I guess I can't explain my problem properly. I want to explain this to you with a picture.
Picture 1
In the first picture you can see the hashtags in the trend section. These hashtags are searched for the highest total and it is checked whether the date has passed. If valid data is available, the first 5 hashtags are taken.
Picture 2
In the second picture, it is checked whether the posts in the hashtag are in the post, if any, the oldest date value is taken, LIMIT is set to 1 and the id value from the oyuncular table is matched with sid. Thus, the name of the person sharing can be accessed.
Picture 3
My English is a little bad, I hope I could explain it properly.
SELECT
social_trend.hashtag,
social_trend.total,
social_trend.tarih,
social_post.sid,
social_post.tarih,
social_post.post,
oyuncular.id,
oyuncular.isim
FROM
social_trend
INNER JOIN
social_post
ON
social_post.post LIKE '%social_trend.hashtag%' ORDER BY social_post.tarih LIMIT 1
INNER JOIN
oyuncular
ON
oyuncular.id = social_post.sid
WHERE
social_trend.tarih > UNIX_TIMESTAMP() ORDER BY social_trend.total DESC LIMIT 5
YOu should use a sibquery
and add a proper join between subqiery and social_trend
(i assumed sing both sid)
SELECT
social_trend.hashtag,
social_trend.total,
social_trend.tarih,
t.sid,
t.tarih,
t.post,
oyuncular.id,
oyuncular.isim
FROM (
select social_post.*
from social_post
INNER JOIN social_trend ON social_post.post LIKE concat('%',social_trend.hashtag,'%' )
ORDER BY social_post.tarih LIMIT 1
) t
INNER JOIN social_trend ON social_trend.hashtag= t.post
INNER JOIN oyuncular ON oyuncular.id = t.sid
WHERE
social_trend.tarih > UNIX_TIMESTAMP() ORDER BY social_trend.total DESC LIMIT 5
but looking to your new explanation and img seems you need
SELECT
t.hashtag,
t.total,
t.tarih_trend,
t.sid,
t.tarih,
t.post,
oyuncular.id,
oyuncular.isim
FROM (
select social_post.sid
, social_post.tarih
, social_post.post
, st.hashtag
, st.total
, st.tarih tarih_trend
from social_post
INNER JOIN (
select * from social_trend
WHERE social_trend.tarih > UNIX_TIMESTAMP()
order by total DESC LIMIT 5
) st ON social_post.post LIKE concat('%',st.hashtag,'%' )
ORDER BY social_post.tarih LIMIT 5
) t
INNER JOIN oyuncular ON oyuncular.id = t.sid
Related
This almost seems like a scope issue- the select statement in the subquery doesn't recognize table 'candidate':
SELECT
candidate.id AS id,
candidate.image AS image,
candidate.name AS name,
candidate.party AS party,
player.order AS player_order,
c_pcts.pct AS pct
FROM `candidate`
INNER JOIN players player ON player.candidate_id = candidate.id
INNER JOIN lineups lineup ON player.lineup_id = lineup.id
INNER JOIN (
SELECT
pct
FROM candidate_pcts p
INNER JOIN weekly_game game ON p.weekly_game_id = (
SELECT id FROM weekly_game ORDER BY date DESC LIMIT 1
) WHERE p.candidate_id = candidate.id
) c_pcts
WHERE lineup.id = '31'
ORDER BY player.order ASC
gives the error: "Unknown column 'candidate.id' in 'where clause'." If instead of "FROM candidate_pcts p" I put
FROM candidate_pcts p, candidate c
then it doesn't see 'p.weekly_game_id' ...huh?
Seems like I need to identify the 'candidate' table for the subquery somehow but everything I'm trying leads me only further astray. And I have tried a mess of things: order of the tables, explicitly identifying them everywhere i could think of, backticks. I should note that the nested subquery works like a charm. Here it is again:
SELECT
pct
FROM `candidate_pcts`
INNER JOIN weekly_game game ON candidate_pcts.weekly_game_id = (
SELECT id FROM weekly_game ORDER BY date DESC LIMIT 1
) WHERE candidate_pcts.candidate_id = '5'
with a hardcoded an id value there, of course. I can supply database structure if needed here, but this is long already. The 'weekly_game' table is simply a set of scores for each candidate each week and we only want the most recent week's score, thus the 'ORDER BY date DESC LIMIT 1' clause.
Thanks very much for your time.
Tables:
table candidate: {id, image, name, party}
table candidate_pcts: {id, candidate_id, pct, weekly_game_id}
table lineups: {id, date, user_id}
table players: {id,candidate_id,lineup_id,order}
table weekly_game: {id,date}
You are basically on the right track around the problem. In essence the nested sub-select does not know about candidate.id. It you break apart the query and just look at the sub-select in question:
SELECT
pct
FROM candidate_pcts p
INNER JOIN weekly_game game ON p.weekly_game_id = (
SELECT id FROM weekly_game ORDER BY date DESC LIMIT 1
) WHERE p.candidate_id = candidate.id
You can see there is NO reference whatsoever in that query to the candidate table other than in your where clause, thus this is an unknown column.
