3 word sentence need to reverse only middle word without using any string inbuilt function like charAt(), toCharArray(), split() in java.
Example:
input: "Here we go"
output: "Here ew go"
you can user StringBuilder to convert a string to char[] and bypass toCharArray(), then modify it.
Since technically String constructor is also a inbuilt, you need to print directly from that char[]
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I need to convert to string. Here is my code
single_para = doc.paragraphs[1]
str(single_para)
Use doc.paragraphs[1].text. This returns the text of the paragraph as a string.
I would like to parse json string using JObject.Parse() of NewtonSoft.Json. Assume that the json string is like this:
{"json":"{\"count\":\"123\"}"}
The result of jObject.First.ToString() is "json": "{\"count\":\"123\"}".
The result of jObject["json"].ToString() is {"count":"123"}. Enumerating gets the same result as this.
The testing code I used is like this.
[TestMethod()]
public void JsonParseTest()
{
var json = "{\"json\":\"{\\\"count\\\":\\\"123\\\"}\"}";
var jObject = JObject.Parse(json);
Console.WriteLine($"json : {json}");
Console.WriteLine($"jObject.First.ToString() : {jObject.First}");
Console.WriteLine($"jObject[\"json\"].ToString() : {jObject["json"]}");
}
We can see that enumerating of jObject will lose the character '\'. What is the problem? I would be appreciated for any suggestion :)
EDIT 1
The version of NewtonSoft is 12.0.3 released in 2019.11.09.
The parser isn't loosing anything. There is no literal \ in your example. The backslashes are purely part of the JSON syntax to escape the " inside the string vlue. The value of the key json is {"count":"123"}.
If you want to have backslashes in that value (however I don't see why you would want that), then you need add them, just like you added them in your C# string (C# and JSON happen to have the same escaping mechanism):
{"json":"{\\\"count\\\":\\\"123\\\"}"}
with leads to the C# code:
var json = "{\"json\":\"{\\\\\\\"count\\\\\\\":\\\\\\\"123\\\\\\\"}\"}";
So I'm writing a JSON parser in OCaml, and I need to get a slice of a string. More specifically, I need to get the first n characters of a string so I can pattern-match with them.
Here's an example string:
"null, \"field2\": 25}"
So, how could I use just a couple lines of OCaml code to get just the first 4 characters (the null)?
P.S. I've already thought about using something like input.[0..4] but I'm not entirely sure how that works, I'm reasonably new to OCaml and the ML family.
Using build-in sub function should do the work:
let example_string = "null, \"field2\": 25}"
(*val example_string : string = "null, \"field2\": 25}" *)
let first_4 = String.sub example_string 0 4
(*val first_4 : string = "null" *)
I suggest you to look at official documentation:
https://caml.inria.fr/pub/docs/manual-ocaml/libref/String.html
And if you are not doing this for self teaching I would strongly suggest using one of available libraries for the purpose, such as yojson (https://ocaml-community.github.io/yojson/yojson/Yojson/index.html) for example.
We use Freemarker to transform one JSON to another. The input JSON is something like this:
{"k1": "a", "k2":"line1. \n line2"}
Post using the Freemarker template, the JSON is converted to:
{ \n\n "p1": "a", \n\n "p2": "line1. \n line2"}
Here is the logic we use to do the transformation
final Map<String, Object> input = JsonConverter.convertFromJson(input, Map.class);
final Template template = freeMarkerConfiguration.getTemplate("Template1.ftl");
final Writer out = new StringWriter();
template.process(input, out);
out.flush();
final String newlineFilteredResult = new JSONObject(out.toString).toString();
The conversion to JSON object fails due to a newline character inside a string for key k2 and gives the following exception:
Caused by: org.json.JSONException: Unterminated string at ...
I tried using the following but nothing works:
1. JSONObject.quote
2. JSONValue.escape
3. out.toString().replaceAll("[\n\r]+", "\\n");
I get the following exception due to the newline characters at the beginning as well:
Caused by: org.json.JSONException: Missing value at 1 [character 2 line 1]
Could someone please point me in the correct direction.
Edit
After further clarification from OP he had "${key}": "${value}" in his freemarker template and ${value} could contain line brakes. The solution in this case is to use ${value?json_string}.
Starting from FreeMarker 2.3.32 you can write "${key}": ${value?c} instead of "${key}": "${value}", because if the left-side of ?c is a string, now instead of failing, it quotes and escapes the string. Thus you don't even have to know if the left-side is a number/boolean, which must not be quoted (and ?c won't quote them), or a string, which must be quoted, as it's automatic.
Also, if the left-value is known to be missing/null sometimes, them ?cn will handle that case by printing a null literal.
Also, check out the c_format setting for best results, but by default string formatting is JSON compatible, so using ?c will be an improvement even without setting that.
I have a string that needs to read from the database and sent as JSON. How can I make sure all quotes are escaped properly and handle any other characters that might make the String invalid JSON?
So for example I have the following code..
def jsonFormatted = new groovy.json.JsonBuilder(products:finalList).toPrettyString()
And finalList variable is an array of HashMaps, where each Map has a key value pair, for example..
"Product Id" -> "555"
"Product Name" -> "32" Flat Screen TV"
Because that open quote in product name is not escaped, the program which reads the JSON on the other end breaks.
Any solution that uses JsonBuilder or JsonSlurper libraries would be optimal.
It seems the only problem was I was calling toPrettyString() instead of toString() of JsonBuilder. Calling toString made JsonBuilder to escape that open quote. Special thanks to Gerd Castan for pointing this out.