Is it possible to get array/object number values.
I have a table called tableA:
create table "tableA" (
"_id" serial,
"userId" integer,
"dependentData" jsonb);
INSERT INTO "tableA"
("_id", "userId", "dependentData")
VALUES('55555', '1191', '[{"_id": 133, "type": "radio", "title": "questionTest7", "question": "questionTest7", "response": {"value": ["option_11"]}, "dependentQuestionResponse": [{"_id": 278, "type": "text", "title": "questionTest8", "question": "questionTest8", "response": {"value": ["street no 140"]}, "dependentQuestionResponse": []}]}, {"_id": 154, "type": "dropdown", "title": "questionTest8", "question": "questionTest8", "response": {"value": ["option_14"]}, "dependentQuestionResponse": []}]');
Array number is to be fetched. Output should be require below.
_id
userId
array/object
55555
1191
[0,0,1]
You can try something like this
select id, user_id,
(
with
base as (
select o1, oo1.a oo1 from (
select jsonb_array_elements(t.a) o1
from (select depend_data as a) t
) o
left join lateral (select a from jsonb_array_elements(o.o1-> 'dependentQuestionResponse') a) oo1 on true
)
select json_agg(nn) from (
select dense_rank() over(order by b.o1) - 1 nn, b.o1 from base b
union all
select dense_rank() over(order by b.o1) - 1 nn, b.oo1 from base b where oo1 is not null
order by nn
) tz
) as array_object
from
(select 55555 as id,
1191 as user_id,
'[{"_id": 133, "type": "radio", "title": "questionTest7", "question": "questionTest7", "response": {"value": ["option_11"]}, "dependentQuestionResponse": [
{"_id": 278, "type": "text", "title": "questionTest8", "question": "questionTest8", "response": {"value": ["street no 140"]},"dependentQuestionResponse": []}]},
{"_id": 154, "type": "dropdown", "title": "questionTest8", "question": "questionTest8", "response": {"value": ["option_14"]}, "dependentQuestionResponse": []}]'::jsonb as depend_data) t
notice
[
{
"date": "2022. 10. 16.",
"type": 3,
"title": "friend",
"content": "JJ friend",
"parameter": "test"
},
{
"date": "2022. 10. 16.",
"type": 3,
"title": "friend",
"content": "testtest friend",
"parameter": "test1"
}
]
I wanna search and remove in json {"date": "2022. 10. 16.","type": 3,"title": "friend","content": "testtest friend","parameter": "test1"} where id = 'test2'
There's a separate column for the ID.
update UserTable set notice = json_remove(notice, json_search(notice, 'one',
'{"date": "2022. 10. 16.","type": 3,"title": "friend","content": "testtest friend","parameter": "test1"}')) where id = 'test2'";
SELECT JSON_ARRAYAGG(jsonvalue)
FROM src_table
CROSS JOIN JSON_TABLE(src_table.notice,
'$[*]' COLUMNS (jsonvalue JSON PATH '$')) jsontable
WHERE jsonvalue <> CAST('{"date": "2022. 10. 16.","type": 3,"title": "friend","content": "testtest friend","parameter": "test1"}' AS JSON)
My json format in one of the sql columns "jsoncol" in the table "jsontable" is like below.
Kindly help me to get this data using JSON_QUERY or JSON_VALUE
Please pay attention to the brackets and double quotes in the key value pairs...