Since a subselect is, in essence, made before the outer select that references it, the subselect must be a standalone, executable query.
Thanks to all, especially Mike for that excellent explanation. What I did was restructured the query like so:
SELECT
candidate.id AS id,
candidate.image AS image,
candidate.name AS name,
candidate.party AS party,
player.order AS player_order,
pcts.pct AS pct
FROM `candidate`
INNER JOIN players player ON player.candidate_id = candidate.id
INNER JOIN lineups lineup ON player.lineup_id = lineup.id
LEFT JOIN (
SELECT
p.candidate_id AS pct_id, pct AS pct
FROM candidate_pcts p
INNER JOIN weekly_game game ON p.weekly_game_id = (
SELECT id FROM weekly_game ORDER BY date DESC LIMIT 1
)
) pcts
ON pct_id = candidate.id
WHERE lineup.id = '$lineup_id'
ORDER BY player.order ASC
I have property pictures in table with their sort_order starting from 0 to number of pictures.
What I would like to do is select pictures but I would like it to start from 2.
My approach was:
SELECT * FROM property_photos AS pp1
JOIN property_photos AS pp2 ON pp1.p_id = pp2.p_id
where pp2.sort_order =2
and pp2.sort_order <2
and pp1.sort_order >2
and pp1.p_id = 3
So what I am trying to gain here is the sort order would be like 2,0,1,3,4,5,6,7
so I need a self join but my query doesn't work
you don't need a join on this,
SELECT *
FROM property_photos
WHERE p_id = 3
ORDER BY (sort_order = 2) DESC, sort_order
I have a query which does the job but instead of the trans_inventory (which is an ID of the location) I need to get the location_name.
This one is working to get the id
SELECT *
FROM {TABLE}
WHERE trans_product = 646
ORDER BY trans_date2 DESC Limit 1
But I wonder if I can do it this way, somehow embed the location table, I have tried but below doesn't work
SELECT *, site_location.location_name
FROM site_trans
cross join
(select *
From site_location)
site_location
WHERE trans_product=646 ORDER BY trans_date2 DESC Limit 1
sl.location in the JOIN must be the site_location location id field name - I used locastion_id but it might be likely id as well. I used LEFT JOIN to avoid missing site_trans in case there is no matching location id.
SELECT s.*, sl.location_name
FROM site_trans AS s
LEFT JOIN site_location AS sl ON sl.location_id = s.location_id
WHERE s.trans_product=646
ORDER BY s.trans_date2 DESC
Limit 1
This query below is perfect in producing the result for horse_id = 1 ... but I want to do this for all horses in the database. Can anyone share with me how to tweak this query so I can do that?
SELECT figures.entry_id,
max(figures.beyer)
FROM
( SELECT hrdb_lines.horse_id,
hrdb_entries.entry_id,
hrdb_lines.beyer
FROM hrdb_entries
INNER JOIN hrdb_lines
ON hrdb_lines.horse_id = hrdb_entries.horse_id
WHERE hrdb_lines.horse_id = 1
ORDER BY hrdb_lines.line_date DESC
LIMIT 2
) as figures
Perhaps I'm doing it all wrong too.
I think the following would generate the desired results:
SELECT `entry_id`, `beyer`
FROM (SELECT hrdb_entries.entry_id,
MAX( hrdb_lines.beyer )
FROM hrdb_entries
INNER JOIN hrdb_lines
ON hrdb_lines.horse_id = hrdb_entries.horse_id
GROUP BY hrdb_lines.horse_id
ORDER BY hrdb_lines.line_date DESC
) AS figures
If I'm understanding your question, something like this should be close:
SELECT
figures.horse_id,
figures.entry_id,
max(figures.beyer)
FROM
(SELECT
hrdb_lines.horse_id,
hrdb_entries.entry_id,
hrdb_lines.beyer
FROM hrdb_entries
INNER JOIN hrdb_lines ON hrdb_lines.horse_id = hrdb_entries.horse_id
ORDER BY hrdb_lines.line_date DESC
) as figures
GROUP BY figures.horse_id
One option to limit the MAX to just the most recent 2 beyer fields is to add a row number to the results and only include rows 1 and 2.
