I'm trying to convert a raw query to a Laravel query builder but when I use the raw method I can't make it to write in a query builder
Here is my raw query
SELECT GROUP_CONCAT(CONCAT(a.qty,' ',a.uqc) SEPARATOR ' ,') as quantity,a.exporter
FROM (select sum(shipping_bill_items.quantity) as qty, `exporters`.name as exporter,`shipping_bill_items`.uqc
from `shipping_bill_items`
inner join `shipping_bill` on `shipping_bill`.`id` = `shipping_bill_items`.`shipping_bill_id`
inner join `exporters` on `exporters`.`id` = `shipping_bill`.`exporter_id`
group by `exporters`.name,`shipping_bill_items`.`uqc`
ORDER BY `exporters`.`name` ASC ) a
group by a.exporter;
I tried to write seems couldn't help any please help me to rewrite this!
below which I tired to rewrite attempt to solve the problem
$Details=DB::select('a.exporter')
->addSelect(DB::raw("GROUP_CONCAT(CONCAT(a.qty,' ', a.uqc) SEPARATOR ' ,') as quantity"))
->from("select sum(shipping_bill_items.quantity) as qty, 'exporters'.name as exporter, 'shipping_bill_items'.uqc from 'shipping_bill_items' inner join 'shipping_bill' on 'shipping_bill'.'id' = 'shipping_bill_items'.'shipping_bill_id' inner join 'exporters' on 'exporters'.'id' = 'shipping_bill'.'exporter_id' group by 'exporters'.name, 'shipping_bill_items'.'uqc' ORDER BY 'exporters'.'name' ASC as a")
->groupBy('a.exporter')
->get();
I tried to add an image for references but I couldn't add it here is the table that I want to achieve a result
quantity
exporter
45.65 MTS
1st Exporter
1404.25 LTR,114170 NO
2nd Exporter
5168 NOS,47856 PCS,74648 SET
3ed Exporter
Related
I have the following query:
SELECT OBJ_DESC_ERRORS.description, OBJ_DESC_ERRORS.object, OBJ_DESC_ERRORS.count_errors, OBJ_ERRORS.count_total FROM
(SELECT `metrics_event`.`description`, `metrics_event`.`object`, COUNT(`metrics_event`.`id`) AS `count_errors` FROM `metrics_event`
INNER JOIN `metrics_session` ON (`metrics_event`.`session_id` = `metrics_session`.`id`)
WHERE (`metrics_session`.`training_id` = 4 AND NOT (`metrics_session`.`completed_at` IS NULL) )
GROUP BY `metrics_event`.`description`, `metrics_event`.`object` ORDER BY `count_errors` DESC ) as OBJ_DESC_ERRORS
JOIN
(SELECT `metrics_event`.`object`, COUNT(`metrics_event`.`id`) AS `count_total` FROM `metrics_event`
INNER JOIN `metrics_session` ON (`metrics_event`.`session_id` = `metrics_session`.`id`)
WHERE (`metrics_session`.`training_id` = 4 AND NOT (`metrics_session`.`completed_at` IS NULL) )
GROUP BY `metrics_event`.`object` ORDER BY `count_total` DESC ) as OBJ_ERRORS
ON OBJ_DESC_ERRORS.object = OBJ_ERRORS.object
which produces the following result:
As you can see I'm basically running the same query twice. The reason for that is that I need to have that count_errors broken down by each aggregation of object + description, but I also need the count_total to be only aggregated by object. This was the way I could think of. Now I'd like to know if this is the best I can do or if it can be optimized even further.
If so I have no clue how. Googling and searching similar topics on this is difficult because the optimization task depends on the query itself, so keywords here didn't help me much.
Get rid of the inner ORDER BYs; they do nothing useful.
