This question already has answers here:
How to remove the stripes that appears when using linear gradient property [duplicate]
(2 answers)
Closed 1 year ago.
I have been learning CSS and I was trying the
linear-gradient().
This works fine when I use "to right".
background-image: linear-gradient(to right, #92EFFD, ##4E65FF);
My actual code is:
<!DOCTYPE html>
<html lang="en">
<head>
<style>
body{
background-image: linear-gradient(to right, #92EFFD, #4E65FF)
}
</style>
</head>
<body>
</body>
</html>
But when I remove "to right" it's like:
background-image: linear-gradient( #92EFFD, #4E65FF);
My actual code in this case:
<!DOCTYPE html>
<html lang="en">
<head>
<style>
body{
background-image: linear-gradient(#92EFFD, #4E65FF)
}
</style>
</head>
<body>
</body>
</html>
The out put is this.
What I wanted is to set the linear gradient top to bottom but it is not working
Am I doing wrong anywhere or my code is wrong. Can you help me out?
To set gradient position you can simply use "deg" you can open inspect element in your browser to adjust according to your requirement.
Default position is top to bottom
background-image: linear-gradient(#92EFFD, #4E65FF);
background-image: linear-gradient(180deg , #92EFFD, #4E65FF);
Try this tool if you want, I usually pick it for the CSS gradients and it helps me a lot!
https://cssgradient.io/
Related
This question already has answers here:
Adding external CSS in an HTML file
(5 answers)
Closed 2 years ago.
So I tried displaying an image by making a selector class with a background-image attribute then calling it using the <div> tag. The first time the selector class was between the <head> tags. Everything seems to work fine:
<html>
<head>
<meta name="viewport" content="width=device-width, initial-scale=1">
<style>
body, html {
margin: 0;
}
.bg {
/* The image used */
background-image: url("images.jpeg");
/* Full height */
height: 100%;
/* Center and scale the image nicely */
background-position: center;
background-size: cover;
}
</style>
</head>
<body>
<div class="bg"></div>
</body>
</html>
But when I put the selector class inside a separate CSS file, it doesn’t seem to work. Here is the code for the HTML file:
<html>
<head>
<meta name="viewport" content="width=device-width, initial-scale=1">
<style>
body, html {
margin: 0;
}
</style>
</head>
<body>
<div class="bg"></div>
</body>
</html>
Here’s for the CSS:
.bg {
/* The image used */
background-image: url("images.jpeg");
/* Full height */
height: 100%;
/* Center and scale the image nicely */
background-position: center;
background-size: cover;
}
Could someone please kindly tell me what I did wrong? I thank you in advance!
Don't forget to import your separate css file on your html page :
<link rel="stylesheet" href="style.css">
And be careful for the right path.
Add a link tag inside of head in your HTML to connect your styles to the HTML.
<head>
<link rel="stylesheet" href="xxx.css">
</head>
Replace xxx.css with the path to your css file.
Check the Mozilla docs for details.
I tried all possible answers but nothing works. When I put this code
I have a gray screen only. The picture is in the same folder which I use for code. I use notepad. I am a beginner.
I've tried all your answers but nothing works only gray screen. The image works when I put just src=(image.png) but not working if I want a background with URL(image.png)
You'll need to add the body tag, like so:
<html>
<head>
<title> Piotr#Ewa World </title>
<style>
body {
background: url("IMG_20180505_204226.png");
background-size: contain; /* Or "cover" */
background-repeat: no-repeat;
}
</style>
</head>
<body>
</body>
</html>
So I've been searching for a bit why my background is not showing up, ill start with my bg css:
body {
background-image: linear-gradient
(to right, #0F2027, #203A43, #2C5364, #2C5364, #203A43, #0F2027) !important;
}
When I inspect element my html and body both have a width of 0px which is why it's not showing I guess.
I use Bootstrap 3 and removing it from my page does fix the issue but I use Bootstrap for a lot so that doesn't really work for me.
One cheap fix I use currently is creating a span inside the body tag with a single character and then making it's opacity 0 and hiding it in a corner but obviously this should only be temporary.
I've tried background-color which does work so I'm guessing there is some conflict between Bootstrap 3 and background-image or linear-gradient.
Does anyone know of a proper way to fix this issue?
EDIT: As pointed out in the comments, I realize if the body width is 0px it can't show my bg but what's causing my body width to be 0px?
EDIT2: Added HTML for reproduction:
<!DOCTYPE HTML>
<htmL>
<head>
<title>Index</title>
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.min.css" />
<link rel="stylesheet" href="css/mycss.css" />
</head>
<body>
</body>
</htmL>
What is causing this behaviour is the rule margin:0 from normalize.less.
If you set the margin of the body to any value except 0, the background-image will render.
body {
margin: 1px;
background-image: linear-gradient(to right, #0F2027, #203A43, #2C5364, #2C5364, #203A43, #0F2027);
}
You just need to remove a space after "linear-gradient". This css property should be written like this linear-gradient() and in the brackets you can put your code. The overall code should be like below.
body {background-image: linear-gradient(to right, #0F2027, #203A43, #2C5364, #2C5364, #203A43, #0F2027) !important;}
I'm a veteran to CSS and HTML, but never before have I seen this problem. I have the background image, CSS, and HTML files placed properly. I believe I have all the code right too since I checked it against a site I already made, but my image will not appear for anything.
CSS
body {
background-image: url(am-stage.png);
background-repeat: no-repeat;
background-color: black;
background-size: 100% 100%;
}
HTML
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title> AM </title>
<link rel="stylesheet" type="text/css" href="css.css">
</head>
<body>
</body>
</html>
EDIT: Chrome is giving an error saying that the CSS file can't be found. Not sure why though. The CSS is in the same directory as the HTML and the image.
I figured it out, Sublime wasn't saving the CSS as a CSS file. I told it to save as a CSS, but it wasn't adding the extension this time for some reason. I just chose CSS and manually put in the .css at the end and now it's working.
This question already has answers here:
Making gradient background fill page with css
(7 answers)
Closed 6 years ago.
I have a simple HTML page. I want to make background of the page gradient. I have written following code but instead of creating a single gradient from black to white running from top of the page to the bottom of the page, the browser (chrome) is creating multiple small repeating patterns of the gradient. What am I doing wrong?
<!DOCTYPE html>
<html lang="en" xmlns:font-variant="http://www.w3.org/1999/xhtml">
<head>
<meta charset="UTF-8">
<title>HTML Test</title>
<style type="text/css" media="screen">
body{
background-color:#000000;
background-image:linear-gradient(#000000,#ffffff);
}
</style>
</head>
<body>
</body>
</html>
Just add:
body, html {
height: 100% !important;
}
This will span the body across the whole viewport height.
need to specified body height or need some dummy content. then your code work fine.
<style type="text/css" media="screen">
body{
background-color:#000000;
background-image:linear-gradient(#000000,#ffffff);
height:700px;
}
</style>