{
"Company": [
{
"Info": {
"Address": "123"
},
"Name": "ABC",
"Id": 999
},
{
"Info": {
"Address": "456"
},
"Name": "XYZ",
"Id": 888
}
]
}
I am trying to retrieve all the company names using sql query. Thanks in advance
You can use:
SELECT j.name
FROM table_name t
CROSS APPLY JSON_TABLE(
t.value,
'$.Company[*]'
COLUMNS(
name VARCHAR2(200) PATH '$.Name'
)
) j
Which, for the sample data:
CREATE TABLE table_name (
value CLOB CHECK (value IS JSON)
);
INSERT INTO table_name (value)
VALUES ('{
"Company": [
{
"Info": {
"Address": "123"
},
"Name": "ABC",
"Id": 999
},
{
"Info": {
"Address": "456"
},
"Name": "XYZ",
"Id": 888
}
]
}');
Outputs:
NAME
ABC
XYZ
db<>fiddle here
You can easily use JSON_TABLE() function for this case rather provided the DB version is at least 12.1.0.2 such as
SELECT name
FROM jsontable,
JSON_TABLE(jsoncol,
'$' COLUMNS(NESTED PATH '$."Company"[*]'
COLUMNS(name VARCHAR2 PATH '$."Name"')))
Demo
I have started using MySQL 8 and trying to update JSON data type in a mysql table
My table t1 looks as below:
# id group names
1100000 group1 [{"name": "name1", "type": "user"}, {"name": "name2", "type": "user"}, {"name": "techDept", "type": "dept"}]
I want to add user3 to the group1 and written below query:
update t1 set names = JSON_SET(names, "$.name", JSON_ARRAY('user3')) where group = 'group1';
However, the above query is not working
I suppose you want the result to be:
[{"name": "name1", "type": "user"}, {"name": "name2", "type": "user"}, {"name": "techDept", "type": "dept"}, {"name": "user3", "type": "user"}]
This should work:
UPDATE t1 SET names = JSON_ARRAY_APPEND(names, '$', JSON_OBJECT('name', 'user3', 'type', 'user'))
WHERE `group` = 'group1';
But it's not clear why you are using JSON at all. The normal way to store this data would be to create a second table for group members:
CREATE TABLE group_members (
member_id INT PRIMARY KEY,
`group` VARCHAR(10) NOT NULL,
member_type ENUM('user','dept') NOT NULL DEFAULT 'user',
name VARCHAR(10) NOT NULL
);
Then store one per row.
Adding a new member would be like:
INSERT INTO group_members
SET `group` = 'group1', name = 'user3';
So much simpler than using JSON!
I have JSON stored in a SQL Server database table in the below format. I have been able to fudge a way to get the values I need but feel like there must be a better way to do it using T-SQL. The JSON is output from a report in the below format where the column names in "columns" correspond to the "rows"-"data" array values.
So column "Fiscal Month" corresponds to data value "11", "Fiscal Year" to "2019", etc.
{
"report": "Property ETL",
"id": 2648,
"columns": [
{
"name": "Fiscal Month",
"dataType": "int"
},
{
"name": "Fiscal Year",
"dataType": "int"
},
{
"name": "Portfolio",
"dataType": "varchar(50)"
},
{
"name": "Rent",
"dataType": "int"
}
],
"rows": [
{
"rowName": "1",
"type": "Detail",
"data": [
11,
2019,
"West Group",
10
]
},
{
"rowName": "2",
"type": "Detail",
"data": [
11,
2019,
"East Group",
10
]
},
{
"rowName": "3",
"type": "Detail",
"data": [
11,
2019,
"East Group",
10
]
},
{
"rowName": "Totals: ",
"type": "Total",
"data": [
null,
null,
null,
30
]
}
]
}
In order to get at the data in the 'data' array I currently have a 2 step process in T-SQL where I create a temp table, and insert the row key/values from '$.Rows' there. Then I can then select the individual columns for each row
CREATE TABLE #TempData
(
Id INT,
JsonData VARCHAR(MAX)
)
DECLARE #json VARCHAR(MAX);
DECLARE #LineageKey INT;
SET #json = (SELECT JsonString FROM Stage.Report);
SET #LineageKey = (SELECT LineageKey FROM Stage.Report);
INSERT INTO #TempData(Id, JsonData)
(SELECT [key], value FROM OPENJSON(#json, '$.rows'))
MERGE [dbo].[DestinationTable] TARGET
USING
(
SELECT
JSON_VALUE(JsonData, '$.data[0]') AS FiscalMonth,
JSON_VALUE(JsonData, '$.data[1]') AS FiscalYear,
JSON_VALUE(JsonData, '$.data[2]') AS Portfolio,
JSON_VALUE(JsonData, '$.data[3]') AS Rent
FROM #TempData
WHERE JSON_VALUE(JsonData, '$.data[0]') is not null
) AS SOURCE
...
etc., etc.
This works, but I want to know if there is a way to directly select the data values without the intermediate step of putting it into the temp table. The documentation and examples I've read seem to all require that the data have a name associated with it in order to access it. When I try and access the data directly at a position by index I just get Null.