Rewrite the query something like this:
SELECT
me.description,
me.object,
SUM(...) AS count_errors,
SUM(...) AS count_total
FROM `metrics_event` AS me
INNER JOIN `metrics_session` AS ms ON (me.`session_id` = ms.`id`)
WHERE ms.`training_id` = 4
ms.`completed_at` IS NOT NULL
GROUP BY me.`description`, me.`object`
ORDER BY `count_total` DESC
Since a boolean expression evaluates as 1 for TRUE, else 0, devise the argument to SUM() to be a boolean expression that provides the desired COUNT.
i have some query and i just know how to query on mysql (phpmyadmin)
i got information if using DB::select we cannot to use paginate, so we need change to DB::table(some query) to using pagination.
but the problem is i am confuse how to convert my query into DB::table(some query)
Here is my code
$daily = DB::select("
SELECT
employees.employee_name,
COUNT(DISTINCT DATE(attendance.attendance_datetime)) as jumlah,
locations.location_name,
TIME(MIN(attendance.attendance_datetime)) as check_in,
CASE
WHEN ISNULL(TIME(MIN(attendance.attendance_datetime))) THEN attendance_absence.remarks
WHEN TIME(MIN(attendance.attendance_datetime)) > '08:05:00' THEN (SELECT TIMEDIFF('08:05:00', MIN(TIME(attendance_datetime))))
WHEN TIME(MIN(attendance.attendance_datetime)) <= '08:05:00' THEN 'Good'
ELSE 'No Record'
END as detail_telat,
attendance_absence.remarks as remarks
FROM
employees
LEFT JOIN attendance ON employees.employee_name = attendance.attendance_name AND DATE(attendance.attendance_datetime) = '$date'
LEFT JOIN locations ON employees.location_id = locations.id
LEFT JOIN attendance_absence ON attendance_absence.employee_name = employees.employee_name AND attendance_absence.absences_date = '$date'
WHERE locations.location_name LIKE '%'
GROUP BY employees.employee_name
ORDER BY employees.employee_name
")->paginate(3);
please help me to convert my query into eloquent or query builder, or any suggestion ?
Currently, pagination operations that use a groupBy statement cannot be executed efficiently by Laravel. If you need to use a groupBy with a paginated result set, it is recommended that you query the database and create a paginator manually.
Check documentation
I have a query:
SELECT hs.*
FROM hire_screening hs
INNER JOIN
(SELECT resume_id, MAX(created_date) AS MaxDateTime
FROM hire_screening
GROUP BY resume_id) hire_screening
ON hs.resume_id = hire_screening.resume_id
AND hs.created_date = hire_screening.MaxDateTime
This is my table:
I need the answer like this:
I tried this:
$query = HireScreening::find()-
->select(["hire_screening.screening_id","hs.resume_id",
"MAX(hs.created_date) AS
MaxDateTime","hs.screening_by","hsl.screening_level as
hr_level","hss.screening_status as
hr_status","hr.candidate_name","hsm.screening_mode as
hr_mode","hire_screening.created_date","hs.screening_date"])
->innerJoin('hire_screening as hs','hs.resume_id =
hire_screening.resume_id')
->leftJoin('hire_screening_level as
hsl','hire_screening.screening_level = hsl.id')
->leftJoin('hire_screening_mode as
hsm','hire_screening.screening_mode = hsm.id')
->leftJoin('hire_screening_status as
hss','hire_screening.screening_status = hss.id')
->leftJoin('hire_resume as
hr','hire_screening.resume_id=hr.resume_id')
//->where(['hire_screening.created_date = MaxDateTime'])
->groupBy(['resume_id']);
//->having(['hire_screening.created_date' =>
'hs.MaxDateTime']);
$query->orderBy(['created_date' => SORT_DESC]);
But it didn't shows the answer. I need the distinct resume_id's with latest created date. The sql query shows the correct answer.I want to write this query in my search model. Please help me to convert this query into yii2.
If there is a table MyTable, then you can use simplier query grouping the table by resume_id:
SELECT
screening_id,
resume_id,
screening_by,
screening_date,
screening_level,
screening_mode,
screening_status,
reject_reason,
remarks,
created_by,
MAX(created_date) AS created_date
FROM MyTable
GROUP BY resume_id;
Using simplify query helps to avoid an errors. Also you could create a view or a stored procedure using the query and call this from your PHP code.
I am in the process of building a dashboard and need to extract some data from a somewhat complex schema.
