I have a table that consists of the following data, I would like to know whether it is possible to get a Month (i.e Jan, Feb) wise count of Reservations that happened and also Month wise count for each location.
PNR
Location
Reservation Date
Passenger Name
Travel Date
PNR81239087
Mumbai
2019-10-01 12:19:00
Ram
2019-11-06 15:59:00
PNR81239090
Kerala
2019-10-01 15:18:00
Kannan
2019-12-03 19:18:00
PNR812390199
Mumbai
2019-10-01 17:19:00
Ram
2019-11-01 18:39:00
For example,
Month Wise Count (including all locations) should look something like this,
Month
Count
October-2019
3
Monthwise count for each location:
Month
Count
Location
October-2019
2
Mumbai
October-2019
1
Kerala
I think this will work for you
Month Wise Count (including all locations) :
select MONTHNAME(Reservation_Date) as Month, count(*)
from yourTable
group by MONTHNAME(Reservation_Date)
Monthwise count for each location :
select MONTHNAME(Reservation_Date) as Month, count(*), Location
from yourTable
group by MONTHNAME(Reservation_Date), Location
EDIT IN QUESTION :
Changed to Group by Year and Month in one column:
Month Wise Count (including all locations) :
select concat(MONTHNAME(Reservation_Date),'-',Year(Reservation_Date)) as Month-Year,
count(*) as Count
from yourTable
group by concat(MONTHNAME(Reservation_Date),'-',Year(Reservation_Date))
Monthwise count for each location :
select concat(MONTHNAME(Reservation_Date),'-',Year(Reservation_Date)) as Month-Year,
count(*) as Count, Location
from yourTable
group by concat(MONTHNAME(Reservation_Date),'-',Year(Reservation_Date)), Location
You can use this :
/*Location-wise*/
SELECT DATENAME(MONTH, ReservationDate) as [Month],
COUNT(*) AS Count,
Location
FROM Temp
GROUP BY DATENAME(MONTH, ReservationDate), Location
ORDER BY Location DESC
/*All locations*/
SELECT DATENAME(MONTH, ReservationDate) as [Month],
COUNT(*) AS Count
FROM Temp
GROUP BY DATENAME(MONTH, ReservationDate)
You can see this working here : All locations and Locations-wise
Related
I have a table like this: Table Name: Accounting
year
acc
value
2018
in
500
2018
out
500
2019
in
600
2019
out
800
I need to show up to 10-year slots with the highest value (i.e in + out). For example, in this case, 2019 is the highest, my query should show
year
Max Value
2019
1400
My current SQL code is:
SELECT year,acc, MAX(value) as max_value
FROM Accounting
group by year,acc
LIMIT 10
How can I get the desired result?
You need SUM() and ORDER BY:
SELECT year,acc, SUM(value) as sum_value
FROM Accounting
GROUP BY year
ORDER BY sum_value DESC
LIMIT 1;
If you want only ten years to be considered, you need a WHERE clause, for instance:
SELECT year, SUM(value) as sum_value
FROM Accounting
WHERE year >= 2010
GROUP BY year
ORDER BY sum_value DESC
LIMIT 1;
I may be misunderstanding your question, but what it appears you are attempting to complete the following steps.
You are trying to SUM by year, regardless of account type, the amount in the value column.
You are trying to show only the years with the 10 highest summed values over some specified period of time.
One way to approach this would be as follows
SELECT year, SUM(value) as annual_value
FROM Accounting
GROUP BY year
ORDER BY annual_value desc
LIMIT 10
You have to use the SUM() not the MAX(), because you don't want only the highest value, but the total, and then you only have to GROUP BY them by year
SELECT year,sum(value) as max_value
FROM Accounting
group by year
LIMIT 10;
Here's the result:
+------+-----------+
| year | max_value |
+------+-----------+
| 2018 | 1000 |
| 2019 | 1400 |
+------+-----------+
I have requirement to get count of distinct department with total employees in period of month but unfortunately query is not working and throwing error
My table
Department_id emloyee_id date_time
1 1 2020-02-01
1 2 2020-02-04
3 7 2020-02-06
1 4 2020-02-07
expected output
total department=2
total employee of all department=4
But all should work based on last one record , I am getting sql syntax error
Query:
SELECT COUNT(DISTINCT department_id) x, COUNT(*) y
FROM department
WHERE date_time>=DATE_FORMAT(NOW() ,'%Y-%m-01')
AND date_time<DATE(NOW()+INTERVAL 1 DAY and status='1'
You can combine them within only one query :
SELECT COUNT(DISTINCT Department_id), COUNT(DISTINCT employee_id)
FROM department
WHERE date_time >= NOW() - INTERVAL 1 MONTH
AND status = '1';
counting both distinctly.
Update : If you mean to stay within the current month, then also
AND date_time>=DATE_FORMAT(NOW() ,'%Y-%m-01')
might be added to this query as in your original one.
It seems you should use month instead of day and are missing a bracket after month
SELECT COUNT(DISTINCT department_id) AS departments,
COUNT(*) AS employees
FROM department
WHERE date_time>=DATE_FORMAT(NOW() ,'%Y-%m-01')
AND date_time < DATE(NOW()+INTERVAL 1 MONTH)
AND status = '1';
I am calculating weighted formula for a field as sum(revenue)/ Sum(qty) and this is as per the below query. Now I will be creating a view that would store these results as I shown in code below.