SELECT
figures.horse_id,
figures.entry_id,
max(figures.beyer)
FROM
(SELECT
#rn:=if(#prev_horse_id=horse_id,#rn+1,1) rn,
hrdb_lines.horse_id,
hrdb_entries.entry_id,
hrdb_lines.beyer,
#prev_horse_id:=hrdb_lines.horse_id
FROM hrdb_entries
INNER JOIN hrdb_lines ON hrdb_lines.horse_id = hrdb_entries.horse_id
INNER JOIN (SELECT #rn:=0) r
ORDER BY hrdb_lines.horse_id, hrdb_lines.line_date DESC
) as figures
WHERE rn <= 2
GROUP BY figures.horse_id
im trying to get my query to group rows by month and year from the assignments table, and count the number of rows that has a certain value from the leads table. they are linked together as the assignments table has an id_lead field, which is the id of the row in the leads table.
d_new would be a count of the assignments for leads for the month whose website is newsite.com
d_subprime would be a count of the assignments for leads for the month whose website is not newsite.com
here are the tables being used:
`leads`
id (int)
website (varchar)
`assignments`
id_lead (int)
date_assigned (int)
heres my query which is not working:
SELECT
MONTHNAME(FROM_UNIXTIME(a.date_assigned)) as d_month,
YEAR(FROM_UNIXTIME(a.date_assigned)) as d_year,
(select COUNT(*) from leads where website='newsite.com' ) as d_new,
(select COUNT(*) from leads where website!='newsite.com') as d_subprime
FROM assignments as a
left join leads as l on (l.id = a.id_lead)
where id_dealership='$id_dealership2'
GROUP BY
d_month,
d_year
ORDER BY
d_year asc,
MONTH(FROM_UNIXTIME(a.date_assigned)) asc
$id_dealership is a variable containing a id of the dealership im trying to view the count for.
any help would be greatly appreciated.
You can sort of truncate your timestamps to months and use the obtained values for grouping, then derive the necessary date parts from them:
SELECT
YEAR(d_yearmonth) AS d_year,
MONTHNAME(d_yearmonth) AS d_month,
…
FROM (
SELECT
LAST_DAY(FROM_UNIXTIME(a.date_assigned)) as d_yearmonth,
…
FROM assignments AS a
LEFT JOIN leads AS l ON (l.id = a.id_lead)
WHERE id_dealership = '$id_dealership2'
GROUP BY
d_yearmonth
) AS s
ORDER BY
d_year ASC,
MONTH(d_yearmonth) ASC
Well, LAST_DAY() doesn't really truncate a timestamp, but it does turn all the values belonging to the same month into the same value, which is basically what we need.
And I guess the counts should be related to the rows you are actually selecting, which is not what your subqueries are. Something like this might do:
…
COUNT(d.website = 'newsite.com' OR NULL) AS d_new,
/* or: COUNT(d.website) - COUNT(NULLIF(d.website, 'newsite.com')) AS d_new */
COUNT(NULLIF(d.website, 'newsite.com')) AS d_subprime
…
Here's the entire query with all the modifications mentioned:
SELECT
YEAR(d_yearmonth) AS d_year,
MONTHNAME(d_yearmonth) AS d_month,
d_new,
d_subprime
FROM (
SELECT
LAST_DAY(FROM_UNIXTIME(a.date_assigned)) as d_yearmonth,
COUNT(d.website = 'newsite.com' OR NULL) AS d_new,
COUNT(NULLIF(d.website, 'newsite.com')) AS d_subprime
FROM assignments AS a
LEFT JOIN leads AS l ON (l.id = a.id_lead)
WHERE id_dealership = '$id_dealership2'
GROUP BY
d_yearmonth
) AS s
ORDER BY
d_year ASC,
MONTH(d_yearmonth) ASC
This should do the trick:
SELECT
YEAR(FROM_UNIXTIME(a.date_assigned)) as d_year,
MONTHNAME(FROM_UNIXTIME(a.date_assigned)) as d_month,
l.website,
COUNT(*)
FROM
assignments AS a
INNER JOIN leads AS l on (l.id = a.id_lead) /*are you sure, that you need a LEFT JOIN?*/
WHERE id_dealership='$id_dealership2'
GROUP BY
d_year, d_month, website
/*an ORDER BY is not necessary, MySQL does that automatically when grouping*/
If you really need a LEFT JOIN, be aware that COUNT() ignores NULL values. If you want to count those as well (which I can't imagine to make sense) write it like this:
SELECT
YEAR(FROM_UNIXTIME(a.date_assigned)) as d_year,
MONTHNAME(FROM_UNIXTIME(a.date_assigned)) as d_month,
l.website,
COUNT(COALESCE(l.id, 1))
FROM
assignments AS a
LEFT JOIN leads AS l on (l.id = a.id_lead)
WHERE id_dealership='$id_dealership2'
GROUP BY
d_year, d_month, website
Start with
SELECT
MONTHNAME(FROM_UNIXTIME(a.date_assigned)) as d_month,
YEAR(FROM_UNIXTIME(a.date_assigned)) as d_year,
SUM(IF(l.website='newsite.com',1,0) AS d_new,
SUM(IF(l.website IS NOT NULL AND l.website!='newsite.com',1,0) AS d_subprime
FROM assignments AS a
LEFT JOIN leads AS l ON l.id = a.id_lead
WHERE id_dealership='$id_dealership2'
GROUP BY
d_month,
d_year
ORDER BY
d_year asc,
MONTH(FROM_UNIXTIME(a.date_assigned)) asc
and work from here: The field id_dealership is neither in leads nor in assignments, so you need more work.
If you edit your question to account for id_dealership we might be able to help you further.