MySQL Error Code 1064 from workbench when create a table - mysql

I am trying to create a table using MySQL workbench, but the error msg shows this error. Check online, it shows " often due to using reserved words, missing data in the database, or mistyped/obsolete commands. " But, I did not use any reserved words or missing data. So not sure why this error happens. Thanks!
Operation failed: There was an error while applying the SQL script to the database.
Executing:
CREATE TABLE `assign`.`users` (
`id` INT NOT NULL AUTO_INCREMENT,
`email` VARCHAR(128) NOT NULL,
`nickname` VARCHAR(255) NOT NULL,
`password` VARCHAR(128) NOT NULL,
`created_at` VARCHAR(45) NOT NULL DEFAULT 'CURRENT_TIMESTAMP()',
PRIMARY KEY (`id`),
UNIQUE INDEX `email_UNIQUE` (`email` ASC) VISIBLE)
ENGINE = InnoDB
DEFAULT CHARACTER SET = utf8;
ERROR 1064: You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near ')
ENGINE = InnoDB
DEFAULT CHARACTER SET = utf8' at line 8

Related

Error 1064 when importing SQL generated from MySQL Workbench forward engineering

I am trying to import a schema into MySQL (MariaDB 10.1.36) and I am getting the above error. I also tried direct forward engineering in MySQL Workbench but the results are the same.
ERROR 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near ')
ENGINE = InnoDB
Sample code that fails is:
CREATE TABLE IF NOT EXISTS `example`.`adhere` (
`adhere_id` BIGINT(20) NOT NULL AUTO_INCREMENT,
`description` VARCHAR(100) NOT NULL,
`id_uuid` VARCHAR(36) NULL,
PRIMARY KEY (`adhere_id`),
INDEX `ix_tmp_autoinc` (`adhere_id` ASC) VISIBLE)
ENGINE = InnoDB
AUTO_INCREMENT = 19
DEFAULT CHARACTER SET = latin1;
I tried changing the backticks into single quotes in vain, I later removed them to same result. The expectation is to have the table created so do the rest structured like so.
remove the VISIBLE word
DEMO
CREATE TABLE IF NOT EXISTS `example`.`adhere`
(
`adhere_id` BIGINT(20) NOT NULL AUTO_INCREMENT,
`description` VARCHAR(100) NOT NULL,
`id_uuid` VARCHAR(36) NULL,
PRIMARY KEY (`adhere_id`),
INDEX `ix_tmp_autoinc` (`adhere_id` ASC)
)
Check that your version of mariadb supports invisible/visible indexes here https://mariadb.com/kb/en/library/invisible-columns/ and if not turn off the option in mysql workbench here https://dev.mysql.com/doc/workbench/en/wb-table-editor-indexes-tab.html

Generated SQL script from workbench doesn`t work on MariaDB server

I created a scheme in mysql workbench and exported this scheme into SQL code.
.
When I want to generate table user on my server I am getting error.
Script:
CREATE TABLE IF NOT EXISTS 'user' (
'id' INT NOT NULL AUTO_INCREMENT,
'registerDate' TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
'login' VARCHAR(255) NOT NULL,
'password' VARCHAR(255) NOT NULL,
'status' TINYINT NOT NULL,
'credits' INT NOT NULL DEFAULT 0,
PRIMARY KEY ('id'),
UNIQUE INDEX 'login_UNIQUE' ('login' ASC) VISIBLE)
ENGINE = InnoDB;
Error #1064 - You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near ''user' ( 'id' INT NOT NULL AUTO_INCREMENT, 'registerDate' TIMESTAMP NOT NU' at line 1
I dont understand where is an error? I didnt see anything wrong.
Version on server: 10.1.32-MariaDB