My question is, if I select this w_revenue out of the view and want to see per year, how will I aggregate to show it per year? See desired outputs.
select month,item, sum(revenue)/ Sum(qty) as w_revenue,
year
from my_revenue_table
group by month, year,item;
create view xyz as
select month,item, sum(revenue)/ Sum(qty) as w_revenue,
year
from my_revenue_table
group by month, year,item;
select w_revenue
from xyz.
How do I do this so as to aggregate this per year?
Year Month Item Revenue Qty Sum(revenue)/Sum(Qty)
2019 Mar A 10 2 5
2019 Mar B 30 3 10
2019 Feb C 50 1 50
2019 Feb D 20 2 10
Expected value if I see per year:
Year Sum(revenue)/Sum(Qty)
2019 13.75 (10+30+50+20)/(2+3+1+2)
group on by year then create another view as
create view abc as
select sum(revenue)/ Sum(qty) as w_revenue, year
from my_revenue_table
group by year;
and call
select * from xyz union all
select null, null, a.* from abc a
to combine them, if I understood you correctly.
or revenue per year repeating at every row as
select x.*,
(select w_revenue
from abc
where year = x.year) as w_revenue_year
from xyz x
You cannot do the aggregation you want from the view. You don't have enough information.
If you change the view to something like this:
create view xyz as
select year, month, item,
sum(revenue)/ Sum(qty) as w_revenue,
sum(qty) as total_qty
from my_revenue_table
group by month, year, item;
Then you can aggregate the results as:
select year, sum(w_revenue * total_qty) / sum(total_qty)
from xyz
group by year;
EDIT:
Or just modify the view to have the information you want:
create view xyz as
select year, month, item,
sum(revenue)/ Sum(qty) as w_revenue,
sum(qty) as total_qty,
(sum(sum(revenue)) over (partition by year, item) /
sum(sum(qty)) over (partition by year, item)
) as w_revenue_year
from my_revenue_table
group by month, year, item;
So what i'm trying to do here, is that i am trying to count the number of repeat users (users who made more than one order) in a period of time, let it be month day or year, the case here is months
i'm currently running mysql mariadb and i'm pretty much a beginner in mysql, i've tried multiple subqueries but all have failed till now
This is what i have tried so far ..
This returns all the number of users with no ordering count condition
Since people are asking for sample data, here is what the data is looking like at the moment:
Order_Creation_Date - User_ID - Order_ID
2019-01-01 123 1
2019-01-01 123 2
2019-01-01 231 3
2019-01-01 231 4
This is the query i am using to get the result but it keeps on returning total number of users within the month
select month(o.created_at)month,
year(o.created_at)year,
count(distinct o.user_uuid) from orders o
group by month(o.created_at)
having count(*)>1
and this returns the number of users as 1 ..
select month(o.created_at)month,
year(o.created_at)year,
(select count(distinct ord.user_uuid) from orders ord
where ord.user_uuid = o.user_uuid
group by ord.user_uuid
having count(*)>1) from orders o
group by month(o.created_at)
Expected result will be from the sample data above
Month Count of repeat users
1 2
If you want the number of users that make more than one purchase in January, then do two levels of aggregations: one by user and month and the other by month:
select yyyy, mm, sum( num_orders > 1) as num_repeat_users
from (select year(o.created) as yyyy, month(o.created) as mm,
o.user_uuid, count(*) as num_orders
from orders o
group by yyyy, mm, o.user_uuid
) o
group by yyyy, mm;
I think you should try something like this which will return USer_ID list Month and Year wise who ordered more that once for the period-
SELECT
[user_uuid],
MONTH(o.created_at) month,
YEAR(o.created_at) year,
COUNT(o.user_uuid)
FROM orders o
GROUP BY
MONTH(o.created_at),YEAR(o.created_at)
HAVING COUNT(*) > 1;
For more, if you are looking for the count that how many users placed more that one order, you can just place the above query as a sub query and make a count on column 'user_uuid'
UserId, SRC, DST, Mode, Dist, Year
1,CHN,IND,airplane,200,1990
2,IND,CHN,airplane,200,1991
3,IND,CHN,airplane,200,1992
4,RUS,IND,airplane,200,1990
5,CHN,RUS,airplane,200,1992
6,AUS,PAK,airplane,200,1991
I want to find the total distance traveled by a user in a particular year.
Ex: <Id> <Distance> <year>
1 200 1991
1 600 1993
2 400 1991
2 200 1992
How do I write query for this?
You need to add holidays.year in group by clause
select holidays.id, sum(holidays.distance) as totaldistance, holidays.year
from holidays
group by holidays.id ,holidays.year
order by holidays.id ASC
Your groupings are UserID and Year so:
SELECT UserID, SUM(Dist), Year
FROM table
GROUP BY UserID,Year
SELECT USERID, YEAR, SUM (DIST)
FROM TABLE_USER_DISTANCE
GROUP BY USERID, YEAR;