Using OCTAVE only...
How can I rerun the code automatically after it ends. Like I want to make a program in which if the input is incorrect value it will end the program and rerun again.
I tried that by writting there a file name and it works but this will only work until I change my file name.
You can wrap your main script in a wrapper script which performs the loop.
% In main.m
disp( 'Hello from main' );
Question = "Do you want to rerun? ";
Response = input( Question, 's');
% in wrapper.m
Response = 'yes';
while strcmp( Response, 'yes' )
main
end
Related
The following function works (it opens and moves the desired file to a new or preexisting directory). But, I receive an error message concerning line 11 of the function execute 'bwipeout '.expand(s:oldFileName). The error I receive is E93: More than one match for <the old file name>. I don't understand how this is possible because it has already successfully moved the file to the s:newFileName and the old file has been deleted. The new file's buffer doesn't have the same name as the old buffer. So, how would there be more than one match for the name of the old buffer?
command! -nargs=0 -bar MoveFile call s:functionMoveFile()
function s:functionMoveFile() abort
call dirvish#open("edit", 0)
let s:oldFileName = expand("%:p")
call inputsave()
let s:newFileName = input("Move file here: ",expand(s:oldFileName),"file")
call inputrestore()
if s:newFileName != '' && s:newFileName != s:oldFileName
execute 'sav '.fnameescape(s:newFileName)
let s:newFileDirectory = expand("%:p:h")
call delete(s:oldFileName)
execute 'Dirvish '.expand(s:newFileDirectory)
execute 'bwipeout '.expand(s:oldFileName)
endif
endfunction
I can prepend silent! to line 11 to avoid the error message. But, that isn't a proper fix. I don't know what else I should try because I am not asking vim to wipeout the new buffer and the old file's name doesn't match the new one. The command works as desired, but I would like to know what is incorrect about what I'm doing.
Thank you for your help.
I got a problem with running Octave function (ODE), I've tried already present solutions for this problem but nothing is working. I've also tried by saving my filename as egzamin.m but it too not worked.
Code from octave :
function dx=egzamin(x,t)
dx=zeros(4,1);
b=0;
g=9.81;
x1=x(1);
y1=x(2);
Vx=x(3);
Vy=x(4);
dx(1)=Vx;
dx(2)=Vy;
dx(3)=-b*Vx*sqrt(Vx.^2+Vy.^2);
dx(4)=-b*Vy*sqrt(Vx.^2+Vy.^2)-g;
endfunction
N=mod(291813,100);
x1=0;
y1=0;
Vx=20+N;
Vy=20+N;
t=0:0.01:500;
sol=lsode("egzamin",[x1,y1,Vx,Vy],t);
plot(sol(:,1),sol(:,2))
The error is :
error: 'x' undefined near line 5 column 4
error: called from
egzamin at line 5 column 3
Since the file starts with function, it is not a script file,
as explained in the doc:
Unlike a function file, a script file must not begin with the keyword
function
Add any statement (even dummy like 1;) before the function line to get a script file.
# dummy statement to get a script file instead of a function file
1;
function dx=egzamin(x,t)
g = 9.81;
Vx = x(3);
Vy = x(4);
dx = [Vx, Vy, 0, -g];
endfunction
N=mod(291813,100);
x1=0;
y1=0;
Vx=20+N;
Vy=20+N;
t=0:0.01:500;
sol=lsode("egzamin",[x1,y1,Vx,Vy],t);
plot(sol(:,1),sol(:,2))
A very clear explanation of what's going on is given here.
You need to save the function (thus from function to endfunction and naught else) as egzamin.m, and then execute the rest of the code in a script or at the command line. Alternatively, provided Octave does that the same as what MATLAB does nowadays, first put your script (N=(..) to plot()) and then the function.
This is necessary since you are defining your function first, so it doesn't have any inputs yet, as you don't define them until later. The function needs to have its inputs defined before it executes, hence you need to save your function separately.
You can of course save your "script" bit, thus everything which is currently below your function declaration, as a function as well, simply don't give it in- and outputs, or, set all the input parameters here as well. (Which I wouldn't do as it's the same as your
egzamin then.) e.g.
function []=MyFunc()
N=mod(291813,100);
x1=0;
y1=0;
Vx=20+N;
Vy=20+N;
t=0:0.01:500;
sol=lsode("egzamin",[x1,y1,Vx,Vy],t);
plot(sol(:,1),sol(:,2))
endfunction
As a homework assignment, I'm writing a code that uses the bisection method to calculate the root of a function with one variable within a range. I created a user function that does the calculations, but one of the inputs of the function is supposed to be "fun" which is supposed to be set equal to the function.
Here is my code, before I go on:
function [ Ts ] = BisectionRoot( fun,a,b,TolMax )
%This function finds the value of Ts by finding the root of a given function within a given range to a given
%tolerance, using the Bisection Method.