I have a select statement (see below) that I am using to extract information, but need to conduct some filtering on part of the select statement, and I'm struggling.
select distinct j.id 'Job_Id'
, js.outcome 'Outcome'
,(select string from property where parent_sheet_id = ps.id and name= 'Build_Type') as 'Build_Type'
from job j, job_step js, property_sheet ps, property p
where j.id = js.job_id
and ps.entity_id=js.id
and ps.id=p.parent_sheet_id
and ps.entity_type='step'
and p.name = 'Id'
group by j.id
order by j.id desc;
I am sure that there is a better way of doing this query, and I would appreciate any other suggestions, but I am mostly attempting to place a filter on the nested select statement which has an alias of "Build_Type", but when I try it appears not to work. I've read some blogs that this is not possible, so I am a little stuck.
Any help would be much appreciated.
Thanks.
select
ps.id,
Build_Type.string
from
property_sheet as ps
left join
property as Build_Type
on ps.id = Build_Type.parent_sheet_id and Build_Type.name = 'Build_Type'
where Build_Type....
MySQL Server Version: Server version: 4.1.14
MySQL client version: 3.23.49
Tables under discussion: ads_list and ads_cate.
Table Relationship: ads_cate has many ads_list.
Keyed by: ads_cate.id = ads_list.Category.
I am not sure what is going on here, but I am trying to use COUNT() in a simple agreggate query, and I get blank output.
Here is a simple example, this returns expected results:
$queryCats = "SELECT id, cateName FROM ads_cate ORDER BY cateName";
But if I modify it to add the COUNT() and the other query data I get no array return w/ print_r() (no results)?
$queryCats = "SELECT ads_cate.cateName, ads_list.COUNT(ads_cate.id),
FROM ads_cate INNER JOIN ads_list
ON ads_cate.id = ads_list.category
GROUP BY cateName ORDER BY cateName";
Ultimately, I am trying to get a count of ad_list items in each category.
Is there a MySQL version conflict on what I am trying to do here?
NOTE: I spent some time breaking this down, item by item and the COUNT() seems to cause the array() to disappear. And the the JOIN seemed to do the same thing... It does not help I am developing this on a Yahoo server with no access to the php or mysql error settings.
I think your COUNT syntax is wrong. It should be:
COUNT(ads_cate.id)
or
COUNT(ads_list.id)
depending on what you are counting.
Count is an aggregate. means ever return result set at least one
here you be try count ads_list.id not null but that wrong. how say Myke Count(ads_cate.id) or Count(ads_list.id) is better approach
you have inner join ads_cate.id = ads_list.category so Count(ads_cate.id) or COUNT(ads_list.id) is not necessary just count(*)
now if you dont want null add having
only match
SELECT ads_cate.cateName, COUNT(*),
FROM ads_cate INNER JOIN ads_list
ON ads_cate.id = ads_list.category
GROUP BY cateName
having not count(*) is null
ORDER BY cateName
all
SELECT ads_cate.cateName, IFNULL(COUNT(*),0),
FROM ads_cate LEFT JOIN ads_list
ON ads_cate.id = ads_list.category
GROUP BY cateName
ORDER BY cateName
Did you try:
$queryCats = "SELECT ads_cate.cateName, COUNT(ads_cate.id)
FROM ads_cate
JOIN ads_list ON ads_cate.id = ads_list.category
GROUP BY ads_cate.cateName";
I am guessing that you need the category to be in the list, in that case the query here should work. Try it without the ORDER BY first.
You were probably getting errors. Check your server logs.
Also, see what happens when you try this:
SELECT COUNT(*), category
FROM ads_list
GROUP BY category
Your array is empty or disappear because your query has errors:
there should be no comma before the FROM
the "ads_list." prefix before COUNT is incorrect
Please try running that query directly in MySQL and you'll see the errors. Or try echoing the output using mysql_error().
Now, some other points related to your query:
there is no need to do ORDER BY because GROUP BY by default sorts on the grouped column
you are doing a count on the wrong column that will always give you 1
Perhaps you are trying to retrieve the count of ads_list per ads_cate? This might be your query then:
SELECT `ads_cate`.`cateName`, COUNT(`ads_list`.`category`) `cnt_ads_list`
FROM `ads_cate`
INNER JOIN `ads_list` ON `ads_cate`.`id` = `ads_list`.`category`
GROUP BY `cateName`;
Hope it helps?