, we would just use row_number()... but you tagged your question MySQL 5.6. I find that the simplest way to express this is with a correlated subquery:
SELECT d.id, d.wid, c.*
FROM wcd d
INNER JOIN cases c ON c.wcd_id = d.id
WHERE c.id = (
SELECT max(c2.id)
FROM wcd d2
INNER JOIN cases c2 ON c2.wcd_id = d2.id
WHERE d2.wid = d.wid AND c2.reason_id = c.reason_id
)
AND d.wid = 5685;
Then you must use MIN and get rid of the Where Clause.because
('162', '5684')
('161', '5684')
because
SELECT
d.id
, d.wid
,
c.*
FROM
wcd d
LEFT JOIN
cases c
ON c.wcd_id = d.id
inner JOIN (SELECT MIN(id) AS min_id FROM cases GROUP BY reason_id) c2
ON c2.min_id = c.id
see http://sqlfiddle.com/#!9/fb4569/26

MySQL latest related record from more than one table

Assuming a main "job" table, and two corresponding "log" tables (one for server events and the other for user events, with quite different data stored in each).
What would be the best way to return a selection of "job" records and the latest corresponding log record (with multiple fields) from each of the two "log" tables (if there are any).
Did get some inspiration from: MySQL Order before Group by
The following SQL would create some example tables/data...
CREATE TABLE job (
`id` int(11) NOT NULL AUTO_INCREMENT,
`name` tinytext NOT NULL,
PRIMARY KEY (id)
);
CREATE TABLE job_log_server (
`id` int(11) NOT NULL AUTO_INCREMENT,
`job_id` int(11) NOT NULL,
`event` tinytext NOT NULL,
`ip` tinytext NOT NULL,
`created` datetime NOT NULL,
PRIMARY KEY (id),
KEY job_id (job_id)
);
CREATE TABLE job_log_user (
`id` int(11) NOT NULL AUTO_INCREMENT,
`job_id` int(11) NOT NULL,
`event` tinytext NOT NULL,
`user_id` int(11) NOT NULL,
`created` datetime NOT NULL,
PRIMARY KEY (id),
KEY job_id (job_id)
);
INSERT INTO job VALUES (1, 'Job A');
INSERT INTO job VALUES (2, 'Job B');
INSERT INTO job VALUES (3, 'Job C');
INSERT INTO job VALUES (4, 'Job D');
INSERT INTO job_log_server VALUES (1, 2, 'Job B Event 1', '127.0.0.1', '2000-01-01 00:00:01');
INSERT INTO job_log_server VALUES (2, 2, 'Job B Event 2', '127.0.0.1', '2000-01-01 00:00:02');
INSERT INTO job_log_server VALUES (3, 2, 'Job B Event 3*', '127.0.0.1', '2000-01-01 00:00:03');
INSERT INTO job_log_server VALUES (4, 3, 'Job C Event 1*', '127.0.0.1', '2000-01-01 00:00:04');
INSERT INTO job_log_user VALUES (1, 1, 'Job A Event 1', 5, '2000-01-01 00:00:01');
INSERT INTO job_log_user VALUES (2, 1, 'Job A Event 2*', 5, '2000-01-01 00:00:02');
INSERT INTO job_log_user VALUES (3, 2, 'Job B Event 1*', 5, '2000-01-01 00:00:03');
INSERT INTO job_log_user VALUES (4, 4, 'Job D Event 1', 5, '2000-01-01 00:00:04');
INSERT INTO job_log_user VALUES (5, 4, 'Job D Event 2', 5, '2000-01-01 00:00:05');
INSERT INTO job_log_user VALUES (6, 4, 'Job D Event 3*', 5, '2000-01-01 00:00:06');
One option (only returning 1 field from each table) would be to use nested sub-queries... but the ORDER BY will have to be done in separate queries to the GROUP BY (x2):
SELECT
*
FROM
(
SELECT
s2.*,
jlu.event AS user_event
FROM
(
SELECT
*
FROM
(
SELECT
j.id,
j.name,
jls.event AS server_event
FROM
job AS j
LEFT JOIN
job_log_server AS jls ON jls.job_id = j.id
ORDER BY
jls.created DESC
) AS s1
GROUP BY
s1.id
) AS s2
LEFT JOIN
job_log_user AS jlu ON jlu.job_id = s2.id
ORDER BY
jlu.created DESC
) AS s3
GROUP BY
s3.id;
Which actually seems to perform quite well... just not very easy to understand.
Or you could try to return and sort the log records in two separate sub-queries:
SELECT
j.id,
j.name,
jls2.event AS server_event,
jlu2.event AS user_event
FROM
job AS j
LEFT JOIN
(
SELECT
jls.job_id,
jls.event
FROM
job_log_server AS jls
ORDER BY
jls.created DESC
) AS jls2 ON jls2.job_id = j.id
LEFT JOIN
(
SELECT
jlu.job_id,
jlu.event
FROM
job_log_user AS jlu
ORDER BY
jlu.created DESC
) AS jlu2 ON jlu2.job_id = j.id
GROUP BY
j.id;
But this seems to take quite a bit longer to run... possibly because of the amount of records it's adding to a temporary table, which are then mostly ignored (to keep this short-ish, I've not added any conditions to the job table, which would otherwise be only returning active jobs).
Not sure if I've missed anything obvious.
How about the following SQL Fiddle. It produces the same results as both of your queries.
SELECT j.id, j.name,
(
SELECT s.event
FROM job_log_server s
WHERE j.id = s.job_id
ORDER BY s.id DESC
LIMIT 1
)AS SERVER_EVENT,
(
SELECT u.event
FROM job_log_user u
WHERE j.id = u.job_id
ORDER BY u.id DESC
LIMIT 1
)AS USER_EVENT
FROM job j
EDIT SQL Fiddle:
SELECT m.id, m.name, js.event AS SERVER_EVENT, ju.event AS USER_EVENT
FROM
(
SELECT j.id, j.name,
(
SELECT s.id
FROM job_log_server s
WHERE j.id = s.job_id
ORDER BY s.id DESC
LIMIT 1
)AS S_E,
(
SELECT u.id
FROM job_log_user u
WHERE j.id = u.job_id
ORDER BY u.id DESC
LIMIT 1
)AS U_E
FROM job j
) m
LEFT JOIN job_log_server js ON js.id = m.S_E
LEFT JOIN job_log_user ju ON ju.id = m.U_E