Fa = fun(a);
Fb = fun(b);
if Fa * Fb > 0
disp('Error: The function has no roots in between the given bounds')
else
xNS = (a + b)/2;
toli = abs((b-a)/2);
FxNS = fun(xns);
if FxNS == 0
Ts = xNS;
break
end
if toli , TolMax
Ts = xNS;
break
end
if fun(a) * FxNS < 0
b = xNS;
else
a = xNS;
end
end
Ts
end
The input arguments are defined by our teacher, so I can't mess with them. We're supposed to set those variables in the command window before running the function. That way, we can use the program later on for other things. (Even though I think fzero() can be used to do this)
My problem is that I'm not sure how to set fun to something, and then use that in a way that I can do fun(a) or fun(b). In our book they do something they call defining f(x) as an anonymous function. They do this for an example problem:
F = # (x) 8-4.5*(x-sin(x))
But when I try doing that, I get the error, Error: Unexpected MATLAB operator.
If you guys want to try running the program to test your solutions before posting (hopefully my program works!) you can use these variables from an example in the book:
fun = 8 - 4.5*(x - sin(x))
a = 2
b = 3
TolMax = .001
The answer the get in the book for using those is 2.430664.
I'm sure the answer to this is incredibly easy and straightforward, but for some reason, I can't find a way to do it! Thank you for your help.
To get you going, it looks like your example is missing some syntax. Instead of either of these (from your question):
fun = 8 - 4.5*(x - sin(x)) % Missing function handle declaration symbol "#"
F = # (x) 8-4.5*(x-sin9(x)) %Unless you have defined it, there is no function "sin9"
Use
fun = #(x) 8 - 4.5*(x - sin(x))
Then you would call your function like this:
fun = #(x) 8 - 4.5*(x - sin(x));
a = 2;
b = 3;
TolMax = .001;
root = BisectionRoot( fun,a,b,TolMax );
To debug (which you will need to do), use the debugger.
The command dbstop if error stops execution and opens the file at the point of the problem, letting you examine the variable values and function stack.
Clicking on the "-" marks in the editor creates a break point, forcing the function to pause execution at that point, again so that you can examine the contents. Note that you can step through the code line by line using the debug buttons at the top of the editor.
dbquit quits debug mode
dbclear all clears all break points
I currently have a MATLAB function that looks like this:
function outfile=multi_read(modelfrom,modelto,type)
models=[modelfrom:1:modelto];
num_models=length(models);
model_path='../MODELS/GRADIENT/'
for id=1:num_models
fn=[model_path num2str(models(id)) '/']; %Location of file to be read
outfile=model_read(fn,type); %model_read is a separate function
end
end
The idea of this function is to execute another function model_read for a series of files, and output these files to the workspace (not to disk). Note that the output from model_read is a structure! I want the function to save the file to the workspace using sequential names, similar to typing:
file1=multi_read(1,1,x)
file2=multi_read(2,2,x)
file3=multi_read(3,3,x)
etc.
which would give file1, file2 and file3 in the workspace, but instead by recalling the command only once, something like:
multi_read(1,3,x)
which would give the same workspace output.
Essentially my questions is, how do I get a function to output variables with multiple names without having to recall the function multiple times.
As suggested in the comment I would try this approach which is more robust, at least IMHO:
N = tot_num_of_your_files; %whatever it is
file = cellfun(#(i)multi_read(i,i,x),mat2cell(1:N,1,ones(1,N)),...
'UniformOutput' , false); %(x needs to be defined)
You will recover objects by doing file{i}.
Here is code to do what you ask:
for i = 1:3
istr=num2str(i)
line = ['file' istr '= multi_read(' istr ', ' istr ', x)']
eval(line)
end
Alternatively, here is code to do what you should want:
for i = 1:3
file{i} = multi_read(i,i,x)
end
I have caught myself in a issue, I know its not that difficult but I couldnt figure out how to implement it. I have an m file that looks like
clear;
PVinv.m_SwF=20e3
for m=1:1:70;
PVinv.m_SwF=PVinv.m_SwF+1e3;
Lmin = PVinv.InductanceDimens();
Wa_Ac = PVinv.CoreSizeModel();
PVinv.CoreSelect(Wa_Ac);
[loss_ind_core,loss_ind_copper] = PVinv.InductorLossModel(PVinv.m_L_Selected);
Total_Inductor_Loss=loss_ind_core+loss_ind_copper
plot(PVinv.m_SwF,Total_Inductor_Loss,'--gs');
hold on
xlim([10e3 90e3])
set(gca,'XTickLabel',{'10';'20';'30';'40';'50';'60';'70';'80';'90'})
grid on
xlabel('Switching Frequency [kHz]');
ylabel('Power loss [W]');
end
And the function that is of interest is CoreSelect(Wa_Ac)
function obj = CoreSelect(obj, WaAc)
obj.m_Core_Available= obj.m_Core_List(i);
obj.m_L_Selected.m_Core = obj.m_Core_Available;
end
I want to change the value of i from obj.m_Core_List(1) to obj.m_Core_List(27) within that for loop of main m file. How can I get the value of the function coreselect when I call it in main m file
For eg for m=1 to 70 I want the function to take the value of i=1 then execute till plot command and then same with but i=2 and so on
Any suggestion would be really helpful
I'm not sure I understand your question perfectly, but I think you want to pass an index i to the CoreSelect function, and loop i from 1 to 27 outside of the function. Try this:
function obj = CoreSelect(obj, WaAc, i)
...
end
for i=1:27,
PVInv.CoreSelect(WaAc,i);
end