I hope I understand your question correctly. If you know the columns names you need one OPENJSON() call with explicit schema, but if you want to read the JSON structure from $.columns, you need a dynamic statement.
JSON:
DECLARE #json nvarchar(max) = N'{
"report": "Property ETL",
"id": 2648,
"columns": [
{
"name": "Fiscal Month",
"dataType": "int"
},
{
"name": "Fiscal Year",
"dataType": "int"
},
{
"name": "Portfolio",
"dataType": "varchar(50)"
},
{
"name": "Rent",
"dataType": "int"
}
],
"rows": [
{
"rowName": "1",
"type": "Detail",
"data": [
11,
2019,
"West Group",
10
]
},
{
"rowName": "2",
"type": "Detail",
"data": [
11,
2019,
"East Group",
10
]
},
{
"rowName": "3",
"type": "Detail",
"data": [
11,
2019,
"East Group",
10
]
},
{
"rowName": "Totals: ",
"type": "Total",
"data": [
null,
null,
null,
30
]
}
]
}'
Statement for fixed structure:
SELECT *
FROM OPENJSON(#json, '$.rows') WITH (
[Fiscal Month] int '$.data[0]',
[Fiscal Year] int '$.data[1]',
[Portfolio] varchar(50) '$.data[2]',
[Rent] int '$.data[3]'
)
Dynamic statement:
DECLARE #stm nvarchar(max) = N''
SELECT #stm = CONCAT(
#stm,
N',',
QUOTENAME(j2.name),
N' ',
j2.dataType,
N' ''$.data[',
j1.[key],
N']'''
)
FROM OPENJSON(#json, '$.columns') j1
CROSS APPLY OPENJSON(j1.value) WITH (
name varchar(50) '$.name',
dataType varchar(50) '$.dataType'
) j2
SELECT #stm = CONCAT(
N'SELECT * FROM OPENJSON(#json, ''$.rows'') WITH (',
STUFF(#stm, 1, 1, N''),
N')'
)
PRINT #stm
EXEC sp_executesql #stm, N'#json nvarchar(max)', #json
Result:
--------------------------------------------
Fiscal Month Fiscal Year Portfolio Rent
--------------------------------------------
11 2019 West Group 10
11 2019 East Group 10
11 2019 East Group 10
30
Yes, it is possible without temporary table:
DECLARE #json NVARCHAR(MAX) =
N'
{
"report": "Property ETL",
"id": 2648,
"columns": [
{
"name": "Fiscal Month",
"dataType": "int"
},
{
"name": "Fiscal Year",
"dataType": "int"
},
{
"name": "Portfolio",
"dataType": "varchar(50)"
},
{
"name": "Rent",
"dataType": "int"
}
],
"rows": [
{
"rowName": "1",
"type": "Detail",
"data": [
11,
2019,
"West Group",
10
]
},
{
"rowName": "2",
"type": "Detail",
"data": [
11,
2019,
"East Group",
10
]
},
{
"rowName": "3",
"type": "Detail",
"data": [
11,
2019,
"East Group",
10
]
},
{
"rowName": "Totals: ",
"type": "Total",
"data": [
null,
null,
null,
30
]
}
]
}
}';
And query:
SELECT s.value,
rowName = JSON_VALUE(s.value, '$.rowName'),
[type] = JSON_VALUE(s.value, '$.type'),
s2.[key],
s2.value
FROM OPENJSON(JSON_QUERY(#json, '$.rows')) s
CROSS APPLY OPENJSON(JSON_QUERY(s.value, '$.data')) s2;
db<>fiddle demo
Or as a single row per detail:
SELECT s.value,
rowName = JSON_VALUE(s.value, '$.rowName'),
[type] = JSON_VALUE(s.value, '$.type'),
JSON_VALUE(s.value, '$.data[0]') AS FiscalMonth,
JSON_VALUE(s.value, '$.data[1]') AS FiscalYear,
JSON_VALUE(s.value, '$.data[2]') AS Portfolio,
JSON_VALUE(s.value, '$.data[3]') AS Rent
FROM OPENJSON(JSON_QUERY(#json, '$.rows')) s;
db<>fiddle demo 2