sql update int column based on previous int column

I have a basic table FoodSales in which there is 3 columns SaleForDay decimal (10,2), SalesToDate decimal (10,2), ItemOrder Int
the data is like so
SaleForDay|SalesToDate|ItemOrder
4.99|4.99|1
12.99||2
14.99||3
5.99||4
I'm trying to get the result
SaleForDay|SalesToDate|ItemOrder
4.99|4.99|1
12.99|17.98|2
14.99|32.97|3
5.99|38.96|4
The method here is SalesToDate = the previous itemorder SalesToDate + the Current SaleforDay value.
To help out.
CREATE TABLE #FruitSales
(
SaleForDay DECIMAL (10, 2),
SalesToDate DECIMAL (10, 2),
ItemOrder INT
);
INSERT INTO #FruitSales (SaleForDay, SalesToDate, ItemOrder)
VALUES ('4.99', '4.99', '1'),
('12.99', NULL, '2'),
('14.99', NULL, '3'),
('5.99', NULL, '4');
SELECT * FROM #FruitSales;
DROP TABLE #FruitSales;
Thanks for the help, i realize this is probably simple as pie.
CREATE TABLE #FruitSales
(
SaleForDay DECIMAL (10, 2),
SalesToDate DECIMAL (10, 2),
ItemOrder INT
);
INSERT INTO #FruitSales (SaleForDay, SalesToDate, ItemOrder)
VALUES ('4.99', '4.99', '1'),
('12.99', NULL, '2'),
('14.99', NULL, '3'),
('5.99', NULL, '4');
update f
SET SalesToDate = (select sum(saleforday) from #FruitSales ff where ff.itemorder <= f.itemorder)
from #FruitSales f
SELECT * FROM #FruitSales;
Try this:
;WITH CumulativeData AS
(
SELECT b.ItemOrder, SUM(a.SaleForDay) AS TotalSales
FROM #FruitSales a INNER JOIN #FruitSales b
ON a.ItemOrder <= b.ItemOrder
GROUP BY b.ItemOrder
)
UPDATE a
SET a.SalesToDate = TotalSales
FROM #FruitSales a INNER JOIN CumulativeData b
ON a.ItemOrder = b.ItemOrder;
Another alternative:
UPDATE a
SET SalesToDate = TotalSales
FROM #FruitSales a CROSS APPLY
(SELECT SUM(SaleForDay) TotalSales FROM #FruitSales b WHERE b.ItemOrder <= a.ItemOrder) b