MySQL Workbench schema synchronization causing error 1064

I'm using MySQL Workbench to try to create a schema for my database. When I try to sync it up to the server, I'm getting an error 1064. Here's the full log:
Executing SQL script in server
ERROR: Error 1064: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'VISIBLE,
PRIMARY KEY (`id`),
CONSTRAINT `buildings_rel`
FOREIGN KEY (`bu' at line 10
SQL Code:
CREATE TABLE IF NOT EXISTS `rentals`.`apartments` (
`beds` INT(11) NOT NULL,
`baths` INT(11) NOT NULL,
`area` INT(11) NOT NULL,
`price_min` INT(11) NOT NULL,
`price_max` INT(11) NOT NULL,
`available_now` BIT(1) NOT NULL,
`building_id` INT(11) NULL DEFAULT NULL,
`id` INT(11) NOT NULL AUTO_INCREMENT,
INDEX `buildings_rel_idx` (`building_id` ASC) VISIBLE,
PRIMARY KEY (`id`),
CONSTRAINT `buildings_rel`
FOREIGN KEY (`building_id`)
REFERENCES `rentals`.`buildings` (`id`)
ON DELETE NO ACTION
ON UPDATE NO ACTION)
ENGINE = InnoDB
DEFAULT CHARACTER SET = utf8
I don't really know SQL so I'm having trouble figuring out what exactly is wrong here. I expected the Workbench to create correct code, I'm a little surprised that it seems to be this glitchy. Any help appreciated, thank you.
Got it! As some of the commentors said, I had to set a different target version in the MySQL Workbench settings. Thanks!
Change the Default Target MySQL Version to match your mysql version.
Home -> Edit -> Preferences -> Modeling -> MySQL -> Default Target MySQL Version

MySQL: SQL Syntax and other errors only in Linux server

Please have a look in below SQL code
DROP TABLE IF EXISTS `xxx`.`reminder` ;
CREATE TABLE IF NOT EXISTS `xxx`.`reminder` (
`idreminder` INT NOT NULL AUTO_INCREMENT,
`patient_idpatient` INT NOT NULL,
`remind_about` TEXT NOT NULL,
`reminder_time` TIME NOT NULL,
`reminder_date` DATE NOT NULL,
`active` TINYINT(1) NOT NULL,
`repeat_action` TINYINT(1) NOT NULL,
`date_created` TIMESTAMP NULL,
`last_updated` TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (`idreminder`),
INDEX `fk_Reminder_patient1_idx` (`patient_idpatient` ASC),
CONSTRAINT `fk_Reminder_patient1`
FOREIGN KEY (`patient_idpatient`)
REFERENCES `myglukose`.`patient` (`idpatient`)
ON DELETE CASCADE
ON UPDATE NO ACTION)
ENGINE = InnoDB;
When I copy this into PhpMyAdmin, I get the following error
#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '`
I have 2 questions.
I really don't spot the error, what is it?
Important thing is that these auto generated SQL code from MySQL Work Bench!! All of these worked very well in Windows with XAMPP and all these issues are with Ubuntu running LAMP.Not only this error,in some tables I am also getting the error #1293 - Incorrect table definition; there can be only one TIMESTAMP column with CURRENT_TIMESTAMP in DEFAULT or ON UPDATE clause
Why all of this with Ubuntu (14.04)? I installed LAMP by following this - http://devoncmather.com/setting-aws-ec2-instance-lamp-git/
How to fix this, if any issue with installation, any recommended alternate tutorial?

PhPMyAdmin Error #1064; Syntax Error

I'm trying to put together a MySQL database for a forum, And when I try to make a section table I keep encountering a problem
#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'TYPE = INNODB' at line 7
Here's the code:
CREATE TABLE sections (
sect_id INT(8) NOT NULL AUTO_INCREMENT,
sect_name VARCHAR(255) NOT NULL,
sect_desc VARCHAR(255) NOT NULL,
UNIQUE INDEX sect_name_unique (sect_name),
PRIMARY KEY (sect_id)
) TYPE=INNODB;
Use the following query
CREATE TABLE IF NOT EXISTS sections (
sect_id INT(8) NOT NULL AUTO_INCREMENT,
sect_name VARCHAR(255) NOT NULL,
sect_desc VARCHAR(255) NOT NULL,
UNIQUE INDEX sect_name_unique (sect_name),
PRIMARY KEY (sect_id)
) ENGINE=InnoDB
To mention the type of engine use ENGINE keyword.